Pptg101213 Motion Gallego

69
Describing Motion |Graphing Motion |Problems Related to Motion 28 July 2012 1 REDG 2011

Transcript of Pptg101213 Motion Gallego

Page 1: Pptg101213 Motion Gallego

Describing Motion |Graphing Motion |Problems Related to Motion

28 July 2012 1 REDG 2011

Page 2: Pptg101213 Motion Gallego

Motion

28 July 2012 2 REDG 2011

What is your speed from house to school?

Do you have the same speed from school to house?

Page 3: Pptg101213 Motion Gallego

Motion

28 July 2012 3 REDG 2011

What is your average speed?

Page 4: Pptg101213 Motion Gallego

Motion

28 July 2012 4 REDG 2011

total distance traveled

total time of travel =

Distance (within the trip)

total time to cover that distance =

sum of speeds

number of speeds added =

Page 5: Pptg101213 Motion Gallego

Motion

28 July 2012 5 REDG 2011

Calculate the average speed and the instantaneous speeds at t=1, t=2 and t=3.

Page 6: Pptg101213 Motion Gallego

Motion

28 July 2012 6 REDG 2011

Calculate the average velocity and the instantaneous velocities at t=1, t=2 and t=3.

Page 7: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 7 REDG 2011

Punzy’s home is 10km away from his school. Every morning, he rides jeeney with his friends and travel for 15 minutes. What is the average speed of Punzy’s jeepney?

Page 8: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 8 REDG 2011

Johnny the Walker walks from his house to his farm 150 meters away in 10 min. Calculate his speed in m/s. At this speed, how long will it take him to cover 1 km?

Page 9: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 9 REDG 2011

Wind Airlines travels from Chimp Island to Bulbagaga that are 600km apart. The plane travels at the speed of 450km/h. If it leaves the Chimp Island at 3:00pm, what time will it arrive in Bulbagaga?

Page 10: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 10 REDG 2011

Woogie Boogie has been running for 2 hours and 15 minutes at a maintained speed of 30 kilometer per hour. How far has he covered?

Page 11: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 11 REDG 2011

A student drives 4.8-km trip to school and averages a speed of 22.6 m/s. On the return trip home, the student travels with an average speed of 16.8 m/s over the same distance. What is the average speed (in m/s) of the student for the two-way trip?

Page 12: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 12 REDG 2011

One car traveling at 30 kph and another car traveling at 40 kph left from the same place at the same time and traveled in opposite directions. How long will it take before the cars are 630 kilometers apart?

Page 13: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 13 REDG 2011

Two teams are competing in swimming relay races. Swimmer A pushes off two seconds ahead of Swimmer B with 50m left to go. If swimmer A swims at an average speed of 1.9m/s and swimmer B swims at an average speed of 2.1m/s, who wins the race? How far ahead (in seconds and meters) is the winner?

Page 14: Pptg101213 Motion Gallego

Motion

28 July 2012 14 REDG 2011

Determine the maximum speed based on the data

given

Consider the data below for the first 10 minutes of a teacher’s

trip along SRP to school.

Time

(min)

Position

(km)

0 0

1 0.4

2 0.8

3 1.3

4 2.1

5 2.5

6 2.7

7 3.8

8 5.0

9 6.4

10 7.6

Page 15: Pptg101213 Motion Gallego

Motion

28 July 2012 15 REDG 2011

Plot the data in a graph.

The position-time information of a giant turtle is shown in the data table below.

Time (h) Position (km)

0 0

1 0.3

2 0.6

3 0.9

4 1.2

5 1.5

6 1.8

Page 16: Pptg101213 Motion Gallego

Motion

28 July 2012 16 REDG 2011

Determine the speed per time interval.

The position-time information of a giant turtle is shown in the data table below.

Time (h) Position (km) Speed (km/h)

0 0

1 0.3

2 0.6

3 0.9

4 1.2

5 1.5

6 1.8

Page 17: Pptg101213 Motion Gallego

Motion

28 July 2012 17 REDG 2011

Plot the speed vs time graph

The position-time information of a giant turtle is shown in the data table below.

Time (h) Position (km) Speed (km/h)

0 0 0

1 0.3 0.3

2 0.6 0.3

3 0.9 0.3

4 1.2 0.3

5 1.5 0.3

6 1.8 0.3

Page 18: Pptg101213 Motion Gallego

Motion

28 July 2012 18 REDG 2011

0

0.3

0.6

0.9

1.2

1.5

1.8

2.1

0 1 2 3 4 5 6

Position

(km)

time (h)

Page 19: Pptg101213 Motion Gallego

The Slope

28 July 2012 19 REDG 2011

0

0.3

0.6

0.9

1.2

1.5

1.8

2.1

0 1 2 3 4 5 6

Position

(km)

time (h)

x (xf –xi)

y (yf –yi)

Page 20: Pptg101213 Motion Gallego

The Slope

28 July 2012 20 REDG 2011

The slope of the position versus time graph is SPEED or VELOCITY

Page 21: Pptg101213 Motion Gallego

The Slope

28 July 2012 21 REDG 2011

v

t

(a) Data of the travel (b) Position versus time of (a)

(c) Velocity versus time graph of (b)

Page 22: Pptg101213 Motion Gallego

The Slope

28 July 2012 22 REDG 2011

Rank the lines above from the one with the lowest to highest velocity.

d

t

A

B

C

Page 23: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 23 REDG 2011

Provide the speed versus time graph of the graphs above.

d

t

A

B

C

v

t

A

B

C

Page 24: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 24 REDG 2011

Translate the following verbal descriptions into d vs t graphs. Draw two lines per graph.

A. moving slow B. moving fast

1 A. moving in + constant velocity

B. moving in – constant velocity

2 A. moving in increasing +velocity

B. moving in decreasing +velocity

3 A. moving in increasing -velocity

B. moving in decreasing -velocity

4

Page 25: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 25 REDG 2011

Translate the following verbal descriptions into graphs. Draw two lines per graph.

d

t

B

A

A. moving slow B. moving fast

1

Page 26: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 26 REDG 2011

Translate the following verbal descriptions into graphs. Draw two lines per graph.

d

t B

A

A. moving in + constant velocity B. moving in – constant velocity

2

Page 27: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 27 REDG 2011

Translate the following verbal descriptions into graphs. Draw two lines per graph.

d

t

A

B

A. moving in increasing +velocity B. moving in decreasing +velocity

3

Page 28: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 28 REDG 2011

Translate the following verbal descriptions into graphs. Draw two lines per graph.

d

t

A

B

A. moving in increasing -velocity B. moving in decreasing -velocity

4

Page 29: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 29 REDG 2011

Describe the velocity of the object.

position, d

time, t

Page 30: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 30 REDG 2011

Describe the velocity of the object.

position, d

time, t

Page 31: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 31 REDG 2011

Describe the velocity of the object.

position, d

time, t

Page 32: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 32 REDG 2011

Describe the velocity of the object.

position, d

time, t

Page 33: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 33 REDG 2011

Act the motion

position, d

time, t

Page 34: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 34 REDG 2011

The motions of several objects is depicted in the position vs time graph below.

Which object(s) is/are at rest (not moving)?

Page 35: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 35 REDG 2011

The motions of several objects is depicted in the position vs time graph below.

Which object(s) is/are changing direction?

Page 36: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 36 REDG 2011

The motions of several objects is depicted in the position vs time graph below.

Which object(s) is/are accelerating?

Page 37: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 37 REDG 2011

The motions of several objects is depicted in the position vs time graph below.

Which object is traveling the fastest?

Page 38: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 38 REDG 2011

The motions of several objects is depicted in the position vs time graph below.

Which object is traveling the slowest?

Page 39: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 39 REDG 2011

What is the slope of velocity versus time graph?

ACCELERATION

Page 40: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 40 REDG 2011

Describe the acceleration of the graph below

v

t

v

t

v

t constant positive constant negative zero

Page 41: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 41 REDG 2011

total distance traveled

total time of travel =

Distance (within the trip)

total time to cover that distance =

sum of speeds

number of speeds added =

Page 42: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 42 REDG 2011

What is Car A’s speed at t=50s?

What is the difference between the motion of Car A and Car B?

Page 43: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 43 REDG 2011

What is Car A’s acceleration during t=8 and t=10?

Which car has greater velocity at t=6?

Which car has greater acceleration at t=6?

Page 44: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 44 REDG 2011

What is the car’s acceleration during the interval AB?

Describe the car’s motion at during the interval FG?

Page 45: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 45 REDG 2011

During which time interval is the acceleration the greatest?

Page 46: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 46 REDG 2011

What is the maximum speed reached by the object during the entire travel?

Page 47: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 47 REDG 2011

During the interval t=8 to t=10, describe what is happening to the motion of the object?

Page 48: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 48 REDG 2011

t=1s t=2s t=4s t=6s t=3s t=5s

1

t=1s t=2s t=4s t=6s t=3s t=5s

2

t=1s t=2s t=4s t=6s t=3s t=5s 3

Page 49: Pptg101213 Motion Gallego

Graphical Analysis

28 July 2012 49 REDG 2011

The red dots below are oil drop patterns of Car A and Car B. Each dot was made 1s after the other. Tell whether each statement is TRUE or FALSE.

Both cars have a constant velocity.

Both cars have an accelerated motion.

Car A is accelerating, Car B is not.

Car B is accelerating, Car A is not.

Car B is has greater acceleration than Car A.

Page 50: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 50 REDG 2011

Page 51: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 51 REDG 2011

total distance traveled

total time of travel =

Distance (within the trip)

total time to cover that distance =

sum of speeds

number of speeds added =

Page 52: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 52 REDG 2011

This is called speedometer. What does it measure, average speed or instantaneous

speed?

Page 53: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 53 REDG 2011

The speedometer in every car also has an odometer that records the distance traveled. If it reads zero at the start of the trip and 35km half an hour later, what is its average speed in km/h?

Page 54: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 54 REDG 2011

Constant Velocity

How far does a car reach if it is running at a constant speed of 10m/s for 3 seconds?

Page 55: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 55 REDG 2011

Constant Velocity

If a cheetah can maintain a constant speed of 25m/s, it will cover 25 meters every second. At this rate, how far will it travel in 10 seconds? In 1 minute?

Page 56: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 56 REDG 2011

Constant Velocity

A car traveled a total distance of 45m in 15 seconds. What is the car’s speed?

Page 57: Pptg101213 Motion Gallego

Accelerated Motion

28 July 2012 57 REDG 2011

Rate of change of velocity ACCELERATION

Page 58: Pptg101213 Motion Gallego

Accelerated Motion

28 July 2012 58 REDG 2011

Accelerating

A graphical representation of the motion of Lola’s pink car is illustrated below. What is the acceleration of her car?

Page 59: Pptg101213 Motion Gallego

Accelerated Motion

28 July 2012 59 REDG 2011

Accelerating

A car that changes its speed from 5m/s to 10m/s in 5 seconds undergoes an acceleration of 1m/s2.

Page 60: Pptg101213 Motion Gallego

Accelerated Motion

28 July 2012 60 REDG 2011

Accelerating

In 5 seconds, a car moving in a straight line increases its speed from 50km/h to 65 km/h, while a truck goes from rest to 15km/h in a straight line. Which undergoes a greater acceleration? What is the acceleration of each vehicle?

Page 61: Pptg101213 Motion Gallego

Accelerated Motion

28 July 2012 61 REDG 2011

Accelerating

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car.

Page 62: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 62 REDG 2011

1 2 3 4

Page 63: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 63 REDG 2011

f i

f i

f i

v va

t

at v v

v v at

2

ave

ave

f i

dv

t

d v t

v vd t

2

2

2

2

2

2

2

2

1

2

f i

i i

i i

i

i

v vd t

v at vd t

v t at v td

v t atd

d v t at

2 2

2

2

2

f i

f i f i

f i

v vd t

v v v v

a

v vd

a

f iv vt

a

Solve for t

1 2 3 4

Page 64: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 64 REDG 2011

Identify the given and the “required” of the following problems. Write the frame formula of each.

An airplane accelerates down a runway at 3.20m/s2 for 32.8s until finally lifts off the ground. Determine the distance traveled before take-off.

Page 65: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 65 REDG 2011

Identify the given and the “required” of the following problems. Write the frame formula of each.

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled.

Page 66: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 66 REDG 2011

Identify the given and the “required” of the following problems. Write the frame formula of each.

A feather is dropped on the moon from a height of 1.40 meters. The feather accelerates to the ground at 1.67m/s2. Determine the time for the feather to fall to the surface of the moon.

Page 67: Pptg101213 Motion Gallego

Problem Solving (Related to Motion)

28 July 2012 67 REDG 2011

Identify the given and the “required” of the following problems. Write the frame formula of each.

A bullet leaves a rifle with a muzzle velocity of 521m/s. while accelerating through the barrel of the rifle, the bullet moves a distance of 0.840m. Determine the acceleration of the bullet.

Page 68: Pptg101213 Motion Gallego

28 July 2012 68 REDG 2011

Most explanation and examples in this presentation are based of the lesson presentation of The Physics Classroom & Conceptual Physics. The clip arts used were taken from

different sites that I thought are free to use. This is for classroom use only.

Page 69: Pptg101213 Motion Gallego

Pass your assignment

28 July 2012 REDG 2011 69