Performance Test on Pelton Wheel Turbine
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Transcript of Performance Test on Pelton Wheel Turbine
7/18/2019 Performance Test on Pelton Wheel Turbine
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PERFORMANCE TEST ON PELTON WHEEL TURBINE
AIM: To conduct performance test on the given Pelton wheel turbine
APPARATUS: Pelton wheel turbine test rig.
SPECIFICATIONS:
v SUPPLY PUMP / MOTOR
CAPACITY : 5 hp, 3 ph, 440V, 50Hz, AC.
v TURBINE
- Mean Dia. : 250mm
- No. of Buckets : 20
- Dia. Of Jet : 18mm- Runaway Speed : 1800 RPM
- Turbine Head : 24 - 46 mts (min to max.)
v LOADING : Brake Drum
v BRAKE DRUM RADIUS : 0.15m
v MAX. SHAFT OUTPUT
FROM TURBINE : 2.5 hp. (Approx.)
vCOEFFICIENT OF DISCHARGE : Cd = 0.98
DESCRIPTION OF APPARATUS:
The actual experimental facility supplied consists of a Centrifugal Pump
Set, Turbine Unit, Sump Tank, Collecting, Notch Tank arranged in such a way
that the whole unit works on recirculation water system. The Centrifugal Pump
Set supplies the water from the sump tank to the turbine through control valve
which has the marking to meter the known quantity of water. The water after
passing through the Turbine units enters the collecting tank. The water then
flows back to the sump tank through Notch tank which is fixed with 600 V-
notch for the measurement of flow rate.
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The loading of the turbine is achieved by rope brake drum connected to
spring balance. The provision for measurement of turbine speed (digital RPM
indicator), Head on turbine (pressure gauge) are built in on the control panel.
THEORY:
Hydraulic (or Water) Turbines are the machines, which uses the energy of
water (Hydro-Power) and convert it into mechanical energy. Thus the turbines
becomes the prime mover to run the electrical generators to produce the
electricity, Viz, Hydro-electric power.
The turbines are classified as Impulse & Reaction types. In impulse
turbine, the head of water is completely converted into a jet, which impulses the
forces on the turbine. In reaction turbine, it is the pressure of following water,
which rotates the runner of turbine. Of many types of turbine, the Pelton wheel,
most commonly used, falls into the category of turbines. While Francis &
Kaplan falls in category of impulse reaction turbines.
A Turbine acts as a pump in reverse, to subtract energy from a fluid
system. In impulse turbine the fluid energy, first in the potential form, is next
converted wholly into the kinetic energy by means of one nozzle before striking
the runner. The jet ensuing from the nozzle is made to impinge on the runner
tangentially as shown in the figure. A powerful jet issues out of the nozzle,
impinges on the buckets provided on the periphery of the nozzle. In practice
these buckets are usually spoon shaped, with a central ridge splitting the
impinging jet into two halves which are deflected backward. As there is no
pressure variation in flow, the fluid partly fills the buckets and the fluid remains
in contact with the atmosphere. The nozzle is provided with spear mechanism
to control the quantity of the water. The actual energy transfer from jet to wheel
is by changing the momentum of the stream. The impact thus produced causes
the runner to rotate and hence produces mechanical power at the shaft.
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The main parts of a Pelton turbine are:
a) Spear Valve Mechanism :
In a Pelton turbine the flow regulation is done with the help of a spear
shaped needle valve. It consists of a spear connected to a shaft with a
hand wheel at its end.
By rotating the hand wheel the spear valve can be moved inside the
nozzle axially. When the spear is moved forward it reduces the flow area
and hence flow through nozzle reduces, similarly when it is moved
backwards flow increases. Water flow can also be regulated by the gate
valve provided.
b) Runner with Buckets :
The runner consists of a circular disc with a number of evenly spaced
double hemispherical buckets fixed along its periphery. The disc is
mounted on a shaft. The buckets are divided into two parts by a sharp
splitter edge at the centre, which divides striking of the jet into two equal
parts. The buckets are so shaped that after flowing around its inner
surface, the water leaves it with a relative velocity almost opposite in
direction to the original jet but does not interface with the passage of
water to the bucket preceding it during rotation. There is notch cut at
outer rim of each bucket only when it is almost normal to the jet.c) Casing :
The casing of a Pelton turbine has no hydraulic function to perform. It is
provided only to prevent splashing and to lead the water to the tailrace. It
is generally made up of stainless steel and it is fabricated to form ‘D’
section. Front part of the casing is made of acrylic.
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PROCEDURE:
1) Connect the supply water pump-water unit to 3 ph, 440V, 30A, electrical
supply, with neutral and earth connections and ensure the correct
direction of the pump motor unit.
2) Keep the Gate Valve and Sphere valve closed.
3) Keep the Brake Drum loading at zero.
4) Press the green button of the supply pump starter. Now the pump picks-
up the full speed and becomes operational.
5) Slowly open the Sphere Valve so that the turbine rotor picks the speed
and conduct experiment on constant speed and constant head.
6) Note down the speed, load, and pressure gauge readings.
Tabulate the readings.
A. TO OBTAIN CONSTANT SPEED CHARACTERISTICS: (Operating Characteristics)
1) Keep the Spear Valve opening at some speed.
2) For different brake drum loads on the Turbine change the gate valve
setting between maximum and minimum so that the speed is held
constant.
3) Tabulate the readings as per Table given.
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CONSTANT SPEED CHARATERISTICS
METHOD: By keeping sphere valve position maximum and
By changing the Gate valve position.
SPEED OFTHE
TURBINE‘N’ RPM
INLETPRESSURE
‘PI’ inKg/cm2
THROATPRESSURE
‘PT’ inKg/cm2
LOAD ‘F1’
In Kg
LOAD ‘F2’
In Kg
DIFFERENCEOF PI & PT ‘h’
in Kg/cm2
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B. TO OBTAIN CONSTANT HEAD CHARACERISTICS:
1) Keep the Spear valve at a particular position and adjust the gate
Valve setting so as to get corresponding pressure.2) For different Brake Load, note down the speed, pressure gauge,
vacuum gauge. Tabulate the readings as per Table given.
SPEED OF
THE
TURBINE
‘N’ RPM
INLET
PRESSURE
‘PI’ in
Kg/cm2
THROAT
PRESSURE
‘PT’ in
Kg/cm2
LOAD ‘F1’
In Kg
LOAD ‘F2’
In Kg
DIFFERENCE
OF PI & PT ‘h’
in Kg/cm2
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CALCULATIONS
1. Head on Turbine in meters of water ‘H’ :
H = 10 PI in m of water.
Where, P is the Pressure Gauge reading in Kg / cm2.
2. Flow Rate of Water through the Turbine ‘Q’ :
A1x A2 √2g HV
Qtheo
= Cd x ----------------------- m3 /sec
√ (A12
- A22)
Where, A1 = Area of Intel section of venturi = πD12/4 in m
2
A2 = Area of Throat section of venturi= πD22/4 in m2
A1 = Area of inlet section = 1.963 x 10-3
m2
D1 = Inlet diameter = 0.05 m
A2 = Area of inlet section = 4.91 x 10-4
m2
D2 = Throat diameter = 0.025 m
Hv = 10 x h in mtrs
h = (Difference in pressure read from pressure gauge)
3. Hydarulic input to the turbine, Phyd
:
Phyd
= (W Q H)/1000 in kW
Where, W = Specific Weight of the water.
= 9810 N/m3
Q = Discharge in m3/sec (From formulae – 2)
H = Head on turbine in m of water. (From formulae – 1)
4. Break power of the turbine:
2 x π x N x ( F1 - F
2 ) x 9.81 x r
BP = ----------------------------------------
60000
Where,‘N’ is speed in rpm,
‘F1’&‘F
2’ = Load in Kgf,
r = 0.145 m radius of brake drum.
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5. Turbine Efficiency :
% ηtur
= BP / Phyd
x 100
6. Unit quantities - under unit head,
a) Unit speed, Nu = N / H1/2
Where, N = Speed in rpm
H = Head in m.
b) Unit power, Pu = P / H3/2
Where, P = Power output BPshaft in watts
H = Head in m.
c) Unit discharge, Qu = Q / H1/2
Where, Q = Discharge in m
3
/sec H = Head in m.
7. Specific speed,
N P1/2
Ns = ---------
H5/4
Where, N = Speed in rpm
P = Power output BPshaft in watts
H = Head in m.
Part load BPSHAFT
8. Percentage full load = ----------------------- x 100
Max. Load BPSHAFT
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TABLE OF CALCULATIONS(CONSTANT HEAD)
SPEED OF
THETURBINE‘N’ RPM
H in meters Discharge ,Qin m3/sec
Power
Output,BPshaft in KW
Hydraluic
Power, Phyd
in kWTurbine
Efficiency
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UNIT QUANTITIES UNDER UNIT HEAD
Unit Speed,
“Nu”
Unit Power,
“Pu”
Unit Discharge,
“Qu”
Specific speed
“Ns”
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GRAPHS:
FOR CONSTANT HEAD METHOD:
a) UNIT SPEED Vs UNIT DISCHARGE
FOR CONSTANT SPEED METHOD:a) DISCHARGE Vs EFFICIENCY
b) DISCHARGE Vs BP
c) EFFICIENCY Vs % FULL LOAD
RESULTS AND CONCLUSIONS:
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