Proofs Using vOut

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Proofs Using vOut 1. V v -V A 2. V>-B A 3. -V>-N A -Bv-N GOAL A v B A>G B>G G A v B G Set up the vOut Strategy

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Proofs Using vOut. A v B A > G B > G G. A v B. G. 1. V v -VA 2. V > -BA 3. -V > -NA -Bv-NGOAL. Set up the vOut Strategy. Proofs Using vOut. A v B A > G B > G G. A v B. G. 1. V v -V A 2. V > -BA 3. -V > -NA -Bv-N GOAL. - PowerPoint PPT Presentation

Transcript of Proofs Using vOut

Page 1: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A

-Bv-N GOAL

A v BA>GB>GG

A v B

G

Set up the vOut Strategy

Page 2: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A

-Bv-N GOAL

A v BA>GB>GG

A v B

G

... by making the missing conditionals new goals.

Page 3: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A

V>(-Bv-N) GOAL

-V>(-Bv-N) GOAL -Bv-N 1,?,? vO

A v BA>GB>GG

A v B

G

Prove the top goal using the >I Strategy

Page 4: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A4. V PA

-Bv-N GOAL V>(-Bv-N) 4-? >I

-V>(-Bv-N) GOAL -Bv-N 1,?,? vO

A v BA>GB>GG

A v B

G

Apply >O whenever you can.

Page 5: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A4. V PA -B 2,4 >O -Bv-N GOAL V>(-Bv-N) 4-? >I

-V>(-Bv-N) GOAL -Bv-N 1,?,? vO

A v BA>GB>GG

A v B

G

... and your goal comes by vIn

Page 6: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A4. V PA5. -B 2,4 >O6. -Bv-N 5 vI7. V>(-Bv-N) 4-6 >I

-V>(-Bv-N) GOAL -Bv-N 1,7,? vO

A v BA>GB>GG

A v B

G

Now use >In to obtain your second goal.

Page 7: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A4. V PA5. -B 2,4 >O6. -Bv-N 5 vI7. V>(-Bv-N) 4-6 >I8. -V PA

-Bv-N GOAL -V>(-Bv-N) 8-? >I -Bv-N 1,7,? vO

A v BA>GB>GG

A v B

G

Apply >O whenever you can.

Page 8: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A4. V PA5. -B 2,4 >O6. -Bv-N 5 vI7. V>(-Bv-N) 4-6 >I8. -V PA -N 3,8 >O -Bv-N GOAL -V>(-Bv-N) 8-? >I -Bv-N 1,7,? vO

A v BA>GB>GG

A v B

G

... and your goal comes by vIn

Page 9: Proofs Using vOut

Proofs Using vOut1. V v -V A2. V>-B A3. -V>-N A4. V PA5. -B 2,4 >O6. -Bv-N 5 vI7. V>(-Bv-N) 4-6 >I8. -V PA9. -N 3,8 >O10. -Bv-N 9 vI11. -V>(-Bv-N) 8-10>I12. -Bv-N 1,7,11 vO

A v BA>GB>GG

A v B

G

The proof is now complete.

Page 10: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A

(A&B)v(A&C) GOAL

A v BA>GB>GG

A v B

G

Do &Out whenever you can

Page 11: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A2. A 1 &O3. B v C 1 &O

(A&B)v(A&C) GOAL

A v BA>GB>GG

A v B

G

Set up the vOut Strategy

Page 12: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A2. A 1 &O3. B v C 1 &O

(A&B)v(A&C) 3,?,? vO

A v BA>GB>GG

A v B

G

Set the missing conditionals as new goals.

Page 13: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A2. A 1 &O3. B v C 1 &O

B >[(A&B)v(A&C)] GOAL

C >[(A&B)v(A&C)] GOAL (A&B)v(A&C) 3,?,? vO

A v BA>GB>GG

A v B

G

Use >In to prove the first goal.

Page 14: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A2. A 1 &O3. B v C 1 &O4. B PA

(A&B)v(A&C) GOAL B >[(A&B)v(A&C)] 4-? >I

C >[(A&B)v(A&C)] GOAL (A&B)v(A&C) 3,7,? vO

A v BA>GB>GG

A v B

G

Prove A&B so that you can use vIn to obtain the goal.

Page 15: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A2. A 1 &O3. B v C 1 &O4. B PA5. A&B 2,4 &I (A&B)v(A&C) GOAL B >[(A&B)v(A&C)] 4-? >I

C >[(A&B)v(A&C)] GOAL (A&B)v(A&C)

A v BA>GB>GG

A v B

G

Now the subproof can be completed with vIn.

Page 16: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A2. A 1 &O3. B v C 1 &O4. B PA5. A&B 2,4 &I6. (A&B)v(A&C) 5 vI7. B >[(A&B)v(A&C)] 4-6 >I

C >[(A&B)v(A&C)] GOAL (A&B)v(A&C) 3,7,? vO

A v BA>GB>GG

A v B

G

Now set up the >In Strategy to prove the second goal.

Page 17: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A2. A 1 &O3. B v C 1 &O4. B PA5. A&B 2,4 &I6. (A&B)v(A&C) 5 vI7. B >[(A&B)v(A&C)] 4-6 >I8. C PA

(A&B)v(A&C) GOAL C >[(A&B)v(A&C)] 8-? >I (A&B)v(A&C) 3,7,? vO

A v BA>GB>GG

A v B

G

This subproof can be completed in the same way.

Page 18: Proofs Using vOut

Proofs Using vOut1. A&(BvC) A2. A 1 &O3. B v C 1 &O4. B PA5. A&B 2,4 &I6. (A&B)v(A&C) 5 vI7. B >[(A&B)v(A&C)] 4-6 >I8. C PA9. A&C 2,8 &I10. (A&B)v(A&C) 9 vI11. C >[(A&B)v(A&C)] 8-10 >I12. (A&B)v(A&C) 3,7,11 vO

A v BA>GB>GG

A v B

G

The proof is now complete.