Playing card game with finite projective geometry Bogya... · 2016. 10. 27. · Playing card game...
Transcript of Playing card game with finite projective geometry Bogya... · 2016. 10. 27. · Playing card game...
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Playing card game with �nite projective
geometry
Norbert Bogya
University of Szeged, Bolyai Institute
CADGME, 2016
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 1 / 22
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Natural questions
I How can we construct such cards?
I Does it work with non-8 symbols?
I If yes, does it work with any number of symbols?
I (How many cards are in a deck?)
I How can we realise such cards?
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 4 / 22
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Geometry
Euclid of Alexandria
300 BCE
Elements
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 5 / 22
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Big problem
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Projective plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 7 / 22
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Projective plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 7 / 22
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Projective plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 7 / 22
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Projective plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 7 / 22
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Projective plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 7 / 22
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Projective plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 7 / 22
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Projective plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 7 / 22
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Projective plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 7 / 22
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Projective plane
I Given any two distinct points, there is exactly one line incidentwith both of them.
I There are four points such that no line is incident with morethan two of them.
I Parallel postulate
Instead:
Given any two distinct lines, there is exactly one point incident withboth of them.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 8 / 22
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Fano plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 9 / 22
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Fano plane
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 9 / 22
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Fano plane
12
3
4
5
6 7
Points: {1,2,3,4,5,6,7}
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 10 / 22
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Fano plane
12
3
4
5
6 7
Points: {1,2,3,4,5,6,7}Lines: {{1,2,4},{1,3,7},{1,5,6},{2,3,5},{3,4,6},{4,5,7},{2,6,7}}
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 10 / 22
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Fano plane
12
3
4
5
6 7
Points: {1,2,3,4,5,6,7}Lines: {{1,2,4},{1,3,7},{1,5,6},{2,3,5},{3,4,6},{4,5,7},{2,6,7}}
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 10 / 22
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Dobble revisited: Natural questions
I How can we construct such cards?
I Does it works with non-8 symbols?
I If yes, does it works with any number of symbols?
I (How many cards is in a deck?)
I How can we realise such cards?
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 11 / 22
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How can we construct such cards?
Answer is simple: �nite projective planes.
I Point = symbol
I Line = card
I Given any two distinct card,there is exactly one commonsymbol with both of them.
I Given any two distinctsymbols, there is exactlyone card with both of them.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 12 / 22
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How can we construct such cards?
Answer is simple: �nite projective planes.
I Point = symbol
I Line = card
I Given any two distinct card,there is exactly one commonsymbol with both of them.
I Given any two distinctsymbols, there is exactlyone card with both of them.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 12 / 22
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How can we construct such cards?
Answer is simple: �nite projective planes.
I Point = symbol
I Line = card
I Given any two distinct card,there is exactly one commonsymbol with both of them.
I Given any two distinctsymbols, there is exactlyone card with both of them.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 12 / 22
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Does it works with non-8 symbols?
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Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 13 / 22
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Does it works with non-8 symbols?
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Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 13 / 22
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Does it works with any number of symbols?
No.
Order of the projective plane # sysmbols per cardn n + 12 3 13 4 14 5 15 6 16 7 do not exist7 8 18 9 19 10 410 11 do not exist
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 14 / 22
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Does it works with any number of symbols?
No.
Order of the projective plane # sysmbols per cardn n + 12 3 13 4 14 5 15 6 16 7 do not exist7 8 18 9 19 10 410 11 do not exist
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 14 / 22
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Does it works with any number of symbols?
What are the orders such that projective planes can be constructed?
I If n is a prime power then projective planes can always beconstructed.
I If not, then we have no idea.
Conjecture
If n is not prime power then there is no projective plane with order n.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 15 / 22
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Does it works with any number of symbols?
What are the orders such that projective planes can be constructed?
I If n is a prime power then projective planes can always beconstructed.
I If not, then we have no idea.
Conjecture
If n is not prime power then there is no projective plane with order n.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 15 / 22
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Does it works with any number of symbols?
What are the orders such that projective planes can be constructed?
I If n is a prime power then projective planes can always beconstructed.
I If not, then we have no idea.
Conjecture
If n is not prime power then there is no projective plane with order n.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 15 / 22
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How many cards is in a deck?
Answer is simple: 55. (We count them.)
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 16 / 22
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How many cards is in a deck?
Answer is simple: 55. (We count them.)
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 16 / 22
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How many cards is in a deck?
Theorem
If a projective plane has a line with n + 1 points then
(1) every line of the plane contains n + 1 points;
(2) every point of the plane is incident with n + 1 lines;
(3) the plane has n2 + n + 1 points and
(4) the plane has n2 + n + 1 lines.
8 symbols per card = every line contains 8 points
Then n = 7. So the number of lines (cards) is 72 + 7+ 1 = 57.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 17 / 22
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How many cards is in a deck?
Theorem
If a projective plane has a line with n + 1 points then
(1) every line of the plane contains n + 1 points;
(2) every point of the plane is incident with n + 1 lines;
(3) the plane has n2 + n + 1 points and
(4) the plane has n2 + n + 1 lines.
8 symbols per card = every line contains 8 points
Then n = 7. So the number of lines (cards) is 72 + 7+ 1 = 57.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 17 / 22
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How many cards is in a deck?
Theorem
If a projective plane has a line with n + 1 points then
(1) every line of the plane contains n + 1 points;
(2) every point of the plane is incident with n + 1 lines;
(3) the plane has n2 + n + 1 points and
(4) the plane has n2 + n + 1 lines.
8 symbols per card = every line contains 8 points
Then n = 7.
So the number of lines (cards) is 72 + 7+ 1 = 57.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 17 / 22
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How many cards is in a deck?
Theorem
If a projective plane has a line with n + 1 points then
(1) every line of the plane contains n + 1 points;
(2) every point of the plane is incident with n + 1 lines;
(3) the plane has n2 + n + 1 points and
(4) the plane has n2 + n + 1 lines.
8 symbols per card = every line contains 8 points
Then n = 7. So the number of lines (cards) is 72 + 7+ 1 = 57.
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 17 / 22
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How many cards is in a deck?
8 symbols per card = every line contains 8 points
Then n = 7. So the number of lines (cards) is 72 + 7+ 1 = 57.
�Answer is simple: 55.�
I Where are two missingcards?
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 18 / 22
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How many cards is in a deck?
8 symbols per card = every line contains 8 points
Then n = 7. So the number of lines (cards) is 72 + 7+ 1 = 57.
�Answer is simple: 55.�
I Where are two missingcards?
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 18 / 22
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How many cards is in a deck?
8 symbols per card = every line contains 8 points
Then n = 7. So the number of lines (cards) is 72 + 7+ 1 = 57.
�Answer is simple: 55.�
I Where are two missingcards?
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 18 / 22
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� � l
��
e
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 19 / 22
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� � l
��
e
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 19 / 22
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� � l
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e
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 19 / 22
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How many cards is in a deck?
8 symbols per card = every line contains 8 points
Then n = 7. So the number of lines (cards) is 72 + 7+ 1 = 57.
�Answer is simple: 55.�
I Where are two missingcards?
I Is this the real model orsomething else?
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 20 / 22
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How can we realise such cards?
Wolfram Mathematica and GAP demonstrations
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 21 / 22
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The End
Thank you for your attention!
Norbert Bogya (Bolyai Institue) Dobble and Finite Projective Planes CADGME, 2016 22 / 22