Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force...
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Transcript of Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force...
![Page 1: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/1.jpg)
Linear Impulse – Momentum Relationship
Ft = mv = m(v2-v1)Impulse (Ns)Product of a force applied over a period of
time (Ft)Momentum (kg m/s)Quantity of motion. Product of mass * velocity
(mv)Positive (negative) changes in Linear
Momentum are created by Net positive (negative) Linear Impulse.
Course Reader: Kinetics, p 48 - 53; Linear Impulse 53-61
![Page 2: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/2.jpg)
LINEAR IMPULSEWhy? • Mechanism for controlling linear velocity of the
total body center of mass• Necessary for successful completion of general
locomotion tasks, and athletic movements
Vv1
Vh1
Vv2
Vh2
Ft = mv = m(v2-v1)= mv2 - mv1
t
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Net Linear Impulse (F*t) Generation
-800
-600
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-200
0
200
400
600
800
0.000 0.040 0.080 0.120 0.160 0.200 0.240
Time (s)
Ground Reaction Force (N)
Horizontal
Vertical
Positive Impulse
Negative Impulse
Linear impulse magnitude = area under the force-time curve, is dependent upon …1) Ground reaction force magnitude (F)2) ground contact duration (t)
Free BodyDiagram
FFvv
FFhh
BWBW
Net Vertical Force = Fv(+)+BW(-)
touchdown take-off
![Page 4: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/4.jpg)
-800
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0
200
400
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0.000 0.040 0.080 0.120 0.160 0.200 0.240
Time (s)
Ground Reaction Force (N)
Horizontal
Vertical
Positive Impulse
Negative Impulse
Net Linear Impulse, the sum of negative and positive linear impulse generated during the entire ground contact phase (touchdown – take-off)
time=0 touchdown
force=0 take-off
time (s)
Gro
und
reac
tion
forc
e (N
)
Ft = mv = m(v2-v1)= mv2 - mv1
V1V2
Free BodyDiagram
FFvv
FFhh
BWBW
![Page 5: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/5.jpg)
-500
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0
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1000
0.000 0.100 0.200 0.300
How do you generate large Horizontal Impulse (force*time)? force, time, or a combination of force & time
• The mechanical goal of the task influences how Impulse is generated
e.g. sprinters need to generate horizontal impulse quickly
Time (s) after ground contact
Hor
izon
tal G
RF
(N
)
![Page 6: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/6.jpg)
-500
-250
0
250
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750
1000
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0.000 0.050 0.100 0.150 0.200 0.250
time (s) after contact
Hor
izon
tal G
RF
(N
)
Vh = 1.30 m/s Vh = 1.29 m/s
Similar net changes in linear momentum can be achieved with different force-time
linear impulse characteristics
![Page 7: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/7.jpg)
-400-200
0
200400
600800
1000
120014001600
1800
0.000 0.050 0.100 0.150 0.200 0.250
H GRFH GRF
V GRFV GRF
Time (s) after contactTime (s) after contact
TouchdownTouchdown
Impulse-Momentum Relationship Impulse-Momentum Relationship FFt = HI = m(Vt = HI = m(V22-V-V11))
mVmVhh11
FFhhtt
Take-OffTake-Off
mVmVhh22
![Page 8: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/8.jpg)
-400-200
0
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600800
1000
120014001600
1800
0.000 0.050 0.100 0.150 0.200 0.250
H GRFH GRF
V GRFV GRF
Time (s) after contactTime (s) after contact
TouchdownTouchdown
Impulse-Momentum Relationship Impulse-Momentum Relationship FFt = HI = m(Vt = HI = m(V22-V-V11))
mVmVvv11
Take-OffTake-Off
mVmVvv22
FFvvtt
![Page 9: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/9.jpg)
-400-200
0
200400
600800
1000
120014001600
1800
0.000 0.050 0.100 0.150 0.200 0.250
H GRFH GRF
V GRFV GRF
Time (s) after contactTime (s) after contact
TouchdownTouchdown
Calculating Net Linear Impulse Using GeometryCalculating Net Linear Impulse Using Geometry
mVmVvv11
Take-OffTake-Off
mVmVvv22mVmVhh11
Take-OffTake-Off
mVmVhh22
![Page 10: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/10.jpg)
Push Tip Load
Plate Departure
Back Somersault: Take-off Phase
Vv
Vh
BackwardsRotation
Needs: Needs: Vertical Impulse (net positive), Vertical Impulse (net positive), Horizontal Impulse (net negative), Horizontal Impulse (net negative), Backward-directed Angular ImpulseBackward-directed Angular Impulse
How?How?
![Page 11: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/11.jpg)
BACK Somersault
FFVV
FFHH
FFRRFFVV
FFHH
time prior to take-off take-off
Generation of Linear Impulse Generation of Linear Impulse During a Back DiveDuring a Back Dive
Near Zero Initial Near Zero Initial TBCMTBCM
Momentum (mv)Momentum (mv)
Net Positive Vert. mvNet Positive Vert. mvNet Negative Horiz. Net Negative Horiz. mvmv
InitiationInitiation Take-OffTake-Off
![Page 12: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/12.jpg)
-500
0
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1000
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2500
-0.5 -0.4 -0.3 -0.2 -0.1 0 0.1
Time Prior to Take-off (s)
Force (N)
Horizontal RF
Vertical RF
VRF
BACK Somersault
time prior to take-off take-off
FFVV
FFHH
FFRRFFVV
Generation of Linear Impulse Generation of Linear Impulse During a Back DiveDuring a Back Dive
time prior to take-off take-off
FFHH
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QuickTime™ and aDV/DVCPRO - NTSC decompressor
are needed to see this picture.
Mechanical objective of the shot put: • Vertical Impulse (net positive)• Horizontal impulse (net negative - translate backward)
![Page 14: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/14.jpg)
F=malinear acceleration of the athlete’s center of mass is determined
by the sum of forces acting on the center of mass
Free Body Diagram
Mass-Acceleration Diagram
FFvv
FFhh
FFBWBW
Vertical
Fv = FBW(-) + Fv
(+)
Fv = mav
Fv = m (v/t)Fv t = m (v)
ah
aavv
Linear Impulse – Momentum RelationshipFt = mv = m(v2-v1)
![Page 15: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/15.jpg)
F=malinear acceleration of the athlete’s center of mass is determined by
the sum of forces acting on the center of mass
Free Body Diagram
Mass-Acceleration Diagram
FFvv
FFhh
FFBWBW
Horizontal
Fh = Fh(+)
Fh = mah
Fv = m (v/t)Fv t = m (v)
ah
aavv
Linear Impulse – Momentum RelationshipFt = mv = m(v2-v1)
![Page 16: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/16.jpg)
Verticalforce
Horizontalforce
BWBW
HGRFHGRFVGRFVGRF
BWBWBWBW
V GRFV GRF == BWBW V GRFV GRF >> BWBW
Linear Impulse – Momentum Relationship
Ft = mv = m(v2-v1)
V GRFV GRF = 0= 0
![Page 17: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/17.jpg)
Verticalforce
Horizontalforce
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0
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600
800
1000
1200
-0.500 -0.400 -0.300 -0.200 -0.100 0.000
Bodyweight
Time (s) prior to departure
GroundReaction
Forces(Newtons)
BWBW BWBWBWBW
HGRFHGRFVGRFVGRF
![Page 18: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/18.jpg)
-600
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-200
0
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-0.500 -0.400 -0.300 -0.200 -0.100 0.000
Body weight
Time (s) prior to departure
GroundReaction Forces
(Newtons)
Net Impulse = Change in Momentum( Force) *(time) = (mass)*(velocity)
Increase in the positive vertical velocity
Increase in the negative horizontalvelocity
(+) verticalimpulse
(-) horizontalimpulse
![Page 19: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/19.jpg)
Mechanics of each phase influence the mechanics during the next phase.
Impulse generation during the unseating phase will influence initial conditions of the blocking phase.
Impulse Projectile motion
Momentum Transfer
![Page 20: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/20.jpg)
Mechanical Objective of the Shot PutMaximize the horizontal distance traveled by the shot
Projectile Motion
![Page 21: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/21.jpg)
How does the shot become a projectile?
Total body momentum is generated and passed on to the shot
![Page 22: Linear Impulse – Momentum Relationship F t = m v = m(v2-v1) Impulse (Ns) Product of a force applied over a period of time ( F t) Momentum (kg.](https://reader036.fdocuments.us/reader036/viewer/2022062515/56649c785503460f9492dfa4/html5/thumbnails/22.jpg)
Take-Home Message
Each foot (ground) contact is an opportunity to:
a) increase, b) decrease, or
c) maintain your total body momentum.