Kinematics, Dynamics and Vibrations Dynamics and...Kinematics, Dynamics and Vibrations ......
Transcript of Kinematics, Dynamics and Vibrations Dynamics and...Kinematics, Dynamics and Vibrations ......
Kinematics, Dynamics and Vibrations
Dr. Mustafa ArafaMechanical Engineering Department
American University in [email protected]
Outline
A. Kinematics of mechanisms
B. Dynamics of mechanisms
C. Rigid body dynamics
D. Natural frequency and resonance
E. Balancing of rotating &reciprocating equipment
F. Forced vibrations (e.g., isolation, force transmission, support motion)
References
• Shigley & Uicker: Theory of Machines and Mechanisms
• Norton: Design of Machinery
• Rao: Mechanical Vibrations
• Beer & Johnston: Vector Mechanics for Engineers
A.Kinematics of mechanisms
Four-bar linkage
Slider-crank mechanism
Scotch yoke mechanism
Four-bar mechanism
2
2
sin
cos
aA
aA
y
x
Obtain coordinates of point A:
222
222
yx
yyxx
BdBc
ABABb
Obtain coordinates of point B:
2 equations in 2 unknowns: Bx and By
Analytical position analysis
Write vector loop equation:
Using complex vectors:
01432 iiii
decebeae
01432 RRRR
Solve for 3 and 4
Velocity analysis
10
Vector loop equation
After solving for position, take the derivative:
01432 iiii
decebeae
0432432 iceibeiae
iii
0432432
iiiceibeiaei
Solve for 3 and 4
Acceleration analysis
01432 iiii
decebeae
0432432
iiiceibeiaei
04433224
243
232
22
iiiiiiceicebeibeaeiae
Write vector loop equation:
Take two derivatives:
B. Dynamics of mechanisms
• Free Body Diagrams
Force analysis
Links 2 and 3Link 2
232323232
1212121212
23212
23212
2
2
2
G
G
G
IFRFR
FRFRT
amFF
amFF
xyyx
xyyx
yyy
xxx
3
32233223
43434343
33243
33243
3
3
3
GPPPP
GP
GP
IFRFR
FRFR
FRFR
amFFF
amFFF
xyyx
xyyx
xyyx
yyyy
xxxx
Link 3 (F23=-F32)
Link 4
• F34=-F43
443434343
141414144
44314
44314
4
4
4
G
G
G
IFRFR
FRFRT
amFF
amFF
xyyx
xyyx
yyy
xxx
In one matrix equation
• We have 9 equations and 9 unknowns
44
4
4
3
3
3
2
2
2
12
14
14
43
43
32
32
12
12
14144334
43432323
32321212
4
4
4
3
3
3
2
2
2
00000
010100000
001010000
00000
000101000
000010100
10000
000001010
000000101
TI
am
am
FRFRI
Fam
Fam
I
am
am
T
F
F
F
F
F
F
F
F
RRRR
RRRR
RRRR
G
G
G
PPPPG
PG
PG
G
G
G
y
x
xyyx
yy
xx
y
x
y
x
y
x
y
x
y
x
xyxy
xyxy
xyxy
C. Rigid body dynamics
Basic equations
Particle dynamics
A thin circular rod is supported in a vertical plane by a bracket at A. A spring of stiffness k = 40 N/m is attached at A and fits loosely on the rod. The spring has an undeformed length equal to the arc of the circle AB. A 200-g collar C (not attached to the spring) can slide without friction. Knowing that the collar is released from rest when = 30⁰, determine the maximum height above point B reached by the collar. Determine also the maximum velocity.
20
Rigid body dynamics
At a forward speed of 30 ft/s, the truck brakes were applied, causing the wheels to stop rotating. It was observed that the truck skidded to a stop in 20 ft.
Determine the magnitude of the normal reaction and the friction force at each wheel as the truck skidded to a stop.
21
Rigid body dynamics
2 2
0 0
2
2
0 30 2 20
v v a x x
a
22.5 ft sa
x GxF ma
Free-body diagram:
22.5A BF F m
y GyF maA BW mg N N
G GM I 7 4 4 5B B A AN F F N
But ,A A B BF N F N
22.5A BN N m
A BN N mg 0.699
0.35 , 0.65A BN mg N mg
, ,A BN N Unknowns:
D. Natural frequency and resonance
Model of a vibrating system
Mass and spring
Mass, spring & damper
Forced vibration
2 DOF systems
Modal Analysis
E. Balancing of rotating & reciprocating equipment
Static Unbalance
• Acting through the center of mass of the rotor
• Can be corrected at a single location (plane)
• Can be detected without spinning the rotor
Couple Unbalance
• Rotor is statically balanced, but dynamically unbalanced
Dynamic Unbalance
• Combination of static & couple unbalance
F. Forced vibrations (e.g., isolation, force transmission, support motion)
Forced vibration
Equation of motion:
Steady-state solution:
Where:
Or:
Frequency response
Support motion
Relative motion:
Support motion
Absolute motion:
Vibration isolation
Force transmitted