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    SIRKUIT 3 FASA

    (Balanced 3-phase )Semester Genap 2009/2010Prodi Teknik Elektro

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    Consider the complex roots of unity:

    Find all the roots of:

    Then find the sum of the roots

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    Balanced ComplexNumbers

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    Balanced ComplexNumbers

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    It is evident from above that the sum of any threeroots of the cube-root of any complex number isabsolutely zero.

    This is the essence of a balanced three phasesystem and indeed the most powerful tool in powertransmission.

    The results below are self-evident.

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    Let us use the above discovery and

    KCL: Suppose we have three currents such that

    o

    o o i1 = I0

    , i2 = I120

    , i3 = I240

    If

    we decide to sup ply i1 , i2 , i3 to a load ;

    as shown below we make int eresting conclusions :

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    Balances 3-phase Currents

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    Balances 3-phase Currents Clearly,

    I n = i1 + i2 + i3

    But, i1 + i2 + i3 = 0

    I n = 0

    I n = 0; needless to have neutral wire

    There is always NO neutral wire

    in a balanced 3 phase system

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    Advantages of balanced 3-phase supply

    1.The elimination of a neutral wire is clearly thebiggest saving.

    2. If we wanted to supply the same amount ofpower using single phases, we would have used 6wires! But we have managed with just 3 of them.

    3. The fact that line voltages are higher means thatthe line currents are lower hence reduced I2Rlosses.

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    Line & Phase Values

    In practice, when a 3-phase system is used, we dohave both the currents & voltages as 3- phase. Theirvalues may be given as phase or line values.

    Let us consider a balanced 3-phase voltage system.

    Just as we did in the case of currents, the voltage isgiven by:

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    Line & Phase Values It is however usual to measure voltage between

    one phase & another phase. So the value is that ofone phase with respect to the other. Since it ismeasured between one phase & another it is

    referred as the line voltage.

    The line voltages must the phasor differences asshown below:

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    Line & Phase Values

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    Phasors for Phase & LineVoltages

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    Phase & Line Voltages The following conclusions are made:

    1. The line voltages also constitute a balanced 3-phase system.

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    Line & Phase Values Please note that:

    1. In a 3-phase system; the line values

    (voltage & current) are the ones specified.

    2. It is very dangerous to touch any two line wire

    (because of much higher voltages). 3. All valuesare rms.

    4. Red, Yellow, Blue representv.v1 , v2 , v3

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    Line & Phase Values While it is easy to identify phase & line voltages;

    caution is taken on phase & line currents.

    It is easier to assume that phase & line currents arethe same.

    S & D l 3 h

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    Star & Delta 3-phrepresentation

    There are two distinct ways of representing 3- phasevoltages/currents;

    Star or Delta. [Star is sometimes called Wye].

    Let us re-draw the phasors for 3-phase voltages.

    S & D l 3 h

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    Star & Delta 3-phrepresentation

    S & D l 3 h

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    Star & Delta 3-phrepresentation

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    It is noted that:

    A Star connection has a neutral point (n) and canbe accessed when need arises. But the Deltaconnection does not have one.

    Hence in a Delta connection only the line voltagescan be measured. But in the Star connection bothline & phase voltages are measurable.

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    Star-Star connection Supply-load connections

    Sumber Beban

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    Star-Delta connection Supply-load connections

    I3

    I2

    I1i1

    i2

    i3

    n

    Sumber

    Beban

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    Line & Phase currents In the star connection; the line current=phase

    current.

    But in Delta connection; the line current DOES NOTequal to phase current e.g.

    i1 I1

    But we may use KCL to find the relationshipsbetween line and phase currents.

    i1 I1 + I3 = 0

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    Power in 3-phase We know that is 1-phase;

    Power= VI cos But in 3 phase;

    Total power

    = 3VI cos ;

    where V, I are phase values. Total power=

    where VL , I L are line values (assume I = I L )

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    3-phase ExercisesExercise 1:

    v1 (t ) = Vsin(wt) =reference voltage;

    express v2 (t ), v3 (t) as sin e functions.

    Exercise 2 :

    A 2MW,11kV,3 phase source uses 80% of its capacity to sup ply a load.

    determine the current if power factor is 0.5

    Exercise 3:

    A 0.6MW, 416V, 3-phase, 50Hz load has a power factorof 0.5. Determine the necessary capacitors and showtheir connections so as to improve the power factor to0.9.

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    Solution 1

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    Solution 2

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    Solution 3

    The power factor improvement is done byconnecting a capacitor between @ phase & theneutral point.

    [Though it is possible to connect a capacitorbetween phases but then the capacitors are moreexpensive because of the higher (line) voltages].

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    Star-Star connection Supply-load connections

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    Solution 3

    Since @ capacitor is connected across a phase &neutral; phase voltages must be used.

    We are at liberty to use the phasor diagramstudied earlier

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    Solution 3

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    Solution 3

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    Solution 3

    In pratice use nearest orhigher valuable availableon market

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    Question 4

    A 440V, 3-ph, Y-connected source has two loadsconnected as:

    One load is balanced in @ phase with

    Z=10+j5. The second load is balanced in @ phasewith

    Z=15+j0. (i) Find the average power to @ load.

    (ii) Find the total power delivered.

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    Total load =(10+j5)+(15+j0)=25+j5=Z

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    Latihan Soal

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    Soal 1

    Diket A = 5 + j3 dan B = 8300

    Hitung;

    1. A + B 2. AB

    3. A * B

    4. A / B

    Dalam bentuk vektor dan komplexs

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    Soal 2

    2 buah watt meter dipasang pada supply dengansystem 3 kawat 3 phase. Jika tegangan beban 400V dan arus 20 A, hitung

    A. Pembacaan watt meter saat faktor daya = 1

    B. Pembacaan watt meter saat faktor daya =

    0.5

    C. Pembacaan watt meter saat faktor daya = 0

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    Soal 3

    Suatu sistem 3 phase 4 kawat mempunyai bebanZa = 10L00 , Zb = 20L300 dan Zc =

    10L-300 . Beban tersebut dihubungkan bintang dandisupply tegangan 400 V, 50 Hz. Hitung arus yangmengalir pada masing- masing fasa dan arusnetralnya.

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    Soal 4

    Sistem 400 Volt ( fasa ke fasa ), 3 fasa, 50 Hzmensupply beban yang seimbang dengan besarbeban 8 + j6 ohm. Hitung daya keseluruhan yang

    disupply dan faktor daya dari arus yang ditarik darisumber

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    LATIHAN SOAL

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    Soal 5

    3 impedansi yang mempunyai nilai yang sama,tahanan 8 ohm dan reaktansi 6 ohm, dihubungkanpada suulay 200 V, 3 phase.

    Hitung daya yang dibutuhkan jika

    Dihubung bintang

    Dihubung delta/ segitiga

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    Soal 6

    Suatu beban yang dihubung bintang denganimpedansi 8+j6 ohm dihubungkan dengan supply100 V dan 3 phase. Hitung nilai kapasitor yang harus

    dipasang jika ingin merubah faktor dayanyamenjadi 0.9

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