EE 314 Signal and Linear System Analysis
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis Slide 1 of 14
Summary of Last Lecture
Lecture 8 EE 314 Signal and Linear System Analysis
β’ Applying a causal input (π₯π₯(π‘π‘)) to a causal LTI systems with impulse response β(π‘π‘) gives rise to a causal output π¦π¦ π‘π‘ :
0
( ) ( ) ( )t
y t x h t dΟ Ο Ο= ββ«
( )h t
0
( ) ( )t
h x t dΟ Ο Ο= ββ«
Slide 2 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
β’ Revisiting the prior RC example Let π π π π = 1/2 = ππππ, hence,
Input: π£π£ππππ π‘π‘ = π’π’ π‘π‘ β π’π’(π‘π‘ β 1)β’ Analytical soln is: For, 0 < t < 1
2( ) 2 ( )th t e u tβ=
0
( ) ( ) ( )t
out inv t v h t dΟ Ο Ο= ββ« ( ) ( )2
0
1 2t
te dΟ Οβ β= β« 2 2
0
2t
te e dΟ Οβ= β«
2 2
0
tte e Οβ = ( )2 2 1t te eβ= β 21 teβ= β( )( )21 ( ) ( 1)te u t u tβ= β β β
Slide 3 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
For, t > 1
Final result
1
0 1
( ) ( ) ( ) ( ) ( )t
out in inv t v h t d v h t dΟ Ο Ο Ο Ο Ο= β + ββ« β«1
0
( ) 0h t dΟ Ο= β +β«12 2
0
te e Οβ =
( )2 2 1te eβ= β 2( 1) 2t te eβ β β= β( )2( 1) 2 ( 1)t te e u tβ β β= β β
( )( ) ( )2 2( 1) 2( ) 1 ( ) ( 1) ( 1)t t toutv t e u t u t e e u tβ β β β= β β β + β β
( ) ( )2 2( 1)1 ( ) 1 ( 1)t te u t e u tβ β β= β + β β
Slide 4 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
( ) ( )2 2( 1)( ) 1 ( ) 1 ( 1)t toutv t e u t e u tβ β β= β + β β
Slide 5 of 14
β βππ + π‘π‘ => Shift then flipβ(β(ππ β π‘π‘)) => Flip then shift
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
β’ Letβs evaluate the convolution graphically
Overlay a plot of π£π£ππππ(ππ) with a plot of β(π‘π‘ β ππ), compute the area under the product (for 0 β€ ππ β€ π‘π‘), then vary π‘π‘.
0
( ) ( ) ( )t
out inv t v h t dΟ Ο Ο= ββ«
( )inv t( )h t
We need π£π£ππππ(ππ)
We need β(π‘π‘ β ππ)
Flip then shift by π‘π‘
The area under the product!!
ORβ(π‘π‘ β ππ) = β(β(ππ β π‘π‘))
Shift by π‘π‘ then flip
Slide 6 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
β’ Start with π‘π‘ < 0
0
( ) ( ) ( )t
y t x h t dΟ Ο Ο= ββ«
( ( ))h tΟβ β ( )x Οπ‘π‘ = β0.5 π π π π π π
0=
( ( 0.5))h Οβ β
The area under the product?
0.5
0
( 0.5) ( ) ( )y x h t dΟ Ο Οβ
β = ββ«
Slide 7 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
β’ Now, consider 0 β€ π‘π‘ < 1
0
( ) ( ) ( )t
y t x h t dΟ Ο Ο= ββ«
( ( ))h tΟβ β ( )x Οπ‘π‘ = +0.6 π π π π π π
2( )
0
2t
te dΟ Οβ β= β«
2( ) 2 ( )th t e u tβ=
( ) ( ( ))x h tΟ Οβ β
Slide 8 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
β’ Now, consider π‘π‘ > 1
0
( ) ( ) ( )t
y t x h t dΟ Ο Ο= ββ«
( ( ))h tΟβ β
( )x Ο
π‘π‘ = +1.5 π π π π π π
12( )
0
2 te dΟ Οβ β= β«
Slide 9 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
MATLAB code
Slide 10 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
β’ More Convolution Examples
MATLAB code
Slide 11 of 14
Graphical Convolution
Lecture 8 EE 314 Signal and Linear System Analysis
β’ Systems connected in series
β’ Systems connected in parallel
( )z t1( ) ( )* ( )z t x t h t=
2( ) ( )* ( )y t z t h t=
( )1 2( )* ( ) * ( )x t h t h t=
( )1 2( )** )( ()x t h t h t=
1( ) ( )* ( ) ( )* ( )Ny t x t h t x t h t= + +
[ ]1( )* ( ) ( )Nh t tx t h+ +=
Slide 12 of 14
Causal LTI System
Lecture 8 EE 314 Signal and Linear System Analysis
β’ Causality A LTI system is causal if it does NOT rely on future inputs in
order to determine the current output.o All real/physical systems are causal β They can not anticipate
future inputs!!
o i.e., A causal system has an impulse response that is a causal function.
( ) 0 for all 0h t tβ = <
( ) ( ) ( )y t x h t dΟ Ο Οβ
ββ
= ββ« Consider ππ > π‘π‘ βΌ
Would use future values of π₯π₯ π‘π‘to determine π¦π¦(π‘π‘)!!
Does this system have memory?
Give an example of a system that does NOT have memory?
( )h t
0
( ) ( )t
x h t dΟ Ο Ο= ββ«
Slide 13 of 14
Next Lecture
Lecture 8 EE 314 Signal and Linear System Analysis
β’ LTI Sinusoidal Response
β’ Reading Assignment: Chap. 2.7
Slide 14 of 14
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