Tube Bending Calculations
2
PIPE FABRICATION STANDARD PIPE BENDS Each bend should be checked for availability of pipe in the required over-all leugth, arrd to determine that over-all dimensions are rvithin the limits of transporta- tion facilities. 6 EVELOPED LENGTH = I.571 R No, I QUARTER BEND-9Oo DEVELOPED LENGTH = ANGLE (in degrees) x R x 0.01745 No. rj BEND - 46'T0 89' SINGLE OFFSET OUARTER BENO l*+o3o3R Et(b.,os' Euffl\ DEVELOPED LENGTH = 0.785R 0.828 R I DEVELOPED LENGTH = 2 x DEVELOPED LENGTH oF NO. 5 BEND No.4 CROSSOVER EENO DEVELOPED LENGTH = 6.283 R No 8 DOUBLE OFFSET U BEND FOR DIMENSIONS . SEE NEXT PAGE No.5 OFFSET BEND DEVELOPED LENGTH = 6.283R + 2X No.9 EXPANSION U BEND (tHEtX|slFooTonlE3i) o s No. 2 DEVELOPED LENGTH = 6.12?B No.6 SINGLE OFFSET U BEND rn L(/.m DDVELOP LENGTH = 3.142R No.7 U- BENo- lSOo 1l 1 DA'AP I F ---- - 'j DEVELOPED LENGTH = 9.425R No. lO DOUBLE OFFSET EXPANSION 8€N0 No. 3 45' BEND DEVELOPED LENGTH - ANCLE (hdegrees)xRx0.01745 N0. 3tBENo -LESs THAN 45. DEVELOPED LENGTH = ANGLE (indegrees)x8x0.0U45 No.7i BEND- gfro t79' n A .z,z:\ PIPE DIAMETER No. ll CIRCLE BENO 143
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Transcript of Tube Bending Calculations
8/2/2019 Tube Bending Calculations
http://slidepdf.com/reader/full/tube-bending-calculations 1/2
PIPE FABRICATION
STANDARD PIPE BENDSEach bend should be checked for availability of pipe
in the required over-all leugth, arrd to determine thatover-all dimensions are rvithin the limits of transporta-tion facilities.
6EVELOPED LENGTH = I.571 R
No, I QUARTER BEND-9Oo
DEVELOPED LENGTH = ANGLE(in degrees) x R x 0.01745
No. rj BEND - 46'T0 89'
SINGLE OFFSET OUARTER BENO
l*+o3o3R
Et(b.,os'Euffl\DEVELOPED LENGTH = 0.785R
0.828 R I
DEVELOPED LENGTH =2 x DEVELOPED LENGTH oF NO. 5 BEND
No.4 CROSSOVER EENO
DEVELOPED LENGTH = 6.283 R
No 8 DOUBLE OFFSET U BEND
FOR DIMENSIONS . SEE NEXT PAGE
No.5 OFFSET BEND
DEVELOPED LENGTH = 6.283R + 2X
No.9 EXPANSION U BEND(tHEtX|slFooTonlE3i)
o
s
No. 2
DEVELOPED LENGTH = 6.12?B
No.6 SINGLE OFFSET U BEND
rnL(/.mDDVELOP LENGTH = 3.142R
No.7 U- BENo- lSOo
1l1 DA'AP
I
F ---- - 'jDEVELOPED LENGTH = 9.425R
No. lO DOUBLE OFFSET EXPANSION 8€N0
No. 3 45' BEND
DEVELOPED LENGTH - ANCLE(hdegrees)xRx0.01745
N0. 3tBENo -LESs THAN 45.
DEVELOPED LENGTH = ANGLE(indegrees)x8x0.0U45
No.7i BEND- gfro t79'
n
A
.z,z:\
PIPE DIAMETERNo. ll CIRCLE BENO
143
8/2/2019 Tube Bending Calculations
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ITT GRINNELL- PIPING DESIGN AND ENGINEERING
CAI,CIJLATION OI'
@iuen: R arrd a.
To rt,ntl: T and. arc.
T: R Lan!2
Arc : Angle (in degrees)
x R x 0.01745
PIPE BENDS
Giam: L, O and R.
n>oTo f.nd; AB, e, T
and arc.
CD:R_O
AB : \/CDr}:Tt --n,
L : \/-AC2- BCa : BC tan <,
Arc: Angle (in degrees) XnX0.0l?4b
la: ZACD - IACB
tr'or? and arc
seefirst calculatron.It R<O then CD:O-E and a:180o-
( I AC D + I AC B) . Other values remain the same.
Qium: R1, R2,
and O.
To f,nd.: L, a, arq,and arc2.
BC:Rt+R2-O
AC:h+nz.BC
cr: COS-' ,n
Arcl :41"1" (in degrees) Xlilx 0,01745
Arc2 :4tr"1" (in degrees) XRrX 0.01?45
@iren: Ry 8.2, L and, O.
O1ff:'*Rz'
To f,nd; a, X and arc.
BC-Rt+n2-O
tc : lP-+ cz
IACB : tao-t#
e : IACB - IACD IACD : stn-l
AD: x:'VAe - Ai+E*Arcr: 4nt1" (in degrees) XArX 0.01746
Arc2: 41"1" (in degrees) XErX 0.01746
If O> al +R2 BC:O-(fu*82), and c=180' - ( IACB + IACD). Other values remain the
same.
,/ AAD : +^.-1 LCD
L: \/TC' - Be: BCtano
IACB : tan-'ffOipen: R and O,
To find: L, a and arc.
BC:2R -O AC :2R,.BCa: cos-' 7
Giuen: R, O and, L.o <2R
Tofind: a,X and arc.
BC:2R-OAD :2R
: \8,+ BC,=ZA,
ICAB : tao-'Bf
BCoiS.t:
t
^oosP:t
cc:90"-(tDAC+ICAB)Arc:Angle (in degrees) XAX0.01?45
It O>2n then BC:O-2R, and a:90"-IDAC + ICAB. Other values remain the sa,me.
Qium: O, A a;;.d B
To find,: L, a and P
E:\/ETTL: \/E +T -A
ar
No. 5 OFFSET BEND
t44
