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Transcript of Tcp de Plataforma
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Codeware, Inc.
Sarasota, FL, USA
www.codeware.com
COMPRESS Pressure Vessel Design Calculations
Item: Split Stream Dearator
Vessel No: V-1234
Customer: Magaladon Oil Venture
Contract: C-45490-R56
Designer: John Doe
Date: April 1, 2001
You can edit this page by selecting Cover Page settings...in the reportmenu.
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Table of Contents
General Arrangement Drawing..............................................................................................................................1/108
Deficiencies Summary............................................................................................................................................2/108
Nozzle Schedule......................................................................................................................................................4/108
Nozzle Summary.....................................................................................................................................................5/108
Pressure Summary.................................................................................................................................................6/108
Revision History......................................................................................................................................................7/108
Settings Summary...................................................................................................................................................8/108
Radiography Summary.........................................................................................................................................10/108
Thickness Summary.............................................................................................................................................11/108
Weight Summary...................................................................................................................................................12/108
Long Seam Summary...........................................................................................................................................13/108
Hydrostatic Test....................................................................................................................................................14/108
Vacuum Summary.................................................................................................................................................15/108
Ellipsoidal Head #2...............................................................................................................................................16/108
Straight Flange on Ellipsoidal Head #2...............................................................................................................19/108
Cylinder #1.............................................................................................................................................................22/108
Saddle #1...............................................................................................................................................................24/108
Nozzle #2 (N2)........................................................................................................................................................31/108
Copy of Nozzle #2 (N3).........................................................................................................................................45/108
Copy of Copy of Nozzle #2 (N4)...........................................................................................................................59/108
Copy of Copy of Copy of Nozzle #2 (N5).............................................................................................................73/108
Straight Flange on Ellipsoidal Head #1...............................................................................................................87/108
Ellipsoidal Head #1...............................................................................................................................................90/108
Nozzle #1 (N1)........................................................................................................................................................93/108
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General Arrangement Drawing
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Deficiencies Summary
Deficiencies for Copy of Copy of Copy of Nozzle #2 (N5)Nozzle is located on top of the parent component's longitudinal seam. Move the longitudinal seam or activate theoption switch "Through a Category A Joint" in the nozzle dialog.
Deficiencies for Copy of Copy of Nozzle #2 (N4)Nozzle is located on top of the parent component's longitudinal seam. Move the longitudinal seam or activate theoption switch "Through a Category A Joint" in the nozzle dialog.
Deficiencies for Copy of Nozzle #2 (N3)Nozzle is located on top of the parent component's longitudinal seam. Move the longitudinal seam or activate the
option switch "Through a Category A Joint" in the nozzle dialog.
Deficiencies for Nozzle #2 (N2)Nozzle is located on top of the parent component's longitudinal seam. Move the longitudinal seam or activate the
option switch "Through a Category A Joint" in the nozzle dialog.
Deficiencies for Saddle #1Circumferential stress at the saddle horns is excessive.Compressive stress over saddle is excessive.
Warnings Summary
Warnings for Copy of Copy of Copy of Nozzle #2 (N5)Nozzle reinforcing pad extends over the parent component'slongitudinal seam. This may result in improper fit-up forwelding. Designer review is recommended. (warning)
Warnings for Copy of Copy of Nozzle #2 (N4)Nozzle reinforcing pad extends over the parent component's longitudinal seam. This may result in improper fit-up for
welding. Designer review is recommended. (warning)
Warnings for Copy of Nozzle #2 (N3)Nozzle reinforcing pad extends over the parent component's longitudinal seam. This may result in improper fit-up forwelding. Designer review is recommended. (warning)
Warnings for Ellipsoidal Head #2Internal design temperature varies across this chamber. (warning)External design temperature varies across this chamber. (warning)
External design pressure varies across this chamber. (warning)Check the following component(s): (warning)Cylinder #1 (warning)
Warnings for Nozzle #2 (N2)Nozzle reinforcing pad extends over the parent component's longitudinal seam. This may result in improper fit-up forwelding. Designer review is recommended. (warning)
ASME B16.5 / B16.47 Flange Warnings Summary
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ASME B16.5 / 16.47 Flanges with Warnings
FlangeApplicableWarnings
Nozzle #2 (N2) 1
Copy of Nozzle #2 (N3) 1
Copy of Copy of Nozzle #2 (N4) 1
Copy of Copy of Copy of Nozzle #2 (N5) 1Nozzle #1 (N1) 1, 2
ASME B16.5 / 16.47 Flange Warnings
No. Warning
1For Class 150 flanges, ASME B16.5 para. 5.4.3 recommends gaskets to be in accordance with NonmandatoryAppendix B, Table B1, Group No. I.
2For Class 150 flanges when temperature exceeds 400 F, care should be taken to avoid imposing severeexternal loads and/or thermal gradients or leakage may develop. ASME B16.5 para. 2.5.2.
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Nozzle Schedule
Nozzlemark
Service Size MaterialsImpactTested
Normalized Fine Grain Flange Blind
N1 Nozzle #1 NPS 6 Sch 40 (Std)Nozzle SA-106 B Smls pipe No No No NPS 6 Class 150
WN A105No
Pad SA-516 70 No No No
N2 Nozzle #2 NPS 6 Sch 40 (Std)Nozzle SA-106 B Smls pipe No No No NPS 6 Class 150
WN A105No
Pad SA-516 70 No No No
N3 Copy of Nozzle #2 NPS 6 Sch 40 (Std) Nozzle SA-106 B Smls pipe No No No NPS 6 Class 150WN A105 No
Pad SA-516 70 No No No
N4 Copy of Copy of Nozzle #2 NPS 6 Sch 40 (Std)Nozzle SA-106 B Smls pipe No No No NPS 6 Class 150
WN A105No
Pad SA-516 70 No No No
N5 Copy of Copy of Copy of Nozzle #2 NPS 6 Sch 40 (Std)Nozzle SA-106 B Smls pipe No No No NPS 6 Class 150
WN A105No
Pad SA-516 70 No No No
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Nozzle Summary
Nozzle
mark
OD
(in)
tn
(in)
Req tn
(in)A1? A2?
ShellReinforcement
Pad Corr
(in)
Aa/A
r(%)
Nom t
(in)
Design t
(in)
User t
(in)
Width
(in)
tpad(in)
N1 6.625 0.28 0.28 Yes Yes 0.5478* 0.524 2 0.5478 0 100.0
N2 6.625 0.28 0.28 Yes Yes 0.5 0.5 2 0.5 0 103.5
N3 6.625 0.28 0.28 Yes Yes 0.5 0.5 2 0.5 0 103.5
N4 6.625 0.28 0.28 Yes Yes 0.5 0.5 2 0.5 0 103.5
N5 6.625 0.28 0.28 Yes Yes 0.5 0.5 2 0.5 0 103.5
tn: Nozzle thickness
Req tn: Nozzle thickness required per UG-45/UG-16
Nom t: Vessel wall thickness
Design t: Required vessel wall thickness due to pressure + corrosion allowance per UG-37
User t: Local vessel wall thickness (near opening)
Aa: Area available per UG-37, governing condition
Ar: Area required per UG-37, governing condition
Corr: Corrosion allowance on nozzle wall* Head minimum thickness after forming
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Pressure Summary
Pressure Summary for Chamber bounded by Ellipsoidal Head #1 and Ellipsoidal Head #2
Identifier
P
Design
( psi)
T
Design
( F)
MAWP
( psi)
MAP
( psi)
MAEP
( psi)
Te
external
( F)
MDMT
( F)
MDMT
Exemption
Impact
Tested
Ellipsoidal Head #2 100 650 105.57 112.31 15 650 -55 Note 1 No
Straight Flange on Ellipsoidal Head #2 100 650 215.43 229.18 22.31 650 -55 Note 2 No
Cylinder #1 100 311 102.25 102.25 N/A 311 -20 Note 3 No
Straight Flange on Ellipsoidal Head #1 100 650 215.43 229.18 22.31 650 -55 Note 2 No
Ellipsoidal Head #1 100 650 105.57 112.31 15 650 -55 Note 4 No
Saddle #1 100 311 102.25 N/A N/A N/A N/A N/A N/A
Nozzle #1 (N1) 100 650 112.2 118.23 15 650 -20.51Nozzle Note 5 No
Pad Note 6 No
Nozzle #2 (N2) 100 311 102.25 102.25 N/A 311 -20Nozzle Note 5 No
Pad Note 7 No
Copy of Nozzle #2 (N3) 100 311 102.25 102.25 N/A 311 -20Nozzle Note 5 No
Pad Note 7 No
Copy of Copy of Nozzle #2 (N4) 100 311 102.25 102.25 N/A 311 -20Nozzle Note 5 No
Pad Note 7 No
Copy of Copy of Copy of Nozzle #2 (N5) 100 311 102.25 102.25 N/A 311 -20Nozzle Note 5 No
Pad Note 7 No
Chamber design MDMT is -20 FChamber rated MDMT is -20 F @ 102.25 psi
Chamber MAWP hot & corroded is 102.25 psi @ 311 F
Chamber MAP cold & new is 102.25 psi @ 70 F
This pressure chamber is not designed for external pressure.
Notes for MDMT Rating:
Note # Exemption Details
1. Straight Flangegoverns MDMT
2.Material impact test exemption temperature from Fig UCS-66 Curve B = -7 FFig UCS-66.1 MDMT reduction = 72 F, (coincident ratio = 0.4444)
Rated MDMT of -79F is limited to -55F by UCS-66(b)(2)
UCS-66 governing thickness = 0.5 in
3. Material is impact test exempt per UG-20(f) UCS-66 governing thickness = 0.5 in
4. Straight Flangegoverns MDMT
5. Nozzle is impact test exempt to -155 F per UCS-66(b)(3) (coincident ratio = 0.0743).
6.Pad impact test exemption temperature from Fig UCS-66 Curve B = -2.41 FFig UCS-66.1 MDMT reduction = 18.1 F, (coincident ratio = 0.8194) UCS-66 governing thickness = 0.5478 in.
7. Pad is impact test exempt per UG-20(f) UCS-66 governing thickness = 0.5 in.
Design notes are available on the Settings Summarypage.
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Revision History
No. Date Operator Notes
0 8/18/2014 spineyro New vessel created ASME Section VIII Division 1 [COMPRESS 2014 Build 7400]
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Settings Summary
COMPRESS 2014 Build 7400
Units: U.S. Customary
Datum Line Location: 0.00" from right seam
Design
ASME Section VIII Division 1, 2013 Edition
Design or Rating: Get Thickness from Pressure
Minimum thickness: 0.0625" per UG-16(b)
Design for cold shut down only: No
Design for lethal service (full radiography required): No
Design nozzles for: Design P, find nozzle MAWP and MAP
Corrosion weight loss: 100% of theoretical loss
UG-23 Stress Increase: 1.20
Skirt/legs stress increase: 1.0
Minimum nozzle projection: 6"Juncture calculations for > 30 only: Yes
Preheat P-No 1 Materials > 1.25" and
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UG-22 Loadings
UG-22(a) Internal or External Design Pressure : Yes
UG-22(b) Weight of the vessel and normal contents under operating or test conditions: Yes
UG-22(c) Superimposed static reactions from weight of attached equipment (external loads): No
UG-22(d)(2) Vessel supports such as lugs, rings, skirts, saddles and legs: Yes
UG-22(f) Wind reactions: No
UG-22(f) Seismic reactions: No
UG-22(j) Test pressure and coincident static head acting during the test: NoNote: UG-22(b),(c) and (f) loads only considered when supports are present.
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Radiography Summary
Radiography for Chamber bounded by Ellipsoidal Head #1 and Ellipsoidal Head #2
Component
Longitudinal Seam Left Circumferential Seam Right Circumferential Seam
MarkCategory(Fig
UW-3)
Radiography / JointType
Category(Fig
UW-3)
Radiography / JointType
Category(Fig
UW-3)
Radiography / JointType
Ellipsoidal Head #2 N/A Seamless No RT N/A N/A BFull UW-11(a) / Type1
RT1
Cylinder #1 AFull UW-11(a) / Type1
BFull UW-11(a) / Type1
BFull UW-11(a) / Type1
RT1
Ellipsoidal Head #1 N/A Seamless No RT BFull UW-11(a) / Type1
N/A N/A RT1
Nozzle Longitudinal SeamNozzle to Vessel
Circumferential SeamNozzle free end Circumferential
Seam
Nozzle #2 (N2) N/A Seamless No RT D N/A / Type 7 CUW-11(a)(4) exempt /
Type 1N/A
Copy of Nozzle #2 (N3) N/A Seamless No RT D N/A / Type 7 CUW-11(a)(4) exempt /
Type 1N/A
Copy of Copy of Nozzle #2 (N4) N/A Seamless No RT D N/A / Type 7 CUW-11(a)(4) exempt /
Type 1N/A
Copy of Copy of Copy of Nozzle #2 (N5) N/A Seamless No RT D N/A / Type 7 CUW-11(a)(4) exempt /Type 1 N/A
Nozzle #1 (N1) N/A Seamless No RT D N/A / Type 7 CUW-11(a)(4) exempt /Type 1
N/A
Nozzle Flange Longitudinal Seam Flange FaceNozzle to Flange Circumferential
Seam
ASME B16.5/16.47 flange attached to Nozzle #2(N2)
N/A Seamless No RT N/A N/A / Gasketed CUW-11(a)(4) exempt /Type 1
N/A
ASME B16.5/16.47 flange attached to Copy ofNozzle #2 (N3)
N/A Seamless No RT N/A N/A / Gasketed CUW-11(a)(4) exempt /Type 1
N/A
ASME B16.5/16.47 flange attached to Copy ofCopy of Nozzle #2 (N4)
N/A Seamless No RT N/A N/A / Gasketed CUW-11(a)(4) exempt /Type 1
N/A
ASME B16.5/16.47 flange attached to Copy of
Copy of Copy of Nozzle #2 (N5)N/A Seamless No RT N/A N/A / Gasketed C
UW-11(a)(4) exempt /
Type 1N/A
ASME B16.5/16.47 flange attached to Nozzle #1
(N1)N/A Seamless No RT N/A N/A / Gasketed C
UW-11(a)(4) exempt /
Type 1N/A
Chamber bounded by Ellipsoidal Head #1 and Ellipsoidal Head #2 - UG-116(e) Radiography:RT1
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Thickness Summary
Component
IdentifierMaterial Diameter
(in)
Length
(in)
Nominal t
(in)
Design t
(in)
Total Corrosion
(in)
Joint
ELoad
Ellipsoidal Head #2 SA-516 70 195 ID 49.2978 0.5478* 0.5478 0 1.00 External
Straight Flange on Ellipsoidal Head #2 SA-516 70 195 ID 2 1.125 0.9729 0 1.00 External
Cylinder #1 SA-516 70 196 OD 433 0.5 0.4891 0 1.00 Internal
Straight Flange on Ellipsoidal Head #1 SA-516 70 195 ID 2 1.125 0.9729 0 1.00 External
Ellipsoidal Head #1 SA-516 70 195 ID 49.2978 0.5478* 0.5478 0 1.00 External
Nominal t: Vessel wall nominal thickness
Design t: Required vessel thickness due to governing loading + corrosion
Joint E: Longitudinal seam joint efficiency
* Head minimum thickness after forming
Load
internal: Circumferential stress due to internal pressure governs
external: External pressure governs
Wind: Combined longitudinal stress of pressure + weight + wind governs
Seismic: Combined longitudinal stress of pressure + weight + seismic governs
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Weight Summary
Component
Weight ( lb) Contributed by Vessel ElementsSurface Area
ft2Metal
New*
Metal
Corroded*Insulation
InsulationSupports
LiningPiping
+ Liquid
OperatingLiquid
Test Liquid
New Corroded New Corroded
Ellipsoidal Head #2 7,055.7 7,055.7 0 0 0 0 0 0 37,192.1 37,192.1 332
Cylinder #1 37,611.1 37,611.1 0 0 0 0 0 0 466,798 466,798 1,851
Ellipsoidal Head #1 7,050.3 7,050.3 0 0 0 0 0 0 37,194.7 37,194.7 332
Saddle #1 3,006 3,006 0 0 0 0 0 0 0 0 223
TOTAL: 54,723 54,723 0 0 0 0 0 0 541,184.8 541,184.8 2,737
* Shells with attached nozzles have weight reduced by material cut out for opening.
Component
Weight ( lb) Contributed by AttachmentsSurface Area
ft2Body FlangesNozzles &Flanges
PackedBeds
TraysTray
SupportsRings &
ClipsVerticalLoads
New Corroded New Corroded
Ellipsoidal Head #2 0 0 0 0 0 0 0 0 0 0
Cylinder #1 0 0 152.3 152.3 0 0 0 0 0 7
Ellipsoidal Head #1 0 0 37.2 37.2 0 0 0 0 0 2
TOTAL: 0 0 189.5 189.5 0 0 0 0 0 9
Vessel operating weight, Corroded: 54,913 lb
Vessel operating weight, New: 54,913 lb
Vessel empty weight, Corroded: 54,913 lb
Vessel empty weight, New: 54,913 lb
Vessel test weight, New: 596,097 lb
Vessel test weight, Corroded: 596,097 lb
Vessel surface area: 2,746 ft2
Vessel center of gravity location - from datum - lift condition
Vessel Lift Weight, New: 54,913 lb
Center of Gravity: 217.7727"
Vessel Capacity
Vessel Capacity** (New): 64,901 US gal
Vessel Capacity** (Corroded): 64,901 US gal
**The vessel capacity does not include volume of nozzle, piping or other attachments.
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Long Seam Summary
Shell Long Seam Angles
Component Seam 1 Seam 2 Seam 3
Cylinder #1 0 140.6751 281.3501
Shell Plate Lengths
Component
Starting
Angle Plate 1 Plate 2 Plate 3
Cylinder #1 0 240" 240" 134.1813"
*Plate Lengths use the circumference of the vessel based on the mid diameter of the components
Shell Rollout
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Hydrostatic Test
Shop test pressure determination for Chamber bounded by Ellipsoidal Head #1 and Ellipsoidal Head #2 basedon MAWP per UG-99(b)
Shop hydrostatic test gauge pressure is 132.921 psi at 70 F (the chamber MAWP = 102.247 psi)
The shop test is performed with the vessel in the horizontal position.
IdentifierLocal testpressure
psi
Test liquidstatic head
psi
UG-99(b)stressratio
UG-99(b)pressure
factor
Ellipsoidal Head #2 140.195 7.274 1.0638 1.30
Straight Flange on Ellipsoidal Head #2 140.195 7.274 1.0638 1.30
Cylinder #1 (1) 140.195 7.274 1 1.30
Straight Flange on Ellipsoidal Head #1 140.195 7.274 1.0638 1.30
Ellipsoidal Head #1 140.195 7.274 1.0638 1.30
Copy of Copy of Copy of Nozzle #2 (N5) 133.138 0.217 1 1.30
Copy of Copy of Nozzle #2 (N4) 133.138 0.217 1 1.30
Copy of Nozzle #2 (N3) 133.138 0.217 1 1.30
Nozzle #1 (N1) 136.785 3.864 1 1.30
Nozzle #2 (N2) 133.138 0.217 1 1.30
Notes:
(1) Cylinder #1 limits the UG-99(b) stress ratio.(2) The zero degree angular position is assumed to be up, and the test liquid height is assumed to the top-most
flange.
The field test condition has not been investigated for the Chamber bounded by Ellipsoidal Head #1 and Ellipsoidal
Head #2.
The test temperature of 70 F is warmer than the minimum recommended temperature of 10 F so the brittle fracture
provision of UG-99(h) has been met.
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Vacuum Summary
Component Line of Support
Elevation
above Datum
(in)
Length Le
(in)
Ellipsoidal Head #2 - 484.2978 N/A
- 1/3 depth of Ellipsoidal Head #2 451.25 N/A
Straight Flange on Ellipsoidal Head #2 Left - 435 469.5
Straight Flange on Ellipsoidal Head #2 Right - 433 469.5
Cylinder #1 Left - 433 469.5
Cylinder #1 Right - 0 469.5
Straight Flange on Ellipsoidal Head #1 Left - 0 469.5
Straight Flange on Ellipsoidal Head #1 Right - -2 469.5
- 1/3 depth of Ellipsoidal Head #1 -18.25 N/A
Ellipsoidal Head #1 - -51.2978 N/A
Note
For main components, the listed value of 'Le' is the largest unsupported length for the component.
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Ellipsoidal Head #2
ASME Section VIII Division 1, 2013 Edition
Component: Ellipsoidal HeadMaterial Specification: SA-516 70 (II-D p.22, ln. 6)
Straight Flangegoverns MDMT
Internal design pressure: P = 100 psi @ 650 FExternal design pressure: Pe= 15 psi @ 650 F
Static liquid head:
Ps= 0 psi (SG=1, Hs=0" Operating head)Pth= 7.27 psi (SG=1, Hs=201.5" Horizontal test head)
Corrosion allowance: Inner C = 0" Outer C = 0"
Design MDMT = -20F No impact test performedRated MDMT = -55F Material is not normalized
Material is not produced to fine grain practice
PWHT is not performedDo not Optimize MDMT / Find MAWP
Radiography: Category A joints - Seamless No RTHead to shell seam - Full UW-11(a) Type 1
Estimated weight*: new = 7,055.7 lb corr = 7,055.7 lbCapacity*: new = 4,460.3 US gal corr = 4,460.3 US gal
* includes straight flange
Inner diameter = 195"Minimum head thickness = 0.5478"Head ratio D/2h = 2 (new)
Head ratio D/2h = 2 (corroded)Straight flange length Lsf = 2"
Nominal straight flange thickness tsf = 1.125"
Results Summary
The governing condition is external pressure.
Minimum thickness per UG-16 = 0.0625" + 0"= 0.0625"Design thickness due to internal pressure (t) = 0.5189"
Design thickness due to external pressure (te) = 0.5478"Maximum allowable working pressure (MAWP) = 105.57psi
Maximum allowable pressure (MAP) = 112.31psi
Maximum allowable external pressure (MAEP) = 15psi
Design thickness for internal pressure, (Corroded at 650 F) UG-32(d)(1)
t = P*D / (2*S*E - 0.2*P) + Corrosion
= 100*195 / (2*18,800*1 - 0.2*100) + 0= 0.5189"
The head internal pressure design thickness is 0.5189".
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Maximum allowable working pressure, (Corroded at 650 F) UG-32(d)(1)
P = 2*S*E*t / (D + 0.2*t) - Ps= 2*18,800*1*0.5478 / (195 +0.2*0.5478) - 0= 105.57 psi
The maximum allowable working pressure (MAWP) is 105.57psi.
Maximum allowable pressure, (New at 70 F) UG-32(d)(1)
P = 2*S*E*t / (D + 0.2*t) - Ps= 2*20,000*1*0.5478 / (195 +0.2*0.5478) - 0
= 112.31 psi
The maximum allowable pressure (MAP) is 112.31psi.
Design thickness for external pressure, (Corroded at 650 F) UG-33(d)
Equivalent outside spherical radius (Ro)
Ro = Ko*Do= 0.895*196.0956
= 175.5055 in
A = 0.125 / (Ro/ t)= 0.125 / (175.5055 / 0.547748)
= 0.00039
From Table
CS-2:B =
4,806.1918
psi
Pa = B / (Ro/ t)= 4,806.1918 / (175.5055 / 0.5477)
= 15 psi
t = 0.5477" + Corrosion = 0.5477" + 0" = 0.5477"
Check the external pressure per UG-33(a)(1) UG-32(d)(1)
t = 1.67*Pe*D / (2*S*E - 0.2*1.67*Pe) + Corrosion= 1.67*15*195 / (2*18,800*1 - 0.2*1.67*15) + 0
= 0.1299"
The head external pressure design thickness (te) is 0.5477".
Maximum Allowable External Pressure, (Corroded at 650 F) UG-33(d)
Equivalent outside spherical radius (Ro)
Ro = Ko*Do
= 0.895*196.0956= 175.5055 in
A = 0.125 / (Ro/ t)
= 0.125 / (175.5055 / 0.5478)= 0.00039
From TableCS-2:
B =4,806.6512psi
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Pa = B / (Ro/ t)= 4,806.6512 / (175.5055 / 0.5478)
= 15.0029 psi
Check the Maximum External Pressure, UG-33(a)(1) UG-32(d)(1)
P = 2*S*E*t / ((D + 0.2*t)*1.67) - Ps2= 2*18,800*1*0.5478 / ((195 +0.2*0.5478)*1.67) - 0
= 63.21 psi
The maximum allowable external pressure (MAEP) is 15psi.
% Extreme fiber elongation - UCS-79(d)
EFE = (75*t / Rf)*(1 - Rf/ Ro)
= (75*1.125 / 33.7125)*(1 - 33.7125 / infinity)
= 2.5028%
The extreme fiber elongation does not exceed 5%.
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Straight Flange on Ellipsoidal Head #2
ASME Section VIII Division 1, 2013 Edition
Component: Straight Flange
Material specification: SA-516 70 (II-D p. 22, ln. 6)Material impact test exemption temperature from Fig UCS-66 Curve B = -7 F
Fig UCS-66.1 MDMT reduction = 72 F, (coincident ratio = 0.4444)Rated MDMT of -79F is l imited to -55F by UCS-66(b)(2)
UCS-66 governing thickness = 0.5 in
Internal design pressure: P = 100 psi @ 650 F
External design pressure: Pe= 15 psi @ 650 F
Static liquid head:
Pth = 7.27 psi (SG = 1, Hs= 201.5", Horizontal testhead)
Corrosion allowance Inner C = 0" Outer C = 0"
Design MDMT = -20 F No impact test performed
Rated MDMT = -55 F Material is not normalizedMaterial is not produced to Fine Grain PracticePWHT is not performed
Radiography: Longitudinal joint - Seamless No RTCircumferential joint - Full UW-11(a) Type 1
Estimated weight New = 392.3 lb corr = 392.3 lb
Capacity New = 258.57 US gal corr = 258.57 US gal
ID = 195"Length
Lc= 2"
t = 1.125"
Design thickness, (at 650 F) UG-27(c)(1)
t = P*R / (S*E - 0.60*P) + Corrosion= 100*97.5 / (18,800*1.00 - 0.60*100) + 0
= 0.5203"
Maximum allowable working pressure, (at 650 F) UG-27(c)(1)
P = S*E*t / (R + 0.60*t) - Ps= 18,800*1.00*1.125 / (97.5 + 0.60*1.125) - 0
= 215.43 psi
Maximum allowable pressure, (at 70 F) UG-27(c)(1)
P = S*E*t / (R + 0.60*t)
= 20,000*1.00*1.125 / (97.5 + 0.60*1.125)= 229.18 psi
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External Pressure, (Corroded & at 650 F) UG-28(c)
L / Do = 469.5 / 197.25 = 2.3802Do/ t = 197.25 / 0.9729 = 202.7441From table G: A = 0.000186
From tableCS-2:
B = 2,280.8705 psi
Pa = 4*B / (3*(Do/ t))
= 4*2,280.87 / (3*(197.25 / 0.9729))= 15 psi
Design thickness for external pressure Pa= 15 psi
ta = t + Corrosion = 0.9729 + 0 = 0.9729"
Maximum Allowable External Pressure, (Corroded & at 650 F) UG-28(c)
L / Do = 469.5 / 197.25 = 2.3802Do/ t = 197.25 / 1.125 = 175.3333
From table G: A = 0.000239From table
CS-2:B = 2,934.3375 psi
Pa = 4*B / (3*(Do/ t))= 4*2,934.34 / (3*(197.25 / 1.125))
= 22.31 psi
% Extreme fiber elongation - UCS-79(d)
EFE = (50*t / Rf)*(1 - Rf/ Ro)
= (50*1.125 / 98.0625)*(1 - 98.0625 / infinity)
= 0.5736%
The extreme fiber elongation does not exceed 5%.
Allowable Compressive Stress, Hot and Corroded- ScHC, (table CS-2)
A = 0.125 / (Ro/ t)
= 0.125 / (98.625 / 1.125)
= 0.001426
B = 9,110 psi
S = 18,800 / 1.00 = 18,800 psi
ScHC = min(B, S) = 9,110 psi
Allowable Compressive Stress, Hot and New- ScHN
ScHN = ScHC= 9,110 psi
Allowable Compressive Stress, Cold and New- ScCN, (table CS-2)
A = 0.125 / (Ro/ t)
= 0.125 / (98.625 / 1.125)
= 0.001426
B = 13,615 psi
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S = 20,000 / 1.00 = 20,000 psi
ScCN = min(B, S) = 13,615 psi
Allowable Compressive Stress, Cold and Corroded- ScCCScCC = ScCN
= 13,615 psi
Allowable Compressive Stress, Vacuum and Corroded- ScVC, (tableCS-2)
A = 0.125 / (Ro/ t)
= 0.125 / (98.625 / 1.125)
= 0.001426
B = 9,110 psi
S = 18,800 / 1.00 = 18,800 psi
ScVC = min(B, S) = 9,110 psi
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Cylinder #1
ASME Section VIII Division 1, 2013 Edition
Component: Cylinder
Material specification: SA-516 70 (II-D p. 22, ln. 6)Material is impact test exempt per UG-20(f)
UCS-66 governing thickness = 0.5 in
Internal design pressure: P = 100 psi @ 311 F
Static liquid head:
Pth = 7.27 psi (SG = 1, Hs= 201.5", Horizontal test
head)
Corrosion allowance Inner C = 0" Outer C = 0"
Design MDMT = -20 F No impact test performed
Rated MDMT = -20 F Material is not normalizedMaterial is not produced to Fine Grain Practice
PWHT is not performed
Radiography: Longitudinal joint - Full UW-11(a) Type 1Left circumferential joint - Full UW-11(a) Type 1
Right circumferential joint - Full UW-11(a) Type 1
Estimated weight New = 37,611.1 lb corr = 37,611.1 lb
Capacity New = 55,980.27 US gal corr = 55,980.27 US gal
OD = 196"
LengthLc
= 433"
t = 0.5"
Design thickness, (at 311 F) Appendix 1-1
t = P*Ro/ (S*E + 0.40*P) + Corrosion
= 100*98 / (20,000*1.00 + 0.40*100) + 0= 0.4891"
Maximum allowable working pressure, (at 311 F) Appendix 1-1
P = S*E*t / (Ro- 0.40*t) - Ps= 20,000*1.00*0.5 / (98 - 0.40*0.5) - 0
= 102.25 psi
Maximum allowable pressure, (at 70 F) Appendix 1-1
P = S*E*t / (Ro- 0.40*t)
= 20,000*1.00*0.5 / (98 - 0.40*0.5)= 102.25 psi
% Extreme fiber elongation - UCS-79(d)
EFE = (50*t / Rf)*(1 - Rf/ Ro)
= (50*0.5 / 97.75)*(1 - 97.75 / infinity)
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= 0.2558%
The extreme fiber elongation does not exceed 5%.
Allowable Compressive Stress, Hot and Corroded- ScHC, (table CS-2)
A = 0.125 / (Ro/ t)
= 0.125 / (98 / 0.5)
= 0.000638
B = 9,156 psi
S = 20,000 / 1.00 = 20,000 psi
ScHC = min(B, S) = 9,156 psi
Allowable Compressive Stress, Hot and New- ScHNScHN = ScHC
= 9,156 psi
Allowable Compressive Stress, Cold and New- ScCN, (table CS-2)
A = 0.125 / (Ro/ t)
= 0.125 / (98 / 0.5)= 0.000638
B = 9,196 psi
S = 20,000 / 1.00 = 20,000 psi
ScCN = min(B, S) = 9,196 psi
Allowable Compressive Stress, Cold and Corroded- ScCCScCC = ScCN
= 9,196 psi
Allowable Compressive Stress, Vacuum and Corroded- ScVC, (tableCS-2)
A = 0.125 / (Ro/ t)
= 0.125 / (98 / 0.5)
= 0.000638
B = 9,156 psi
S = 20,000 / 1.00 = 20,000 psi
ScVC = min(B, S) = 9,156 psi
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Saddle #1
Saddle material:
Saddle construction is: Centered webSaddle allowable stress: Ss= 20,000 psi
Saddle yield stress: Sy= 38,000 psiSaddle distance to datum: 47.0239 in
Tangent to tangent length: L = 437 inSaddle separation: Ls= 377.9522inVessel radius: R = 98 in
Tangent distance left: Al= 10.0239 inTangent distance right: Ar= 49.0239 in
Saddle height: Hs= 110.0478inSaddle contact angle: = 120
Web plate thickness: ts= 0.625 inBase plate length: E = 171.0667inBase plate width: F = 10 in
Base plate thickness: tb= 0.75 inNumber of stiffener ribs: n = 9
Largest stiffener rib spacing: di= 22.6958 in
Stiffener rib thickness: tw= 0.5 inSaddle width: b = 9 inAnchor bolt size & type: 1.25 inch series 8 threaded
Anchor bolt material:Anchor bolt allowable shear: 15,000 psiAnchor bolt corrosion allowance: 0 in
Anchor bolts per saddle: 2Base coefficient of friction: = 0.45
Weight on left saddle: operating corr =23,306 lb, test new =265,973 lb
Weight on right saddle: operating corr =28,601 lb, test new =327,118 lbWeight of saddle pair =3,006 lb
Notes:
(1) Saddle calculations are based on the method presented in "Stresses in Large Cylindrical Pressure Vessels onTwo Saddle Supports" by L.P. Zick.
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LoadVessel
condition
Bending + pressure between saddles(psi)
Bending + pressure at the saddle(psi)
S1(+)
allow(+)
S1(-)
allow(-)
S2(+)
allow(+)
S2(-)
allow(-)
Weight Operat ing 10,112 20,000 143 9,156 10,035 20,000 66 9,156
Weight Test 15,301 34,200 1,632 9,196 14,421 34,200 752 9,196
LoadVessel
condition
Tangentialshear (psi)
Circumferentialstress (psi)
Stress oversaddle (psi)
Splitting (psi)
S3 allowS4
(horns)
allow(+/-)
S5 allow S6 allow
Weight Operat ing 483 16,000 -4,771 30,000 3,767 16,750 824 13,333
Weight Test 5,521 27,360 -54,572 34,200 43,085 34,200 9,427 34,200
Load Case 1: Weight ,Operating
Longitudinal stress between saddles (Weight ,Operating, left saddle loading and geometry govern)
S1= +- 3*K1*Q*(L / 12) / (*R2*t)
= 3*0.8428*23,306*(437 / 12) / (*97.752*0.5)= 143 psi
Sp= P*R / (2*t)= 102.25*97.5 / (2*0.5)
= 9,969 psi
Maximum tensile stress S1t= S1+ Sp= 10,112psiMaximum compressive stress (shut down) S1c= S1= 143psi
Tensile stress is acceptable (
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Maximum tensile stress S2t= S2+ Sp= 10,035psi
Maximum compressive stress (shut down) S2c= S2= 66psi
Tensile stress is acceptable (
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S6= K8*Q / Ae= 0.2035*28,601 / 7.0611
= 824psi
Stress in saddle is acceptable (
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S3= K2.2*Qshear/ (R*t)
= 1.1707*230,510.18 / (97.75*0.5)= 5,521psi
Tangential shear stress is acceptable ( 34,200 psi)**
Saddle splitting load (right, Weight ,Test)
Area resisting splitting force = Web area + wear plate area
Ae= Heff*ts+ tp*Wp= 11.2978*0.625 + 0*0= 7.0611 in2
S6= K8*Q / Ae= 0.2035*327,118 / 7.0611
= 9,427psi
Stress in saddle is acceptable (
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Bolt shear stress = 13,546.8 / (0.929*1*2) = 7,291 psi
Anchor bolt stress is acceptable (
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The base plate thickness of 0.75 in is adequate.
Foundation bearing check
Sf= Qmax/ (F*E)
= 328,621 / (10*171.0667)= 192 psi
Concrete bearing stress 1,658 psi ; satisfactory.
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Nozzle #2 (N2)
ASME Section VIII Division 1, 2013 Edition
tw(lower)= 0.25 in
Leg41= 0.3125 in
tw(upper)= 0.25 in
Leg42= 0.375 inLeg43= 0.3125 in
hnew= 1 in
Dp= 10.625 in
te= 0.5 in
Note: round inside edges per UG-76(c)
Location and Orientation
Located on: Cylinder #1
Orientation: 0
Nozzle center line offset to datum line: 413 in
End of nozzle to shell center: 104 in
Passes through a Category A joint: No
Nozzle
Access opening: No
Material specification: SA-106 B Smls pipe (II-D p. 14, ln. 19)
Description: NPS 6 Sch 40 (Std)Inside diameter, new: 6.065 in
Nominal wall thickness: 0.28 in
Corrosion allowance: 0 in
Projection available outside vessel, Lpr: 2.5 in
Internal projection, hnew: 1 in
Projection available outside vessel to flange face, Lf: 6 in
Local vessel minimum thickness: 0.5 in
Liquid static head included: 0 psi
Longitudinal joint efficiency: 1
Reinforcing Pad
Material specification: SA-516 70 (II-D p. 22, ln. 6)
Diameter: 10.625 in
Is split: No
ASME B16.5-2009 Flange
Description: NPS 6 Class 150 WN A105
Bolt Material: SA-193 B7 Bolt
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Blind included: No
Rated MDMT: -55F per UCS-66(b)(1)(b)
Liquid static head: 0 psi
MAWP rating: 226.7 psi@311F
MAP rating: 285 psi@70F
Hydrotest rating: 450 psi@70F
PWHT performed: No
Circumferential joint radiography: Full UW-11(a) Type 1
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Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn- Cn) + te)
= MIN(2.5*(0.5 - 0), 2.5*(0.28 - 0) + 0.5)
= 1.2 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(h, 2.5*(t - C), 2.5*(ti- Cn- C))
= MIN(1, 2.5*(0.5 - 0), 2.5*(0.28 - 0 - 0))= 0.7 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn/ (Sn*E - 0.6*P)
= 102.247*3.0325 / (17,100*1 - 0.6*102.247)
= 0.0182 in
Required thickness trfrom UG-37(a)
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Required thickness trper Interpretation VIII-1-07-50
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Area required per UG-37(c)
Allowable stresses: Sn= 17,100, Sv= 20,000, Sp= 20,000 psi
fr1= lesser of 1 or Sn/ Sv= 0.855
fr2= lesser of 1 or Sn/ Sv= 0.855
fr3= lesser of fr2or Sp/ Sv= 0.855
fr4= lesser of 1 or Sp/ Sv= 1
A = d*tr*F + 2*tn*tr*F*(1 - fr1)
= 6.065*0.5*1 + 2*0.28*0.5*1*(1 - 0.855)
= 3.073in2
Area available from FIG. UG-37.1
A1= larger of the following= 0.0001in2
= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
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= 6.065*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0.0001 in2
= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
= 2*(0.5 + 0.28)*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0 in2
A2= smaller of the following= 0.5372in2
= 5*(tn- trn)*fr2*t
= 5*(0.28 - 0.0182)*0.855*0.5
= 0.5596 in2
= 2*(tn- trn)*(2.5*tn+ te)*fr2= 2*(0.28 - 0.0182)*(2.5*0.28 + 0.5)*0.855
= 0.5372 in2
A3= smaller of the following= 0.3352in2
= 5*t*ti*fr2= 5*0.5*0.28*0.855
= 0.5985in2
= 5*ti*ti*fr2= 5*0.28*0.28*0.855
= 0.3352in2
= 2*h*ti*fr2= 2*1*0.28*0.855
= 0.4788in2
A41 = Leg2*fr3
= 0.31252*0.855
= 0.0835in2
A42 = Leg2*fr4
= 0.3752*1
= 0.1406in2
A43 = Leg2*fr2
= 0.31252
*0.855= 0.0835in2
A5 = (Dp- d - 2*tn)*te*fr4= (10.625 - 6.065 - 2*0.28)*0.5*1
= 2in2
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Area = A1+ A2+ A3+ A41+ A42+ A43+ A5= 0.0001 + 0.5372 + 0.3352 + 0.0835 + 0.1406 + 0.0835 + 2
= 3.1801in2
As Area >= A the reinforcement is adequate.
UW-16(d) Weld Check
Inner fillet: tmin = lesser of 0.75 or tnor te= 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 =0.2188 in
Outer fillet: tmin = lesser of 0.75 or teor t = 0.5 in
tw(min) = 0.5*tmin= 0.25in
tw(actual) = 0.7*Leg = 0.7*0.375 = 0.2625 in
Lower fillet: tmin = lesser of 0.75 or tnor t = 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 = 0.2188in
Upper groove: tmin = lesser of 0.75 or tnor te= 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
Lower groove: tmin = lesser of 0.75 or tnor t = 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion
= 102.247*3.0325 / (17,100*1 - 0.6*102.247) + 0
= 0.0182 in
ta = max[ ta UG-27, ta UG-22]
= max[ 0.0182 , 0 ]
= 0.0182 in
tb1 = P*Ro/ (S*E + 0.4*P) + Corrosion
= 102.247*98 / (20,000*1 + 0.4*102.247) + 0
= 0.5 in
tb1 = max[ tb1, tb UG16]
= max[ 0.5 , 0.0625 ]
= 0.5 in
tb = min[ tb3, tb1]
= min[ 0.245 , 0.5 ]
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= 0.245 in
tUG-45 = max[ ta, tb]
= max[ 0.0182 , 0.245 ]
= 0.245 in
Available nozzle wall thickness new, tn= 0.875*0.28 = 0.245 in
The nozzle neck thickness is adequate.
Allowable stresses in joints UG-45 and UW-15(c)
Groove weld in tension: 0.74*20,000 = 14,800 psi
Nozzle wall in shear: 0.7*17,100 = 11,970 psi
Inner fil let weld in shear: 0.49*17,100 = 8,379 psi
Outer fi llet weld in shear: 0.49*20,000 = 9,800 psi
Upper groove weld in tension: 0.74*20,000 = 14,800 psi
Lower fillet weld in shear: 0.49*17,100 = 8,379 psi
Strength of welded joints:
(1) Inner fillet weld in shear(/ 2)*Nozzle OD*Leg*Si= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(2) Outer fillet weld in shear(/ 2)*Pad OD*Leg*So= (/ 2)*10.625*0.375*9,800 = 61,334.69 lbf
(3) Nozzle wall in shear
(/ 2)*Mean nozzle dia*tn*Sn= (/ 2)*6.345*0.28*11,970 = 33,404.4 lbf
(4) Groove weld in tension(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
(5) Lower fillet weld in shear(/ 2)*Nozzle OD*Leg*Sl= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(6) Upper groove weld in tension
(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
Loading on welds per UG-41(b)(1)
W = (A - A1+ 2*tn*fr1*(E1*t - F*tr))*Sv= (3.073 - 0.0001 + 2*0.28*0.855*(1*0.5 - 1*0.5))*20,000
= 61,458.87lbf
W1-1 = (A2+ A5+ A41+ A42)*Sv= (0.5372 + 2 + 0.0835 + 0.1406)*20,000
= 55,226lbf
W2-2 = (A2+ A3+ A41+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 0.0835 + 0.0835 + 2*0.28*0.5*0.855)*20,000
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= 25,575.2lbf
W3-3 = (A2+ A3+ A5+ A41+ A42+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 2 + 0.0835 + 0.1406 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 68,387.2lbf
Load for path 1-1 lesser of W or W1-1= 55,226 lbfPath 1-1 through (2) & (3) = 61,334.69 + 33,404.4 = 94,739.09lbfPath 1-1 is stronger than W1-1so it is acceptable per UG-41(b)(1).
Load for path 2-2 lesser of W or W2-2= 25,575.2 lbfPath 2-2 through (1), (4), (5), (6) = 27,248.84 + 38,504.14 + 27,248.84 + 38,504.14 = 131,505.96lbfPath 2-2 is stronger than W2-2so it is acceptable per UG-41(b)(1).
Load for path 3-3 lesser of W or W3-3= 61,458.87 lbfPath 3-3 through (2), (4), (5) = 61,334.69 + 38,504.14 + 27,248.84 = 127,087.67lbfPath 3-3 is stronger than W so it is acceptable per UG-41(b)(2).
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Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary (in2)
For P = 102.25 psi @ 70 FThe opening is adequately reinforced
UG-45Nozzle WallThickness
Summary(in)
The nozzlepasses UG-45
Arequired
Aavailable
A1 A2 A3 A5A
weldstreq tmin
3.073 3.1801 0.0001 0.5372 0.3352 2 0.3076 0.245 0.245
UG-41 Weld Failure Path Analysis Summary (lbf)All failurepaths are stronger than the applicable weld loads
Weld loadW
Weld loadW1-1
Path 1-1strength
Weld loadW2-2
Path 2-2strength
Weld loadW3-3
Path 3-3strength
61,458.87 55,226 94,739.09 25,575.2 131,505.96 68,387.2 127,087.67
UW-16 Weld Sizing Summary
Weld descriptionRequired weld
size (in)Actual weld
size (in)Status
Nozzle to pad fillet (Leg41) 0.196 0.2188 weld size is adequate
Pad to shell fillet (Leg42) 0.25 0.2625 weld size is adequate
Nozzle to inside shell fillet (Leg 43) 0.1960.2188
(corroded)weld size is adequate
Nozzle to pad groove (Upper) 0.196 0.25 weld size is adequate
Nozzle to shell groove (Lower) 0.196 0.25 weld size is adequate
Calculations for internal pressure 102.25 psi @ 70 F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn+ (tn- Cn) + (t - C))
= MAX(6.065, 3.0325 + (0.28 - 0) + (0.5 - 0))
= 6.065 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn- Cn) + te)
= MIN(2.5*(0.5 - 0), 2.5*(0.28 - 0) + 0.5)= 1.2 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(h, 2.5*(t - C), 2.5*(ti- Cn- C))
= MIN(1, 2.5*(0.5 - 0), 2.5*(0.28 - 0 - 0))
= 0.7 in
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Nozzle required thickness per UG-27(c)(1)
trn = P*Rn/ (Sn*E - 0.6*P)
= 102.247*3.0325 / (17,100*1 - 0.6*102.247)
= 0.0182 in
Required thickness trfrom UG-37(a)
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Required thickness trper Interpretation VIII-1-07-50
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Area required per UG-37(c)
Allowable stresses: Sn= 17,100, Sv= 20,000, Sp= 20,000 psi
fr1= lesser of 1 or Sn/ Sv= 0.855
fr2= lesser of 1 or Sn/ Sv= 0.855
fr3= lesser of fr2or Sp/ Sv= 0.855
fr4= lesser of 1 or Sp/ Sv= 1
A = d*tr
*F + 2*tn
*tr
*F*(1 - fr1
)
= 6.065*0.5*1 + 2*0.28*0.5*1*(1 - 0.855)
= 3.073in2
Area available from FIG. UG-37.1
A1= larger of the following= 0.0001in2
= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
= 6.065*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0.0001 in2
= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
= 2*(0.5 + 0.28)*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0 in2
A2= smaller of the following= 0.5372in2
= 5*(tn- trn)*fr2*t
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= 5*(0.28 - 0.0182)*0.855*0.5
= 0.5596 in2
= 2*(tn- trn)*(2.5*tn+ te)*fr2= 2*(0.28 - 0.0182)*(2.5*0.28 + 0.5)*0.855
= 0.5372 in2
A3= smaller of the following= 0.3352in2
= 5*t*ti*fr2= 5*0.5*0.28*0.855
= 0.5985in2
= 5*ti*ti*fr2= 5*0.28*0.28*0.855
= 0.3352in2
= 2*h*ti*fr2= 2*1*0.28*0.855
= 0.4788in2
A41 = Leg2*fr3
= 0.31252*0.855
= 0.0835in2
A42 = Leg2*fr4
= 0.3752*1
= 0.1406in2
A43 = Leg2
*fr2= 0.31252*0.855
= 0.0835in2
A5 = (Dp- d - 2*tn)*te*fr4= (10.625 - 6.065 - 2*0.28)*0.5*1
= 2in2
Area = A1+ A2+ A3+ A41+ A42+ A43+ A5
= 0.0001 + 0.5372 + 0.3352 + 0.0835 + 0.1406 + 0.0835 + 2= 3.1801in2
As Area >= A the reinforcement is adequate.
UW-16(d) Weld Check
Inner fillet: tmin = lesser of 0.75 or tnor te= 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
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tc(actual) = 0.7*Leg = 0.7*0.3125 =0.2188 in
Outer fillet: tmin = lesser of 0.75 or teor t = 0.5 in
tw(min) = 0.5*tmin= 0.25in
tw(actual) = 0.7*Leg = 0.7*0.375 = 0.2625 in
Lower fillet: tmin = lesser of 0.75 or tnor t = 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 = 0.2188in
Upper groove: tmin = lesser of 0.75 or tnor te= 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
Lower groove: tmin = lesser of 0.75 or tnor t = 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion
= 102.247*3.0325 / (17,100*1 - 0.6*102.247) + 0
= 0.0182 in
ta = max[ ta UG-27, ta UG-22]
= max[ 0.0182 , 0 ]
= 0.0182 in
tb1 = P*Ro/ (S*E + 0.4*P) + Corrosion= 102.247*98 / (20,000*1 + 0.4*102.247) + 0
= 0.5 in
tb1 = max[ tb1, tb UG16]
= max[ 0.5 , 0.0625 ]
= 0.5 in
tb = min[ tb3, tb1]
= min[ 0.245 , 0.5 ]
= 0.245 in
tUG-45 = max[ ta, tb]
= max[ 0.0182 , 0.245 ]
= 0.245 in
Available nozzle wall thickness new, tn= 0.875*0.28 = 0.245 in
The nozzle neck thickness is adequate.
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Allowable stresses in joints UG-45 and UW-15(c)
Groove weld in tension: 0.74*20,000 = 14,800 psi
Nozzle wall in shear: 0.7*17,100 = 11,970 psi
Inner fil let weld in shear: 0.49*17,100 = 8,379 psi
Outer fi llet weld in shear: 0.49*20,000 = 9,800 psi
Upper groove weld in tension: 0.74*20,000 = 14,800 psi
Lower fillet weld in shear: 0.49*17,100 = 8,379 psi
Strength of welded joints:
(1) Inner fillet weld in shear
(/ 2)*Nozzle OD*Leg*Si= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(2) Outer fillet weld in shear(/ 2)*Pad OD*Leg*So= (/ 2)*10.625*0.375*9,800 = 61,334.69 lbf
(3) Nozzle wall in shear(/ 2)*Mean nozzle dia*tn*Sn= (/ 2)*6.345*0.28*11,970 = 33,404.4 lbf
(4) Groove weld in tension
(/ 2)*Nozzle OD*tw
*Sg
= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
(5) Lower fillet weld in shear(/ 2)*Nozzle OD*Leg*Sl= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(6) Upper groove weld in tension(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
Loading on welds per UG-41(b)(1)
W = (A - A1+ 2*tn*fr1*(E1*t - F*tr))*Sv= (3.073 - 0.0001 + 2*0.28*0.855*(1*0.5 - 1*0.5))*20,000
= 61,458.87lbf
W1-1 = (A2+ A5+ A41+ A42)*Sv= (0.5372 + 2 + 0.0835 + 0.1406)*20,000
= 55,226lbf
W2-2 = (A2+ A3+ A41+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 0.0835 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 25,575.2lbf
W3-3 = (A2+ A3+ A5+ A41+ A42+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 2 + 0.0835 + 0.1406 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 68,387.2lbf
Load for path 1-1 lesser of W or W1-1= 55,226 lbfPath 1-1 through (2) & (3) = 61,334.69 + 33,404.4 = 94,739.09lbfPath 1-1 is stronger than W1-1so it is acceptable per UG-41(b)(1).
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Load for path 2-2 lesser of W or W2-2= 25,575.2 lbfPath 2-2 through (1), (4), (5), (6) = 27,248.84 + 38,504.14 + 27,248.84 + 38,504.14 = 131,505.96lbfPath 2-2 is stronger than W2-2so it is acceptable per UG-41(b)(1).
Load for path 3-3 lesser of W or W3-3= 61,458.87 lbfPath 3-3 through (2), (4), (5) = 61,334.69 + 38,504.14 + 27,248.84 = 127,087.67lbfPath 3-3 is stronger than W so it is acceptable per UG-41(b)(2).
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Copy of Nozzle #2 (N3)
ASME Section VIII Division 1, 2013 Edition
tw(lower)= 0.25 in
Leg41= 0.3125 in
tw(upper)= 0.25 in
Leg42= 0.375 inLeg43= 0.3125 in
hnew= 1 in
Dp= 10.625 in
te= 0.5 in
Note: round inside edges per UG-76(c)
Location and Orientation
Located on: Cylinder #1
Orientation: 0
Nozzle center line offset to datum line: 393 in
End of nozzle to shell center: 104 in
Passes through a Category A joint: No
Nozzle
Access opening: No
Material specification: SA-106 B Smls pipe (II-D p. 14, ln. 19)
Description: NPS 6 Sch 40 (Std)Inside diameter, new: 6.065 in
Nominal wall thickness: 0.28 in
Corrosion allowance: 0 in
Projection available outside vessel, Lpr: 2.5 in
Internal projection, hnew: 1 in
Projection available outside vessel to flange face, Lf: 6 in
Local vessel minimum thickness: 0.5 in
Liquid static head included: 0 psi
Longitudinal joint efficiency: 1
Reinforcing Pad
Material specification: SA-516 70 (II-D p. 22, ln. 6)
Diameter: 10.625 in
Is split: No
ASME B16.5-2009 Flange
Description: NPS 6 Class 150 WN A105
Bolt Material: SA-193 B7 Bolt
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Blind included: No
Rated MDMT: -55F per UCS-66(b)(1)(b)
Liquid static head: 0 psi
MAWP rating: 226.7 psi@311F
MAP rating: 285 psi@70F
Hydrotest rating: 450 psi@70F
PWHT performed: No
Circumferential joint radiography: Full UW-11(a) Type 1
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Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary (in2)
For P = 102.25 psi @ 311 FThe opening is adequately reinforced
UG-45Nozzle WallThickness
Summary(in)
The nozzlepasses UG-45
Arequired
Aavailable
A1 A2 A3 A5A
weldstreq tmin
3.073 3.1801 0.0001 0.5372 0.3352 2 0.3076 0.245 0.245
UG-41 Weld Failure Path Analysis Summary (lbf)All failurepaths are stronger than the applicable weld loads
Weld loadW
Weld loadW1-1
Path 1-1strength
Weld loadW2-2
Path 2-2strength
Weld loadW3-3
Path 3-3strength
61,458.87 55,226 94,739.09 25,575.2 131,505.96 68,387.2 127,087.67
UW-16 Weld Sizing Summary
Weld descriptionRequired weld
size (in)Actual weld
size (in)Status
Nozzle to pad fillet (Leg41) 0.196 0.2188 weld size is adequate
Pad to shell fillet (Leg42) 0.25 0.2625 weld size is adequate
Nozzle to inside shell fillet (Leg 43) 0.1960.2188
(corroded)weld size is adequate
Nozzle to pad groove (Upper) 0.196 0.25 weld size is adequate
Nozzle to shell groove (Lower) 0.196 0.25 weld size is adequate
Calculations for internal pressure 102.25 psi @ 311 F
Fig UCS-66.2 general note (1) applies.
Nozzle is impact test exempt to -155 F per UCS-66(b)(3) (coincident ratio = 0.0743).
Pad is impact test exempt per UG-20(f).
Nozzle UCS-66 governing thk: 0.245 in
Nozzle rated MDMT: -155 F
Pad UCS-66 governing thickness: 0.5 in
Pad rated MDMT: -20 F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn+ (tn- Cn) + (t - C))
= MAX(6.065, 3.0325 + (0.28 - 0) + (0.5 - 0))
= 6.065 in
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Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn- Cn) + te)
= MIN(2.5*(0.5 - 0), 2.5*(0.28 - 0) + 0.5)
= 1.2 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(h, 2.5*(t - C), 2.5*(ti- Cn- C))
= MIN(1, 2.5*(0.5 - 0), 2.5*(0.28 - 0 - 0))= 0.7 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn/ (Sn*E - 0.6*P)
= 102.247*3.0325 / (17,100*1 - 0.6*102.247)
= 0.0182 in
Required thickness trfrom UG-37(a)
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Required thickness trper Interpretation VIII-1-07-50
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Area required per UG-37(c)
Allowable stresses: Sn= 17,100, Sv= 20,000, Sp= 20,000 psi
fr1= lesser of 1 or Sn/ Sv= 0.855
fr2= lesser of 1 or Sn/ Sv= 0.855
fr3= lesser of fr2or Sp/ Sv= 0.855
fr4= lesser of 1 or Sp/ Sv= 1
A = d*tr*F + 2*tn*tr*F*(1 - fr1)
= 6.065*0.5*1 + 2*0.28*0.5*1*(1 - 0.855)
= 3.073in2
Area available from FIG. UG-37.1
A1= larger of the following= 0.0001in2
= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
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= 6.065*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0.0001 in2
= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
= 2*(0.5 + 0.28)*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0 in2
A2= smaller of the following= 0.5372in2
= 5*(tn- trn)*fr2*t
= 5*(0.28 - 0.0182)*0.855*0.5
= 0.5596 in2
= 2*(tn- trn)*(2.5*tn+ te)*fr2= 2*(0.28 - 0.0182)*(2.5*0.28 + 0.5)*0.855
= 0.5372 in2
A3= smaller of the following= 0.3352in2
= 5*t*ti*fr2= 5*0.5*0.28*0.855
= 0.5985in2
= 5*ti*ti*fr2= 5*0.28*0.28*0.855
= 0.3352in2
= 2*h*ti*fr2= 2*1*0.28*0.855
= 0.4788in2
A41 = Leg2*fr3
= 0.31252*0.855
= 0.0835in2
A42 = Leg2*fr4
= 0.3752*1
= 0.1406in2
A43 = Leg2*fr2
= 0.31252
*0.855= 0.0835in2
A5 = (Dp- d - 2*tn)*te*fr4= (10.625 - 6.065 - 2*0.28)*0.5*1
= 2in2
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Area = A1+ A2+ A3+ A41+ A42+ A43+ A5= 0.0001 + 0.5372 + 0.3352 + 0.0835 + 0.1406 + 0.0835 + 2
= 3.1801in2
As Area >= A the reinforcement is adequate.
UW-16(d) Weld Check
Inner fillet: tmin = lesser of 0.75 or tnor te= 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 =0.2188 in
Outer fillet: tmin = lesser of 0.75 or teor t = 0.5 in
tw(min) = 0.5*tmin= 0.25in
tw(actual) = 0.7*Leg = 0.7*0.375 = 0.2625 in
Lower fillet: tmin = lesser of 0.75 or tnor t = 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 = 0.2188in
Upper groove: tmin = lesser of 0.75 or tnor te= 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
Lower groove: tmin = lesser of 0.75 or tnor t = 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion
= 102.247*3.0325 / (17,100*1 - 0.6*102.247) + 0
= 0.0182 in
ta = max[ ta UG-27, ta UG-22]
= max[ 0.0182 , 0 ]
= 0.0182 in
tb1 = P*Ro/ (S*E + 0.4*P) + Corrosion
= 102.247*98 / (20,000*1 + 0.4*102.247) + 0
= 0.5 in
tb1 = max[ tb1, tb UG16]
= max[ 0.5 , 0.0625 ]
= 0.5 in
tb = min[ tb3, tb1]
= min[ 0.245 , 0.5 ]
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= 0.245 in
tUG-45 = max[ ta, tb]
= max[ 0.0182 , 0.245 ]
= 0.245 in
Available nozzle wall thickness new, tn= 0.875*0.28 = 0.245 in
The nozzle neck thickness is adequate.
Allowable stresses in joints UG-45 and UW-15(c)
Groove weld in tension: 0.74*20,000 = 14,800 psi
Nozzle wall in shear: 0.7*17,100 = 11,970 psi
Inner fil let weld in shear: 0.49*17,100 = 8,379 psi
Outer fi llet weld in shear: 0.49*20,000 = 9,800 psi
Upper groove weld in tension: 0.74*20,000 = 14,800 psi
Lower fillet weld in shear: 0.49*17,100 = 8,379 psi
Strength of welded joints:
(1) Inner fillet weld in shear(/ 2)*Nozzle OD*Leg*Si= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(2) Outer fillet weld in shear(/ 2)*Pad OD*Leg*So= (/ 2)*10.625*0.375*9,800 = 61,334.69 lbf
(3) Nozzle wall in shear
(/ 2)*Mean nozzle dia*tn*Sn= (/ 2)*6.345*0.28*11,970 = 33,404.4 lbf
(4) Groove weld in tension(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
(5) Lower fillet weld in shear(/ 2)*Nozzle OD*Leg*Sl= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(6) Upper groove weld in tension
(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
Loading on welds per UG-41(b)(1)
W = (A - A1+ 2*tn*fr1*(E1*t - F*tr))*Sv= (3.073 - 0.0001 + 2*0.28*0.855*(1*0.5 - 1*0.5))*20,000
= 61,458.87lbf
W1-1 = (A2+ A5+ A41+ A42)*Sv= (0.5372 + 2 + 0.0835 + 0.1406)*20,000
= 55,226lbf
W2-2 = (A2+ A3+ A41+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 0.0835 + 0.0835 + 2*0.28*0.5*0.855)*20,000
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Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary (in2)
For P = 102.25 psi @ 70 FThe opening is adequately reinforced
UG-45Nozzle WallThickness
Summary(in)
The nozzlepasses UG-45
Arequired
Aavailable
A1 A2 A3 A5A
weldstreq tmin
3.073 3.1801 0.0001 0.5372 0.3352 2 0.3076 0.245 0.245
UG-41 Weld Failure Path Analysis Summary (lbf)All failurepaths are stronger than the applicable weld loads
Weld loadW
Weld loadW1-1
Path 1-1strength
Weld loadW2-2
Path 2-2strength
Weld loadW3-3
Path 3-3strength
61,458.87 55,226 94,739.09 25,575.2 131,505.96 68,387.2 127,087.67
UW-16 Weld Sizing Summary
Weld descriptionRequired weld
size (in)Actual weld
size (in)Status
Nozzle to pad fillet (Leg41) 0.196 0.2188 weld size is adequate
Pad to shell fillet (Leg42) 0.25 0.2625 weld size is adequate
Nozzle to inside shell fillet (Leg 43) 0.1960.2188
(corroded)weld size is adequate
Nozzle to pad groove (Upper) 0.196 0.25 weld size is adequate
Nozzle to shell groove (Lower) 0.196 0.25 weld size is adequate
Calculations for internal pressure 102.25 psi @ 70 F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn+ (tn- Cn) + (t - C))
= MAX(6.065, 3.0325 + (0.28 - 0) + (0.5 - 0))
= 6.065 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn- Cn) + te)
= MIN(2.5*(0.5 - 0), 2.5*(0.28 - 0) + 0.5)= 1.2 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(h, 2.5*(t - C), 2.5*(ti- Cn- C))
= MIN(1, 2.5*(0.5 - 0), 2.5*(0.28 - 0 - 0))
= 0.7 in
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Nozzle required thickness per UG-27(c)(1)
trn = P*Rn/ (Sn*E - 0.6*P)
= 102.247*3.0325 / (17,100*1 - 0.6*102.247)
= 0.0182 in
Required thickness trfrom UG-37(a)
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Required thickness trper Interpretation VIII-1-07-50
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Area required per UG-37(c)
Allowable stresses: Sn= 17,100, Sv= 20,000, Sp= 20,000 psi
fr1= lesser of 1 or Sn/ Sv= 0.855
fr2= lesser of 1 or Sn/ Sv= 0.855
fr3= lesser of fr2or Sp/ Sv= 0.855
fr4= lesser of 1 or Sp/ Sv= 1
A = d*tr
*F + 2*tn
*tr
*F*(1 - fr1
)
= 6.065*0.5*1 + 2*0.28*0.5*1*(1 - 0.855)
= 3.073in2
Area available from FIG. UG-37.1
A1= larger of the following= 0.0001in2
= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
= 6.065*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0.0001 in2
= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
= 2*(0.5 + 0.28)*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0 in2
A2= smaller of the following= 0.5372in2
= 5*(tn- trn)*fr2*t
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= 5*(0.28 - 0.0182)*0.855*0.5
= 0.5596 in2
= 2*(tn- trn)*(2.5*tn+ te)*fr2= 2*(0.28 - 0.0182)*(2.5*0.28 + 0.5)*0.855
= 0.5372 in2
A3= smaller of the following= 0.3352in2
= 5*t*ti*fr2= 5*0.5*0.28*0.855
= 0.5985in2
= 5*ti*ti*fr2= 5*0.28*0.28*0.855
= 0.3352in2
= 2*h*ti*fr2= 2*1*0.28*0.855
= 0.4788in2
A41 = Leg2*fr3
= 0.31252*0.855
= 0.0835in2
A42 = Leg2*fr4
= 0.3752*1
= 0.1406in2
A43 = Leg2
*fr2= 0.31252*0.855
= 0.0835in2
A5 = (Dp- d - 2*tn)*te*fr4= (10.625 - 6.065 - 2*0.28)*0.5*1
= 2in2
Area = A1+ A2+ A3+ A41+ A42+ A43+ A5
= 0.0001 + 0.5372 + 0.3352 + 0.0835 + 0.1406 + 0.0835 + 2= 3.1801in2
As Area >= A the reinforcement is adequate.
UW-16(d) Weld Check
Inner fillet: tmin = lesser of 0.75 or tnor te= 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
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tc(actual) = 0.7*Leg = 0.7*0.3125 =0.2188 in
Outer fillet: tmin = lesser of 0.75 or teor t = 0.5 in
tw(min) = 0.5*tmin= 0.25in
tw(actual) = 0.7*Leg = 0.7*0.375 = 0.2625 in
Lower fillet: tmin = lesser of 0.75 or tnor t = 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 = 0.2188in
Upper groove: tmin = lesser of 0.75 or tnor te= 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
Lower groove: tmin = lesser of 0.75 or tnor t = 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion
= 102.247*3.0325 / (17,100*1 - 0.6*102.247) + 0
= 0.0182 in
ta = max[ ta UG-27, ta UG-22]
= max[ 0.0182 , 0 ]
= 0.0182 in
tb1 = P*Ro/ (S*E + 0.4*P) + Corrosion= 102.247*98 / (20,000*1 + 0.4*102.247) + 0
= 0.5 in
tb1 = max[ tb1, tb UG16]
= max[ 0.5 , 0.0625 ]
= 0.5 in
tb = min[ tb3, tb1]
= min[ 0.245 , 0.5 ]
= 0.245 in
tUG-45 = max[ ta, tb]
= max[ 0.0182 , 0.245 ]
= 0.245 in
Available nozzle wall thickness new, tn= 0.875*0.28 = 0.245 in
The nozzle neck thickness is adequate.
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Allowable stresses in joints UG-45 and UW-15(c)
Groove weld in tension: 0.74*20,000 = 14,800 psi
Nozzle wall in shear: 0.7*17,100 = 11,970 psi
Inner fil let weld in shear: 0.49*17,100 = 8,379 psi
Outer fi llet weld in shear: 0.49*20,000 = 9,800 psi
Upper groove weld in tension: 0.74*20,000 = 14,800 psi
Lower fillet weld in shear: 0.49*17,100 = 8,379 psi
Strength of welded joints:
(1) Inner fillet weld in shear
(/ 2)*Nozzle OD*Leg*Si= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(2) Outer fillet weld in shear(/ 2)*Pad OD*Leg*So= (/ 2)*10.625*0.375*9,800 = 61,334.69 lbf
(3) Nozzle wall in shear(/ 2)*Mean nozzle dia*tn*Sn= (/ 2)*6.345*0.28*11,970 = 33,404.4 lbf
(4) Groove weld in tension
(/ 2)*Nozzle OD*tw
*Sg
= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
(5) Lower fillet weld in shear(/ 2)*Nozzle OD*Leg*Sl= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(6) Upper groove weld in tension(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
Loading on welds per UG-41(b)(1)
W = (A - A1+ 2*tn*fr1*(E1*t - F*tr))*Sv= (3.073 - 0.0001 + 2*0.28*0.855*(1*0.5 - 1*0.5))*20,000
= 61,458.87lbf
W1-1 = (A2+ A5+ A41+ A42)*Sv= (0.5372 + 2 + 0.0835 + 0.1406)*20,000
= 55,226lbf
W2-2 = (A2+ A3+ A41+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 0.0835 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 25,575.2lbf
W3-3 = (A2+ A3+ A5+ A41+ A42+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 2 + 0.0835 + 0.1406 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 68,387.2lbf
Load for path 1-1 lesser of W or W1-1= 55,226 lbfPath 1-1 through (2) & (3) = 61,334.69 + 33,404.4 = 94,739.09lbfPath 1-1 is stronger than W1-1so it is acceptable per UG-41(b)(1).
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Copy of Copy of Nozzle #2 (N4)
ASME Section VIII Division 1, 2013 Edition
tw(lower)= 0.25 in
Leg41= 0.3125 in
tw(upper)= 0.25 in
Leg42= 0.375 inLeg43= 0.3125 in
hnew= 1 in
Dp= 10.625 in
te= 0.5 in
Note: round inside edges per UG-76(c)
Location and Orientation
Located on: Cylinder #1
Orientation: 0
Nozzle center line offset to datum line: 353 in
End of nozzle to shell center: 104 in
Passes through a Category A joint: No
Nozzle
Access opening: No
Material specification: SA-106 B Smls pipe (II-D p. 14, ln. 19)
Description: NPS 6 Sch 40 (Std)Inside diameter, new: 6.065 in
Nominal wall thickness: 0.28 in
Corrosion allowance: 0 in
Projection available outside vessel, Lpr: 2.5 in
Internal projection, hnew: 1 in
Projection available outside vessel to flange face, Lf: 6 in
Local vessel minimum thickness: 0.5 in
Liquid static head included: 0 psi
Longitudinal joint efficiency: 1
Reinforcing Pad
Material specification: SA-516 70 (II-D p. 22, ln. 6)
Diameter: 10.625 in
Is split: No
ASME B16.5-2009 Flange
Description: NPS 6 Class 150 WN A105
Bolt Material: SA-193 B7 Bolt
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Blind included: No
Rated MDMT: -55F per UCS-66(b)(1)(b)
Liquid static head: 0 psi
MAWP rating: 226.7 psi@311F
MAP rating: 285 psi@70F
Hydrotest rating: 450 psi@70F
PWHT performed: No
Circumferential joint radiography: Full UW-11(a) Type 1
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Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary (in2)
For P = 102.25 psi @ 311 FThe opening is adequately reinforced
UG-45Nozzle WallThickness
Summary(in)
The nozzlepasses UG-45
Arequired
Aavailable
A1 A2 A3 A5A
weldstreq tmin
3.073 3.1801 0.0001 0.5372 0.3352 2 0.3076 0.245 0.245
UG-41 Weld Failure Path Analysis Summary (lbf)All failurepaths are stronger than the applicable weld loads
Weld loadW
Weld loadW1-1
Path 1-1strength
Weld loadW2-2
Path 2-2strength
Weld loadW3-3
Path 3-3strength
61,458.87 55,226 94,739.09 25,575.2 131,505.96 68,387.2 127,087.67
UW-16 Weld Sizing Summary
Weld descriptionRequired weld
size (in)Actual weld
size (in)Status
Nozzle to pad fillet (Leg41) 0.196 0.2188 weld size is adequate
Pad to shell fillet (Leg42) 0.25 0.2625 weld size is adequate
Nozzle to inside shell fillet (Leg 43) 0.1960.2188
(corroded)weld size is adequate
Nozzle to pad groove (Upper) 0.196 0.25 weld size is adequate
Nozzle to shell groove (Lower) 0.196 0.25 weld size is adequate
Calculations for internal pressure 102.25 psi @ 311 F
Fig UCS-66.2 general note (1) applies.
Nozzle is impact test exempt to -155 F per UCS-66(b)(3) (coincident ratio = 0.0743).
Pad is impact test exempt per UG-20(f).
Nozzle UCS-66 governing thk: 0.245 in
Nozzle rated MDMT: -155 F
Pad UCS-66 governing thickness: 0.5 in
Pad rated MDMT: -20 F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn+ (tn- Cn) + (t - C))
= MAX(6.065, 3.0325 + (0.28 - 0) + (0.5 - 0))
= 6.065 in
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Area = A1+ A2+ A3+ A41+ A42+ A43+ A5= 0.0001 + 0.5372 + 0.3352 + 0.0835 + 0.1406 + 0.0835 + 2
= 3.1801in2
As Area >= A the reinforcement is adequate.
UW-16(d) Weld Check
Inner fillet: tmin = lesser of 0.75 or tnor te= 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 =0.2188 in
Outer fillet: tmin = lesser of 0.75 or teor t = 0.5 in
tw(min) = 0.5*tmin= 0.25in
tw(actual) = 0.7*Leg = 0.7*0.375 = 0.2625 in
Lower fillet: tmin = lesser of 0.75 or tnor t = 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 = 0.2188in
Upper groove: tmin = lesser of 0.75 or tnor te= 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
Lower groove: tmin = lesser of 0.75 or tnor t = 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion
= 102.247*3.0325 / (17,100*1 - 0.6*102.247) + 0
= 0.0182 in
ta = max[ ta UG-27, ta UG-22]
= max[ 0.0182 , 0 ]
= 0.0182 in
tb1 = P*Ro/ (S*E + 0.4*P) + Corrosion
= 102.247*98 / (20,000*1 + 0.4*102.247) + 0
= 0.5 in
tb1 = max[ tb1, tb UG16]
= max[ 0.5 , 0.0625 ]
= 0.5 in
tb = min[ tb3, tb1]
= min[ 0.245 , 0.5 ]
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= 25,575.2lbf
W3-3 = (A2+ A3+ A5+ A41+ A42+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 2 + 0.0835 + 0.1406 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 68,387.2lbf
Load for path 1-1 lesser of W or W1-1= 55,226 lbfPath 1-1 through (2) & (3) = 61,334.69 + 33,404.4 = 94,739.09lbfPath 1-1 is stronger than W1-1so it is acceptable per UG-41(b)(1).
Load for path 2-2 lesser of W or W2-2= 25,575.2 lbfPath 2-2 through (1), (4), (5), (6) = 27,248.84 + 38,504.14 + 27,248.84 + 38,504.14 = 131,505.96lbfPath 2-2 is stronger than W2-2so it is acceptable per UG-41(b)(1).
Load for path 3-3 lesser of W or W3-3= 61,458.87 lbfPath 3-3 through (2), (4), (5) = 61,334.69 + 38,504.14 + 27,248.84 = 127,087.67lbfPath 3-3 is stronger than W so it is acceptable per UG-41(b)(2).
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Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary (in2)
For P = 102.25 psi @ 70 FThe opening is adequately reinforced
UG-45Nozzle WallThickness
Summary(in)
The nozzlepasses UG-45
Arequired
Aavailable
A1 A2 A3 A5A
weldstreq tmin
3.073 3.1801 0.0001 0.5372 0.3352 2 0.3076 0.245 0.245
UG-41 Weld Failure Path Analysis Summary (lbf)All failurepaths are stronger than the applicable weld loads
Weld loadW
Weld loadW1-1
Path 1-1strength
Weld loadW2-2
Path 2-2strength
Weld loadW3-3
Path 3-3strength
61,458.87 55,226 94,739.09 25,575.2 131,505.96 68,387.2 127,087.67
UW-16 Weld Sizing Summary
Weld descriptionRequired weld
size (in)Actual weld
size (in)Status
Nozzle to pad fillet (Leg41) 0.196 0.2188 weld size is adequate
Pad to shell fillet (Leg42) 0.25 0.2625 weld size is adequate
Nozzle to inside shell fillet (Leg 43) 0.1960.2188
(corroded)weld size is adequate
Nozzle to pad groove (Upper) 0.196 0.25 weld size is adequate
Nozzle to shell groove (Lower) 0.196 0.25 weld size is adequate
Calculations for internal pressure 102.25 psi @ 70 F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn+ (tn- Cn) + (t - C))
= MAX(6.065, 3.0325 + (0.28 - 0) + (0.5 - 0))
= 6.065 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn- Cn) + te)
= MIN(2.5*(0.5 - 0), 2.5*(0.28 - 0) + 0.5)= 1.2 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(h, 2.5*(t - C), 2.5*(ti- Cn- C))
= MIN(1, 2.5*(0.5 - 0), 2.5*(0.28 - 0 - 0))
= 0.7 in
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Nozzle required thickness per UG-27(c)(1)
trn = P*Rn/ (Sn*E - 0.6*P)
= 102.247*3.0325 / (17,100*1 - 0.6*102.247)
= 0.0182 in
Required thickness trfrom UG-37(a)
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Required thickness trper Interpretation VIII-1-07-50
tr = P*Ro/ (S*E + 0.4*P)
= 102.247*98 / (20,000*1 + 0.4*102.247)
= 0.5 in
Area required per UG-37(c)
Allowable stresses: Sn= 17,100, Sv= 20,000, Sp= 20,000 psi
fr1= lesser of 1 or Sn/ Sv= 0.855
fr2= lesser of 1 or Sn/ Sv= 0.855
fr3= lesser of fr2or Sp/ Sv= 0.855
fr4= lesser of 1 or Sp/ Sv= 1
A = d*tr
*F + 2*tn
*tr
*F*(1 - fr1
)
= 6.065*0.5*1 + 2*0.28*0.5*1*(1 - 0.855)
= 3.073in2
Area available from FIG. UG-37.1
A1= larger of the following= 0.0001in2
= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
= 6.065*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0.0001 in2
= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)
= 2*(0.5 + 0.28)*(1*0.5 - 1*0.5) - 2*0.28*(1*0.5 - 1*0.5)*(1 - 0.855)
= 0 in2
A2= smaller of the following= 0.5372in2
= 5*(tn- trn)*fr2*t
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= 5*(0.28 - 0.0182)*0.855*0.5
= 0.5596 in2
= 2*(tn- trn)*(2.5*tn+ te)*fr2= 2*(0.28 - 0.0182)*(2.5*0.28 + 0.5)*0.855
= 0.5372 in2
A3= smaller of the following= 0.3352in2
= 5*t*ti*fr2= 5*0.5*0.28*0.855
= 0.5985in2
= 5*ti*ti*fr2= 5*0.28*0.28*0.855
= 0.3352in2
= 2*h*ti*fr2= 2*1*0.28*0.855
= 0.4788in2
A41 = Leg2*fr3
= 0.31252*0.855
= 0.0835in2
A42 = Leg2*fr4
= 0.3752*1
= 0.1406in2
A43 = Leg2
*fr2= 0.31252*0.855
= 0.0835in2
A5 = (Dp- d - 2*tn)*te*fr4= (10.625 - 6.065 - 2*0.28)*0.5*1
= 2in2
Area = A1+ A2+ A3+ A41+ A42+ A43+ A5
= 0.0001 + 0.5372 + 0.3352 + 0.0835 + 0.1406 + 0.0835 + 2= 3.1801in2
As Area >= A the reinforcement is adequate.
UW-16(d) Weld Check
Inner fillet: tmin = lesser of 0.75 or tnor te= 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
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tc(actual) = 0.7*Leg = 0.7*0.3125 =0.2188 in
Outer fillet: tmin = lesser of 0.75 or teor t = 0.5 in
tw(min) = 0.5*tmin= 0.25in
tw(actual) = 0.7*Leg = 0.7*0.375 = 0.2625 in
Lower fillet: tmin = lesser of 0.75 or tnor t = 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 = 0.2188in
Upper groove: tmin = lesser of 0.75 or tnor te= 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
Lower groove: tmin = lesser of 0.75 or tnor t = 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion
= 102.247*3.0325 / (17,100*1 - 0.6*102.247) + 0
= 0.0182 in
ta = max[ ta UG-27, ta UG-22]
= max[ 0.0182 , 0 ]
= 0.0182 in
tb1 = P*Ro/ (S*E + 0.4*P) + Corrosion= 102.247*98 / (20,000*1 + 0.4*102.247) + 0
= 0.5 in
tb1 = max[ tb1, tb UG16]
= max[ 0.5 , 0.0625 ]
= 0.5 in
tb = min[ tb3, tb1]
= min[ 0.245 , 0.5 ]
= 0.245 in
tUG-45 = max[ ta, tb]
= max[ 0.0182 , 0.245 ]
= 0.245 in
Available nozzle wall thickness new, tn= 0.875*0.28 = 0.245 in
The nozzle neck thickness is adequate.
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Allowable stresses in joints UG-45 and UW-15(c)
Groove weld in tension: 0.74*20,000 = 14,800 psi
Nozzle wall in shear: 0.7*17,100 = 11,970 psi
Inner fil let weld in shear: 0.49*17,100 = 8,379 psi
Outer fi llet weld in shear: 0.49*20,000 = 9,800 psi
Upper groove weld in tension: 0.74*20,000 = 14,800 psi
Lower fillet weld in shear: 0.49*17,100 = 8,379 psi
Strength of welded joints:
(1) Inner fillet weld in shear
(/ 2)*Nozzle OD*Leg*Si= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(2) Outer fillet weld in shear(/ 2)*Pad OD*Leg*So= (/ 2)*10.625*0.375*9,800 = 61,334.69 lbf
(3) Nozzle wall in shear(/ 2)*Mean nozzle dia*tn*Sn= (/ 2)*6.345*0.28*11,970 = 33,404.4 lbf
(4) Groove weld in tension
(/ 2)*Nozzle OD*tw
*Sg
= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
(5) Lower fillet weld in shear(/ 2)*Nozzle OD*Leg*Sl= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(6) Upper groove weld in tension(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
Loading on welds per UG-41(b)(1)
W = (A - A1+ 2*tn*fr1*(E1*t - F*tr))*Sv= (3.073 - 0.0001 + 2*0.28*0.855*(1*0.5 - 1*0.5))*20,000
= 61,458.87lbf
W1-1 = (A2+ A5+ A41+ A42)*Sv= (0.5372 + 2 + 0.0835 + 0.1406)*20,000
= 55,226lbf
W2-2 = (A2+ A3+ A41+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 0.0835 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 25,575.2lbf
W3-3 = (A2+ A3+ A5+ A41+ A42+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 2 + 0.0835 + 0.1406 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 68,387.2lbf
Load for path 1-1 lesser of W or W1-1= 55,226 lbfPath 1-1 through (2) & (3) = 61,334.69 + 33,404.4 = 94,739.09lbfPath 1-1 is stronger than W1-1so it is acceptable per UG-41(b)(1).
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Load for path 2-2 lesser of W or W2-2= 25,575.2 lbfPath 2-2 through (1), (4), (5), (6) = 27,248.84 + 38,504.14 + 27,248.84 + 38,504.14 = 131,505.96lbfPath 2-2 is stronger than W2-2so it is acceptable per UG-41(b)(1).
Load for path 3-3 lesser of W or W3-3= 61,458.87 lbfPath 3-3 through (2), (4), (5) = 61,334.69 + 38,504.14 + 27,248.84 = 127,087.67lbfPath 3-3 is stronger than W so it is acceptable per UG-41(b)(2).
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Blind included: No
Rated MDMT: -55F per UCS-66(b)(1)(b)
Liquid static head: 0 psi
MAWP rating: 226.7 psi@311F
MAP rating: 285 psi@70F
Hydrotest rating: 450 psi@70F
PWHT performed: No
Circumferential joint radiography: Full UW-11(a) Type 1
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Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary (in2)
For P = 102.25 psi @ 311 FThe opening is adequately reinforced
UG-45Nozzle WallThickness
Summary(in)
The nozzlepasses UG-45
Arequired
Aavailable
A1 A2 A3 A5A
weldstreq tmin
3.073 3.1801 0.0001 0.5372 0.3352 2 0.3076 0.245 0.245
UG-41 Weld Failure Path Analysis Summary (lbf)All failurepaths are stronger than the applicable weld loads
Weld loadW
Weld loadW1-1
Path 1-1strength
Weld loadW2-2
Path 2-2strength
Weld loadW3-3
Path 3-3strength
61,458.87 55,226 94,739.09 25,575.2 131,505.96 68,387.2 127,087.67
UW-16 Weld Sizing Summary
Weld descriptionRequired weld
size (in)Actual weld
size (in)Status
Nozzle to pad fillet (Leg41) 0.196 0.2188 weld size is adequate
Pad to shell fillet (Leg42) 0.25 0.2625 weld size is adequate
Nozzle to inside shell fillet (Leg 43) 0.1960.2188
(corroded)weld size is adequate
Nozzle to pad groove (Upper) 0.196 0.25 weld size is adequate
Nozzle to shell groove (Lower) 0.196 0.25 weld size is adequate
Calculations for internal pressure 102.25 psi @ 311 F
Fig UCS-66.2 general note (1) applies.
Nozzle is impact test exempt to -155 F per UCS-66(b)(3) (coincident ratio = 0.0743).
Pad is impact test exempt per UG-20(f).
Nozzle UCS-66 governing thk: 0.245 in
Nozzle rated MDMT: -155 F
Pad UCS-66 governing thickness: 0.5 in
Pad rated MDMT: -20 F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn+ (tn- Cn) + (t - C))
= MAX(6.065, 3.0325 + (0.28 - 0) + (0.5 - 0))
= 6.065 in
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Area = A1+ A2+ A3+ A41+ A42+ A43+ A5= 0.0001 + 0.5372 + 0.3352 + 0.0835 + 0.1406 + 0.0835 + 2
= 3.1801in2
As Area >= A the reinforcement is adequate.
UW-16(d) Weld Check
Inner fillet: tmin = lesser of 0.75 or tnor te= 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 =0.2188 in
Outer fillet: tmin = lesser of 0.75 or teor t = 0.5 in
tw(min) = 0.5*tmin= 0.25in
tw(actual) = 0.7*Leg = 0.7*0.375 = 0.2625 in
Lower fillet: tmin = lesser of 0.75 or tnor t = 0.28 in
tc(min) = lesser of 0.25 or 0.7*tmin= 0.196in
tc(actual) = 0.7*Leg = 0.7*0.3125 = 0.2188in
Upper groove: tmin = lesser of 0.75 or tnor te= 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
Lower groove: tmin = lesser of 0.75 or tnor t = 0.28 in
tw(min) = 0.7*tmin= 0.196in
tw(actual) = 0.25 in
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion
= 102.247*3.0325 / (17,100*1 - 0.6*102.247) + 0
= 0.0182 in
ta = max[ ta UG-27, ta UG-22]
= max[ 0.0182 , 0 ]
= 0.0182 in
tb1 = P*Ro/ (S*E + 0.4*P) + Corrosion
= 102.247*98 / (20,000*1 + 0.4*102.247) + 0
= 0.5 in
tb1 = max[ tb1, tb UG16]
= max[ 0.5 , 0.0625 ]
= 0.5 in
tb = min[ tb3, tb1]
= min[ 0.245 , 0.5 ]
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= 0.245 in
tUG-45 = max[ ta, tb]
= max[ 0.0182 , 0.245 ]
= 0.245 in
Available nozzle wall thickness new, tn= 0.875*0.28 = 0.245 in
The nozzle neck thickness is adequate.
Allowable stresses in joints UG-45 and UW-15(c)
Groove weld in tension: 0.74*20,000 = 14,800 psi
Nozzle wall in shear: 0.7*17,100 = 11,970 psi
Inner fil let weld in shear: 0.49*17,100 = 8,379 psi
Outer fi llet weld in shear: 0.49*20,000 = 9,800 psi
Upper groove weld in tension: 0.74*20,000 = 14,800 psi
Lower fillet weld in shear: 0.49*17,100 = 8,379 psi
Strength of welded joints:
(1) Inner fillet weld in shear(/ 2)*Nozzle OD*Leg*Si= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(2) Outer fillet weld in shear(/ 2)*Pad OD*Leg*So= (/ 2)*10.625*0.375*9,800 = 61,334.69 lbf
(3) Nozzle wall in shear
(/ 2)*Mean nozzle dia*tn*Sn= (/ 2)*6.345*0.28*11,970 = 33,404.4 lbf
(4) Groove weld in tension(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
(5) Lower fillet weld in shear(/ 2)*Nozzle OD*Leg*Sl= (/ 2)*6.625*0.3125*8,379 = 27,248.84 lbf
(6) Upper groove weld in tension
(/ 2)*Nozzle OD*tw*Sg= (/ 2)*6.625*0.25*14,800 = 38,504.14 lbf
Loading on welds per UG-41(b)(1)
W = (A - A1+ 2*tn*fr1*(E1*t - F*tr))*Sv= (3.073 - 0.0001 + 2*0.28*0.855*(1*0.5 - 1*0.5))*20,000
= 61,458.87lbf
W1-1 = (A2+ A5+ A41+ A42)*Sv= (0.5372 + 2 + 0.0835 + 0.1406)*20,000
= 55,226lbf
W2-2 = (A2+ A3+ A41+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 0.0835 + 0.0835 + 2*0.28*0.5*0.855)*20,000
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= 25,575.2lbf
W3-3 = (A2+ A3+ A5+ A41+ A42+ A43+ 2*tn*t*fr1)*Sv= (0.5372 + 0.3352 + 2 + 0.0835 + 0.1406 + 0.0835 + 2*0.28*0.5*0.855)*20,000
= 68,387.2lbf
Load for path 1-1 lesser of W or W1-1= 55,226 lbfPath 1-1 through (2) & (3) = 61,334.69 + 33,404.4 = 94,739.09lbfPath 1-1 is stronger than W1-1so it is acceptable per UG-41(b)(1).
Load for path 2-2 lesser of W or W2-2= 25,575.2 lbfPath 2-2 through (1), (4), (5), (6) = 27,248.84 + 38,504.14 + 27,248.84 + 38,504.14 = 131,505.96lbfPath 2-2 is stronger than W2-2so it is acceptable per UG-41(b)(1).
Load for path 3-3 lesser of W or W3-3= 61,458.87 lbfPath 3-3 through (2), (4), (5