Synthetic Division Notes

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Synthetic Division Algebra 2 CP

Transcript of Synthetic Division Notes

Page 1: Synthetic Division Notes

Synthetic DivisionAlgebra 2 CP

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Synthetic Division A trick for dividing polynomials Helps us solve for the roots of polynomials Only works when we divide by 1st degree

(linear) polynomials

)2()11183( 24 xxxxExponent can’t be larger than 1!

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Synthetic Division

)24()1152( 24 xxxx

)2()11183( 24 xxxx

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Your Turn On your Synthetic Division Notes packet,

complete problems 1 – 5. Decide if it’s possible to use synthetic division to

divide the two polynomials

1. Yes 2. Yes 3. No 4. No 5. No

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Division Vocab Review

Dividend Divisor

2)3()65( 2 xxxx

Quotient

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Preparing for Synthetic Division Can only be used when the divisor is in the

form:

To divide, you will need the constant term of your divisor: set your divisor equal to 0 and solve!

x – c

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Preparing for Synthetic Division, cont. Polynomials need to be written in expanded,

standard polynomial form. For the polynomial to be expanded sequentially,

ALL terms must be listed AKA: If you’re missing terms, they must be filled in

with “place holders.”

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Preparing for Synthetic Division, cont.

xxx 273 35

xxx 273 35

020703 2345 xxxxx

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Your Turn On your Synthetic Division Notes packet, write

the dividend in expanded standard polynomial form for problems 6 – 10.

6.

7.

8.

9.

10.

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*Synthetic Division Steps Example Problem:

)2()11183( 24 xxxx

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Prep Step Linear Divisor?

x – 2 Dividend in Expanded Standard Polynomial

Form? 3x4 – 8x2 – 11x + 1 3x4 + – 8x2 – 11x + 1 3x4 + 0x3 – 8x2 – 11x + 1

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Step 12

Write the constant value of the divisor (c) here.

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Step 22

Write all the coefficients of the expanded dividend here.

3 0 -8 -11 1

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Step 32

“Drop” the 1st coefficient underneath the line.

3 0 -8 -11 1

3

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Step 42

Multiply “c” by the last value underneath the line. Write their product just underneath the next coefficient.

3 0 -8 -11 1

6

3

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Step 52

Add together the numbers in that column and write their sum underneath the line.

3 0 -8 -11 1

6

3 6

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Step 62

Multiply “c” by the last value underneath the line. Write their product just underneath the next coefficient.

3 0 -8 -11 1

6 12

3 6

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Step 72

Repeat steps 5 and 6 until a number appears in the box underneath the last column.

3 0 -8 -11 1

6 12 8 -6

3 6 4 -3 -5

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Step 8 – Naming the Quotient2

In the last row are the coefficients of the quotient in decreasing order. The quotient is one degree less than the dividend.

3 0 -8 -11 1

6 12 8 -6

3 6 4 -3 -5

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Step 8 – Naming the Quotient3 6 4 -3 -5

The number in the box is the remainder. )2()11183( 24 xxxx

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Your Turn On your Synthetic Division Notes packet,

solve for the quotient of problems 11 – 14 using synthetic division

11.

12.

13.

14.