Synthetic Division - WordPress.com

24
Example: ( βˆ’ + ) Γ· ( βˆ’ ) BEGIN HOW – TO: SYNTHETIC DIVISION

Transcript of Synthetic Division - WordPress.com

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

BEGIN

HOW – TO: SYNTHETIC DIVISION

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #1: Draw a corner and a baseline.

NEXT

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #2: Look at the expression you’re dividing by. Put the OPPOSITE of the number sitting next to x in the corner.

5

NEXT

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #3: Next to the corner, write the coefficients of each term of the first polynomial. Don’t forget placeholders!!!

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #4: Drop down the first number outside of the corner below the baseline.

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

5 4

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #5: Multiply the number in the corner by the number you just dropped down below the baseline. Write the result above the baseline in the next column.

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

x 4

5 4 20

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #6: You should now have a column with two values. Add them together, and write the result below the baseline.

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

x 4 20

+5 4 20 +

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #7: Multiply the number in the corner by the number you just added to the baseline. Put this above the baseline in the next column.

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

x 4 20

+5 4 20 100

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #8: Repeat steps 6 & 7 until there are no empty spots below the baseline.

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

x 4 20 98

+5 4 20 100 +

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #8: (Cont.) Repeat steps 6 & 7 until there are no empty spots below the baseline.

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

x 4 20 98

+5 4 20 100 490

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #8: (Cont.) Repeat steps 6 & 7 until there are no empty spots below the baseline.

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

x 4 20 98 491

+5 4 20 100 490 +

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #9: Each number on the baseline represents the coefficient of a variable with ONE LESS degree than the column started out with. The constant’s column gives the remainder.

5 4 0 -2 1

NEXT

π‘₯3 π‘₯2 π‘₯ 𝑐

x 4 20 98 491

+5 4 20 100 490

π‘₯2 π‘₯ 𝑐 𝑅

Example: (πŸ’π’™πŸ‘ βˆ’ πŸπ’™ + 𝟏) Γ· (𝒙 βˆ’ πŸ“)

Step #10: Write out the result of the division.

5 4 0 -2 1 π‘₯3 π‘₯2 π‘₯ 𝑐

x 4 20 98 491

+5 4 20 100 490

π‘₯2 π‘₯ 𝑐 𝑅

= πŸ’π’™πŸ + πŸπŸŽπ’™ + πŸ—πŸ– +πŸ’πŸ—πŸ

𝒙 βˆ’ πŸ“

Try this one on your own!

πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

Don’t click β€œNext” until you’ve completed the problem!

NEXT

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

Draw corner and baseline!

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

-2

Look at the polynomial you’re dividing by. Put the OPPOSITE of the number sitting next to x in the corner.

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

-2 3 7 2

Write the coefficients of the first polynomial!

π‘₯2 π‘₯ 𝑐

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

-2 3 7 2

-2 3 Drop down the first number.

π‘₯2 π‘₯ 𝑐

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

-2 3 7 2

-2 3

-2 -6

-2 βˆ™ 3 = -6

π‘₯2 π‘₯ 𝑐

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

-2 3 7 2

-2 3 1

-2 -6

7 + -6 = 1

π‘₯2 π‘₯ 𝑐

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

-2 3 7 2

-2 3 1

-2 -6 -2

-2 βˆ™ 1 = -2

π‘₯2 π‘₯ 𝑐

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

-2 3 7 2

-2 3 1 0

-2 -6 -2

2 + -2 = 0

π‘₯2 π‘₯ 𝑐

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

NEXT

-2 3 7 2

-2 3 1 0

-2 -6 -2

Write what powers each coefficient now represents.

π‘₯2 π‘₯ 𝑐

π‘₯ 𝑐 𝑅

Example: πŸ‘π’™πŸ + πŸ•π’™ + 𝟐 Γ· 𝒙 + 𝟐

-2 3 7 2

-2 3 1 0

-2 -6 -2

Write final answer.

π‘₯2 π‘₯ 𝑐

π‘₯ 𝑐 𝑅

= πŸ‘π’™ + 𝟏