Study Guide Review Guide Review UNIT 5 Key Vocabulary alternate exterior angles (ángulos alternos...

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12 43 56 87 l t m 67° 35° y 67° 67° x A B CD F E Study Guide Review UNIT 5 Study Guide Review Key Vocabulary alternate exterior angles (ángulos alternos externos) alternate interior angles (ángulos alternos internos) corresponding angles (ángulos correspondientes (para líneas)) exterior angle (ángulo externo) interior angle (ángulos internos) remote interior angle (ángulo interno remoto) same-side interior angles (ángulos internos del mismo lado) similar (semejantes) transversal (transversal) Angle Relationships in Parallel Lines and Triangles How can you solve real-world problems that involve angle relationships in parallel lines and triangles? Find each angle measure when m6 = 81°. MODULE 11 11 ? ESSENTIAL QUESTION EXAMPLE 1 m5 m5 = 180° - 81° = 99° 5 and 6 are supplementary angles. m1 m1 = 99° 1 and 5 are corresponding angles. m3 m3 = 180° - 81° = 99° 3 and 6 are same-side interior angles. A B C Are the triangles similar? Explain your answer. y = 180° - (67° + 35°) y = 78° x = 180° - (67° + 67°) x = 46° The triangles are not similar, because they do not have 2 or more pairs of corresponding congruent angles. EXAMPLE 2 © Houghton Mifflin Harcourt Publishing Company 421 Unit 5

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Page 1: Study Guide Review Guide Review UNIT 5 Key Vocabulary alternate exterior angles (ángulos alternos externos) alternate interior angles (ángulos alternos internos) corresponding angles

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Study Guide ReviewUNIT 5

Study Guide ReviewKey Vocabularyalternate exterior angles

(ángulos alternos externos)

alternate interior angles (ángulos alternos internos)

corresponding angles (ángulos correspondientes (para líneas))

exterior angle (ángulo externo)

interior angle (ángulos internos)

remote interior angle (ángulo interno remoto)

same-side interior angles (ángulos internos del mismo lado)

similar (semejantes)

transversal (transversal)

Angle Relationships in Parallel Lines and Triangles

How can you solve real-world problems that involve angle relationships in parallel lines and triangles?

Find each angle measure when m∠6 = 81°.

MODULE1111111111111111111111111111111111111111111111111111MODULE1111

? ESSENTIAL QUESTION

Find each angle measure when m

EXAMPLE 1

m∠5

m∠5 = 180° - 81° = 99°

5 and 6 are supplementary angles.

m∠1

m∠1 = 99°

1 and 5 are corresponding angles.

m∠3

m∠3 = 180° - 81° = 99°

3 and 6 are same-side interior angles.

A

B

C

Are the triangles similar? Explain your answer.

y = 180° - (67° + 35°)

y = 78°

x = 180° - (67° + 67°)

x = 46°

The triangles are not similar, because they do not have 2 or more pairs of corresponding congruent angles.

EXAMPLE 2

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A

E

G

F

C B

H

D

M

L

KJ

40°

125°

K DC

A BE H

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G F

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4 cm

3 cm 5 cm

10 cm

y cm

x cm

EXERCISES

1. If m∠GHA = 106°, find the measures of the given angles. (Lesson 11.1)

2. Find the missing angle measures. (Lesson 11.2)

3. Is the larger triangle similar to the smaller triangle? Explain your answer. (Lesson 11.3)

4. Find the value of x and y in the figure. (Lesson 11.3)

5. If m∠CJI = 132° and m∠EIH = 59°, find the measures of the given angles. (Lesson 11.1)

m∠EGC =

m∠EGD =

m∠BHF =

m∠HGD =

m∠IKJ =

m∠HIB =

m∠EIJ =

m∠AIK =

m∠JKL =

m∠LKM =

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Manuel’s house

Thomas’s houseSchool

9 mi

5 mi

10 ft

10 ft

s

r h = 10 cm

w = 10 cmℓ = 25 cm

7 in.18 in.

b

Thomas drew a diagram to represent the location of his house, the school, and his friend Manuel’s house. What is the distance from the school to Manuel’s house? Round your answer to the nearest tenth.

EXERCISESFind the missing side lengths. Round your answers to the nearest hundredth. (Lesson 12.1)

1.

2.

EXAMPLE 2

a2 + b2 = c2

52 + 92 = c2

25 + 81 = c2

c2 = 106

c = √_

106 ≈ 10.3

The distance from the school to Manuel’s house is about 10.3 miles.

The Pythagorean Theorem

How can you use the Pythagorean Theorem to solve real-world problems?

Find the missing side length. Round your answer to the nearest tenth.

MODULE1212? ESSENTIAL QUESTION

Find the missing side length.

EXAMPLE 1

a2 + b2 = c2

72 + b2 = 182

49 + b2 = 324

b2 = 275

b = √_

275 ≈ 16.6

The length of the leg is about 16.6 inches.

Key Vocabularyhypotenuse (hipotenusa)

legs (catetos)Pythagorean Theorem

(teorema de Pitágoras)

423Unit 5

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5 ft

7.5 ft

xO 4

4

2

-2

-4

-2-4

y

A B

C

Key Vocabularycone (cono)

cylinder (cilindro)

sphere (esfera)

Volume

How can you solve real-world problems that involve volume?

Find the volume of the cistern. Round your answer to the nearest hundredth. Use 3.14 for π.

V = πr 2h

≈ 3.14 ⋅ 2.52 ⋅ 7.5

≈ 3.14 ⋅ 6.25 ⋅ 7.5

≈ 147.19

The cistern has a volume of approximately 147.19 cubic feet.

Find the volume of a sphere with a radius of 3.7 cm. Write your answer in terms of π and to the nearest hundredth.

The volume of the sphere is approximately 67.54π cm3, or 212.07 cm3.

MODULE1313? ESSENTIAL QUESTION

Find the volume of the cistern. Round your answer to the nearest

EXAMPLE 1

EXAMPLE 2

V = 4 _ 3 πr 3

≈ 4 _ 3 ⋅ π ⋅ 3.73

≈ 4 _ 3 ⋅ π ⋅ 50.653

≈ 67.54π

V = 4 _ 3 πr 3

≈ 4 _ 3 ⋅ 3.14 ⋅ 3.73

≈ 4 _ 3 ⋅ 3.14 ⋅ 50.653

≈ 212.07

3. Hye Sun has a modern coffee table whose top is a triangle with the following side lengths: 8 feet, 3 feet, and 5 feet. Is Hye Sun’s coffee table top a right triangle? (Lesson 12.2)

4. Find the length of each side of triangle ABC. If necessary, round your answers to the nearest hundredth. (Lesson 12.3)

_

AB

_

BC

_

AC

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12 mm

4 mm34 in.

50 in.

EXERCISESFind the volume of each figure. Round your answers to the nearest hundredth. Use 3.14 for π. (Lessons 13.1, 13.2, 13.3)

1.

2.

3.

4.

5.

6.

7. Find the volume of a ball with a radius of 1.68 inches.

8. A round above-ground swimming pool has a diameter of 15 ft and a height of 4.5 ft. What is the volume of the swimming pool?

9. A paper cup in the shape of a cone has a height of 4.7 inches and a diameter of 3.6 inches. What is the volume of the paper cup?

10 cm

1.4 m

2.2 m

11.2 in.

0.8 in.

13.3 yd

10 yd

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Unit Project

ACTIVITY

Hydrologist A hydrologist needs to determine if an underground aquifer,

which is roughly cylindrical in shape, is totally filled with water. The diameter of

the aquifer is 70 meters, and its depth is 9 meters. The mass of the water in it is

2.7 × 10 7  kilograms. One cubic meter of water has a mass of about 1000 kilograms.

Is the aquifer totally filled with water? Explain how you determined your answer.

MATH IN CAREERS

The Wheel of TheodorusThe Wheel of Theodorus is named after Theodorus of Cyrene,

who lived at the time of Pythagoras of the Pythagorean theorem.

For this project you will draw and decorate a Wheel of Theodorus.

You’ll need a large piece of paper, a right angle, and a ruler.

Begin with a right triangle that has both legs 1 unit long.

Next, draw a second right triangle so that the hypotenuse

of the first triangle is one of the legs of the second triangle

and the other leg is 1 unit long, as shown in the diagram.

Draw a third right triangle beginning with the

hypotenuse of the second triangle as one leg of the third

triangle and a 1-unit leg as the other leg.

Continue drawing right triangles in this manner until you

have 16 triangles.

Decorate your Wheel of Theodorus.

Calculate the lengths of the hypotenuses of the

16 triangles.

Write a brief report on Theodorus of Cyrene.

Use the space below to write down any questions you

have or important information from your teacher.This Wheel of Theodorus shows the first four triangles.

8.G.7

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