Stationary states and nonlinear dynamics in PT-symmetric ......n+1 +u n−1 −2u n)+iγnu n, n ∈...
Transcript of Stationary states and nonlinear dynamics in PT-symmetric ......n+1 +u n−1 −2u n)+iγnu n, n ∈...
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Stationary states and nonlinear dynamics
in PT-symmetric dNLS lattices
Dmitry Pelinovsky
Department of Mathematics and Statistics, McMaster University, Ontario, Canada
Department of Applied Mathematics, Nizhny Novgorod State Technical University, Russia
Nonlinear Waves–Theory and ApplicationsBeijing, China, June 14, 2013
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 1 / 21
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PT-symmetric quantum mechanics
Consider the evolution problem
idu
dt= Hu, u(·, t) ∈ L2, t ∈ R,
where H is a linear operator with a domain in L2. If H is Hermitian, thenσ(H) ⊂ R and e−itH is a unitary group on L2.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 2 / 21
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PT-symmetric quantum mechanics
Consider the evolution problem
idu
dt= Hu, u(·, t) ∈ L2, t ∈ R,
where H is a linear operator with a domain in L2. If H is Hermitian, thenσ(H) ⊂ R and e−itH is a unitary group on L2.
Let us now assume that H is not Hermitian but PT -symmetric, where
P stands for parity transformation
T stands for time reversion and complex conjugation.
In other words, there is an operator P : L2 → L2 such that P2 = Id and
H = PHP, or THT = PHP, or PTH = HPT ,
where Tu(t) = u(−t) [C.M. Bender, 2007]
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 2 / 21
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Properties of PT-symmetric systems
If u(t) is a solution of the evolution equation, then
v(t) = PTu(t) = Pu(−t)
is also a solution of the same system
idv
dt= Hv ⇒ −iP
du
dt= HPu ⇒ −i
d u
dt= Hu ⇒ i
du
dt= Hu.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 3 / 21
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Properties of PT-symmetric systems
If u(t) is a solution of the evolution equation, then
v(t) = PTu(t) = Pu(−t)
is also a solution of the same system
idv
dt= Hv ⇒ −iP
du
dt= HPu ⇒ −i
d u
dt= Hu ⇒ i
du
dt= Hu.
If E is an eigenvalue and U is an eigenfunction, then E is also aneigenvalue with the eigenfunction PU, because
u(t) = Ue−iEt ⇒ v(t) = PUe−i E t .
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 3 / 21
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Properties of PT-symmetric systems
If u(t) is a solution of the evolution equation, then
v(t) = PTu(t) = Pu(−t)
is also a solution of the same system
idv
dt= Hv ⇒ −iP
du
dt= HPu ⇒ −i
d u
dt= Hu ⇒ i
du
dt= Hu.
If E is an eigenvalue and U is an eigenfunction, then E is also aneigenvalue with the eigenfunction PU, because
u(t) = Ue−iEt ⇒ v(t) = PUe−i E t .
Bender’s Conjecture: For many physically relevant PT -symmetric operatorsH, all eigenvalues are real and all eigenfunctions are PT -symmetric.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 3 / 21
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Examples of PT -symmetric operatorsConsider a Schrödinger operator
H := −∂2x + V (x), where V (−x) = V (x).
This operator is PT -symmetric w.r.t. space reflection: Pu(x) := u(−x).
a harmonic oscillator with a linear damping term
V (x) = x2 + iγx =
(
x +iγ
2
)2
+γ2
4
The spectrum of H is purely discrete and real
σ(H) =
{
γ2
4+ 1 + 2m, m ∈ N0
}
.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 4 / 21
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Examples of PT -symmetric operatorsConsider a Schrödinger operator
H := −∂2x + V (x), where V (−x) = V (x).
This operator is PT -symmetric w.r.t. space reflection: Pu(x) := u(−x).
a harmonic oscillator with a linear damping term
V (x) = x2 + iγx =
(
x +iγ
2
)2
+γ2
4
The spectrum of H is purely discrete and real
σ(H) =
{
γ2
4+ 1 + 2m, m ∈ N0
}
.
an unharmonic oscillator
V (x) = x2(−ix)γ .
The spectrum of H is purely discrete and real for γ > 0(Bender C. M.; Boettcher S.; PRL 80 (1998) 5243).
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 4 / 21
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Goals of our studies
We consider the PT-symmetric discrete nonlinear Schrödinger equation
idun
dt= un+1 − 2un + un−1 + Vnun + |un|
2un, n ∈ S ⊂ Z,
where V−n = Vn.
If S = Z and Vn is spatially extended, we show that the spectrum ofthe linear Schrödinger operators is not real (P., Kevrekidis,Franzeskakis, EPL 101 (2013), 11002).
If S = Z and Vn is compactly supported, we prove existence oflocalized states (Kevrekidis, P., Tyugin, SIAD (2013), accepted).
If S = {1, 2, ..., 2N} and Vn = iγ(−1)n, we study nonlinear dynamicsof PT-symmetric oscillators (Kevrekidis, P., Tyugin, JPA (2013),submitted).
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 5 / 21
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Spectrum of the linear DNLS equationConsider the spatially extended PT -symmetric potential,
Eun = − (un+1 + un−1 − 2un) +(
n2 + iγn)
un, n ∈ Z.
The spectrum is purely discrete for any γ ∈ R because
Re(Vn) = n2 → ∞ as n → ∞.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 6 / 21
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Spectrum of the linear DNLS equationConsider the spatially extended PT -symmetric potential,
Eun = − (un+1 + un−1 − 2un) +(
n2 + iγn)
un, n ∈ Z.
The spectrum is purely discrete for any γ ∈ R because
Re(Vn) = n2 → ∞ as n → ∞.
Using the discrete Fourier transform:
un =1
2π
∫ π
−πu(k)e−ikndk,
we convert the spectral problem to the differential equation
d2u
dk2+ γ
du
dk+ [E − 2 + 2 cos(k)] u(k) = 0,
subject to the 2π-periodicity of u(k).Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 6 / 21
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Complex spectrumIf v(k) = u(k)eγk/2, then v(k) satisfies the Mathieu equation:
d2v
dk2+
[
E − 2 −γ2
4+ 2 cos(k)
]
v = 0,
subject to the condition v(k + 2π) = eπγ v(k). We are looking for theFloquet multiplier µ∗ = eπγ of the monodromy matrix associated with theMathieu equation.
0 5 10 15 20−30
−20
−10
0
10
20
30
E
∆(E)
0 5 10 15 20−30
−20
−10
0
10
20
30
E
∆(E)
γ = 1
γ = 0.5
γ = 0.05
0 100 200 300 400
−20
−10
0
10
20
Im(E
)
Re(E)0 5
−202
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 7 / 21
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Spectrum of another linear DNLS equation
Consider the spatially extended potential without real part,
Eun = − (un+1 + un−1 − 2un) + iγnun, n ∈ Z.
If γ = 0, the spectrum is purely continuous.
If γ is large enough, the spectrum is purely discrete.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 8 / 21
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Spectrum of another linear DNLS equation
Consider the spatially extended potential without real part,
Eun = − (un+1 + un−1 − 2un) + iγnun, n ∈ Z.
If γ = 0, the spectrum is purely continuous.
If γ is large enough, the spectrum is purely discrete.
The equivalent differential equation
γdu
dk+ [E − 2 + 2 cos(k)] u = 0,
has the exact solution
u(k) = u(0)eγ−1[(2−E)k−2 sin(k)]. (1)
The 2π-periodicity of the discrete Fourier transform u(k) gives now theeigenvalues E = 2 + iγm, where m is an arbitrary integer.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 8 / 21
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Numerically obtained spectrum
1.5 2 2.5−10
−5
0
5
10
Im(E
)
Re(E)
100 200 300 4000.99
1
1.01
D(I
m(E
))
Eigenvalue Index
1.5 2 2.5
−60
−40
−20
0
20
40
60
Im(E
)
Re(E)
Figure : Eigenvalues for γ = 1 (left) and γ = 0.1 (right).
Conjecture:There exists γ0 ∈ (0,∞) such that the spectrum is purely discrete forγ > γ0. It is a union of the set of simple eigenvalues embedded into avertical strip of the continuous spectrum for γ ∈ (0, γ0).
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 9 / 21
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Stationary states for PT-symmetric dNLS
Consider the stationary PT -symmetric DNLS equation
Ewn = wn+1 + wn−1 + iγ(−1)nwn + |wn|2wn, n ∈ SN := {1, 2, ..., 2N},
subject to the Dirichlet end-point conditions w0 = w2N+1 = 0.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 10 / 21
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Stationary states for PT-symmetric dNLS
Consider the stationary PT -symmetric DNLS equation
Ewn = wn+1 + wn−1 + iγ(−1)nwn + |wn|2wn, n ∈ SN := {1, 2, ..., 2N},
subject to the Dirichlet end-point conditions w0 = w2N+1 = 0.
Eigenvalues of the spectral problem are found explicitly:
γ2 + E 2 = 4 cos2(
πj
1 + 2N
)
, 1 ≤ j ≤ N.
In particular, all eigenvalues are simple and real for γ ∈ (−γN , γN), where
γN := 2 cos
(
πN
1 + 2N
)
.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 10 / 21
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Local bifurcation from a simple real eigenvalue E0
Theorem
There exists a unique (up to a gauge transformation) PT-symmetricsolution w = Pw of the stationary PT-dNLS equation for real E > E0.Moreover, the solution branch is parameterized by a small real parameter asuch that the map R ∋ a → (E ,w) ∈ R× C
2N is C∞ and for sufficientlysmall real a, there is a positive constant C such that
‖w‖2 + |E − E0| ≤ Ca2.
The proof is achieved by Lyapunov–Schmidt reductions
E = E0 +∆, w = aw0 + u, 〈Pw0,u〉 = 0,
and the symmetry constraints that yield real ∆ and PT -symmetric u.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 11 / 21
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Bifurcation from infinity for large E
Theorem
For any γ ∈ (−1, 1), the stationary PT-dNLS equation in the limit of largereal E admits 2N PT-symmetric solutions w = Pw (unique up to a gaugetransformation) such that, for sufficiently large real E , the map E → w isC∞ at each solution and there is an E-independent constant C such that
∣
∣
∣
∣
∣
∣
∑
n∈SN
|wn|2 − 2NE
∣
∣
∣
∣
∣
∣
≤ C .
The difficulty in the proof arises due to the fact that, although thealgebraic equations decouple as E → ∞ with the N independent solutions
Wk = e−iϕkek + e iϕke2N+1−k , 1 ≤ k ≤ N,
where ϕk ∈ R is arbitrary, the nonlinear system does not enjoy thesuperposition principle.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 12 / 21
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Bifurcation from infinity for large E
Setting E = 1δ and w = W√
δ, we write the stationary DNLS equation:
(1 − |Wn|2)Wn = δ [Wn+1 + Wn−1 + iγ(−1)nWn] , n ∈ SN ,
subject to the boundary condition W0 = 0 and W2N = 0.
For N = 1, we have
(1 − |W1|2)W1 = δ
[
W1 − iγW1
]
.
Setting W1 = A1/21 e iϕ1 , we obtain
A1 = 1 − δ cos(2ϕ1), − sin(2ϕ1)− γ = 0,
which yields two branches by the two solutions of sin(2ϕ1) = −γ.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 13 / 21
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Numerical illustration: N = 2
−2 −1 0 1 2 3 4 5 60
1
2
3
4
5
6
E
|w1|2
−2 −1 0 1 2 3 4 5 60
1
2
3
4
5
6
E
|w1|2
−2 −1 0 1 2 3 4 50
1
2
3
4
5
E
|w1|2
−2 −1 0 1 2 3 4 5 60
1
2
3
4
5
6
E
|w2|2
−2 −1 0 1 2 3 4 5 60
1
2
3
4
5
6
E
|w2|2
−2 −1 0 1 2 3 4 50
1
2
3
4
5
6
E
|w2|2
Figure : Nonlinear stationary states for γ = 0.5 (left), γ = 0.75 (middle), andγ = 1.1 (right). The top and bottom rows show components |w1|
2 and |w2|2.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 14 / 21
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Numerical illustration: N = 3
−2 −1 0 1 2 3 40
1
2
3
4
E
|w1|2
−2 −1 0 1 2 3 40
1
2
3
4
5
6
E
|w2|2
−2 −1 0 1 2 3 40
1
2
3
4
5
6
E
|w3|2
−2 −1 0 1 2 3 4 5 6 7 80
1
2
3
4
5
E
|w1|2
−2 −1 0 1 2 3 4 5 6 7 80
1
2
3
4
5
6
7
E
|w2|2
−2 −1 0 1 2 3 4 5 6 7 80
1
2
3
4
5
6
7
8
9
E
|w3|2
Figure : Nonlinear stationary states for γ = 0.25 (top) and γ = 1.1 (bottom).The left, middle, and right columns show components |w1|
2, |w2|2, and |w3|
2.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 15 / 21
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Discrete solitons for PT-symmetric dNLS
Consider the stationary PT -symmetric DNLS equation
Ewn = wn+1 + wn−1 + iγ(−1)nχn∈SNwn + |wn|
2wn, n ∈ Z,
where χn∈SNis a characteristic function for the set SN := {1, 2, ..., 2N}
(PT -symmetric defects).
Theorem
For any γ ∈ (−1, 1), the nonlinear stationary PT-dNLS equation admits 2N
PT-symmetric solutions W = PW ∈ l2(Z) (unique up to a gaugetransformation) such that, for sufficiently small positive δ, the map δ → W
is C∞ at each solution and there is a positive δ-independent constant C:
|W − W0| ≤ Cδ,
where W0 is the PT-symmetric state on the set SN .
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 16 / 21
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Numerical illustrations of discrete solitons for N = 1
0 0.2 0.4 0.6 0.8 10
0.5
1
1.5
2
2.5
3
γ
2 θ
0 0.2 0.4 0.6 0.8 1−6
−4
−2
0
2
4
γ
λ2/δ
Figure : The left panel shows the relative phase 2θ between the two central sitesobtained by the numerical computation and the solvability condition sin(2θ) = γ
(a green dash-dotted line). The right panel shows the squared eigenvalue of thelinearized PT-dNLS equation at the discrete soliton versus γ for each branch.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 17 / 21
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Numerical instabilities of in-phase discrete solitons
0 50 100 150 200 2500.8
0.9
1
1.1
1.2
|u0(t
)|2 ,
|u
1(t
)|2
t 0 50 100 150 200 250
2
4
6
8
10
12
|u0(t
)|2 ,
|u
1(t
))|2
t
0 100 200
100
Figure : The evolution of the unstable in-phase solution for γ = 0 (left) andγ = 0.5 (right).
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 18 / 21
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Nonlinear dynamics of a dimerConsider a PT-symmetric dimer (N = 1) with two complex amplitude:
{
i da
dt= b − iγa + |a|2a,
i db
dt= a + iγb + |b|2b.
For γ ∈ (0, 1), the zero equilibrium is stable.
0 1 2 3 4 5 610
−4
10−2
100
102
104
|a|2
, |b
|2, |a
b|
t 0 5 10 15 20 25 300.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
|a|2
, |b
|2, |a
b|
t
Figure : Left: unbounded growth of the amplitude |b(t)| for the gained oscillator.Right: bounded oscillations of the amplitudes.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 19 / 21
![Page 27: Stationary states and nonlinear dynamics in PT-symmetric ......n+1 +u n−1 −2u n)+iγnu n, n ∈ Z. If γ = 0, the spectrum is purely continuous. If γ is large enough, the spectrum](https://reader034.fdocuments.us/reader034/viewer/2022050409/5f85c0a97ba8f07e7860c417/html5/thumbnails/27.jpg)
Main claims of new work
For the nonlinear dynamics of a finite PT-dNLS chain, we prove thefollowing results:
Solutions of the PT-dNLS equation do not blow up in a finite time.
For values of the gain and loss coefficient γ when the zero equilibriumstate is neutrally stable, the solutions of the finite PT-dNLS equationstarting with small initial data remain bounded for all times.
For the same values of γ, there exist time evolutions of the finitePT-dNLS equation starting with sufficiently large initial data whichgrow exponentially fast for larger times.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 20 / 21
![Page 28: Stationary states and nonlinear dynamics in PT-symmetric ......n+1 +u n−1 −2u n)+iγnu n, n ∈ Z. If γ = 0, the spectrum is purely continuous. If γ is large enough, the spectrum](https://reader034.fdocuments.us/reader034/viewer/2022050409/5f85c0a97ba8f07e7860c417/html5/thumbnails/28.jpg)
Discussions: next goals
General theorems that linear PT-dNLS equation with spatiallyextended potentials has unstable spectrum for any γ 6= 0.
Nonlinear stability of spectrally stable stationary states, e.g. thespectrally stable fundamental discrete soliton for N = 1.
Sharp conditions on the initial data to distinguish bounded oscillationsand exponentially growing trajectories.
Extensions to multi-dimensional and continuous settings of thePT-dNLS equation.
Dmitry Pelinovsky (McMaster University)Nonlinear states in PT-symmetric lattices Nonlinear Waves 21 / 21