Marwan Shehata | LTSpice;Electronics | December 24, 2015

Electronics Project

Name: Marwan Shehata Mohamed Zeitoun

No: #157

Sec: #7

PAGE 1

Question #1 & #2

The circuit we’re going to use in this project

Question #3

The characteristics of the 1N5371B diode:

IZK=1 mA

IZM=79 mA

IZT=20 mA

Source: http://www.onsemi.com/pub_link/Collateral/1N5333B-D.PDF

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Question #4 A)

Changing RL to make IZ≈IZM ≈79 mA

1st Trial

Putting R1= 3kΩ

PAGE 3

2nd Trial

Putting R1= 2kΩ

PAGE 4

3rd Trial

Putting R1= 1.9625kΩ

I’ve got a current flows throw the diode that approximately close to IZM ≈79 mA

PAGE 5

Question #4 B)

Put R1 < R1min , I assumed (R1 = 1000 Ω)<(R1min=1.9625 kΩ)

ID >IZM , and damage occurs to the diode

PAGE 6

Question #5 A)

Adjust R1=R1min=1.9625 kΩ & change RL until IZ≈ IZK≈ 1 mA

∴ RLmin ≈ 721.9 Ω

PAGE 7

Question #5 B)

1st: The voltage probe is at the terminal of the load resistance @RL =RLmin

PAGE 8

2nd: The voltage probe is at the terminal of the load resistance 1000 Ω @RL >RLmin

Observation: Voltage increases on the load resistance

PAGE 9

Question #5 C)

Consider RL<RLmin , where RLmin ≈721.9 Ω

RL=500Ω & we will compare the voltage flow in RL with RL=RLmin and RL=500Ω

Observation: Voltage decreases on the load resistance

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Question #6

The diodes in the circuit are assembled to make a rectifier circuit

and the capacitor works to smoothen the current and make it close to a DC

The circuit without the capacitor

Wave form without the capacitor

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The effect of reducing and increasing of capacitor:

The capacitor is 10mF which is greater than the original one

The resulting current from increasing the capacitor

PAGE 12

The capacitor is 0.05mF which is less than the original one

The resulting current from increasing the capacitor

PAGE 13

Observation: The higher the capacitance the lesser the ripple, and vice versa …in other words; the voltage ripple is

inversely proportional to the capacitance.

Best Regards

Marwan Shehata