Project 2 Final Submission
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Transcript of Project 2 Final Submission
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8/8/2019 Project 2 Final Submission
1/11
Project II
ME370: Mechanical Design
Spring 2010
Zachary Katz
Greg Ledva
Michael Kniney
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8/8/2019 Project 2 Final Submission
2/11
Bearing Reaction Force Calculation
R=Hydrodynamic Rxn ForceR=Angular Contact Rxn FoceFy=0 20+100 = R + R
M=0 20(2.925)+100(8.475)=R(6)
R(y)=151 lbs
R(y)=-31 lbs
Fz=0 10 = R + R
M=0 10(2.925)=R(6)
R(z)=4.9 lbs
R(z)=5.1 lbs
Total Hydrodynamic Reaction Force is 31.4 lbs in the radial direction
Total Angular Contact Reaction Force is 151.1 lbs in the radial direction (split between 2 bearings)
Additional 5 lbs load in the axial direction on angular contact
Hydrodynamic Bearing Calculations
X value can be found using the given stiffness of 100,000 psi and the force in that direction, 20 lbs.
100lbs
20lb
s
5lbs10lbs
R
2R1
2.925" 6" 2.475"y
xz
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8/8/2019 Project 2 Final Submission
3/11
U= Dn= (1.8)(2500rpm)160 =235.6 in/sec
Note: we set D=1.8 from inner diameter of pump sleeve
= 7.2reyns for VG32 @ 80F
Note: 1 reyns = 1x10 (lb in/sec)
P=31.4 lbs (found previously)
Now, use eq(1) to find L= ( 34 2 )L=1.678 in
Hydrodynamic Power Loss Calculation:Ts=
2(21)
12.5 = 4.83 in lb
Note: because our journal sleeve is stationary, U1=0, and U2=U (from previous)
Tr=Ts+Pe(sin ), where P=31.4 lbs, e=.0001345, and = arcsin12)
4
Tr=4.82+(31.4)(.0001345)sin(1.51) = 4.824 in lb
Power loss = = Tr* = (4.825)(261.8 )=1263 in lb/sec = 0.19 hp
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8/8/2019 Project 2 Final Submission
4/11
P=81 lbs
L= 3
3
C=(13140)(81) = 1911 lbs = 8500 N
As a result, every bearing in the BNRS19 series satisfies our loading conditions.
So, we chose a bearing that fits well with our shaft and sleeve of a 45mm ID:
45BNRS19
From the Catalogue, the dimensions of the bearing are:
ID=45mm
OD=68mm
B=12mm
Rmin(fillet)=0.6mm
R1min(fillet)=0.3mm
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8/8/2019 Project 2 Final Submission
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