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SPM PHYSICS PAPER 2 – MODUL TEST 1

SECTION A Answer all the questions in this section QUESTION 1

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QUESTION 2

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QUESTION 3 Diagram 4 shows the arrangement of apparatus of a gas law. The volume of trapped air in the flask is constant. Rajah 4 menunjukkan susunan radas bagi suatu hokum gas. Isipadu udara yang terperangkap dalam kelalang adalah tetap.

(a) State the physical quantity measured by Bourdon gauge? Nyatakan kuantiti fozik yang diukur oieh Toiok Bourdon? __________________________________________________________________________

[1 mark] [1 markah]

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(b) Give one reason why the rubber tube used is as short as possible. Beri satu sebab mengapa tiub getah yang digunakan adalah sependek mungkin. __________________________________________________________________________

[1 mark] [1 markah]

(c) Name the gas law involved. Namakan hukum gas yang terlibat. __________________________________________________________________________

[1 mark] [ 1 markah]

(d) What happen to the reading of Bourdon gauge when the temperature of trapped air is increased?

Apakah berlaku kepada bacaan Totok Bourdon bila suhu udara yarig terperangkap itu bertambah?

__________________________________________________________________________

[1 mark] [1 markah]

(e) The reading of Bourdon gauge is 20kPa when the temperature of trapped air is 30°C. Bacaan tolok Bourdon itu adalah 20 kPa suhu bila suhu udara terperangkap adalah

30°C. (i) State the temperature of 30°C in Kelvin. Nyatakan suhu 30°C dalam Kelvin.

[1mark]

[1 markah] (ii) Calculate the temperature of trapped air when the reading of Bourdon gauge is 25 kPa. Hitung suhu udara terperangkap itu bila bacaan tolok Bourdon adalah 25kPa.

[1 marks] [1 markah]

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QUESTION 4

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QUESTION 5

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QUESTION 6

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QUESTION 7

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QUESTION 8

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SECTION B Answer any one question from this section. QUESTION 9

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QUESTION 10

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SECTION C Answer any one question from this section. QUESTION 11

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QUESTION 12

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SUGGESTED ANSWERS

SECTION A QUESTION 1

QUESTION 2

QUESTION 3

(a) Pressure

(b)

Reduce the volume of trapped air in the tube // to fix the volume of air in the flask.

(c) Pressure Law (d) Increased

(e)(i) (30 + 273) K // 303K (ii) 20 = 25

303 T2 T2 = 378.75 K // 105.75 °C

QUESTION 4

QUESTION 5

QUESTION 6

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QUESTION 7

QUESTION 8

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SECTION B QUESTION 9

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QUESTION 10

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SECTION C QUESTION 11

QUESTION 12

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