Pipe Fitter Trainee

8/9/2019 Pipe Fitter Trainee

1/57

PIPE FITTER TRAININGMODULE

TOPICS

1.1 LINEAR MEASUREMENTS

.

1.2 CONVERSION OF UNITS

1.3 BASIC GEOMETRY.

1.5 SOLVING FOR SIMPLE OFFSET 45 °

.1.7 SOLVING FOR 90° ELBOW L.R.

1.8 SOLVING FOR 45° ELBOW

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ENGLISH SYSTEM

116

316

516

716

916

1116

1316

1516

1 2

18

28

38

58

68

78

1 2 3 4 5 28 3029 31

1211

mm

inch

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METER TAPE READING

METRIC SYSTEMWHAT IS THE MEASUREMENT ?

EXAMPLE 1

ANSWER : 18 mm

mm

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METER TAPE READING

METRIC SYSTEM

EXAMPLE 2

ANSWER : 30 mm

mm

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METER TAPE READING

ENGLISH SYSTEM

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METER TAPE READING

ENGLISH SYSTEM WHAT IS THE MEASUREMENT ?

EXAMPLE 1 ANSWER : 6 1/8 in.

116

316

516

716

916

1116

1316

1516

1 2

18

28

38

58

68

78

3 4 5 6 7 8inch

EEI CORPORATION

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METER TAPE READING

ENGLISH SYSTEM WHAT IS THE MEASUREMENT ?

EXAMPLE 2 ANSWER : 5 1/2 in.

116

316

516

716

916

1116

1316

1516

1 2

18

28

38

58

68

78

3 4 5 6 7 8inch

EEI CORPORATION

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CONVERSION FACTOR

1 Meter = 3.28 Feet1 Meter = 39.37 Inches

1 Meter = 100 Centimeters

1 Meter = 1000 Millimeters

1 Foot = 12 Inches

1 Inch = 2.54 Centimeters

1 Centimeter = 10 Millimeters

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ENGLISH – ENGLISH – ENGLISH –

FRACTION (INCH) DECIMAL (INCH) (MILLIMETER)

1. 1/16 0.0625 1.6

. . .

3. ¼ 0.25 6.4

4. 3/8 0.375 9.8

5. ½ 0.50 12.7

6. 5/8 0.625 16.0

. . .

8. 7/8 0.875 22.2

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. . .

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CONVERSION FACTOR

=1 kilograms 1000 grams = 2.2 pounds

= =

LI UID

1 gallon = 3.785 liters

1 Kilo ascals kPa = 6.894 ounds-force er inch si

PRESSURE



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1. How many feet are there in 5 meters?

5 meters = _______ feet

feet feet

x m 4.1628.3

5 m

.

15 feet = _______ meters

m feet

m x feet 57.428.3

115

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3. How many inches are there in 75 centimeters?

cen me ers = _______ nc es

in1

cm54.2

.

100 inches = _______ inches

cmin

cm xin 2541

54.2100

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5. How many inches are there in 8 Meters?

e ers = _______ nc es

in37.39

m.

1

.

50 Inches = _______ meter



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7. How many centimeters are there in 50 meters?

me ers = _______ cen me ers

cm100

m,

1

8. How many meters are there in 250 centimeters?

250 centimeters = _______ meters

m cm

m x cm 50.2

100

1250



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9. How many millimeters are there in 10 meters?

me ers = _______ m me ers

mm1000

m,

1

.

100 millimeters = _______ meters

m mm m x mm 10.0

10001100



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13.How many millimeters are there in 3 centimeters?

cen me ers = _______ m me ers

mm10

cm1

14.How many centimeters are there in 50 millimeters?

50 millimeters = _______ centimeters

cm mm

cm x mm 5

10

150

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1.3 BASIC GEOMETRY

° 0°

N

90°270° 90°270°W E

180°

180°

S

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1.4 BASIC TRIGONOMETRIC/ SOLID MENSURATION

BASIC TRIGONOMETRIC FUNCTION

c² = a² + b²22

bac +=

b c a² = c² - b²

b² = c² - a² 22 acb −=

22

ca −=

a

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90°60°

45° 45° 30°90°

badjacent

c

a

hypotenuse

opposite

==

==

θ

θ

cos

sin

opposite

θ

b

a

adjacent

opposite==θ tan

a

adjacent

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c² = a² + b²22

bac +=

b c a² = c² - b²

b² = c² - a² 22 acb −=

22

ca −=

a

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BASIC TRIGOMETRIC FUNCTION

b = 4 c = ? b = 4

c = 5 b = ? c = 5

a =3 a =? a =3

² = ² ² a² = c² - b²

a² = 5² - 4² b² = 5² - 3²

c² = 3² + 4²

54322=+=c 345

22=−=a

= -

43522=−=b

EEI CORPORATION

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b

a

Square Circle

bc

Triangle

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Square Circle

b1 b2

Triangle Trapezoid

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1.5 SOLVING FOR SIMPLE OFFSET 45 °

c(a)

FORMULA :

(b)

FOR 45 DEG.ELBOW:

SET = RUN



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1.6 SOLVING FOR ROLLING OFFSET

:

INTRODUCTION:

OFFSET WHICH IS ROLLED OVER TO FORM A DISTANCE CALLED

“R OLL”. TH IS IDEA IS VERY USEFUL IN DETER MINING THE

NUMBER OF DEGREES OF THE BEND OR ELBOW TO BE USED.

SET



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FORMULA :

A

O L L

A = ROLL 2 + SET 2

TRAVEL

SET TRAVEL = A x 1.414

RUN = A x 1 A N G L

RUN =

NOTE :

45 ° fitting

1 = cotangent of angle of 45 °

EEI CORPORATION

fitting

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EXAMPLE :

The roll of a 45 ° offset is 8 in. and the set is 15 in. Findthe len th of the travel and run.

FORMULA :

A = ROLL 2 + SET 2 A = 8 2 + 15 2 = 17 in.

TRAVEL = A x 1.414

=

TRAVEL = 17 x 1.414 = 24 1 / 32 in.

= =

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.

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WHEN THE RE UIRED BEND FOR SIMPLE OR ROLLING OFFSET IS

1.7 SOLVING FOR TAKE-OFF ELBOW L.R.

NOT AVAILABLE, IT CAN BE FABRICATED FROM A 90 o LONGRADIUS WELD ELBOWS. TO FABRICATE CUT-ELBOW (FROM 90 o LR

ELBOW). THE FOLLOWING PROCEDURE CAN BE USEFUL.

I. KNOW THE ACTUAL O.D. OF THE PIPE OR FITTING USED.

REMEMBER THAT NOMINAL PIPE SIZES 12" Ø AND BELOWHAVE THEIR DESIGNATED O.D. ’s .

II . DETERMINE THE TAKE OFF RADIUS (TOR) OF THE 90 LR ELBOWUSED AND CALCULATE THE INSIDE AND OUTSIDE RADII.

WHERE: OD = OUTSIDE DIAMETER

IR = INSIDE RADIUS = TOR – (½ OD)OR = OUTSIDE RADIUS = TOR + ½ OD

OD

TOR = TAKE OFF RADIUS = 1.5 x D (NPS)

TOR

OREEI CORPORATION

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FORMULA FOR TAKE-OFF ELBOW – L.R.

1.7 SOLVING FOR 90° ELBOW L.R.

1. 90° ELBOW – LONG

RADIUS” . – . . : =

8” ENGLISHX 1.5 mmENGLISH

B. METRIC SYSTEM USE - 38.112.00

B. EXAMPLE : SIZE OF PIPE=8”

8” METRIC

.

304.8 mm.

•CHECKING:

12” =

12” = 12”

304.8

25.4

12” x = 304.8mm25.4 mm1”

EEI CORPORATION

. .

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1.8 SOLVING FOR 45° ELBOW

45° ELBOW

A. ENGLISH SYTEM : USE 0.625” ( INCH) = USE ALL SIZE OF PIPE) K E

- O F F

B. METRIC SYSTEM : USE 15.875 (mm) USE ALL SIZE OF PIPE

EXAMPLE :

ENGLISH SYSTEM METRIC SYSTEM

8 “ SIZE OF PIPE

X 0.625

5”

8 “ SIZE OF PIPE

X 15.875

TAKE-OFF

127 mmEXAMPLE

0.625 ENGLISH SYSTEM

x 25.4

FORMULA :

15.875 METRIC SYSTEM

.

DIAMETER X15.875 (METRIC)

EEI CORPORATION

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PIPE FITTER TRAINING MODULE

TOPICS

2.1 ORTHOGRAPHIC DRAWINGS

2. BLUE PRINT READING

, ,

2.2 ISOMETRIC DRAWINGS & DETAILS

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(PLANS, ELEVATION, & SECTION)

Line Types

on nuous ne

Center Line

Dimension Line

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Linetypes

• Visible

• Hidden

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Three Primary Views

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Glass Box concept

• Envision the object

surrounded in a glass

box

onto the pieces of glass

• Each pane shows a 2D

projection of the object

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Projection Planes

The three panes of glass represent the principal

orthographic planesHorizontal

Frontal

Profile

Each plane illustrates two of the principal dimensions:

Height, Width, and Depth

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2 2 ISOMETRIC DRAWINGS & DETAILS


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PLAN

ISOMETRIC VIEW

ELEVATION RIGHT SIDE

VIEW

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90° Elbow use take off 1.5 = English90° Elbow use take off 38.1 = Metric L.R.

45° Elbow use take off 0.625 = English System

45° Elbow use take off 15.875 = Metric System8 IN DIA.

8 x 3/4

Ex. 8"Ø

90° Elbow

long radius

Ex.To get

90° Take Off &

45° Elbow

End of ElbowNote: All(size) B. weld

type fittings.

EEI CORPORATION

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° -

ISOMETRICBOX

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PIPE FITTER TRAINING MODULE

TOPICS

3. STANDARD TRADE SYMBOLS

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3 STANDARD TRADE SYMBOLS


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SYMBOLS OF PIPE ORTHOGRAPHIC & MEANING


90 ° ELBOW UP

TEE DOWN

90 ° ELBOW DOWN

°

TEE UP

45 ° ELBOW DOWN

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EXAMPLE FOR INDICATION OF PIPE FITTINGS BUTT WELD TYPE


PLAN SIDE VIEW ISOMETRICPIPE

SIZEITEM

.

NPS

and

Smaller 90°

Elbow

16 in.

NPS

and

Larger

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SIZEITEM

45°N

45°

Elbow

.

NPS

and

Smaller 45°45°

16 in.

NPS

45°

Line

Thickness0.3mm

and

Larger

45°

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SIZEITEM

* For reducing tees,

sizes shall beindicated.

.

NPS

and

Smaller Tee

” ”* ” ”

16 in.

NPS* ” ”

x

* ” ”and

Larger

*18” x 14”

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SIZEITEM

*6” x 4”*6” x 4”

.

NPS

and

Smaller

Con-

centric

and *4” x 3”*4” x 3”*6” x 4”

*6” x 4”

16 in.

NPS

Eccen-

tric

Redu-

*20” x 18”

*20” x 18”

and

Larger * Indicate double

line for eccentric*18” x 14”

*20” x 18”

*20” x 18” *18” x 14”

EEI CORPORATION

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SIZEITEM

.

NPS

and

Smaller

N

16 in.

NPS

and

Larger

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SIZEITEM

.

NPS

and

Smaller

12” x 4”

16 in.

NPS

-

and

Larger 28” x 16”

EEI CORPORATION

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EXAMPLE FOR INDICATION OF PIPE FITTINGS

(THREADED TYPE )

90°

Elbow




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(THREADED TYPE )

45°

N

45°

Elbow45°

45°




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(THREADED TYPE )


sizes shall be

indicated.

NTee

* 1” x 3/4” * 1” x 3/4”




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(THREADED TYPE )


sizes shall be

indicated.

NCoupling

* 1” x 3/4”




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(THREADED TYPE )

N

Union




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(THREADED TYPE )

N

Cap




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PIPE JOINT SYMBOL

- WELDED JOINT

- SOLDERED

- BELL & SPIGOT

- SCREWED

- FLANGE

- SOCKET WELD

- BUTT WELD

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VALVES

- BALL VALVE - CONTROL VALVE

- GLOBE VALVE

- CHECK VALVE

- DIAPHRAGM VALVE

- PLUG VALVE

- GATE VALVE

- NEEDLE VALVE

- BUTTERFLY VALVE

-

- SAFETY RELIEF VALVE

- ANGLE VALVE

EEI CORPORATION

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