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Pioneer Education NTSE Mock Test

Time: 45 Minutes Max. Marks: 50

Education is not the learning of facts, But the Training of the mind to think.

Name: ________________________________ Roll No.: ________________Mobile No.: ________________________

MENTAL ABILITY TEST (Q. 1 – 50)

Instructions to the Candidates

1. There are total 200 questions in the 3– test Booklet.

2. The division of the question is as follows:

(a) MAT (Q.1 to 50)

(b) Language Test (Q.51 TO 100)

(c) SAT (Q101 to 200) :

(i) Science (101 to 140) (ii) S.S.T (141 to 180) (iii) Maths (181 to 200)

3. Answers are to be given on the OMR Sheet only.

4. Darken the CIRCLE with pen for answering the question.

5. Rough work can be done anywhere in the Test booklet but not on the Answer sheet.

6. Every correct answer will be awarded one mark. There is no negative marking.

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Direction (Q. No. 1): Insert the missing from among the given alternatives.

1.

(a) 262 (b) 622 (c) 631 (d) 824

Ans. (b)

Solution:

In figure (A), (915 – 364) = 551

In figure (B), (789 – 543) = 246

In figure (C), missing number

= (863 – 241) = 622

2. (i) P + Q means ‘P is the father of Q’.

(ii) P Q means ‘P is the brother of Q’.

(iii) P – Q means ‘P is the wife of Q’.

(iv) P Q means ‘P is the mother of Q’.

If P – R + Q, which of the following statements is true?

(a) P is the mother of Q (b) P is the aunt of Q (c) P is the sister of Q (d) P is the brother of Q

Ans. (a)

Solution :

P – R + Q = P – (R is the father of Q.)

= (P is the wife of R.)

So, P is the mother of Q.

Direction (Q. No. 3): In the following question, arrange the given words in a meaningful sequence and

choose the most appropriate sequence from the options given below.

3. (1) Colonel (2) Major (3) General (4) Captain (5) Lieutenant

(a) (5), (4), (2), (1), (3) (b) (3), (4), (5), (2), (1) (c) (1), (2), (5), (3), (4) (d) (5), (4), (2), (3), (1)

Ans. (a)

Solution :

Army designations ins ascending order

Lieutenant Captain Major Colonel General




Direction (Q. No. 4): Study the following letter-number sequence and answer the question given

below:

B 3 K G 5 P D 7 9 E R J I M T 6 Z H Q 3 W 2 A

4. If the first twelve letters/numbers in the above sequence are written in the reverse order, which of the

following letter/number will be seventh to the left to ninth letter/number fro m our right?

(a) K (b) P (c) 5 (d) None of these

Ans. (c)

Solution:

12th term from left is J. Therefore, we have to start the sequence, with J in the reverse order.

Thus, J R E 9 7 D P 5 G K 3 B I M T 6 Z H Q 3 W 2 A

Trick 9 + 7 = 16th left from right

Five twelve numbers/letters is from B to J and their reverse order is JRE97DP5GK3B. Then, finally

arrangement will be J R E 9 7 D P 5 G K 3 B I M T 6 Z H Q 3 W 2 A. Now, according to the question,

seventh to the left to the ninth right means 16th from right is 5.

5. Six friends A, B, C, D, E and F start climbing a hill together. After sometime, it is observed that ‘D’ has

reached the position higher than ‘B’ but not as high as ‘E’, ‘C’ is at a position not higher than ‘D’ and not

lower than ‘A’, who is not lower than ‘F’ and not higher than ‘B’. Who has climbed to the highest

position?

(a) D (b) E

(c) B (d) Cannot be determined

Ans. (b)

Solution:

E > D > B ..(i)

D > C > A > F ..(ii)

B > A

Combining all three, we get

E > D > B > C > A > F

E has climbed the highest position.

6. If 7 * 2 = 81, then what is the value of 8 * 5?

(a) 144 (b) 89 (c) 169 (d) 121




Ans. (c)

Solution:

Rule is a * b = (a + b)2

So, 8 * 5 = (8 + 5)2 = 169

7. My Brother’s date of birth is May 3, 1999 but I do not remember the day, can you tell me which day it

was?

(a) Monday (b) Tuesday (c) Wednesday (d) Thursday

Ans. (a)

Solution:

May 3, 1999 means 1998 complete years + first 4 months upto April of 1999 + 3 days of May.

1600 year have 0 day.

300 year have 1 day.

98 year have 24 leap years + 74 ordinary years.

= (24 2) + (74 1)

= 122 days = 17 weeks + 3 odd days

1998 year you have (0 + 1 + 3) = 4 odd days.

January has 31 days i.e., 3 odd days.

1999 is an ordinary year.

Hence, February has 28 days i.e., 0 odd day.

March has 31 days i.e., 3 odd days.

April has 30 days i.e., 2 odd days.

May 3 gives 3 more odd days.

Total number of odd days on May 3, 1999.

= (4 + 3 + 0 + 3 + 2 + 3) odd days.

= 15 odd days i.e., 1 odd day.

Hence, May 3, 1999 was Monday.

8. In the following multiplication problem, find the numerical values of T, F and H in that order

L T B D F

4 6

3 4 T G F T

2 3 D 4 H D

D 6 L F 6 L 8




(a) 2, 8 and 9 (b) 8, 3 and 9 (c) 6, 3 and 5 (d) 8, 4 and 7

Ans. (b)

Solution:

5 8 1 2 3

4 6

3 4 8 7 3 8

2 3 2 4 9 2

2 6 7 3 6 5 8

T = 8, F = 3 and H = 9

9. Statements

Some keys are chains.

All chains are locks.

All locks are numbers.

No number is a digit.

Conclusions

I. Some keys are numbers. II. All chains are numbers.

III. Some locks are keys. IV. No digit is a chain.

(a) I, II and III follow (b) II and III follow (c) II, III and IV follow (d) All follow

Ans. (d)

Solution :




or

Figure I Figure II Validity

Conclusion I

Conclusion II

Conclusion III

Conclusion IV

All follow.

10. A dog is taken out every evening by the owner whose house faces East. They walk 200 m West, then

500 m in South direction. Which direction should they take to reach home?

(a) North-East (b) North (c) North-West (d) South-East

Ans. (a)

11. As BLOCKED is to YOLXPVW, so also OZFMXS is to

(a) LABOUR (b) LAUNCH (c) NAUGHT (d) RESULT

Ans. (b)

All the latters of the first group are replaced by the corresponding letters from the other end of the

alphabet in the second group.

A B C D E F G H I J K L M

Z Y X W V U T S R Q P O N

12. Out of six towns, Dhulia is bigger than Amalner, Shrirampur is bigger than Nasik, Jalgaon is not as big as

Shrirampur but is bigger than Amalner. Amalner is smaller than Nasik bug bigger than Manmad. Which




is the smallest?

(a) Amalner (b) Nasik (c) Jalgaon (d) Manmad

Ans. (d)

Solution:

Dhulia > Amalner

Jalgaon < Shrirampur

Jalgaon > Nasik

Amalner < Nasik

Amalner > Manmad

13. If 84 72 = 45 and 63 41 = 33, then 94 82 is equal to

(a) 45 (b) 59 (c) 56 (d) 65

Ans. (c)

Solution:

The rule is difference of the digits of the number

84 72 = (8 – 4) (7 – 2) =45

63 41 = (6 – 3) (4 – 1) = 33

94 82 = (9 – 4) (8 – 2) = 56

14. The length of a rectangle is 10 cm more than its breadth. If its perimeter is 84 cm, then what is the

length of the rectangle?

(a) 20 cm (b) 24 cm (c) 28 cm (d) 26 cm

Ans. (d)

Solution:

Let the width of rectangle be x and its length be (x + 10).

Perimeter = 2(1 + b)

2(x + 10 + x) = 84

2x + 20 + 2x = 84

x = 16, x + 10 = 26

Length of the rectangle = 26 cm

15. Asha, Babita, Chinni, Deepa, Evita and Fatima are standing in a row. Babita is between, Fatima and

Deepa. Evita is between Asha and Chinni. Asha does not stand next to either Fatima or Deepa. Chinni

does not stand next to Deepa. Fatima is between which of the following pair of persons?

(a) Chinni and Babita (b) Babita and Deepa (c) Evita and Chinni (d) Asha and Evita

Ans. (a)




Solution:

The order in which all the six women stands is given below.

Asha, Evita, Chinni, Fatima, Babita, Deepa.

Hence, Fatima is between Babita and Chinni.

16. At what angle the hands of a clock are inclined at 15 min past 5?

(a) o1

582

(b) 064 (c) o1

672

(d) o1

722

Ans. (c)

Solution:

Angle traced by hour hand in o

21 360 21h

4 12 4

o1157

2

o0360

Angle traced by min hand in 15 min 15 9060

o o01 1

Required angle 157 90 672 2

Direction (Q. No. 17): Insert the missing number from among the given alternatives.

17.

(a) 0 (b) 8 (c) 125 (d) 216

Ans. (d)

Solution :

(8 – 2)3 = (6)3 = 6 6 6 = 216

In each quarter (a – b)3 pattern is followed.

Direction (Q. No. 18): Study the following information carefully and answer the question given below:

Five persons K, L, M, N and O are sitting around a dining table. K is the mother of M, who is the wife O. N

is the brother of K and L is the husband of K.




18. How is L related to O?

(a) Father (b) Mother-in-law (c) Brother-in-law (d) Father-in-law

Ans. (d)

L is father-in-law of O.

19. How many numbers amongst the numbers 9 to 99 are there which are exactly divisible by 9 but not by

3?

(a) Eight (b) Ten (c) Twelve (d) None of these

Ans. (d)

Solution:

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99

There is no such number because a number which is divisible by 9 is also divisible by 3.

Direction (Q. No. 20): Insert the missing number from among the given alternatives.

20.

(a) 0 (b) 2 (c) 11 (d) 12

Ans. (c)

Solution:

The number inside the circle is equal to the difference between the sum of numbers at the extremities

of the numbers at the extremities of the vertical diameter.

I. (5 + 6) – (7 + 40 = 0

II. (7 + 6) – (8 + 4) = 1

III. (11 + 2) – (2 + 0) = 11

21. In the following number series, how many 5s are there which are immediately preceded by an odd

number and immediately followed by an even number?

2 4 9 7 6 5 5 4 3 7 9 4 5 8 3 5 6 7 9 8 4 2 5 6 7 5 2

(a) Two (b) Three (c) Four (d) Five

Ans. (b)

Solution:

Odd number 5 Even number




Thus, there are three such 5s.

Direction (Q. No. 22): In the question given below, which one of the following four interchanges in

signs and/or numbers would make the given equation correct.

22. 3 + 5 – 2 = 4

(a) + and – , 2 and 3 (b) + and –, 2 and 5 (c) + and – , 3 and 5 (d) None of these

Ans. (c)

Solution:

5 – 3 + 2 = 4 (+ and – , 3 and 5)

23. If 17th January of a year was Monday, what will be the day on 19th June of the same year? (February

has 28 days.)

(a) Sunday (b) Monday (c) Tuesday (d) Wednesday

Ans. (a)

Solution :

Number of days between 17th January and 19th June

= 14 days in January + 28 days in February + 31 days in March + 30 days in April + 31 days in May + 19

days in June = 153 days.

Number of weeks = 153 6

217 7

days

Day after 21 weeks will be Monday again. Day after 6 days will be Sunday. Day on 19th June will be

Sunday.

Direction (Q. No. 24): In the following question, a letter series is given in which some of the letters are

missing. The missing letters are given in that order as one of the alternatives below it. Choose the

correct alternative.

24. a b _ _ _ b _ b b a a _

(a) a b a a b (b) a b b a b (c) b a a a b (d) b a b b a

Ans. (c)

Solution:

The series is : a, b b; a a, b; a, b b; a a, b

Direction (Q. No. 25): Choose the set of numbers from the four alternatives which is similar to the

given set.




25. Given set (256, 64, 16)

(a) (160, 40, 10) (b) (144, 36, 9) (c) (80, 20, 5) (d) (64, 32, 8)

Ans. (b)

Solution:

All the numbers in the each sent can be expressed in terms of power of 2.

26. 69 is divided into 3 parts such that the first number is the arithmetic mean of the other two numbers .

The second number is 4 more than the third number. The three numbers are

(a) 23, 27, and 19 (b) 21, 27 and 23 (c) 23, 25 and 21 (d) 19, 29 and 21

Ans. (c)

Solution :

Let the third number be x.

Second number = x + 4

Arithmetic mean of second and third numbers = (x + x + 4)/2

= (2x + 4)/2 = x + 2

First number = x + 2

So, x + 2 + x + 4 + x = 69

or 3x + 6 = 69

3x = 69 – 6

x = 63/3

x = 21

First number = 21 + 2 = 23

Secondary number = 21 + 4 = 25

Third number = 21

27. The reflex angle between the hands of a clock at 10 : 25 is

(a) 0180 (b) 01

1922

(c) 0195 (d) 01

1972

Ans. (d)

Solution:

Angle traced by hour hand in

o o125 360 125 1h 312

12 12 12 2

Angle traced by minute hand in 25 min




= o

036025 150

60

Reflex angle = o

0 1360 312 150

2

= o o

0 1 1360 162 197

2 2

28. Statements Some teachers are professors.

Some professors are readers.

All readers are rectors.

Conclusions I. Some readers are teachers.

II. Some rectors are teachers.

III. All rectors are readers.

(a) None follows (b) Only 1 follows (c) Only II follows (d) All follow

Ans. (a)

29. At what time between 4 and 5 O’ clock, will the hands of a watch point in opposite directions?

(a) 45 min past 4 (b) 40 min past 4 (c) 4

5011

min past 4 (d) 6

5411

min past 4

Ans. (d)

Solution:

At 4 O’clock, the hands are 20 min apart from each other and for having in the oppos ite direction they

needs to be 30 min apart. From fig, (i) and fig. (ii), it is clear that minute hand has to travel. (20 + 30)

min space in order to be in opposite direction of each other.

Now, 55 min space is gained in 60 min.

Therefore, 50 min space will be gained in 60 6

50 min of 5455 11

min.

Hence, the hands of the clock will be in opposite direction at 6

5411

min past 4.

30. If + is , is +, is – and – is , then the value of 24 12 + 4 6 + 2 – 3 is

(a) 30 (b) 4 (c) 5 (d) 6

Ans. (a)

Solution:

Using proper symbols, we get




= 24 – 12 4 + 6 2 3

= 24 – 3 + 3 3 = 24 – 3 + 9 = 30

31. A sum of Rs 1420 is distributed among 7 men, 11 women and 10 boys, so that each woman gets thrice

the amount that a boy gets, and the share of one man equals the sum of the shares of a woman and a

boy. Find the sum of the shares of the women and the boys put together.

(a) 1220 (b) 660 (c) 860 (d) 760

Ans. (c)

Solution:

1 woman = 3 boys

1 man = 1 woman + 1 boy

1 man = 3 boys + 1 boy

1 man = 4 boys

7 men : 11 women : 10 boys

(7 4) boys : (11 3) boys : 10 boys

28 : 33 : 10

Hence, each part of the ratio = 1420

71 = 20

Share of 11 women = 33 20 = Rs 660

Share of 10 boys = 10 20 = Rs 200

Share of the shares of 11 women and 20 boys

= 660 + 200 = 860

32. Ravi is 7th ranks ahead of Sumit in a class of 39. If Sumit’s rank is 17th from the last, what is Ravi’s rank

from the top?

(a) 14th (b) 12th (c) 16th (d) 11th

Ans. (c)

Solution:

Sumit is 17th from the last and Ravi is 7th rank ahead means Ravi is 24th rank from the last.

So, Ravi’s rank from the top

= 39 – 24 + 1 = 16 th

Direction (Q. No. 33): Find the missing term in the following series.

33. ACEGI, JLNPR, SUWYA, ?, KMOQS

(a) LBGHI (b) ADIFH (c) YWXAC (d) BDFHJ

Ans. (d)




Solution :

A _ C _ E _ G_ I, i.e., there is a gap of one letter in the first group.

Second group starts with J, i.e., Immediately after the last letter I in the first group and there is a gap of

one J _ L _ N _ P_ R. Following this pattern, the answer is BDFHJ.

Direction (Q. No. 34): In the following question below, you are given a figure (X) followed by four

figures (a), (b), (c), and (d) such that (X) is embedded in one of them. Trace out the correct alternative.

34. Problem Figure

Ans. (d)

35. Problem Figure

Ans. (d)

Solution:

The second figure in each row forms the outermost and innermost part of the third figure, and the first

one forms the middle part.

36. Problem Figure Answer Figures

Ans. (d)

Solution:

Except the upper left design other three designs exchange their positions in anti-clockwise direction

and designs insides rotate by 450.




37. Problem Figure Answer Figure

Ans. (a)

Solution:

In each successive problem figure, the flags moves one, two, three and so on step in clockwise direction.

Direction (Q. No. 38-39): Choose the figure which is different from other figures.

38.

Ans. (b)

Solution :

Except figure (b) all the mirror images while it is a water image of G.

39.

Ans. (d)

Solution:

In figure (d), there is not path with three arms while other figures have 1, 2, 3 and 4 arm parts.

40. Problem Figure

Ans. (b)

Direction (Q. No. 41): Choose the alternative which most closely resembles the mirror image of the

given combination.




41. DOCTOR 7829

Ans. (c)

Direction (Q. No. 42): Choose the alternative which most closely resembles the water image of the

given combination.

42. UP 15847

Ans. (a)

Directions (Q. No. 43) In following question, three figures (x), (y) and (z) showing a sequence of

folding a paper are given. The figure depicts the cut made on the folded paper. Select the answer from

the alternatives which would most closely resemble the third figure when it is unfolded.

43. Problem Figure Answer Figure

Ans. (b)

Directions (Q. No. 44-46): Read the following information carefully and answer the questions that

follow.

Ram paint a cubical box with three different colours, green, white and yellow with instructions that two

opposite faces must have the same colour. He was asked to cut this box into twenty seven small cubes

of equal size.

44. How many small cubes will be there with no face painted at all?

(a) 2 (b) 8 (c) 4 (d) 1

Ans. (d)

Solution:

Number of smaller cubes without painted (no surface painted) = (N – 2)3

( 27 smaller cubes, it means N = 3)

= (3 – 2)3 = 1

45. How many cubes will be there with all the three colours on them?

(a) 3 (b) 5 (c) 8 (d) 4

Ans. (c)




Solution:

Numbers of cubes have all three colours = 8, because all corner cubes have all three colours.

46. How many cubes will be there with only one face painted in blue?

(a) 4 (b) 6 (c) 2 (d) 3

Ans. NA

47. Count the number of triangles and squares in the figure given below.

(a) 26 Triangles and 8 squares (b) 32 triangles and 8 squares

(c) 27 triangles and 9 squares (d) 30 triangles and 10 squares

Ans. (b)

48. How many squares are there in the following figure?

(a) 14 (b) 16 (c) 22 (d) 12

Ans. (a)

Directions (Q. No. 49) In the following question, find one correct answer figure from your alternatives

which resembles the pattern formed when the transparent sheet, having a design folded along the

dotted line.




49.

Ans. (a)

Directions (Q. No. 50) In the following question, there is a diagram marked (X). with one or more dots

placed in it. This diagram is followed by four other figures, marked (a), (b), (c) and (d) only one of

which is such as to make possible the placement of the dot (s) satisfying the same conditions as in the

original diagram. Find the correct alternative in each case.

50.

Ans. (d)

Note: Question No. 46 has been discarded.

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