Part of Made in India,Design Innovation

Workshop,2015

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PHYSICS INVESTIGATORY PROJECT ON

OHM’S LAW

Do  you  know  why  a  100  W  bulb  glows  brighter  than  a  40  W  bulb?  Ohm’s  law  will  help  you  understand  this,  it  states  that  the  voltage  drop  across  a  component  equals  the  product  of  thecurrent  flowing  through  it  and  its  resistance  (  V=  I  R  ).  Hence,  a  100  W  bulb  glows  brighter  as  itoffers  less  resistance  as  compared  to  a  40  W  bulb.  Now,  to  verify  this  law  one  needs  to  make  acircuit  using  a  breadboard,  an  LED,  a  100  Ω  resistor,  a  9V  baQery  and  a  few  connecRng  wires.  A  mulRmeter  was  connected  in  series  to  complete  the  circuit.  The  current  across  the  resistor  wascalculated  using  a  mulRmeter  and  it  was  also  calculated  theoreRcally  using  Ohm’s  law.  Both  thevalues  were  found  to  be  approximately  same.

Again,  if  a  100  Ω  resistor  was  replaced  by  a  1  kΩ,  and  likewise  its  current  value  was  calculated(as  above),  both  the  theoreRcal  and  the  mulRmeter  values  were  approximately  the  same.However,  it  was  also  observed  that  the  current  value  and  also  the  brightness  of  the  LEDdecreased  as  compared  to  the  former  case.  AlternaRvely,  the  value  of  resistance  (R=V/I)  wasalso  found  using  the  mulRmeter  readings  of  voltage  and  current  across  the  resistor,  which  wasnearly  equal  to  the  theoreRcal  value  of  the  resistance.  It  was  inferred  that  the  raRo  of  voltageto  current  remains  the  same  for  a  fixed  resistance.  Hence,  Ohm’s  law  was  verified.

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You  may  refer  to  this  video:  Ohm’s  LawFor  more  projects  visit  our  website:  CoolJunk  

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