P1 Variation Modul 2
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Transcript of P1 Variation Modul 2
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Tasksheet 2 : Variations Name : ___________________________ Class : ____________ Example : (a) Varies Directly
Given that A is directly proportional to B and A = 15 when B = 5, express A in terms of B.
Answer : A ∝B A = kB 15 = k(5)
k = 5
15
= 3 Hence, A = 3B
(b) Varies Inversely Given that C varies inversely as D and
C = 2 when D = 9, express C in terms of D.
Answer :
C ∝D1
C = kD1
2 = k(91 )
k = 2 )19(
k = 18
Hence, C = D18
Answer all questions. 1. Given that G is directly proportional to s and G = 20 when s = 3, express G in terms of s. 2. The table shows the values of N and R.
Given that N varies directly as R, find the value of a.
N 5 a R 30 12
3. The table shows the values of x and y. Given that x varies directly as the square of y, calculate the value of m.
x 44 m y 4 2
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4. The table shows the values of P and Q. Given that P varies directly as the square of Q, calculate the value of i.
P 200 72 Q 10 i
5. The table shows the values of u and v. Given that u varies inversely as the square of v, calculate the value of w.
u 16 w v 2 6
6. The table shows the values of E and F.
Given that E varies inversely as F, find the value of g.
E 2 g F 3 12
7. Given that S varies inversely as T and S = 7 when T = 5, express S in terms of T.
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8. The table shows the values of P and Q. Given that P varies inversely as the square of Q, calculate the value of R
P 31
3
Q 5 R
9. The table shows the values of P, Q and R.
Given that P varies directly as Q and inversely as R, find the value of m and n.
P Q R 2 3 4
10 m 12 20 60 n
10. The table shows the values of d, e and f.
Given that d varies directly as square of e and inversely as square root of f , find the value of x and y.
d e f 4 1 4
10 x 16
51
31
y
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Answers for Tasksheet 2 : Variations Name : ___________________________ Class : ____________ Answer all questions. 1. Given that G is directly proportional to s and G = 20 when s = 3, express G in terms of s. Answer : G ∝ s G = ks 20 = k(3)
k = 320
Hence, G = 320 s
2. The table shows the values of N and R.
Given that N varies directly as R, find the value of a.
N 5 a R 30 12
Answer : N ∝R N = kR 5 = k(30)
k = 305
= 61
Hence, N = 61 R
a = 61 (12)
= 2.
3. The table shows the values of x and y. Given that x varies directly as the square of y, calculate the value of m.
x 44 m y 4 2
Answer : x ∝ 2y x = k 2y 44 = k(4) 2
k = 1644
= 4
11
Hence, x = 4
11 2y
m = 4
11 (2) 2
= 11 4. The table shows the values of P and Q. Given that P varies directly as the square of Q, calculate the value of i.
K 200 72 L 10 i
Answer : P ∝ 2Q P = k 2Q 200 = k(10) 2
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k =
100200
= 2 Hence, P = 2 2Q 72 = 2(i) 2
i = 2
72
= 6 5. The table shows the values of u and v. Given that u varies inversely as the square of v, calculate the value of w.
u 16 w v 2 6
Answer :
u ∝ 2
1v
u = k 2
1v
16 = k( 221 )
k = 64
Hence, u = 2
64v
w = 2664
= 9
16
6. The table shows the values of E and F.
Given that E varies inversely as F, find the value of g.
E 2 g F 3 12
Answer :
E ∝F1
E = kF1
2 = k(31 )
k = 6
7. Given that S varies inversely as T and S = 7 when T = 5, express S in terms of T. Answer :
S ∝T1
S = kT1
7 = k(51 )
k = 35
Hence, S = T35
8. The table shows the values of P and Q. Given that P varies inversely as the square of Q, calculate the value of R
P 31
3
Q 5 R
Answer :
P ∝ 2
1Q
P = k 2
1Q
31 = k( 25
1 )
k = 325
Hence, P = )(3
252Q
3 = )(3
252R
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Hence, E = F6
g = 126
= 21
R = )3(3
25
= 35
= 321
9. The table shows the values of P, Q and R.
Given that J varies directly as Q and inversely as L , find the value of m and n.
P Q L 2 3 4
10 m 12 20 60 n
Answer :
P ∝RQ
P = k )(RQ
2 = k(43 )
k = 2(34 )
= 38
Hence, P = 38 )(
RQ
10 = 38 )
12( m
m = 10 )29(
= 45.
Hence, P = 38 )(
LK
20 = 38 )60(
n
10. The table shows the values of d, e and f.
Given that d varies directly as square of e and inversely as square root of f , find the value of x and y.
d e f 4 1 4
10 x 16
51
31
y
Answer :
d ∝f
e2
d = k(f
e2
)
4 = k(4
12
)
k = 4(12 )
= 8
Hence, d = 8(f
e2
)
10 = 8 )16
(2x
x = 2
10
= 5 .
Hence, d = 8(f
e2
)
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n = 20
160
= 8.
51 = 8
⎟⎟⎟⎟⎟
⎠
⎞
⎜⎜⎜⎜⎜
⎝
⎛⎟⎠⎞
⎜⎝⎛
y
2
31
y = 2
598
⎟⎠⎞
⎜⎝⎛ ×
= 81
1600
= 19.75 (2 d.p.)