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Transcript of One Dimensional Non-Homogeneous Conduction Equation P M V Subbarao Associate Professor Mechanical...
One Dimensional Non-Homogeneous Conduction Equation
P M V Subbarao
Associate Professor
Mechanical Engineering Department
IIT Delhi
Another simple Mathematical modification…..But finds innumerable number of Applications….
Further Mathematical Analysis : Homogeneous ODE
• How to obtain a non-homogeneous ODE for one dimensional Steady State Heat Conduction problems?
• Blending of Convection or radiation effects into Conduction model.
• Generation of Thermal Energy in a solid body.• GARDNER-MURRAY Ideas.
0
drdrdT
Ad
Blending of Convection or Radiation in Conduction Equation
Body to gain or loose heat
Extended surface
Continuous Convection or Radiation heat transfer to/from fin surface
Conduction heat transfer to /from body.
Conduction through the fin is strengthened or weakened by continuous convection or radiation from/to fin surface.
Mathematical Ideas are More NaturalAn optimum body size is essential for the ability to regulate body temperature by blood-borne heat exchange. For animals in air, this optimum size is a little over 5 kg. For animals living in water, the optimum size is much larger, on the order of 100 kg or so.
This may explain why large reptiles today are largely aquatic and terrestrial reptiles are smaller.
Mathematical Ideas are More Natural
• Reptiles like high steady body temperatures just as mammals and birds.
• They have sophisticated ways to manage flows of heat between their bodies and the environment.
• One common way they do this is to use blood flow within the body to facilitate heat uptake and retard heat loss.
• Blood flow is not effective as a medium of heat transfer everywhere in the body.
• Body shape also enters into the equation. • It also helps expalin the odd appendages like crests and
sails that decorated extinct reptiles like Stegosaurus or mammal-like reptiles like Dimetrodon.
• Theoretical Biologists did Calculations to show these structures could act as very effective heat exchange fins.
• These fins are allowing animals with crests to heat their bodies up to high temperatures much faster than animals without them.
Amalgamation of Conduction and Convection/Radiation
Heat Conducitonin
Heat Conducitonout
Heat ConvectionIn/out
GARDNER-MURRAY ANALYSIS : ASSUMPTIONS
Steady state one dimensional conduction Model. No Heat sources or sinks within the fin . Thermal conductivity constant and uniform in all directions. Heat transfer coefficient constant and uniform over fin faces. Surrounding temperature constant and uniform. Base temperature constant and uniform over fin base. Fin width much smaller than fin height. No bond resistance between fin base and prime surface. Heat flow off fin proportional to temperature excess.
Steady One-dimensional Conduction through Fins
qx qx+dx
qconv or qradiation
Conservation of Energy:
radiationxxcondxcond qqq ,,
convectionxxcondxcond qqq ,,
OR
Substituting and dividing by x:
0)(,,
TThP
x
qq xcondxxcond
Taking limit x tends to zero and using the definition of derivative:
0)( TThPdx
dq
Substitute Fourier’s Law of Conduction:
0)(
TThPdx
dxdT
kAd c
0)(
TThPdx
dxdT
kAd c
Fins with Cartesian Geometry Heat Transfer
Straight fin of triangular profile rectangular C.S.
b
xLxA )(
Straight fin of parabolic profile rectangular C.S.
b
L
x=0b
x=b
bx
qb
L
b
qb
b
x=b x=0
xb
2
)(
b
xLxA
0)(
TThPdx
dxdT
kAd c
Fins with Cartesian Geometry Heat Transfer
Straight fin of triangular profile Circular C.S.
22
4)( x
b
DxA
Straight fin of parabolic profile rectangular C.S.
44
4)( x
b
DxA
0)(
TThPdr
drdT
kAd c
Fins with Cylindrical Geometry Heat Transfer
Circumferential fin of rectangular profile
rrA 2)(
Straight fin of triangular profile
22)( rR
rA
Fin factor for pin Fin:4
& 2d
AπdP
kd
h
A
4
k
hP=m
Fin factor for strip Fin: LALP & 2
k
h
kL
Lh
A
22
k
hP=m
Linear Second order ODE with Constant Coefficients
• This equation has two linearly independent solutions.• The general solution is the linear combination of those two
independent solutions.• Each solution functionx and its second derivative must be
constant multiple of each other.• Therefore, the general solution function of the differential equation
above is:
0mxd
d 22
2
-mxmx eCeCxθ 21
At the base of the fin:
TTbasebase
Infinitely long fin:
LTT tipfintipfin as 0
x C e C e1mx
2-mx
Logic from Mathematics shows that C1 = 0 !
-mx2eCx
At the base of the fin:
02
mbasebase eCTT
mxbase eTTTxT
)(
mx
base
eTT
TxT
)(
For a strip fin:
x
k
h
base
eTT
TxT 2
)(
Rate of Heat Transfer in an Infinitely Long Strip Fin
TTmkAdx
dTkAQ basecs
xcs
0
TTkA
hPkA
dx
dTkAQ base
cscs
xcs
0
surfacefinA
surbasecsx
cs dAxhTThPkAdx
dTkAQ
0
The boundary condition are:0=0)=q(x
Using these gives: (x = b) = C e C eb 1mb
2-mb
and q(x = 0) = k Ld
dxk Lm C e C e
q(x = 0) k Lm(C Cx=0
1mx
2-mx
x=0
1 2
) 0
The foregoing shows that: -mbmb
b eeC
CCC
=
21
b=b)=(x
Longitudinal Fin : Adiabatic Tip
With the general solution for the temperature excess
-mxmx eCeCxθ 21
And from the previous slide
-mbmbb-mbmb
b ee
θCee=Cθ
CCC
21
mb
mxθee
ee
θb
-mxmx-mbmb
b
cosh
coshx
The heat flow through the fin at any location x is:
mb
mxLmkxq
mb
mx
xLk
xLkxq
cosh
sinh
cosh
cosh
d
d
d
d
b
b
And at x=b (heat entering fin base): mbLmkq bb tanh
mbLhkq bb tanh2 21 For a strip fin:
The fin efficiency, , is defined as the ratio of the actual heat dissipation to the ideal heat dissipation if the entire fin were to operate at the base temperature excess
idealq
qactual
Efficiency of Strip Fin
bb
Lb
hLbhQ 2SURFACE2
ideal
For infinitely long strip fin:
TThPkAQ basecsact inf
For Adiabatic strip fin:
mbTThPkAQ basecsadiact tanh