Objective: To use exponential and logarithmic functions to solve problems.
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Transcript of Objective: To use exponential and logarithmic functions to solve problems.
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Lesson 10-5 Applications of Exponential and Logarithmic FunctionsObjective: To use exponential and logarithmic functions to solve problems.
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Applications of exponential & logarithmic functions
Compound InterestContinuous CompoundingExponential Growth or decay (bacteria/ radiation half life)Richter Scale
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Compound interestCompound interest means the each payment is calculated by including the interest previously earned on the investment.
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Investing at 10% interest Compounded Annually
Year Investment at Start Interest Investment at End
0 (Now) $1,000.00 ($1,000.00 × 10% = ) $100.00 $1,100.00
1 $1,100.00 ($1,100.00 × 10% = ) $110.00 $1,210.00
2 $1,210.00 ($1,210.00 × 10% = ) $121.00 $1,331.00
3 $1,331.00 ($1,331.00 × 10% = ) $133.10 $1,464.10
4 $1,464.10 ($1,464.10 × 10% = ) $146.41 $1,610.51
5 $1,610.51
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formula
If you have a bank account whose principal = $1000, and your bank compounds the interest twice a year at an interest rate of 5%, how much money do you have in your account at the year's end?
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Solution
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Continous Compounding
When n gets very large it approaches becoming continuous compounding. The formula is:
P = principal amount (initial investment)r = annual interest rate (as a decimal)t = number of yearsA = amount after time t
rtPeA
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Example
An amount of $2,340.00 is deposited in a bank paying an annual interest rate of 3.1%, compounded continuously. Find the balance after 3 years.Solution
A = 2340 e(.031)(3)
A = 2568.06
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Exponential Growth
A = Pert ...or... A = Pekt ...or... Q =ekt ...or... Q = Q0ekt
k is the growth constant
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Bacteria Growth
In t hours the number of bacteria in a culture will grow to be approximately Q = Q0e2t where Q0 is the original number of bacteria. At 1 PM the culture has 50 bacteria. How many bacteria does it have at 4 PM? at noon?
Q = 50e2(3) Q = 50e2(-1)
Q = 50e6 Q = 50e-2
Q = 20,248 Q = 7
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Practice
1. If you start a bank account with $10,000 and your bank compounds the interest quarterly at an interest rate of 8%, how much money do you have at the year’s end ? (assume that you do not add or withdraw any money from the account)2. An amount of $1,240.00 is deposited in a bank paying an annual interest rate of 2.85 %, compounded continuously. Find the balance after 2½ years.
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Solution1.
2. A = 1240e(.0285)(2.5)
= $1,331.57
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Warm up
The first credit card that you got charges 12.49 % interest to its customers and compounds that interest monthly. Within one day of getting your first credit card, you max out the credit limit by spending $1,200.00 . If you do not buy anything else on the card and you do not make any payments, how much money would you owe the company after 6 months? A = P(1 + )nt
n
r
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Exponential Decay
An artifact originally had 12 grams of carbon-14 present. The decay model A = 12e-0.000121t
describes the amount of carbon-14 present after t years. How many grams of carbon-14 will be present in this artifact after 10,000 years?
A = 12e-0.000121t
A = 12e-0.000121(10,000)
A = 12e-1.21
A = 3.58
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Earthquake – Richter scale
R = log It compares how much
stronger the earthquake is compared to a given standardR= 3.0 then 3 = log 1000 =
I = 1000I0 1000 times the standard
0I
I
0I
I
0I
I
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Earthquake – Richter scale
Haiti 7.0 7 = log
10,000,000 =
Japan 8.9 8.9 = log 794,328,235 =
Virginia 5.9 ?(August 23, 2011)
0I
I
0I
I
0I
I
0I
I
794,328