Paul O. Lewis...Title lewis-bayesian-part1.key Author Paul O. Lewis Created Date 20190804122701Z
Lewis structure H PO - Oregon State...
Transcript of Lewis structure H PO - Oregon State...
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CH2. Molecules and covalent
bondingLewis Structures
VSEPR
MO Theory
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Lewis structure H3PO4
• Skeleton is:
• Count total valence electrons:1 P = 5
3 H = 3
4 O = 24
Total = 32 e- or 16 valence e- pairs.
• 7 e- pairs needed to form s skeleton.
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Lewis structure H3PO4• Add remaining e- pairs:
• Left has a formal charge of +1 on P and -1 on one O, right has 5 e- pairs around P (hypervalence)
• Analysis of phosphoric acid shows purely Td phosphate groups, which requires something beyond either simple Lewis model.
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Resonance in NO3-
experimental
data - nitrate is
planar with 3
equivalent N-O
bonds
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VSEPR model
• Count e- pairs about the central atom (draw Lewis structure if needed). Include non-bonding pairs, but not multiple bonds.
• Geometry maximizes separation:
# e pairs geometry example
2 linear HF2-
3 equilateral triangular BF3
4 tetrahedral (Td) CF4
5 trigonal bipyramidal (TBP) PF5
6 octahedral (Oh) SF6
7 pentagonal bipyramidal IF7
8 square antiprismatic TaF83-
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Drawing Oh and Td molecules
It's often useful to draw octahedra and
tetrahedra with a cubic framework
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Deviations from ideal geometries:
unshared pairs and multiple bonds require larger bite
ex: CH4, NH3, H2O
<H-C-H = 109.5°,
<H-N-H = 107.3,
<H-O-H = 104.5
ex: ICl4-
6 e pairs around I, 2 lone pairs and 4 e pair bonds to Cl
Oh coordination, and geometry is square planar (lone pairs are trans, not cis)
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POCl3
based on Td geometry
< ClPCl = 103.3° due to
repulsion by multiple bond
note that in :PCl3the <ClPCl = 100.3,
the lone pair is
more repulsive
towards other
ligands than the
multiple bond !
Ligands move away from multiple bond
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XeF5+
5 Xe-F bonds and 1 lone
pair on Xe
geometry based on Oh
coordination
lone pair repulsion gives
< FeqXeFeq = 87°
< FaxXeFeq = 78°
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Fajan’s rule
bond polarization is towards
ligands with higher c,
decreasing repulsive effect.
Lone pairs are the most
repulsive.
ex: NH3 vs NF3
< HNH = 107.3°
< FNF = 102.1°
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Inert pair effect
• VSEPR geometries require
hybridization (valence bond term) or
linear combinations (MO term) of
central atom orbitals. For example,
Td angles require sp3 hybrid orbitals.
More on this in MO theory section.
• Period 5 and 6 p-block central atoms
often show little hybridization (ex:
they form bond with orbitals oriented
at 90° as in purely p orbitals). This
can be ascribed to the weaker
bonding of larger atoms to ligands.
In Sn Sb Te
Tl Pb Bi
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Inert pair effect - evidence• Bond angles near 90°:
NH3 107.2 H2O 104.5
AsH3 91.8 H2Se 91
SbH3 91.3 H2Te 89.5
• Increased stability of lower oxidation statesex: Si, and Ge are generally 4+, but Sn and Pb are common as 2+ ions (as in stannous fluoride SnF2)
ex: In and Tl both form monochlorides, B, Al, Ga form trichlorides.
• Vacant coordination sites where the lone pair resides
ex: PbO
PbO unit cell
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Fluxionality
• PF5 if TBP has 2 types of F ligands (equatorial and axial).
• 19F NMR spectra at RT show only a single peak (slightly broadened).
• PF5 is fluxional at RT, i.e. the F ligands exchange rapidly, only a single "average" F ligand is seen by NMR.
• Only occurs if ligand exchange is faster than the analytical method. IR and Raman have shorter interaction times and show 2 types of P-F bonding at RT.
• At low T, exchange is slower and we see 2 NMR peaks in expected 3:2 intensity ratio.
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Berry pseudo-rotation
Sequences of the MD-Simulation of PF5 at 750K
(Daul, C., et al, Non-empirical dynamical DFT calculation
of the Berry pseudorotation of PF5, Chem. Phys. Lett.
1996, 262, 74)
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Molecular Orbitals
Use linear combinations of atomic orbitals to derive symmetry-adapted linear combinations (SALCs).
Use symmetry to determine orbital interactions.
Provide a qualitative MO diagram for simple molecules.
Read and analyze an MO diagram by sketching MO’s / LCAO’s, describing the geometric affect on relative MO energies.
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H2
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Some rules
The number of AO’s and MO’s must be equal.
This follows from the mathematics of independent
linear combinations.
More on symmetry labels later, but they come
from the irreducible representations for the point
group. s MO’s are symmetric about bond axis, p
MO’s are not. Subscipt g is gerade (has center of
symmetry), u is ungerade. Antibonding orbitals
are often given a * superscript.
The bond order = ½ (bonding e- - antibonding e-).
The bond energy actually depends on the
energies of the filled MO’s relative to filled AO’s.
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O2
• MO theory predicts 2 unpaired e-,
this is confirmed by experiment.
• Bond order = ½ (8-4) = 2, as in
Lewis structure.
• MO indicates distribution and
relative energies of the MO's, Lewis
structure says only bonding or non-
bonding.
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I and Ea for atoms and diatomics
species I (kJ/mol) Ea
N 1402
O 1314 142
O2 1165 43
NO 893
F 1681
F2 1515
C 1086 123
C2 300
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Li2 – F2 MO’s
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Some diatomic bond data
bond order r0 in pm D0 in kJ/mol
O2 2 121 494
O2- 1 ½ 126
O22- 1 149
F2 1 142 155
O2+ 2 ½ 112
NO 2 ½ 115
NO+ 3 106
N2 3 110 942
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Spectroscopic data for MO’s
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HF
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Ketalaar triangle
HF
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Hybridization
• Linear combinations of AO’s from same atom
makes hybrid orbitals.
• Hybridization can be included in the MO
diagram.
• In MO theory, any proportion of s and p can
be mixed (the coefficients of the AO’s are
variable). sp and sp3 hybrids are specific
examples.
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H3+
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BeH2
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Correlation diagram for MH2
M < HMH
Be 180°
B 131
C 136
N 103
O 105
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Bonding MO’s in H2O
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NH3
Use triangular H3 MO’s from
above as SALC's of the H
ligand orbitals. Must relabel
to conform with lower
symmetry pt group C3v. They
become a1 and e.
Combine with N valence
orbitals with same symmetry.
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NH3 --calculated MO diagram
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SF6
See textbook Resource Section 5 for SALCs