Lesson # 35 Trigonometric Ratios

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Lesson # 35 Trigonometric Ratios

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Lesson # 35 Trigonometric Ratios. Recall that in the past finding an unknown side of a right triangle required the use of Pythagoras theorem. By using trig ratios we can now solve unknown sides of a triangle and determine all the angles . No more Pythag!. - PowerPoint PPT Presentation

Transcript of Lesson # 35 Trigonometric Ratios

Page 1: Lesson # 35 Trigonometric Ratios

Lesson # 35Trigonometric Ratios

Page 2: Lesson # 35 Trigonometric Ratios

Recall that in the past finding an unknown side of a right triangle required the use of Pythagoras theorem. By using trig ratios we can now solve unknown sides of a triangle and determine all the angles. No more Pythag!

Eg.1- First we must label the sides properly

Adjacent

Opposite

Hypotenuse

Opposite

Adjacent

Hypotenuse

The adjacent side always touches the angle.

Page 3: Lesson # 35 Trigonometric Ratios

Eg. 2 – To remember the trig ratio formulas think SOHCAHTOA

sin opphyp

cos adjhyp

tan oppadj

theta is used to represent the angle in degrees

Eg. 3 – Calculate to 3 decimal places

a) sin 27o =

b) cos 56o =

c) tan 78o =

d) sin 90o =

e) tan 20o =

f) sin 62o =

0.454 0.559 4.705

1.000 0.364 0.883

Page 4: Lesson # 35 Trigonometric Ratios

What cos60o tells us is that if the angle is 60 degrees theratio of the length of the adjacent over the hyp is 0.5.

60o

1

32opp

adj

hyp

60o

4

488opphyp

adj

To determine the unknown angle press sin-1, cos-1, or tan-1

Eg. 4 – Calculate the angle to 1 decimal place

a) sin = 1/2

b) cos = 0.3

c) tan = 8.1

d) sin = 1

e) tan = 0.43

f) sin = 0.71

30o 72.5o

83o

90o 23.3o

45.2o

Page 5: Lesson # 35 Trigonometric Ratios

Eg. 5 Determine unknown measure

Page 6: Lesson # 35 Trigonometric Ratios

Homework

Pg. 228 #2,3,4ab,6-8