8/16/2019 Lecture -05 Welded Connections.ppt

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The weld is assumed as lines of unit width.

f = M/S = 6M/bh 2 since b = 1 and h = L therefore L = 6M/f where f is thedemand, equating to the ca acit! we get the gi"en equation.

8/16/2019 Lecture -05 Welded Connections.ppt

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#ue to the return at the to , the $%& is shifted slightl! to to . 'or the return(as in the numerator) the roduct of area and centriod is ignored as it will bea "er! small "alue.

8/16/2019 Lecture -05 Welded Connections.ppt

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The direct shear acts as shear for the weld along the length. The tensioncom onent due to moment is er endicular to the weld, howe"er it is addedto the shear as welds are alwa!s design for shear.