Kuliah3 Ipr Dua Fasa
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Transcript of Kuliah3 Ipr Dua Fasa
IPR DUA FASA
Muhammad Taufiq Fathaddin
I. Vogel Equation
qo = flow rate, STB/Dqmax = flow rate @ Pwf = 0, STB/DPwf = flowing bottom hole pressure,
psiPr = reservoir pressure, psi
Example 1Diketahui:Pr = 2000 psi (pb = 2000 psi)Q = 1000 bpd @ pwf = 500 psi
1. Determine q max2. Construct IPR Curve3. Determine q at pwf = 1000 psi
Solution
1. Determine qmax@S=0 =
Solution2. Construct IPR Curve
Pwf, psi q, STB/D0 1111.1
200 1080.0400 1031.1600 964.4800 880.0
1000 777.81200 657.81400 520.01600 364.41800 191.12000 0.0
Solution3. Find q for Pwf = 1000 psi Pwf = 1000 psi , q = 777.8 STB/D (obtained
from Figure/Table)
II. Harrison Equation
Example 1Diketahui:Pr = 2000 psi (pb = 2000 psi)Q = 1000 bpd @ pwf = 500 psi
1. Determine q max2. Construct IPR Curve3. Determine q at pwf = 1000 psi
Solution
1. Determine qmax@S=0 =
Solution2. Construct IPR Curve
pwf, psi q, STB/D0 1127.4
200 1083.2400 1030.2600 966.9800 891.2
1000 800.51200 692.11400 562.41600 407.31800 221.72000 0.0
Solution3. Find q for Pwf = 1000 psi Pwf = 1000 psi , q = 800.5 STB/D (obtained
from Figure/Table)
III. Pudjo Sukarno Equation
Example 1Diketahui:Pr = 2000 psi (pb = 2000 psi)Q = 1000 bpd @ pwf = 500 psi
1. Determine q max2. Construct IPR Curve3. Determine q at pwf = 1000 psi
Solution
1. Determine qmax@S=0 =
Solution2. Construct IPR Curve
Pwf, psi q, STB/D0 1063.0
200 1051.0400 1021.4600 974.1800 908.5
1000 823.41200 716.81400 586.01600 427.01800 234.82000 0
Solution3. Find q for Pwf = 1000 psi Pwf = 1000 psi , q = 823.4 STB/D (obtained
from Figure/Table)
IV. Klins Equation
Example 1Diketahui:Pr = 2000 psi (pb = 2000 psi)Q = 1000 bpd @ pwf = 500 psi
1. Determine q max2. Construct IPR Curve3. Determine q at pwf = 1000 psi
Solution1. Determine qmax@S=0 =
Solution2. Construct IPR Curve
Pwf, psi q, STB/D0 1088.9
200 1056.3400 1020.5600 977.0800 921.0
1000 847.01200 749.51400 622.31600 459.41800 254.12000 0.0
Solution3. Find q for Pwf = 1000 psi Pwf = 1000 psi , q = 847 STB/D (obtained
from Figure/Table)
V. Wiggins Equation
qo = flow rate, STB/Dqmax = flow rate @ Pwf = 0, STB/DPwf = flowing bottom hole pressure,
psiPr = reservoir pressure, psi
Example 1Diketahui:Pr = 2000 psi (pb = 2000 psi)Q = 1000 bpd @ pwf = 500 psi
1. Determine q max2. Construct IPR Curve3. Determine q at pwf = 1000 psi
Solution
1. Determine qmax@S=0 =
Solution2. Construct IPR Curve
Pwf, psi q, STB/D0 1190.3
200 1122.8400 1043.8600 953.4800 851.5
1000 738.11200 613.41400 477.11600 329.41800 170.32000 0
Solution3. Find q for Pwf = 1000 psi Pwf = 1000 psi , q = 738.1 STB/D (obtained
from Figure/Table)
Gema-Taufiq Equation
Example 1Diketahui:Pr = 2000 psi (pb = 2000 psi)Q = 1000 bpd @ pwf = 500 psi
1. Determine q max2. Construct IPR Curve3. Determine q at pwf = 1000 psi
Solution
1. Determine qmax@S=0 =
Solution2. Construct IPR Curve
Pwf, psi q, STB/D
0 1156.9200 1104.7400 1038.4600 958.0800 863.5
1000 754.91200 632.11400 495.31600 344.31800 179.22000 0
Solution3. Find q for Pwf = 1000 psi Pwf = 1000 psi , q = 754.9 STB/D (obtained
from Figure/Table)
Task # 1Given data:Pr = 1345 psia (Pb = 3000 psia)A test shows q = 321 bpd at a flowing
pressure of 719 psia.API > 40 and S = 0Calculate:(1). qomax at 1345 psia(2). Construct IPR Curve using Vogel,
Harrison, Pudjo Sukarno Method, Klins, Wiggins, and Gema-Taufiq Methods
(3). Determine q at Pwf = 950 psi