JEE MAIN MOCK TEST

8/17/2019 JEE MAIN MOCK TEST

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JEE MAINTARGET 2016

Class: XII / XIII Date: 27-03-2016 Time: 3 Hours. Max. Marks: 360

MOCK TEST-3

Corporate Office : "POOJA TOWER",3, Gopalpura, Gopalpura Bypass, Jaipur-302 018 (Raj.) INDIA,

Tel.: 0141-5118115website : www.bansalclassesjaipur.com | Email : [email protected]

THISPA

PERCONTAI N

STOTALNU

MBEROFPAG

ES:33

Important Instructions :

1. The question paper consists of '90' objective typequestions. There are '30' questions each inMathematics, Chemistry andPhysics respectively.Please fill the OMR answer Sheet accordingly and

carefully.

2. Each question has four choices (1), (2), (3) and (4)out of which ONLY ONE is correct.

3. You will be awarded 4 marks for each question, if

you have darkened only the bubble correspondingto the correct answer and zero mark if no bubble aredarkened. In all other cases, minus one (–1) mark will be awarded.

4. There is only one correct response for eachquestion. Filling up more than one response in eachquestion will be treated as wrong response andmarks for wrong response will be deductedaccordingly as per instruction 3 above.

5. Use Black or Blue Ball Point Pen only for fillingparticulars.

6. Use of Calculator, Log Table, Slide Rule and Mobileis not allowed.

7. Rough work is to be done on the space provided atthe bottom and in end of the booklet for this purposein the Test Booklet only.

8. On completion of the test, the candidate must handover the Answer Sheet to the Invigilator. However,the candidates are allowed to take away this TestBooklet with them.

9. Do not fold or make any stray marks on the AnswerSheet.

egRoi w. kZfunsZ' k %

1. bl iz'u i= es a 90 fodYikRed izdkj ds iz'u gSxf.kr, jl k;u rFkk HkkSfrd izR;sd es a Øe'k% 30 iz'u gSA dì ;k OMRmÙkj iqfLrdkdksl ghi zdkj rFkk l ko/kkuhiwoZd HkjsaA

2. izR;sd iz'u ds pkj fodYi (1), (2), (3) rFkk (4) gSftues a ls dsoy ,d lgh gSA

3. ;fn vkius lgh mÙkj ls lEcfU/kr xksys dks dkyk fd;k gS] rks vkidks a 4 vad iznku fd;s tk;s axs rFkk ;fn dksbZHkh xksyk dkyk ugha fd;k x;k gS rks 'kw U; vad fn;stk;s axsA vU; lHkh fLFkfr;ks a es a –1 vad fn;s tk;s axsA

4. izR;sd iz'u ds fy, ds oy ,d lgh mÙkj gSA ,d lsvfèkd fodYi ,d iz'u es a Hkjus a ij bUgs a xyr fodYi ekuk tk;s axk rFkk funs Z'k 3 ds vuq lkj xyr fodYi ekurs gq, vad dkV fy;s tk;s axsA

5. xksys dks Hkjus ds fy;s ds oy dkyk ;k uhyk ckWyIokbaV i su dk iz;ksx djs aA

6. lax.kd] y?kqx.kd lkj.kh] ukekafdr iSekuk rFkk eksckbZy dk iz;ksx oftZ r gSA

7. jQ dk;Z djus ds fy, ds oy i"̀B ds uhps fn;s x;s LFkku rFkk iqfLrdk ds vUr es a NksM+ s x;s LFkku dk gh iz;ksx djsaA

8. ijh{kk dh lekfIr ij] fo|kFkhZ viuh mÙkj iqfLrdk oh{kd dks lksis aA ;|fi iz'u iqfLrdk fo|kFkhZ vius lkFk ys tk ldrs gSA

9. mÙkj iqfLrdk dks eksM+ s ugha ;k ml ij fdlh rjg dk fpUg vafdr uk djs aA

Note : ; fn ç'u i = dsfgUnhvuqokn esafo| kFkhZfdl hHkhçdkj dh=qfV ikrkgSrksog vaxzst hek/;e dsç'udksghl ghekudj gy djsaA


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XII / XIII MT-3 [JEE Main] Page # 2

SPACE FOR ROUGH WORK

MATHEMATICS

Q.1 Solut ion of the differential equation

xlog1xlogx

dydx

=

xlog1ey

, y(1) = 0 is

(1) xx =yyee (2) ey =

yex

(3) xx

=

ye

y (4) none

Q.2 Two different packs each of 52 cards areshuffled together then number of ways in which26 cards can be dealt out to a person so thathe does not receive any two cards of same suitand same denomination is(1) 52C26 · 2

26 (2) 52C13 ·49C13

(3) 104C26 (4)52C13 ·

52C13

Q.3 Considerf(x) = | sin –1x | + cos –1 | x | + | tan –1x | + cot –1 | x |,

then if number of integers in the domain of f isn(d) while number of integers in range of f ben(r), then n(d) + n(r) is(1) 0 (2) 2(3) 3 (4) none of these

Q.1 vody lehdj.k xlog1

xlogxdydx

=

xlog1ey

,

y(1) = 0 dk gy gS

(1) xx =yyee (2) ey =

yex

(3) xx =yey (4) dksbZ ugha

Q.2 52 rk'k okyh nks fofHkUu xfM~M;ks a (Packs) dks lkFk&lkFk Hkyh çdkj ls Qs aVk (shuffled) tkrk gS] rks mu rjhdka s dh la[;k] ftues a ,d O;fDr dks 26 rk'k bl çdkj ls çkIr gks fd mldks dksbZ Hkh nks rk'k leku laoxZ (suit) rFk k leku la[;k (denomination) okys ugha feys] gksxh (1) 52C26 · 2

26 (2) 52C13 ·49C13

(3) 104C26 (4)52C13 ·

52C13

Q.3 ekuk f(x) = | sin –1x | + cos –1 | x | + | tan –1x | + cot –1 | x |

gSA ;fn f ds çkUr es a iw .kkZadks a dh la[;k n(d) gStcfd f ds ifjlj es a iw .kkZ adks a dh la[;k n(r) gS] rksn(d) + n(r) dk eku gS(1) 0 (2) 2(3) 3 (4) bues a ls dksbZ ugha

USEFUL DATAAtomic weights: Al = 27, Mg = 24, Cu = 63.5, Mn = 55, Cl = 35.5, O = 16, H = 1, P = 31,Ag = 108, N = 14,Li = 7, I = 127, Cr = 52, K=39, S = 32, Na = 23, C = 12, Br = 80, Fe = 56, Ca = 40, Zn = 65.5, Ti = 48,Ba = 137, U = 238, Co= 59, B =11, F = 19, He = 4, Ne = 20, Ar = 40 , Mo = 96[Take : ln 2 = 0.693, ln 1.1 = 0.095, ln 3 = 1.09, e = 1.6 × 10 –19, me= 9.1 × 10

–31 kg ]Take: ∈

0 = 8.85 × 10 –12 C2 /Nm2, g = 10 m/s2, S

water = 1 cal/gm °C, L

ice = 80 cal/gm. , g = 10 m/s2

unless otherwise stated


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Q.4 The number a, b are selected from the set{1, 2, 3, 4, 5, 6, 7, 8, 9, 10} such that a bwith replacement, then the probability a dividesb is

(1)115

(2)5529

(3)5527

(4)116

Q.5 P is a point (a, b, c). Let A, B, C be images of P in yz, zx and xy planes respectively, then theequation of plane ABC is(1) bcx + acy + abz = 3abc(2) bcx + acy + abz = 2abc(3) bcx + acy + abz = abc(4) bcx + acy + abz = 0

Q.6 If candb,a

are three non-coplanar unitvectors each inclined at an angle of 30°, thenvolume of tetrahedron whose edges are

candb,a

is

(1)12

533 (2)

12533

(3) 12 325 (4) 12 325

Q.7 If in a ABC, cos A + 2cos B + cos C = 2,

then minimum value of cb2

bcab2

ba

is

(1) 2 (2) 4(3) 6 (4) 8

Q.4 leqPp; {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} es a lsçfrLFkkiu djrs gq, la[;kvks a a rFkk b dk p;u bl çdkj fd;k tkrk gS fd a b jgs] rks a }kjk b dks foHkkftr fd;s tkus dh çkf;drk gksxh

(1)115

(2)5529

(3)5527

(4)116

Q.5 ekuk ,d fcUnq P (a, b, c) gSA xy, yz rFkk zx leryks a es a P ds çfrfcEc Øe'k% A, B, C gS] rks lery ABC dk lehdj.k gS(1) bcx + acy + abz = 3abc(2) bcx + acy + abz = 2abc(3) bcx + acy + abz = abc

(4) bcx + acy + abz = 0

Q.6 ;fn cb,a

rFkk rhu vleryh; bdkbZ lfn'k gS

tks ,d nw ljs ls 30° ds dks.k ij >w ds gq, gS] rks ml prq"Qyd dk vk;ru] ftldh dks jas (edges)

cb,a

rFkk gS] gksxk

(1)12

533 (2)

12533

(3)12

325 (4)12

325

Q.7 fdlh ABC es a];fn cos A + 2cos B + cos C = 2 gS] rks

cb2bc

ab2ba

dk U;w ure eku gS

(1) 2 (2) 4(3) 6 (4) 8


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Q.8 If standard deviation of a variate x is , then

standard deviation of c

bax where a, b, c

are constants is

(1)a

c(2) 2

2

a

c

(3)c

b(4)

ca

Q.9 Let A, B, C be point with position vectors as

a

= (2, – 1, 1), b

= (1, 2, 3) and

c

= (3, 1, 2) respectively. If O be the originthen the shortest distance of B from plane OACis

(1) 275

(2)75

(3)7

10(4)

145

Q.10 Consider straight line ax + by = c where a, b, c R+ and a, b, c are distinct. If the line meetsthe coordinate axes at P & Q respectively andthe area of OPQ is independent of a, b & cthen(1) a, b, c are in G.P.(2) a, c, b are in G.P.(3) a, b, c are in A.P.(4) a, c, b are in A.P.

Q.8 ;fn fopj x dk ekud fopyu gS] rksc

bax dk

ekud foypu gksxk (tgk¡ a, b, c fu;rkad gS)

(1)a

c(2) 2

2

a

c

(3) cb (4) ca

Q.9 ekuk A, B, C fcUnq gS ftuds fLFkfr lfn'k dze'k%

a

= (2, – 1, 1), b

= (1, 2, 3) rFkk c

= (3, 1,2) gS aA;fn O ew y fcUnq gS rks lery OACdh fcUnqB ls fuEure nw jh gS

(1) 2 75

(2) 75

(3)7

10(4)

145

Q.10 ekuk ljy js[kk ax + by = c, tgk¡ a, b, c R+

rFkk a, b, c fHkUu&fHkUu gSA ;fn js[kk funs Z'kh v{kks adks Øe'k% P rFkk Q ij feyrh gS rFkk OPQ dk

{ks =Qy a, b rFkk c ls Lora = gS] rks fuEu es a lsdkSulk lR; gks ldrk gS\(tgk¡ O ew y fcUnq gS)(1) a, b, c xq.kksÙkj Js.kh es a gS(2) a, c, b xq.kksÙkj Js.kh es a gS(3) a, b, c lekUrj Js.kh es a gS(4) a, c, b lekUrj Js.kh es a gS


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Q.11 If l() =2x

1cossinLim

xx

2x

where

2

,0 , then value of

4

l equals

(1) 2nl

(2) – 2nl

(3) 2 2nl (4) ln 2

Q.12 Let and be roots of equationx2 – 7x – 5 = 0 with > . If an =

n – n for

n 1, then the value of 2015

20142016

a7a5a

is

(1) 1 (2) 2(3) 3 (4) 5

Q.13 Consider a hyperbola H :36y

4x 22

= 1, then

which of the following cannot be a tangent tothe hyperbola?(1) y = 4x + C (2) y = 2x + C(3) y = 5x + C (4) y = – 7x + C

Q.14 The equation of common tangent to theparabola y2 = 8x and the hyperbola3x2 – y2 = 3 is(1) 2x ± y + 1 = 0 (2) x ± y + 1 = 0(3) x ± 2y + 1 = 0 (4) x ± y + 2 = 0

Q.15 The equation x2 + b2 = 1 – 2bx andx2 + a2 = 1 – 2ax have only one root incommon, then(1) | a – b | = 2 (2) a = b(3) a + b = 0 (4) | a + b | = 2

Q.11 ;fn l() =2x

1cossinLim

xx

2x

,

tgk¡

2

,0 gS] rks

4

l dk eku cjkcj gS

(1) 2nl

(2) – 2nl

(3) 2 2nl (4) ln 2

Q.12 ekuk rFkk lehdj.k x2 – 7x – 5 = 0 ds ew y gS] tgk¡ > gSA ;fn an =

n – n, tgk¡ n 1

gS] rks2015

20142016

a7a5a

dk eku gS

(1) 1 (2) 2(3) 3 (4) 5

Q.13 ekuk ,d vfrijoy; H :36y

4x 22

= 1 gS] rks

fuEu es a ls dkSulh vfrijoy; dh Li'kZ js[kk ugha a gks ldrh gS\(1) y = 4x + C (2) y = 2x + C(3) y = 5x + C (4) y = – 7x + C

Q.14 ijoy; y2 = 8x rFkk vfrijoy; 3x2 – y2 = 3 dh mHk;fu"V Li'kZ js[kk dk lehdj.k gS(1) 2x ± y + 1 = 0 (2) x ± y + 1 = 0(3) x ± 2y + 1 = 0 (4) x ± y + 2 = 0

Q.15 ;fn lehdj.kks a x2 + b2 = 1 – 2bx rFkk x2 + a2 = 1 – 2ax dk ds oy ,d mHk;fu"B ew y gS] rks(1) | a – b | = 2 (2) a = b(3) a + b = 0 (4) | a + b | = 2


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Q.16 The area enclosed by the curves

C1 : arg (z – 2) = 4

,

C2 : arg (z – 2) = 43

and

C3 : (Re (z – 2))2 =

i2zz

on the complex plane is

(1)32

(2)31

(3)65

(4)34

Q.17 Which of the following functions is surjectivebut not injective(1) f : R R, f(x) = x4 + 2x3 – x2 + 1(2) f : R R, f(x) = x3 + x + 1

(3) f : R R+, f(x) = 2x1(4) f : R R, f(x) = x3 + 2x2 – x + 1

Q.18 If

dx)xsecxtan2xx(tane 2x = ex f(x) + C

where f(0) = 0, then the value of

4f equals

(1)4

(2) 1 – 4

(3)4

(4)2

Q.16 lfEeJ lery ij oØks a

C1 : arg (z – 2) = 4

,

C2 : arg (z – 2) = 43

rFkk

C3 : (Re (z – 2))2 =

i2zz

}kjk ifjc) {ks =Qy gS

(1)32

(2)31

(3)65

(4)34

Q.17 fuEu es a ls dkSulk Qyu vkPNknd gS ijUrq ,dSdh ugha gS\(1) f : R R, f(x) = x4 + 2x3 – x2 + 1(2) f : R R, f(x) = x3 + x + 1

(3) f : R R+, f(x) = 2x1(4) f : R R, f(x) = x3 + 2x2 – x + 1

Q.18 ;fn

dx)xsecxtan2xx(tane 2x = ex f(x) + C,

tgk¡ f(0) = 0 gS] rks

4f dk eku cjkcj gS

(tgk¡ C lekdyu fLFkjkad gS)

(1)4

(2) 1 – 4

(3)4

(4)2


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Q.19 If In =

022

2

dx)1x()1nxx(

1x, then the

value of

10

2nnI equals

(1) 8 (2) 12(3) 0 (4) – 8

Q.20 The value(s) of x and y which satisfy theequation

sin2015y = | x3 + x2 – x – 1 | +4xx4x 23

e

+ tan22y + cos4y are(1) x = 1, y = n

(2) x = 1, y = 2n +2

(3) x = – 1, y = 2n(4) x = 1, y = 2n

Q.21 If maximum number of distinct elements in asymmetric matrix of order n be and B beminimum number of zeroes in a triangularmatrix of order n be . If – = 6, then n isequal to

(1) 3 (2) 4(3) 5 (4) 6

Q.22 If in a ABC, if cb1ac1ba1

= 0, then the value

of Ccot

BcotAcot2

22 equals

(1) 2 (2) 3(3) 1 (4) 4

Q.19 ;fn In =

022

2

dx)1x()1nxx(

1xgS] rks

10

2nnI dk eku cjkcj gS

(1) 8 (2) 12(3) 0 (4) – 8

Q.20 lehdj.k

sin2015y = | x3 + x2 – x – 1 | +4xx4x 23

e

+ tan22y + cos4ydks lUrq"V djus okys x rFkk y ds eku gS(1) x = 1, y = n

(2) x = 1, y = 2n +2

(3) x = – 1, y = 2n(4) x = 1, y = 2n

Q.21 n dksfV ds ,d lefer vkO;w g es a fHkUu&fHkUu vo;oks adh vf/kdre la[;k gS rFkk n dksfV ds ,d f=Hkqtkdkj vkO;w g es a 'kw U;ks a dh U;w ure la[;k gSA;fn – = 6 gS] rks n dk eku gS(1) 3 (2) 4

(3) 5 (4) 6

Q.22 ABC es a] ;fn cb1ac1ba1

= 0 gks] rks

Ccot

BcotAcot2

22 dk eku gS

(1) 2 (2) 3

(3) 1 (4) 4


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Q.23 If

1

2

1

2

zz

zz

= 0, then the value of

21

21

zz504z4z2016

equals

(1) 4 (2) 3(3) 2 (4) 1

Q.24 The value of

)108cos72(cos)72cos1()54cos144(sin)54cos72(sin

equals(1) 1 (2) 2

(3) 3 (4) 0

Q.25 If f and g are two functions with g(x) = x – x1

and fog(x) = x3 – 3x

1, then f '(x) is

(1) 3x2 + 3 (2) x2 – 2x

1

(3) 1 + 2x1(4) 3x2 + 4x3

Q.26 If Sn denotes the sum of n terms of an A.P.,

then3n4n

n1n2n3n

SSS2S6S6S2

(1) 1 (2) 2(3) 0 (4) 4

Q.23 ;fn

1

2

1

2

zz

zz

= 0, rks21

21

zz504z4z2016

dk

eku cjkcj gksxk (1) 4 (2) 3(3) 2 (4) 1

Q.24 O;td

)108cos72(cos)72cos1()54cos144(sin)54cos72(sin

dk

eku (1) 1 (2) 2

(3) 0 (4) 4

Q.25 ;fn f rFkk g nks Qyu gS ,oa g(x) = x – x1 rFkk

fog(x) = x3 – 3x

1gS] rks f '(x) cjkcj gS

(1) 3x2 + 3 (2) x2 – 2x

1

(3) 1 + 2x1 (4) 3x2 + 4x3

Q.26 ;fn Sn , fdlh lekUrj Js.kh ds n inks a ds ;ksxQy dks fu:fir djrk gS] rks

3n4n

n1n2n3n

SS

)SS3S3S(2

=

(1) 1 (2) 2(3) 0 (4) 4


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Q.27 The contrapositive of (p q) r is(1) r (p q)(2) ~ r (p q)(3) ~ r ~ p ~ q(4) p (q r)

Q.28 A pole stands vertically inside a triangular parkABC. If the angle of elevation of the top of thepole from each corner of the park is the same,then in ABC the foot of the pole is at(1) centroid (2) circumcentre(3) incentre (4) orthocentre

Q.29 Consider A to be set of all boys in a city. Let Rbe a relation on A such that aRb a liveswithin 1 km from b then

(1) R is reflexive, symmetric but not transitive(2) R is reflexive but not symmetric(3) R is an equivalence relation(4) R is symmetric and transitive but notreflexive

S

Q.30 Let f be twice differentiable function in [a, b],such that f(x) and f "(x) have same sign in[a, b], then

(1) f '(x) = 0 has no real solution [a, b](2) f '(x) = 0 has exactly one real solution in [a,b](3) f '(x) = 0 has atleast one solution in [a, b](4) f '(x) = 0 has atmost one solution in [a, b]

Q.27 (p q) rdk çfr/ku (contrapositive) gS(1) r (p q)(2) ~ r (p q)(3) ~ r ~ p ~ q(4) p (q r)

Q.28 fHkUu&fHkUu yEckbZ dh Hkqtkvks a okys ,d f=Hkqtkdkj ikdZ ABC ds vUnj ,d LrEHk (pole) Å/okZ/kj [kM+ k gSA ikdZ ds çR;sd dksus ls LrEHk ds fljs ds mUu;u dks.k cjkcj gS] rks ABC es a LrEHk dk ikn fuEu es a ls fdl ij gksxk (1) dsUnzd (2) ifjdsUnz(3) vUr%dsUnz (4) yEcdsUnz

Q.29 ekuk A, ,d ns'k es a lHkh yM+dks a dk leqPp; gSAekuk R , A ij ,d lEcU/k bl çdkj gS fd aRb

a, b ls 1 km ds vUnj dh nw jh ij jgrk gS] rks(tgk¡ a, b A)(1) R LorqY;] lefer gS ijUrq laØed ugha gS(2) R LorqY; gS ijUrq lefer ugha gS(3) R rqY;rk lEcU/k gS(4) R lefer rFkk laØed gS ijUrq LorqY; ugha gS

Q.30 ekuk f , vUrjky [a, b] es a f}vodyuh; (twicedifferentiable) Qyu bl çdkj gS fd f(x) rFkk f "(x) ds [a, b] es a leku fpUg gS] rks

(1) f '(x) = 0 dk [a, b] es a dksbZ okLrfod gy ughagS(2) f '(x) = 0 dk [a, b] es a Bhd ,d okLrfod gy gS(3) f '(x) = 0 dk [a, b] de ls de ,d gy gS(4) f '(x) = 0 dk [a, b] es a vf/kdre ,d gy gS


10/33



CHEMISTRY

Q.31 How many following species is / are planarIF5, SF4, I2Cl 6, B2H6, [Cu(NH3)4]

2+ ,

[PtCl4]2– , CrO2Cl2, [Zn(NH3)4]

2+

(1) 2 (2) 3

(3) 4 (4) 5

Q.32 OEtCCHCCH||||

OO

23

COClCH)ii(

EtOH / NaOEt)i(

3

(A)

)ii(

OH / H)i( 2 (B)

The product (B) in the above sequence of reaction is

(1)O

CH – C – CH3

CO Et2

CO Et2

(2)

3

3

COCH|

COOHCHCCH||

O

(3)

O O

CH3H3C

(4)

OCOOH

H3C

Q.31 fuEu es a ls fdruh Lih'kht leryh; gS@gSa

IF5, SF4, I2Cl 6, B2H6, [Cu(NH3)4]2+ ,

[PtCl4]2– , CrO2Cl2, [Zn(NH3)4]

2+

(1) 2 (2) 3

(3) 4 (4) 5

Q.32 OEtCCHCCH||||

OO

23

COClCH)ii(

EtOH / NaOEt)i(

3

(A)

)ii(

OH / H)i( 2 (B)

mi;qZDr vfHkfØ;k Øe es a mRikn (B) gS

(1)

O

CH – C – CH3

CO Et2

CO Et2

(2)

3

3

COCH|

COOHCHCCH||

O

(3)

O O

CH3H3C

(4)

OCOOH

H3C


11/33



Q.33 Identify the incorrect statement with respect tosurface phenomenon:(1) A sol prepared by adding excess AgNO3solution in KI solution, when subjected toelectrophoresis will show coagulation nearcathode.

(2) The conductivity of a soap solutiondecreases steeply at CMC.(3) Tyndall effect will be more prominent in goldsol as compared to rubber sol.(4) Extent of physisorption increases withincrease in temperature initially and thendecreases with temperature.

Q.34 Choose the correct combination of thefollowing statements.(A) Bessemer converter can be used in coppersmelting(B) The Mond's process for nickel involvesreaction of metal with N2 gas(C) Roasted ZnS concentrates can be smeltedin a blast furnace(D) Magnesium can be produced from sea-water by electrolytic process.(1) A and C (2) C and D(3) A, B and D (4) A, C and D

Q.35 Which of the following is not a condensationpolymer?(1) Glyptal (2) Nylon-66(3) Dacron (4) Teflon

Q.33 lrgh ifj?kVuk ds lkis{k xyr dFku igpkfu;s :(1) KI foy;u es a vkf/kD; AgNO3 foy;u feykdj cuk;s x;s lkWy dk tc fo|qr d.k lapyu fd;k tkrk gS rks dSFkksM+ ds fudV LdUnu gksxkA(2) lkcqu ds foy;u dh pkydrk CMC ij rsth ls ?kVrh gSA

(3) jcj lkWy dh vis{kk Lo.kZ lkWy es a fV.My izHkko vf/kd izHkkoh gksxkA(4) rki es a of̀) ds lkFk HkkSfrd vf/k'kks"k.k dh ek=k igys c


12/33



Q.36 A (g) B (g)Rate constant of forward reaction(kf ) = 10

–2 M sec –1

Rate of constant of backward reaction(kb) = 4 × 10

–2 M –1 sec –1

at 300 K.

Find the total pressure in a vessel containingnegligible amount of A(g) and some amount of B(g) at equilibrium. [Given: R = 0.08 litrea t m m o l

–1 K –1]

(1) 12 atm (2) 48 atm(3) 144 atm (4) Data insufficient

Q.37 The element which has least tendency to formnitride is(1) Li (2) Mg(3) Al (4) K

Q.38

H C3 CH3O–CH – CH = CH2 2

major

product.

(1)

H C3 CH3

OH

CH – CH = CH2 2

(2)Me CH3

O – CH = CH – CH3

(3)Me Me

CH – CH = C2 H2

O

(4) None of these

Q.36 A (g) B (g)3 0 0 K ij vxz vfHkfØ;k dk nj fu;rkad (kf ) =10 –2 M sec –1

i'p vfHkfØ;k dk nj fu;rkad (kb) = 4 × 10 –2

M –1 sec –1

lkE; ij A(g) dh ux.; ek=k rFkk B(g) dh dqN

ek=k okys ,d ik= es a dqy nkc Kkr dhft,A[fn;kgS: R = 0.08 litre atm mol –1 K –1](1) 12 atm (2) 48 atm(3) 144 atm (4) vk¡dM+ s vi;kZIr gSA

Q.37 fdl rRo dh ukbVªkbM cukus dh izo`fr lcls de gks rh gS(1) Li (2) Mg(3) Al (4) K

Q.38

H C3 CH3

O–CH – CH = CH2 2

eq[; mRikn

(1)

H C3 CH3

OH

CH – CH = CH2 2

(2)Me CH3

O – CH = CH – CH3

(3)Me Me

CH – CH = C2 H2

O

(4) bues a ls dksbZ ugha


13/33


14/33



Q.44 Glucose reacts with acetic anhydride to form(1) Monoacetate (2) Tetraacetate(3) Pentaacetate (4) Hexaacetate

Q.45 If relative decrease in vapour pressure is 0.5

for a solution containing 1 mol NaCl in 3 molof water, then % ionization of NaCl is :(1) 40 % (2) 60 %(3) 80 % (4) 100 %

Q.46 Choose the correct option :(1) O2 is diamagnetic(2) bond order of CO+ is 2.5(3) at nearly 1000 K, sulphur exist as S2 &paramagnetic(4) NO+ and CO+ both having same bondorder.

Q.47 Which product will not form during thisreaction ?

H

H

H

Zn / OH)ii(

O)i(

2

3

(1)

O|| CHCCH

33

(2)

OO||||

HCCHCCH 23

(3)

O||

HCCHCH 23

(4)

O

H C3

Q.44 Xyw dks l ,lhfVd ,UgkbMªkbM ds lkFk vfHkfØ;k djds cukrk gSA(1) eksuks,lhVsV (2) VsVªk,lhVsV (3) isUVk,lhVsV (4) gSDlk,lhVsV

Q.45 ;fn 3 mol ty es a 1 mol NaCl okys foy;u ds

fy, ok"i nkc es a vkisf{kd deh 0.5 gS] rks NaCl dk % vk;uu gS :(1) 40 % (2) 60 %(3) 80 % (4) 100 %

Q.46 lgh fodYi pqfu;s :(1) O2 izfrpqEcdh; gSA(2) CO+ dk cU/k Øe 2.5 gSA(3) yxHkx 1000 K ij lYQj S2 ds #i es a feyrk gS tks fd vuqpqEcdh; gSA

(4) NO+

rFkk CO+

nksuks a dk cU/k Øe leku gSA

Q.47 bl vfHkfØ;k ds nkSjku dkSulk mRikn ugha cusxkA

H

H

H

Zn / OH)ii(

O)i(

2

3

(1)

O||

CHCCH 33

(2)

OO||||

HCCHCCH 23

(3)

O||

HCCHCH 23

(4)O

H C3


15/33



Q.48 The rate of a certain reaction depends onconcentration (C) according to the equation:

CK1CK

dtdC

2

1

What will be the difference in order of reactionat very low concentration and very highconcentration?(1) 0 (2) 0.5(3) 1 (4) 2

Q.49 Which of the following has the highest meltingpoint?(1) AlF3 (2) AlCl3(3) AlBr3 (4) AlI3

Q.50 Dehydration product of 1,4-diol given below

will be

HOOH||CHCHCHCHCH

18

2223 43POH

(1) (2)

(3) (4)

Q.51 An indicator has a pKa of 7.5. What is the ratioof the concentration of the base form to theconcentration of the acid form, in a buffersolution in which the pH is 6.5 ?

(1)1

10(2)

11

(3)101

(4)5.75.6

Q.48 fdlh fuf'pr vfHkfØ;k dh nj fuEu lehdj.k dsvuqlkj lkUnzrk (C)ij fuHkZj djrh gS :

CK1CK

dtdC

2

1

vfr fuEu lkUnzrk rFkk vfr mPp lkUnzrk ij

vfHkfØ;k dh dksfV es a D;k vUrj gksxk ?(1) 0 (2) 0.5(3) 1 (4) 2

Q.49 fuEu es a ls fdldk xyukad mPpÙke gS?(1) AlF3 (2) AlCl3(3) AlBr3 (4) AlI3

Q.50 uhps fn;s x;s 1,4-MkbZvkWy dk futZyhdj.k mRikn

gksxkA

HOOH||CHCHCHCHCH

18

2223 43POH

(1) (2)

(3) (4)

Q.51 ,d lw pd dk pKa 7.5 gSA cQj foy;u ftles apH 6.5 gS] es a {kkj :i dh lkUnz rk rFkk vEy :i dh lkUnzrk dk vuqikr D;k gS?

(1)1

10(2)

11

(3)101

(4)5.75.6


18/33



Q.56

COOH

COOH

NH2OHH

H

HCl,NaNO2

(1)

COOH

COOH

OHOHH

H

(2)

COOH

COOH

HOHH

HO

(3)

COOH|

OC|CH|COOH

2

(4)

3CH|

OC|COOH

Q.57 Which electronic transition in He ion emitslight of wavelength equal to the longestwavelength emitted in the Paschen seriesof H-atoms?

+

(1) 9 6 (2) 8 6(3) 8 5 (4) 7 3

Q.58 Ammonia can be dried by using(1) CaCl

2

(2) H2

SO4(3) CaO (4) P4O10

Q.56

COOH

COOH

NH2OHH

H

HCl,NaNO2

(1)

COOH

COOH

OHOHH

H

(2)

COOH

COOH

HOHH

HO

(3)

COOH|

OC|CH|COOH

2

(4)

3CH|

OC|COOH

Q.57 He vk;u esa dkSulk bysDVªkWfud laØe.k

H-ijek.kqvks a dh ik'pu Js.kh es a mRlftZr nh?kZÙke rjaxnS/;Z ds cjkcj rjaxnS/;Z dk izdk'k mRlftZr djrk gS?(1) 9 6 (2) 8 6(3) 8 5 (4) 7 3

Q.58 veksfu;k dks fdlds mi;ksx ls lq[kk;k tk ldrk gS

(1) CaCl2 (2) H2SO4(3) CaO (4) P4O10


19/33



Q.59

O

OH 32NaHCO,I

Product.

Major Product is

(1)O O

I

(2)

II

O

OH

(3)

I O

O

(4)

II

O

ONa

Q.60 of H of atomic B is 134.5 Kcal/mol andof H

of atomic F is 118 Kcal/mol. of H of BF3(g)

is – 271.5 Kcal /mol. Average B – F energy

would be(1) 97.7 Kcal / mol (2) 116.6 Kcal / mol(3) 135.4 Kcal / mol (4) 253.3 Kcal / mol

Q.59

O

OH 32NaHCO,I

mRikn

eq[; mRikn gS &

(1) O O

I

(2)

II

O

OH

(3)

I O

O

(4)

II

O

ONa

Q.60 ijek.oh; B dk of H 134.5 Kcal/mol rFkk

ijek.oh; Fdk of H =118 Kcal/mol gSA BF3(g)

dk of H – 271.5 Kcal /mol gS] rks vkS lr B – F

ÅtkZ gksxhA(1) 97.7 Kcal / mol (2) 116.6 Kcal / mol(3) 135.4 Kcal / mol (4) 253.3 Kcal / mol


20/33



PHYSICS

Q.61 For the arrangement shown in figure the timeinterval after which the water jet ceases to crossthe wall. Area of cross section of tank is A andof orifice is a. Hence ( a < < A)

x

H

y

(1)

yx

Hg2

aA 2

(2)

y4x

Hg2

aA 2

(3)

xy4

Hg2

aA 2

(4)

x4y

Hg2

aA 2

Q.61 fp= es a çnf'kZ r O;oLFkk ds fy;s] og le;kUrjky D;k gksxk ftlds i'pkr~ ty /kkjk nhokj ds ikj gksuk :d tkrh gS ? (VS ad dk vuqçLFk dkV {kS=Qy A gS rFkk eq[kfNnz dk vuqizLFk dkV {kS=Qy 'a' gS)Hence ( a < < A)

x

H

y

(1)

yx

Hg2

aA 2

(2)

y4

xH

g

2

a

A 2

(3)

x

y4H

g

2

a

A 2

(4)

x4y

Hg2

aA 2


21/33



Q.62 A small body of superdense material, whosemass is twice the mass of the earth but whosesize is very small compared to the size of earth,starts from rest at a height H


22/33



Q.64 A charge q is placed at the centre of the cavityinside a neutral solid conducting sphere asshown in figure. A negative charge –q is

released from point A. Sphere is fixed andnegative charge is free to move. Given AC = r,here C is the center of the sphere.

(I) Force acting on negative charge is 22

rKq

(II) Negative charge will move along AC line.The correct statement is

qc

A

(1) (I) only (2) (II) only(3) both (I) and (II) (4) both are wrong

Q.65 A closed organ pipe of length L and an openorgan pipe contain gases of densities 1 and2 respectively. The compressibility of gasesare equal in both the pipe. Both the pipes arevibrating in their first overtone with samefrequency. The length of the open organ pipeis

(1)1

2

3L4

(2) 4L / 3

(3)2

1

3L4

(4) L / 3

Q.64 ,d vkos'k q fp= es a n'kkZ;s vuq lkj ,d mnklhu Bks l pkyd xksys ds Hkhrj xqgk ds dsUnz ij j[kk tkrk gSA ,d _.kkos'k –q fcUnq 'A' ls eqDr fd;k tkrk gSA xksyk tfM+ r gS rFkk _.kkos'k xfr ds fy;seqDr gSAfn;k gS : AC = r, ;gk¡ C xksys dk dsUnz gSA

(I) _.kkos'k ij dk;Zjr~ cy 22

rKq

gS

(II) _.kkos'k AC js[kk ds vuqfn'k xfr djsxk lgh dFku gS :

qc

A

(1) ds oy (I) (2) ds oy (II)(3) (I) o (II) nksuks a (4) nksuks a xyr gSa

Q.65 L yEckbZ ds ,d cUn vkWxZu ikbZi rFkk ,d [kqysvkWxZu ikbi es a Øe'k% 1 o 2 ?kuRoks a dh xS ls a Hkjh gSaA nksuks a ikbi es a xS lks a dh lEihM~;rk leku gSAnksuks a ikbi leku vko`fÙk ls muds çFke vf/kLojd es a dEiUu dj jgs gSaA [kqys vkWxZu ikbi dh yEckbZgS:

(1)1

2

3L4

(2) 4L / 3

(3)2

1

3L4

(4) L / 3


23/33



Q.66 In a double slit experiment usingmonochromatic light the fringe pattern shifts bya certain distance on the screen when a micasheet of refractive index 1.6 and thickness 1.964m is introduced in the path of one of the slit.The mica sheet is then removed and the distance

between the slits and the screen is doubled. Itis found that the distance between thesuccessive maxima is now same as theobserved fringe shift upon the introduction of the mica sheet. The wavelength (in Å) of thelight is(1) 4800 (2) 5892(3) 6500 (4) 6728

Q.67 The pitch of a screw gauge is 1 mm and thereare 100 divisions on the circular scale. Whilemeasuring the diameter of wire, the linear scalereads 1mm and 47th division on the circularscale coincide with the reference line. The lengthof wire is 5.6 cm. Find the curved surface area(in cm2) of the wire in appropriate number of significant figures.(1) 2.6 × 10 –5 m2 (2) 2.5 × 10 –5 m2

(3)2.6 × 10 –4 m2 (4) 2.5 × 10 –4 m2

Q.68 Six resistors are connected between A and B

as shown. The equivalent resistance betweenA and B of this network will not depend on thevalue of R, if x is equal to

4 8

5 20R x

BA

(1) 5 ohm (2) 10 ohm(3) 15 ohm (4) 20 ohm

Q.66 f}fLyV ç;ksx ea s ,do.khZ çdk'k ç;qDr djus ij fdlh ,d fLyV ds iFk es a 1.6 viorZukad o 1.964m eksVkbZ dh ,d vHkzd 'khV dks ços'k djkus ij ins Z ij fÝUt çfr:i ,d fuf'pr nw jh ls foLFkkfir gks tkrk gSA fQj vHkzd dh 'khV dks gVkdj fLyVks a o ins Z ds chp nw jh dks nqxquk dj fn;k tkrk gSA ;g

ik;k tkrk gS fd Øekxr mfPpa"B ds chp dh nw jh vc vHkzd 'khV ds ços'k djkus ij çsf{kr fÝUt foLFkkiu ds leku gks tkrh gSA çdk'k dh rjaxnS/;Z (Å es a) gS:(1) 4800 (2) 5892(3) 6500 (4) 6728

Q.67 ,d LØw xSt dk pw M+ h vUrjky 1 mm gS rFkk oÙ̀kh;iSekus ij 100 Hkkx gSaA rkj dk O;kl ekius ij js[kh; iSekuk 1 mm iBu djrk gS rFkk o`Ùkh; iSekusij 47th Hkkx lUnHkZ js[kk ls lEikrh gks rk gSA rkj dh yEckbZ 5.6 cm gSA lkFkZd vadks a dh mfpr la[;k es a rkj dk ofØ; i"̀B {kS=Qy (cm2es a ) Kkr dhft;sA(1) 2.6 × 10 –5 m2 (2) 2.5 × 10 –5 m2

(3)2.6 × 10 –4 m2 (4) 2.5 × 10 –4 m2

Q.68 N% çfrjks/k n'kkZ;s vuqlkj A o B ds chp tqM+ s gSaA x

dk eku fuEu es a ls fdlds cjkcj gksus ij bl usVodZ ds A o Bds chp rqY; çfrjks/k] R ds eku ij fuHkZ j ugha djsxk ?

4 8

5 20R x

BA

(1) 5 ohm (2) 10 ohm(3) 15 ohm (4) 20 ohm


24/33



Q.69 A point object is placed at O at a distance of 15cm in front of a converging lens of focal length10cm. When a concave mirror of focal lengthof 15cm is placed at P co-axially, the final imageis formed at O. It is observed that when theconcave mirror is at Q, then also the final image

is again formed at O (object position). Thedistance PQ is

15cm

OQ P

f = 10cmf = 15cm

(1) 30 cm (2) 15 cm

(3) 10cm (4) data insufficient

Q.70 In the shown figure, a uniform sphere of radius2 metre rolls purely on a plank. Theaccelerations of the centre of sphere and theplank are indicated. The angular acceleration of the sphere is

2m

a = 4m/sz 2 a = 2m/sf 2

(1) 2 rad/s2 Anticlockwise(2) 4 rad/s2 Clockwise(3) 3 rad/s2 Anticlockwise(4) 1 rad/s2 Clockwise

Q.69 ,d fcUnq fcEc 10 cm Qksdl nw jh ds ,d vfHklkjh ySUl ds lkeus 15cmdh nw jh ij O ij j[kk gSA tc15cmQksdl nw jh dk ,d vory niZ.k P ij lek{kh;:i ls j[kk tkrk gS] rks vfUre çfrfcEc O ij curk gSA ;g Hkh ns[kk tkrk gS fd tc vory niZ.k Q ij gks rk gS] rks vfUre çfrfcEc O (fcEc fLFkfr )

ij curk gSA nw jh PQ gS

15cm

OQ P

f = 10cmf = 15cm

(1) 30 cm (2) 15 cm

(3) 10cm (4) vk¡dM+ s vi;kZIr gSa

Q.70 iznf'kZr fp= es a] 2 ehVj f=T;k dk ,d leku xksyk ,d r[rs ij yq


25/33



Q.71 An equimolar mixture of a monoatomic anddiatomic gas is subjected to continuous

expansion such that dQ =31

dU +21

dW. The

equation of the process in terms of the variablepressure P & volume V will be

(1) PV5/4 = constant (2) PV11/8 = constant(3) PV8/3 = constant (4) PV9/4 = constant

Q.72 is the difference between the wavelengthof K line and the minimum wavelength of thecontinuous X-ray spectrum when the X-raytube is operated at a voltage V. If the operating

voltage is changed to3V

, then the above

difference is '. Then

(1) ' < 3 (2) ' = 3(3) ' = 4 (4) ' = 5Q.73 A particle is placed at distance x = a from the

vertex of a thin wire of locus given by x2 = ky(k > 0) as shown in the figure. For the particleto be at rest w.r.t. the wire, the wire is rotatedwith angular velocity about vertical axis y – y'. The value of will be

y

xx=a

y'

(1)kg4

(2)kg2

(3)k2

g3(4)

k2

g

Q.71 ,d ,dijek.kqd o f}ijek.kqd xSl ds leeksyj fe{k.k dks yxkrkj bruk çlkfjr fd;k tkrk gS] fd

dQ =31

dU +21

dW gksA pj nkc P o vk;ru V

ds inks a es a çØe dh lehdj.k gksxh (1) PV5/4 = fu;r (2) PV11/8 = fu;r (3) PV8/3 = fu;r (4) PV9/4 = fu;r

Q.72 K js[kk dh rjaxnS/;Z rFkk lrr~ x- fdj.k LisDVªe dh U;w ure rjaxnS/;Z ds chp vUrj gS tc x-fdj.k ufydk V oksYVrk ij lapkfyr dh tkrh gSA

;fn dk;Zdkjh oksYVrk cnydj 3V

dj nh tk;s, rks

mijksDr vUrj ' gks rk gS] rks(1) ' < 3 (2) ' = 3

(3) ' = 4 (4) ' = 5

Q.73 ,d d.k tks fd fp= es a n'kkZ;s vuqlkj x2 = ky ds:i es a (k > 0) fn;s x;s fcUnqiFk ds ,d irys rkj ds 'kh"kZ ls x = a nw jh ij j[kk tkrk gS] bls rkj ds lkis{k fojke ij cuk;s j[kus ds fy;s rkj dks Å/oZv{k y - y' ds lkis{k '' dks.kh; osx ls ?kqek;k tkrk gS] rks '' dk eku gksxk

y

xx=a

y'

(1)k

g4(2)

k

g2

(3) k2g3

(4) k2

g


26/33



Q.74 A hollow frustum of cone type vessel of heighth has top radius 3r and bottom radius r. Anobject is placed at inner surface of cone asshown. To keep the object at rest w.r.t. vessel,vessel is accelerated with uniform acceleration

îa – a 0

as shown in figure. The value of a0

is equal to6r

a = – a i0 >

2r

(1)

h2

gr(2)

r4

gh

(3)

r22gh (4)

r2gh

Q.75 Two capacitors A and B with capacities 3µFand 2µF are charged to a potential differenceof 2 V and 3 V respectively. The plates of thecapacitors are connected as shown in the figurewith one wire of each capacitor is kept free.The upper plate of A is positive and that of B is

negative. An uncharged 2µF capacitor C withlead wires falls on the free ends to completethe circuit. Calculate the amount of electrostaticenergy left in the system after the completionof the circuit.

2µ F

2µ F3µ F+A

–

B

C

(1) 6.5 J (2) 2.3 J(3) 10 J (4) 5.6 J

Q.74 'kkado çdkj ds ik= ds ,d [kks[kys ÝLVe dh 'kh"kZf=T;k '3r' o vk/kkj f=T;k 'r' gS rFkk bldh Å¡pkbZ'h' gSA oLrq n'kkZ;s vuqlkj 'kadw dh Hkhrjh lrg ij j[kh gSA oLrq dks ik= ds lkis{k fojke ij j[kus dsfy;s fp= es a n'kkZ;s vuqlkj ik= dks ,dleku Roj.k

îa – a0

ls Rofjr fd;k tkrk gSA 'a0

' dk eku gS

6r

a = – a i0 >

2r

(1)

h2

gr(2)

r4

gh

(3) r22gh (4) r2gh

Q.75 3µF o 2µF /kkfjrkvks a okys nks la/kkfj= A o B dksØe'k% 2V o 3V foHkokUrj rd vkosf'kr fd;k tkrk gSA la/kkfj=ks a dh IysVks a dks fp=kuqlkj ,s lstksM+ k tkrk gS fd çR;sd la/kkfj= dk ,d rkj LorU= gksA A dh Åijh IysV /kukRed o B dh Åijh IysV _.kkRed gks rh gSA ,d vukosf'kr 2 µF la/kkfj= C ds yhM rkj ifjiFk dks iw .kZ djus ds fy;seqDr fljks a ij tqM+ tkrs gSaA ifjiFk ds iw .kZ gksus dsi'pkr~ fudk; es a 'ks"k fLFkjoS|qr ÅtkZ dh ek=k dh x.kuk dhft;sA

2µ F

2µ F3µ F+A

–

B

C

(1) 6.5 J (2) 2.3 J(3) 10 J (4) 5.6 J


27/33



Q.76 A capillary tube with very thin walls which isattached to an end of a light rod which is pivotedat its mid point. A mass is suspended throughits other end to keep the rod in horizontalposition. Now the lower end of the capillarytube is just brought in contact with surface of

water. An additional mass 0.157 g is attachedto the other end to keep the rod in horizontalposition. What is the radius of the capillarytube? Surface tension of the water is 0.075 N/ m . ( T a k e g = 1 0 m / s

2). Contact angle betweentube and water is 0º.

(1) 3.3 mm (2) 6.6 mm(3) 9.9 mm (4) 1.1 mm

Q.77 Two bodies of different materials but of equalmass are heated at uniform rate under identicalconditions from 0ºC. One body melts at 60ºC

after heating for 2 minutes while the other meltsat 40ºC after heating for 4 minutes. The ratioof their specific heats is : (Here rate of heatsupplied is kept constant)(1) 1 : 5 (2) 1 : 2(3) 1 : 4 (4) 1 : 3

Q.76 ,d gYdh NM+ tks fd blds e/; fcUnq ij dhyfdr gS] ds ,d fljs ij cgqr iryh nhokjks a okyh ,d ds'kuyh layXu gSA NM+ dks {kSfrt fLFkfr es a cuk;s j[kus ds fy;s blds nw ljs fljs ls ,d nzO;eku yVdk;k tkrk gSA vc ds'kuyh dk fupyk fljk Bhd ty lrg ds lEidZ es a yk;k tkrk gSA NM+ dks

{kSfrt fLFkfr es a cuk;s j[kus ds fy;s nw ljs fljs ij vfrfjDr nzO;eku 0.157 g layXu fd;k tkrk gSAds'kuyh dh f=T;k D;k gS ? ty dk i`"B ruko 0.075 N/m gSA (g = 10 m/s2 yhft;s) A uyh o ty ds chp Li'kZ dks.k 0º gSA

(1) 3.3 mm (2) 6.6 mm(3) 9.9 mm (4) 1.1 mm

Q.77 vyx&vyx inkFkks Z o cjkcj nzO;eku dh nks oLrq;s a0ºC ls ,dleku ifjfLFkfr;ks a ds vUrxZr ,dleku nj ls xeZ dh tkrh gS aA ,d oLrq 2 fefuV xeZ djus

ds i'pkr~ 60ºC ij fi?kyrh gS tcfd nw ljh oLrq4 fefuV xeZ djus ds i'pkr~ 40ºC ij fi?kyrh gS] rks mudh fof'k"V Å"ekvks a dk vuqikr gS : (Hererate of heat supplied is kept constant)(1) 1 : 5 (2) 1 : 2(3) 1 : 4 (4) 1 : 3


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Q.78 A particle of mass 2 kg is subjected to a twodimensional force

F

= ĵy – x2îy2x2 – 2 ; x, y in metersand F in Newton. The particle has kinetic energy

3

8J at point (2, 3). The speed of particle when

it reaches point (1, 2) is(1) 1 m/s (2) 2 m/s(3) 3 m/s (4) none of these

Q.79 M 1 & M2 are two concave mirrors of the samefocal length 10 cm. AB & CD are theirprincipal axes respectively. A point object O iskept on the line AB at distance 15 cm fromM1. The distance between the mirrors is 20cm. Considering two successive reflections firston M1 and then on M2. The distance of finalimage from the line AB is :

15cm

BA3cm

C D

M1M2

(1) 1.5 cm (2) 3 cm(3) 4.5 cm (4) 1 cm

Q.78 2 kg nzO;eku dk ,d d.k ,d f}foeh; cy

F

= ĵy – x2îy2x2 – 2 yx jgk gS ;tgk¡ x, y ehVj es a o F U;w Vu es a gSA d.k dh fcUnq

(2, 3) ij xfrt ÅtkZ38

J gSA fcUnq (1, 2) ij

ig¡qpus ij d.k dh pky gS :(1) 1 m/s (2) 2 m/s(3) 3 m/s (4) bues ls dksbZ ugha

Q.79 10 cm leku Qksdl nw jh ds nks vory niZ.k M1 o M2 gS aA AB o CD Øe'k : muds eq[; v{k gS aA ,d fcUnq fcEc O, M1 ls 15 cm nw jh ij js[kk AB ij j[kk gSA niZ.kks a ds chp nw jh 20 cm gSA nks Øekxr ijkorZuks a igys M1 ij o fQj M2ij fopkj dhft;sA

js[kk AB ls vfUre çfrfcEc dh nw jh gS :

15cm

BA3cm

C D

M1M2

(1) 1.5 cm (2) 3 cm(3) 4.5 cm (4) 1 cm


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Q.80 A non conducting wheel of radius R havingcharge Q, uniformly distributed on the rim of the wheel is free to rotate about a lighthorizontal rod. The rod is suspended by lightinextensible strings and a magnetic field B isapplied as shown in the figure. The initial tension

in the strings are T0. If the breaking tension of the strings are

2T3 0 , find the maxium angular

velocity0 with which the wheel can be rotated.So that string will not break.

d

T0 T0

B

(1) QRBdT0

(2) BQR2

dT20

(3) QRB2dT0

(4) BQR

dT20

Q.81 A particle is projected along a horizontal surfacewhose coefficient of friction varies as µ = A/r2

where r is the distance from the origin in metresand A is a positive constant. The initial positionof the particle is 1m from the origin and itsvelocity is radially outwards. The minimum initialvelocity at this point so that particle never stopsis

(1) (2) gA2

(3) gA2 (4) gA4

Q.80 R f=T;k dk ,d dqpkyd ifg;k ftldh fje ij Q vkos'k ,dleku :i ls forfjr gS, ,d gYdh {kSfrt NM+ ds lkis{k ?kw .kZu ds fy;s eqDr gSA NM+gYdh vfoLrk;Z Mksfj;ks a }kjk vkyfEcr gS rFkk fp= es a n'kkZ;s vuqlkj ,d pqEcdh; {kS= B yxk;k tkrk gSA Mksfj;ks a es a çkjfEHkd ruko T0gSA ;fn Mksfj;ks a dk

Hkatd ruko 2T3 0 gS] rks ifg;k fdl vf/kdre

dks.kh; osx 0 ls ?kqek;k tk ldrk gS rkfd Mks jh VqVs uk ?

d

T0 T0

B

(1) QRBdT0

(2) BQR2

dT2

0

(3) QRB2dT0

(4) BQR

dT20

Q.81 ,d d.k ,d {kSfrt lrg ds vuqfn'k ç{ksfir fd;k tkrk gS ftldk ?k"kZ.k xq.kkad µ = A/r2 ds vuqlkj cnyrk gS tgk¡ r ehVj es a ew y fcUnq ls nw jh gS rFkk A,d /kukRed fu;rkad gSA d.k dh ew y fcUnq lsçkjfEHkd nw jh 1m gS rFkk bldk osx f=T;h; ckgj dh vks j gSA bl fcUnq ij og çkjfEHkd U;w ure osx ftlls fd d.k dHkh ugha :ds] gS

(1) (2) gA2

(3) gA2 (4) gA4


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Q.82 In the given circuit the key is closed at t = 0.The magnetic field energy linked with theinductor at t = loge4 seconds will be

K

L=10H R=4.5

10V r = 0.5

(1) 3J (2) 4J(3) 5J (4) None

Q.83 An ideal diatomic gas with2R5

CV occupies

a volume Vi at pressure Pi. The gas undergoes

a process in which the pressure is proportionalto the volume. At the end of the process, it isfound that the rms speed of the gas moleculeshas doubled from its initial value. The amountof heat that is transferred to the gas is

(1) 3 i i

PV (2) 6 i i

PV

(3) 9 i i

PV (4) Zero

Q.84 A long solenoid having 2000 turns/m is supplied

with current that varies with time according toexpression, A)t120sin(4I . A small co-axial circular coil of 40 turns and radius r = 5cm is located inside the solenoid near its centre.The resistance of coil is 8 . The average rateat which energy is delivered to the small coil is(1) 16.7 mW (2) 88.5 mW(3) 74.6 mW (4) Zero

Q.82 fn;s x;s ifjiFk es a dqath t = 0 ij cUn gSA t = loge4 lSd.M ij çs jd ls lEc) pqEcdh; {kS= ÅtkZgksxh –

K

L=10H R=4.5

10V r = 0.5

(1) 3J (2) 4J(3) 5J (4) dksbZ ugha

Q.832R5

CV okyh ,d vkn'kZ f}ijek.kqd xSl nkc

Pi ij vk;ru Vi ?ks jrh gSA xS l ,d çØe ls xqtjrh gS ftles a nkc] vk;ru ds lekuqikrh gSA çØe dsvUr es a ;g ik;k tkrk gS fd xSlh; v.kqvks a dh oxZek/; ew y pky blds çkjfEHkd eku ls nks xquh gksxbZ gSA xSl dks LFkkukUrfjr dh xbZ Å"ek dh ek=k gS :

(1) 3 i i

PV (2) 6 i i

PV

(3) 9 i i

PV (4) 'kw U;

Q.84 2000 ?ks js /m okyh ,d yEch ifjukfydk dks ,d

/kkjk nh tkrh gS tks le; ds lkFk O;atd A)t120sin(4I ds vuq lkj cnyrh gSA 40 ?ks jks a

o r = 5 cm f=T;k dh ,d NksVh lek{kh; o`Ùkkdkj dq.Myh ifjukfydk ds Hkhrj blds dsUnz ds fudV

fLFkr gSA dq.Myh dk çfrjks/k 8 gSA og vkSlr

nj D;k gS ftlls NksVh dq.Myh dks ÅtkZ nh tkrh gS?(1) 16.7 mW (2) 88.5 mW(3) 74.6 mW (4) 'kw U;


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Q.85 An object of mass M is tied to a string of lengthL and suspended in vertical plane. A variablehorizontal force F is applied on mass so thatthe string finally makes an angle with thevertical. Work done by the force F is :(1) MgL (1 – sin ) (2) MgL

(3) MgL (1 – cos ) (4) MgL (1 + cos )Q.86 The displacement x of a particle in motion is

given as a function of time as x (x – 4) = 1 – 5

cos t then(1) particle execute SHM(2) particle execute oscillatory motion which isnot SHM(3) the motion of particle is not oscillatory(4) the particle is not acted upon by force whenx = 4

Q.87 Each blocks shown in figure has a mass 3 Kg.Each of wire (massless) has cross section0.005 cm2 and Young's modulus 2 × 1011 N/ m2 . Then ratio of longitudinal strain of A tothat of B is

R

P QB

A

(1)41

(2)31

(3)21

(4) 1

Q.85 M nzO;eku dh ,d oLrq L yEckbZ dh ,d Mks jh lsck¡/kk tkrh gS rFkk Å/oZ ry es a yVdk;h tkrh gSAnzO;eku ij ,d ifjorhZ {kSfrt cy F yxk;k tkrk gS ftlls Mks jh vUr es a Å/okZ/kj ls dks.k cukrh gSAcy F }kjk fd;k x;k dk;Z gS :(1) MgL (1 – sin ) (2) MgL

(3) MgL (1 – cos ) (4) MgL (1 + cos )

Q.86 ,d d.k dh xfr dk foLFkkiu x le; ds Qyu ds:i es a x (x – 4) = 1 – 5 cos t }kjk fn;k tkrk gS] rks(1) d.k SHM djrk gS(2) d.k nkSyuh xfr djrk gS tks fd SHM ugha gS(3) d.k dh xfr nkSyuh ugha gks rh gS(4) d.k ij cy dk;Z ugha djrk gS tc x = 4 gS

Q.87 fp= es a n'kkZ;s x;s çR;sd CykWd dk nzO;eku 3 KggSA çR;sd rkj ¼nzO;eku jfgr½ dh vuqçLFk dkV 0.005 cm2 o ;xa xq.kkad 2 × 1011 N/m2 gS] rks Adh vuqnS/;Z fod`fr o B dh vuqnS/;Z fod`fr dk vuqikr gS :

R

P QB

A

(1)41

(2)31

(3)21

(4) 1


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Q.88 With a standard rectangular bar magnet, thetime period of a vibration magnetometer is 4seconds. The bar magnet is cut parallel to itslength into four equal pieces. The time period(in sec.) of the vibration magnetometer whenonly one piece is used is

(1) 16 (2) 8(3) 2 (4) 4

Q.89 A uniform rod AB of mass m and length l is atrest on a smooth horizontal surface. An impulsep is applied to the end B. The time taken bythe rod to turn through a right angle is

(1)Pm2 l

(2)lmp2

(3) p12

ml

(4) lmp12

Q.90 The current through an ideal PN-junctionshown in the following circuit diagram will be

1V 2V

100P N

(1) Zero (2) 1 mA(3) 10 mA (4) 30 mA

Q.88 ,d ekud vk;rkdkj NM+ pqEcd ds lkFk ,d dEiUu pqEcdekih dk vkorZdky 4 lSd.M gSA NM+pqEcd dks bldh yEckbZ ds lekUrj pkj cjkcj Hkkxks a es a dkVk tkrk gSA ds oy ,d Hkkx ç;qDr djusij dEiUu pqEcdekih dk vkorZdky ( lSd.M es a) gS%(1) 16 (2) 8

(3) 2 (4) 4

Q.89 m nzO;eku o l yEckbZ dh ,d le:i NM+ AB ,d fpduh {kSfrt lrg ij fojke ij gSA fljs B ij ,d vkosx P yxk;k tkrk gSA NM+ }kjk 90º ?kw eus es afy;k x;k le; gS :

(1)Pm2 l

(2)lmp2

(3) p12ml

(4)lm p12

Q.90 fuEu ifjiFk fp= es a iznf'kZ r vkn'kZ PN- lfU/k ls/kkjk gksxh &

1V 2V

100P N

(1) 'kw U; (2) 1 mA(3) 10 mA (4) 30 mA


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ROUGH WORK

JEE MAIN MOCK TEST

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