Flare KOD Rev01
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Transcript of Flare KOD Rev01
![Page 1: Flare KOD Rev01](https://reader031.fdocuments.us/reader031/viewer/2022020217/5454ab73b1af9f89308b4930/html5/thumbnails/1.jpg)
Step-1 Plug in required dataStep-2 Assume dia & Length of VesselStep-3Step-4 If Length req > length assumed repeat from Step-2 Step-5 Check Remark
API 521 case is calculated for verification of calculation procedureCase 1,2,3,4 are given as examples, you can plug in your data also
Revision History
Rev. 0 Issued to Downloads section on 5/5/2011
Vary HL such that vol available is >= vol req
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Data required API 521 case Case-1 Case-2 Case-3 Case-4 Case-5Operating press Bara 1.138 1.138 1.138 1.138 1.138Operating temp °C 149 149 149 149 149Mass flow rate of vapour kg/hr 76680 76680 76680 76680 76680Vapour density kg/m3 2.9 2.9 2.9 2.9 2.9Gas viscosity cP 0.01 0.01 0.01 0.01 0.01Mass flow rate of liquid kg/hr 14040 14040 14040 14040 14040Liquid density kg/m3 496.6 496.6 496.6 496.6 496.6Droplet size in micrometer 300 300 300 300 300Miscell draining Vol m3 1.89 1.89 1.89 1.89 1.89Min Liq Hold up time min 30 30 30 30 30
Assume dia & Length of VesselAssume dia of the tank m 2.44 2.29 2.13 1.98 2Assume length of the tank m 5.79 6.25 6.86 7.62 6Total vol m3 27.1 25.7 24.4 23.5 18.8
m 1.4 1.37 1.33 1.28 1.8Required volume m3 2.77 2.56 2.34 2.10 2.67Available volume space m3 2.78 2.57 2.34 2.11 2.98
If Length req > length assumed repeat from Step-2 Length req 5.48 5.95 6.56 7.21 4.27
Remark1 OK OK OK OK OK
mm
Vary HL such that vol available is >= vol reqVary HL1+2 = HL
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** Try to maintain L/D ~ 3
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1 Data requiredOperating press BaraOperating temp °CMass flow rate of vapour kg/hrVapour density kg/m3Gas viscosity cPMass flow rate of liquid kg/hrLiquid density kg/m3Droplet size in micrometerMiscell draining Vol m3Min Liq Hold up time min
m3/s
2
3 Find Drag Coeff from CRe2Eq formed for the graph
4 Based on g, partical dia, gas/liq density & C find UcDrop out vel = UcUc = 1.15*(g*D*(rL-rv)^0.5/(rv*C) m/s
5 Assume dia & Length of VesselAssume dia of the tank mAssume length of the tank m
X sec area A
6 Area occupied in the bottom seg for miscellm
7 Area occupied in the bottom seg for min holdupHold up vol m3
m
8 Balance area is for vapour
9 Heights of the levels
Radius r mmm
mm
Vapour rate Rv
Find C from C(Re)2
C(Re)2= 0.13*10^8*(rv)*(D)^3*(rl-rv)/(m^2)C(Re)2
AL1
AL2
AV
Ht occupied by miscell vol = HL1 + HL2
Area of liq hold up req AL1 + AL2
Vary HL1+2 = HLrf
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mrad
Area of sector m2Area of trianlge m2
m2Vary HL till Area cal = Area req
10 Find liquid drop out time from Hv & Uc
sec
11 Vapour velocity m/s
12 Length req m
Balance ht upto centre r - HL
a angle of one triangle
Area of liq hold up cal = (sector - triangle area)
Vapour space available Hv
f Liquid drop out time Hv/Uc
r-hrf
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API 521 case Case-1 Case-2 Case-3 Case-4 Case-5 0 0
1.138 1.138 1.138 1.138 1.138 0 0 0149 149 149 149 149 0 0 0
76680 76680 76680 76680 76680 0 0 02.9 2.9 2.9 2.9 2.9 0 0 0
0.01 0.01 0.01 0.01 0.01 0 0 014040 14040 14040 14040 14040 0 0 0496.6 496.6 496.6 496.6 496.6 0 0 0300 300 300 300 300 0 0 01.89 1.89 1.89 1.89 1.89 0 0 030 30 30 30 30 0 0 0
7.345 7.345 7.345 7.345 7.345 #DIV/0! #DIV/0! #DIV/0!
5025 5025 5025 5025 5025 #DIV/0! #DIV/0! #DIV/0!
1.24 1.24 1.24 1.24 1.24 #DIV/0! #DIV/0! #DIV/0!
0.730 0.730 0.730 0.730 0.730 #DIV/0! #DIV/0! #DIV/0!
2.44 2.29 2.13 1.98 2 0 0 05.79 6.25 6.86 7.62 6 0 0 0
4.7 4.1 3.6 3.1 3.1 0.0 0.0 0.0
0.33 0.30 0.28 0.25 0.32 #DIV/0! #DIV/0! #DIV/0!
14.14 14.14 14.14 14.14 14.14 #DIV/0! #DIV/0! #DIV/0!2.44 2.26 2.06 1.86 2.36 #DIV/0! #DIV/0! #DIV/0!
1.91 1.55 1.23 0.98 0.47 #DIV/0! #DIV/0! #DIV/0!
2.77 2.56 2.34 2.10 2.67 #DIV/0! #DIV/0! #DIV/0!1.22 1.145 1.065 0.99 1 0 0 01400 1370 1330 1280 1800 0 0 0
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-0.18 -0.225 -0.265 -0.29 -0.8 0 0 01.72 1.77 1.82 1.87 2.50 #DIV/0! #DIV/0! #DIV/0!2.56 2.32 2.07 1.83 2.50 #DIV/0! #DIV/0! #DIV/0!-0.22 -0.25 -0.27 -0.27 -0.48 #DIV/0! #DIV/0! #DIV/0!2.78 2.57 2.34 2.11 2.98 #DIV/0! #DIV/0! #DIV/0!
1.04 0.92 0.8 0.7 0.2 0 0 01.42 1.26 1.10 0.96 0.27 #DIV/0! #DIV/0! #DIV/0!
3.85 4.72 5.99 7.53 15.61 #DIV/0! #DIV/0! #DIV/0!
5.48 5.95 6.56 7.21 4.27 #DIV/0! #DIV/0! #DIV/0!
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0
0000000000
#DIV/0!
#DIV/0!
#DIV/0!
#DIV/0!
00
0.0
#DIV/0!
#DIV/0!#DIV/0!
#DIV/0!
#DIV/0!00
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0#DIV/0!#DIV/0!#DIV/0!#DIV/0!
0#DIV/0!
#DIV/0!
#DIV/0!
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From graph
C(Re)^2 C log(CRe2) log(C )10 60 60 1.00 1.7820 34 34 1.30 1.5330 25 24 1.48 1.4040 20 20 1.60 1.3050 18 17 1.70 1.2660 15 15 1.78 1.18
100 9.5 10.1 2.00 0.98200 6 6.4 2.30 0.78300 4.8 5.0 2.48 0.68400 4 4.2 2.60 0.60500 3.5 3.7 2.70 0.54600 3.2 3.4 2.78 0.51700 3 3.1 2.85 0.48
1000 2.7 2.6 3.00 0.432000 1.9 1.8 3.30 0.284000 1.5 1.4 3.60 0.18
10000 1 1.0 4.00 0.00200000 0.5 0.50 5.30 -0.30
1000000 0.45 0.46 6.00 -0.35
C = 10^(0.0876*(LOG(CRe2))^2 - 1.0357*(LOG(CRe2)) + 2.7271)
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From curve
log(CRe2) log(C )1.00 1.781.30 1.531.48 1.391.60 1.291.70 1.221.78 1.162.00 1.012.30 0.812.48 0.702.60 0.632.70 0.572.78 0.532.85 0.493.00 0.413.30 0.263.60 0.134.00 -0.015.30 -0.306.00 -0.33
y = 0.0876x2 - 1.0357x + 2.7271
0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00
-0.50
0.00
0.50
1.00
1.50
2.00
f(x) = 0.087577169095164 x² − 1.0357465531989 x + 2.72714799744751
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0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00
-0.50
0.00
0.50
1.00
1.50
2.00
f(x) = 0.087577169095164 x² − 1.0357465531989 x + 2.72714799744751