div class=trans-pagebutton class=gotoPage data-page=1Page 1button div class=trans-imageimg data-url=documentdsepp-dse-material-2018-10-26-142-42-k24-k-3-0-and-k3-92-o-82htmlpage=1 data-page=1 class=trans-thumb lazyload alt=Page 1: DSEPP DSE Material · 2018 10 26 · 142 +42 k24 + k 3 = 0 and k3 = 92 = o 82 +122 42 +42 = 0 Solving we have kl = -18 So the equation of the circle is x The slope of the loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAQAAAC1HAwCAAAAC0lEQVR42mM8Uw8AAh0BTZud3BwAAAAASUVORK5CYII= data-src=https:reader033fdocumentsusreader033viewer20220528106081bd1545a564362359e138html5thumbnails1jpg width=140 height=200 divdivdiv class=trans-pagebutton class=gotoPage data-page=2Page 2button div class=trans-imageimg data-url=documentdsepp-dse-material-2018-10-26-142-42-k24-k-3-0-and-k3-92-o-82htmlpage=2 data-page=2 class=trans-thumb lazyload alt=Page 2: DSEPP DSE Material · 2018 10 26 · 142 +42 k24 + k 3 = 0 and k3 = 92 = o 82 +122 42 +42 = 0 Solving we have kl = -18 So the equation of the circle is x The slope of the loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAQAAAC1HAwCAAAAC0lEQVR42mM8Uw8AAh0BTZud3BwAAAAASUVORK5CYII= data-src=https:reader033fdocumentsusreader033viewer20220528106081bd1545a564362359e138html5thumbnails2jpg width=140 height=200 divdivdiv class=trans-pagebutton class=gotoPage data-page=3Page 3button div class=trans-imageimg data-url=documentdsepp-dse-material-2018-10-26-142-42-k24-k-3-0-and-k3-92-o-82htmlpage=3 data-page=3 class=trans-thumb lazyload alt=Page 3: DSEPP DSE Material · 2018 10 26 · 142 +42 k24 + k 3 = 0 and k3 = 92 = o 82 +122 42 +42 = 0 Solving we have kl = -18 So the equation of the circle is x The slope of the loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAQAAAC1HAwCAAAAC0lEQVR42mM8Uw8AAh0BTZud3BwAAAAASUVORK5CYII= data-src=https:reader033fdocumentsusreader033viewer20220528106081bd1545a564362359e138html5thumbnails3jpg width=140 height=200 divdivdiv...