Do Now: Worksheet--Relative Error · 10/10/2013 · Day 8 Literal Equations.notebook 1 October 21,...
Transcript of Do Now: Worksheet--Relative Error · 10/10/2013 · Day 8 Literal Equations.notebook 1 October 21,...
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Day 8 Literal Equations.notebook
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October 21, 2013
Oct 132:21 PM
Monday, October 21, 2013--Day 6
Literal EquationsYWBAT solve an equation (formula) for a specific variable.
HW: Worksheets--Solving Literal Equations AND the bottom of the Do Now sheet
Quiz Thursday--Formulas and Literal Equations
Do Now: Worksheet--Relative Error
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Day 8 Literal Equations.notebook
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October 21, 2013
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Day 8 Literal Equations.notebook
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October 21, 2013
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October 21, 2013
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October 21, 2013
Oct 67:44 PM
Literal Equation--
Examples:
Formula--A type of literal equation that shows a relationship between quantities
Examples:
an equation in which known quantities are expressed with letters
Numerical Equation--an equation in which the known quantities are expressed with numbers.
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October 21, 2013
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When you use a literal equation you may be asked tosolve it for one variable in terms of the others
To do this--pretend that all the other variables except forthe one you are solving for are numbers and proceed as follow the stepsfor solving equations.
Consider:
2x + 5 = 15 Solve for x: ax + b = 3b
Pretend that a and b are numbers and the variable is x.Solve using the steps you used in the numerical equation.
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October 21, 2013
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Practice:
Solve for x:x - a = b
Solve for x: 2ax = 10a2 - 3ax (a≠0) Why do we say that the value of a cannot equal 0?
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October 21, 2013
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Sometimes when you are using a formula you may need to transform it.
For Example:
F=9 C +32 Solve the formula for C. 5
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October 21, 2013
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Solve each of the following formulas for the given variable.
Solve for T: D = R T
Solve for h: V= 1 Bh 3
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October 21, 2013
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Use the formula to solve for the specified variable. Assume no variable is equal to zero. A = P (1 + rt)
a) Solve for P b) Solve for t
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October 21, 2013
Oct 162:21 PM
Use the formula to solve for the specified variable. Assume no variable is equal to zero. K = 1 m v2
a) Solve for m b) Solve for v
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October 21, 2013
Oct 92:55 PM