Determination of No of kanbans

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    Determination of Number of Kanbans

    Bhaskara PI semester PEST

    National Institute of Engineering, Mysore-08

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    SupplyingProcess

    Assemblyprocess

    part

    Production Card

    Finished parts

    Store

    Withdrawal Card

    part

    Kanban Information system

    Kanban (pull) SystemWithdraw/Pull only what is neededReplenish what is withdrawn

    Overall BenefitsPrevents overproductionReduces inventory

    Fig.1. 2 kanban card information system10/22/2013 5:57 AM 2

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    Kanban Information system

    Fig.2. kanban card10/22/2013 5:57 AM 3

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    Process of Kanban sizing

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    Determine the daily demand

    Calculate No. of kanban cards

    or

    quantity per kanban

    Print Kanban

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    Withdrawal Systems

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    Withdrawal system

    Constantquantity,

    non constant cycle

    Constant cycle,

    non constant quantity

    Constant cycle systemforsupplier kanbans

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    Used within the plant

    Shorter lead time

    Improved processes

    where,

    S = safety co efficient (should not be less than 0.1)

    C = container capacity

    D = daily demand

    lead time (days)= Tprocess+Twaiting+Tconveyance+Tkanban collecting

    i). The constant quantity, non-constant cyclewithdrawal system

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    Avg. D X lead time X (1+ S)

    Total No. of kanbansC

    economic lot size+ (D X S)Total No. of kanbansC

    Larger lots

    Smaller lots

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    E.g.: 1. D=100

    lead time=0.5 day

    C=10

    S=0.2

    No. of kanban = [100*0.5*(1+0.2)]/10

    = 6

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    i). The constant quantity, non-constant cyclewithdrawal system.

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    ii). The constant cycle, non-constant quantitywithdrawal system

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    Kanban No. is fixed

    Demand doubles then, only kanban circulation doubles

    Quicker problem identification

    D X (order cycle + lead time + safety period)

    Total No. of kanbans C

    Used within the plantRelatively larger lead time (process/conveyance)

    Order quantity No. of kanban detached by regular collection X C

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    ii). The constant cycle, non-constant quantitywithdrawal system.

    E.g.: 2. D=500

    order cycle= 0.2

    lead time=0.5

    Safety period=0.2

    C=40

    No. of kanban = [500* (0.2+0.5+0.2)]/40

    = 11.25 ~ 12

    Order quantity = 3 * 40

    = 120

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    iii). The constant withdrawal cycle system forSupplier kanbans

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    100 1+ 2Total No. of kanbans [[1]] * 0.2

    5 6

    Total No. of kanbans 14

    D 1+ conveyance intervalTotal No. of kanbans [[No. of days spent for conveyance]] *

    C No. of convey/dayS

    Used forSupplierkanbans

    geographical distance

    longer lead time

    slightly varying quantity

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