Design of Bending Members in Timber. An Example of Timber Beams.

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Design of Bending Members in Design of Bending Members in Timber Timber

Transcript of Design of Bending Members in Timber. An Example of Timber Beams.

Page 1: Design of Bending Members in Timber. An Example of Timber Beams.

Design of Bending Members in TimberDesign of Bending Members in Timber

Page 2: Design of Bending Members in Timber. An Example of Timber Beams.

An Example of Timber Beams

Page 3: Design of Bending Members in Timber. An Example of Timber Beams.

What can go wrong ?What can go wrong ?TIMBER BEAMS:

• Bending failure

• Lateral torsional

buckling

• Shear failure

• Notch failure

• Bearing failure

• Excessive deflections

Page 4: Design of Bending Members in Timber. An Example of Timber Beams.

Bending Strength Bending Strength

Linear elastic stresses

6

sectionsr rectangulafor 2

max

max

bhS

SMS

M

I

My

M

Design Equation:

SFM br Where Fb is the characteristic bending strengthFor timber it is Fb = fb (KDKHKSbKT)

y

Page 5: Design of Bending Members in Timber. An Example of Timber Beams.

Bending failure in Bending failure in compressioncompression

• Only likely for very high grade material

• Benign failure mode

Page 6: Design of Bending Members in Timber. An Example of Timber Beams.

Logging bridge near Pemberton, BC

Glulam I-beam

Page 7: Design of Bending Members in Timber. An Example of Timber Beams.

Bending failure in tensionBending failure in tension

• Most likely failure mode

• Brittle

• Combination of tension and shear, although tension fracture is the initiating mode

Page 8: Design of Bending Members in Timber. An Example of Timber Beams.

Bending capacityBending capacity

Mr = φ Fb S KZb KL

where φ = 0.9

and Fb = fb (KD KH KSb KT )

Lateral torsional buckling

Page 9: Design of Bending Members in Timber. An Example of Timber Beams.
Page 10: Design of Bending Members in Timber. An Example of Timber Beams.

Glulam beams in a Gerber system

Page 11: Design of Bending Members in Timber. An Example of Timber Beams.

Glued-laminated beamsGlued-laminated beams

better laminations

20f-E and 24f-E grades

Page 12: Design of Bending Members in Timber. An Example of Timber Beams.

Glued-laminated beamsGlued-laminated beams

20f-EX and 24f-EX grades

better laminations

Page 13: Design of Bending Members in Timber. An Example of Timber Beams.
Page 14: Design of Bending Members in Timber. An Example of Timber Beams.

Lateral torsional buckling of Lateral torsional buckling of timber beamstimber beams

x

xx

y

y

y

y

Δx

Δyθ

Le

Elastic buckling:Mcr = π / Le √(G J E Iy )

Torsional stiffness

Lateral bending stiffness

Note: The warping stiffness for rectangular shapes is small compared to the torsional and bending stiffness

Page 15: Design of Bending Members in Timber. An Example of Timber Beams.

Lateral torsional buckling of deep I-joists

Page 16: Design of Bending Members in Timber. An Example of Timber Beams.

Capacity of a timber beam subject Capacity of a timber beam subject to lateral torsional bucklingto lateral torsional buckling

Le

Mr

combination of material failure and lateral torsional buckling

Mr = φ Fb S KZb KL

elastic lateral torsional buckling

Mu

material failure

Mr = φ Fb S KZb

Page 17: Design of Bending Members in Timber. An Example of Timber Beams.

Lateral torsional Lateral torsional buckling factor Kbuckling factor KLL KL

1.0

10 30 4020 5000

0.5

practical limit

Slenderness ratio CB = ( Le d / b2 )0.5

KL = 1

CK = ( 0.97 E KSE KT / Fb )0.5

0.67

CB

KL = 1 – 1/3 (CB / CK)4

KL = (0.65 E KSE KT) / (CB2 Fb KX)

Page 18: Design of Bending Members in Timber. An Example of Timber Beams.

Deep glulam beam

Page 19: Design of Bending Members in Timber. An Example of Timber Beams.

Prevention Prevention of lateral of lateral torsional torsional bucklingbuckling

d/bLateral support

at spacing:

< 4 no support

< 5purlins

or tie rods

< 6.5compression

edge held by

decking or joists

< 7.5top edge

plus bridging

< 9 both edges

KKLL = 1.0 = 1.0

when lateral when lateral support is support is

provided as provided as shownshown

d

b

< 610 mm

< 610 mm

< 8d

Page 20: Design of Bending Members in Timber. An Example of Timber Beams.

Bridging for floor joistsBridging for floor joists

Page 21: Design of Bending Members in Timber. An Example of Timber Beams.

Shear stress in a beamShear stress in a beam

Ib

VQ

Ib

VAy

N.A.

y

A

b

τd

τmax = V(0.5A)(d/4) (bd3/12)b=1.5 V/A

Page 22: Design of Bending Members in Timber. An Example of Timber Beams.

Shear in a timber beamShear in a timber beam

Vr = φ Fv 2/3 A KZv

where φ = 0.9

and Fv = fv (KD KH KSv KT ) σv(max) = 1.5 σv(avg)

= 1.5 V / A

σv(max)

σv(avg)

As

Page 23: Design of Bending Members in Timber. An Example of Timber Beams.

UNBC Prince George, BC

Page 24: Design of Bending Members in Timber. An Example of Timber Beams.

Shear failuresShear failures

• One of the very weak properties of wood• Shrinkage cracks often occur at the ends of

beams in the zone of maximum shear stress

• Direct compression transfer of loads in the end zones reduces the total shear force to be carried.

45o

critical section

This part of the load transferred in direct compression

Page 25: Design of Bending Members in Timber. An Example of Timber Beams.

Shear design of glulam beamsShear design of glulam beams

A simple approach for beams where the volume < 2.0 m3:

Vr = φ Fv 2/3 A KN

where φ = 0.9

and Fv = fv (KD KH KSv KT )

KN = notch factor (see next section)

For larger beams this is usually quite conservative and a more sophisticated approach is used (see clause 6.5.7.3)

Page 26: Design of Bending Members in Timber. An Example of Timber Beams.

Notch factor for Glulam beamsNotch factor for Glulam beams

dn

dn

d

e

KN = ( 1 – dn/d )2 For e > d :KN = ( 1 – dn/d )

For e < d :KN = 1 – dne/[d(d – dn)]

Page 27: Design of Bending Members in Timber. An Example of Timber Beams.
Page 28: Design of Bending Members in Timber. An Example of Timber Beams.

Notch effect in Notch effect in sawn lumbersawn lumber

• For notches on the tension side of supports (sawn lumber)

• In new code: Reaction calculation

Fr = Ft A KN

= 0.9

Ft = ft (KD KH KSt KT)

where ft = specified reaction force strength = 0.5 MPa for sawn lumber

KSt = 1.0 for dry and 0.7 for wet service conditions

A = gross cross-section area

KN = notch factor

Area A

NEW !!

Page 29: Design of Bending Members in Timber. An Example of Timber Beams.

Notch factorNotch factorKKNN

ed1

dn

d

dedd

K

n

N

and 1

11

11

6.1006.0

5.0

32

Based on Fracture Mechanics theory

Page 30: Design of Bending Members in Timber. An Example of Timber Beams.

Bearing failure in a timber beamBearing failure in a timber beam

• The “soft” property of wood

• Often governs• Not only compression perpendicular to

grain but also tension of the fibres along edges

tension of fibres along the edges

compression perpendicular to grain

Page 31: Design of Bending Members in Timber. An Example of Timber Beams.
Page 32: Design of Bending Members in Timber. An Example of Timber Beams.
Page 33: Design of Bending Members in Timber. An Example of Timber Beams.

Bearing resistanceBearing resistance

Ab

Qr = Fcp Ab KZcp KB

= 0.8Fcp = fcp (KScp KT)

> 75mmno high bending stress

< 150mm

Bearing factor

Page 34: Design of Bending Members in Timber. An Example of Timber Beams.

Critical bearing areas in woodframe construction

Page 35: Design of Bending Members in Timber. An Example of Timber Beams.

Bearing resistance Bearing resistance (double bearing)(double bearing)

Ab2

Qr = (2/3) Fcp Abavg KZcp KB

= 0.8Fcp = fcp (KD KScp KT)

Ab1 45 deg

Abavg= 0.5(Ab1 +Ab2) but ≤ 1.5 Ab1

Page 36: Design of Bending Members in Timber. An Example of Timber Beams.

Bearing factor KBearing factor KBB

Bearing length or diameter (mm)

Bearing factor KB

< 12.5 1.75

25 1.38

38 1.25

50 1.19

75 1.13

100 1.10

> 150 1.0

Page 37: Design of Bending Members in Timber. An Example of Timber Beams.
Page 38: Design of Bending Members in Timber. An Example of Timber Beams.

DeflectionsDeflections• A serviceability criterion

– Avoid damage to cladding etc. (Δ ≤ L/180)– Avoid vibrations (Δ ≤ L/360)– Aesthetics (Δ ≤ L/240)

• Use unfactored loads

• Typically not part of the code

Δ