Computer applications in civil engineering lab

SHRI RAWATPURA SARKAR INSTITUTE OF TECHNOLOGY,NEW RAIPUR (C.G.)

Computer Applications in Civil Engineering Lab

CIVIL/6th/CACP Lab/Prepared by Vivek Kumar Sinha


Experiment-1

Aim :A C++ program to determine the distribution of flow in a pipe network using Hardy Cross .

#include<iostream.h>

#include<conio.h>

#include<math.h>

void main()

{

clrscr();

int x,L,P,C,i;

float Q,D[50],f[50],F[50],V[50],Sh,Rh,H1,H2,h1,h2,j,J,Fl,fr,FL,B,k,b,H;

cout<<"determination of supply head and residual head of pipe flow \n\n";

cout<<"enter the total length of pipe in mtr.(multiplication of 500)\n\n";

cin>>L;

P=(L/500)-1;

cout<<"total no.of joint of pipe required of 500 mtr.length is ="<<P<<"\n\n";

C=P+1;

cout<<"total no.of changed dia.pipe is ="<<C<<"\n\n";

cout<<"enter the pipe discharge in m3/s \n\n";

cin>>Q;

for(i=1;i<=C;i++)

{

cout<<"enter the value of dia.of "<<i<<" section \n\n";

cin>>D[i];

V[i]=(Q*4)/(3.14*pow(D[i],2));

}

cout<<"calculation of enlargement and contraction losse \n\n";



H1=0;

H2=0;

for(i=1;i<C;i++)

{

if(D[i]<D[i+1])

{

cout<<"loss due to enlargement occur\n\n";

h1=(pow((V[i]-V[i+1]),2))/(2*9.81);

H1=H1+h1;

cout<<"total loss due to enlargement in mtr.is ="<<H1<<"\n\n";

}

else

{

cout<<"loss due to contraction occur\n\n";

h2=(0.5*pow(V[i+1],2))/(2*9.81);

H2=H2+h2;

cout<<"total loss due to contraction in mtr.is ="<<H2<<"\n\n";

}

}

cout<<"calculation of joint loss\n\n";

J=0;

for(i=1;i<=P;i++)

{

cout<<"enter the value of coefficient k \n\n";

cin>>k;

j=(k*pow(V[i+1],2))/(2*9.81);



J=J+j;

}

cout<<"total joint loss in mtr.is ="<<J<<"\n\n";

cout<<"calculation of bend loss\n\n";

B=0;

for(i=1;i<=P;i++)

{

cout<<"enter the value of coefficient k \n\n";

cin>>k;

b=(k*pow(V[i+1],2))/(2*9.81);

B=B+b;

}

cout<<"total bend loss in mtr.is ="<<B<<"\n\n";

cout<<"calculation of friction loss\n\n";

FL=0;

for(i=1;i<=C;i++)

{

cout<<"enter the value of friction coefficient f \n\n";

cin>>fr;

Fl=(fr*500*V[i]*V[i])/(2*9.81*D[i]);

FL=FL+Fl;

}

cout<<"total friction loss in mtr.is ="<<FL<<"\n\n";

H=H1+H2+J+B+FL;

cout<<"total head loss in mtr.="<<H<<"\n";

cout<<"Press 1 for Residual head of Reservoir \n";

cout<<"Press 2 for Supply head of Reservoir\n";



cin>>x;

switch(x)

{ case 1:

cout<<"enter the supply head of reservoir in mtr.\n";

cin>>Sh;

Rh=Sh-H;

cout<<"The Residual head of Reservoir in mtr.is="<<Rh<<"\n";

break;

case 2:

cout<<"enter the residual head of reservoir in mtr.\n";

cin>>Rh;

Sh=Rh+H;

cout<<"The Supply head of Reservoir in mtr.is="<<Sh<<"\n";

}

getch();

}



Experiment-2

Aim: : A C++ program for the computation of friction factor of a circular pipe.


#include<conio.h>

#include<math.h>

fric()

{

char cho;

do

{

clrscr();

double d,v,k,kr,f=0,re;

int ch;

cout<<"\t\t A programe for friction coefficient\n";

cout<<"\nEnter the diameter of pipe in m \n";

cin>>d;

cout<<"\nEnter the velocity of pipe in m/s\n";

cin>>v;

cout<<"\nEnter the kinematic viscosity in stokes\n";

cin>>k;

k=k*.0001;

re=(v*d)/k;

cout<<"\nReynold no is "<<re<<"\n";

if(re<2000)



{

f=64/re;

cout<<"\nFlow is laminar\n";

cout<<"\nValue of friction cofficient f = "<<f;

}

else if(re>4000)

{

cout<<"\n1 for smooth pipe\n2 for rough pipe\n";

cin>>ch;

switch(ch)

{

case 1:

if(4000<re && re<100000)

{

f=(.316/(pow(re,.25)));

cout<<"\nFlow is turbulent\n";


}

else if(re>100000 && re<400000)

{

f=.0032+(.221/(pow(re,.237)));



}

break;



case 2:

f=(1/(pow((2*log10(re/k)+1.74),2)));



break;

}

}

else

cout<<"\nFlow is transition\n";

cout<<"\n\n\n\t\t Do you want to continue\n";

cin>>cho;

}while(cho=='y' || cho=='Y');

return 0;

}

void main()

{

fric();

getch();

}



Experiment -3

Aim: A C++ program for network analysis and determination of critical path of a CPM network

// A PROGRAM FOR CPM NETWORK ANALYSIS //


#include<conio.h>

#include<iomanip.h>

void main()

{

//input data

int i,j,evn,act,H[20],T[20],TL[20];

float t[20];

clrscr();

cout<<"Enter the no. of events";

cin>>evn;

cout<<"\nEnter the no. of activities in network";

cin>>act;

for(i=1;i<=act;i++)

{

cout<<"\nEnter the tail event of activity no. "<<i<<" ";

cin>>T[i];

cout<<"\nEnter the head event of activity no. "<<i<<" ";

cin>>H[i];

cout<<"\nEnter the duration of activity no. "<<i<<" ";

cin>>t[i];



}

float TE[20],temp;

int count;

TE[1]=0;

for(i=2;i<=evn;i++)

{

count=1;

for(j=1;j<=act;j++)

{

if(H[j]==i)

{

TE[i]=TE[T[j]]+t[j];

if(count==1)

{

temp=TE[i];

count++;

}

else if(TE[i]>temp)

temp=TE[i];

}

}

TE[i]=temp;

}

//computation of latest event time

TL[evn]=TE[evn];



for(i=evn-1;i>=1;i--)

{

count=1;

for(j=1;j<=act;j++)

{

if(T[j]==i)

{

TL[i]=TL[H[j]]-t[j];

if(count==1)

{

temp=TL[i];

count++;

}

else if(TL[i]<temp)

{

temp=TL[i];

}

}

}

TL[i]=temp;

}

//computation of float

float TF[20],FF[20],INTF[20],INDF[20];

for(i=1;i<=act;i++)

{



TF[i]=TL[H[i]]-TE[T[i]]-t[i];

FF[i]=TE[H[i]]-TE[T[i]]-t[i];

INDF[i]=TE[H[i]]-TL[T[i]]-t[i];

INTF[i]=TF[i]-FF[i];

}

//output

cout<<"Event time:-\n";

cout<<"EVENT"<<setw(4)<<"TE"<<setw(4)<<"TL";

for(i=1;i<=evn;i++)

{

cout<<endl;

cout<<setw(3)<<i<<setw(6)<<TE[i]<<setw(4)<<TL[i];

}

cout<<endl<<endl<<"ACTIVITY TIME & FLOAT VALUE:-"<<endl<<endl;

cout<<"ACTIVITY"<<setw(10)<<"DURATION"<<setw(4)<<"TF"<<setw(4)<<"FF"<<setw(6)<<"INDF"<<setw(6)<<"TNTF";

for(j=1;j<=act;j++)

{

cout<<endl;

cout<<setw(3)<<T[j]<<"-"<<H[j]<<setw(9)<<t[j]<<setw(8)<<TF[j]<<setw(4)<<FF[j]<<setw(5)<<INDF[j]<<setw(6)<<INTF[j]<<endl;

}

//determination of critical path

count=1;

for(i=1;i<=act;i++)



{

if(TF[i]==0)

{

if(count==1)

{

cout<<T[i]<<"-"<<H[i];

count++;

}

else

cout<<"-"<<H[i];} }getch();}



Experiment-4

A C++ program for determination of vertical effective stress at a given depth for any soil profile and water table conditions

UNIT 3// A program for determination of effective stress //


#include<conio.h>

void main()

{

int n;

float Dw,thk[10],ysat[10],y[10];

int i;

float depth=0,q;

clrscr();

cout<<"\n Enter the number oflayers in the soil mass";

cin>>n;

for(i=1;i<=n;i++)

{

cout<<"\nEnter the effective depth of"<<i<<"th layer (m)";

cin>>thk[i];

}

cout<<"\n Enter the depth of water table below ground below (m)";

cin>>Dw;



cout<<"\n Enter the surcharge load acting on ground surface (KN/m2)";

cin>>q;

for(i=1;i<=n;i++)

{

depth+=thk[i];

if(depth-thk[i]>=Dw)

{

cout<<"\n Enter the saturated unit weight of"<<i<<"th soil layer (kN/m3)";

cin>>ysat[i];

y[i]=0;

}

else

{

if(depth<=Dw)

{

cout<<"\n Enter the bulk unit weight of"<<i<<"th soil layer(kN/m3)";

cin>>y[i];

ysat[i]=0;

}

else

{

cout<<"\n Enter the bulk weight of"<<i<<"th soil (kN/m3)";

cin>>y[i];

cout<<"\n Enter the saturated unit weight of"<<i<<"th soil layer(kN/m3)";

cin>>ysat[i];



}

}

}

//computation of effective stress

float h, stress;

int npts;

cout<<"\n Enter the number of points at which effective stress is to be calculated";

cin>>npts;

for(i=1;i<=npts;i++)

{

cout<<"\n Enter the"<<i<<"th depth at which effective stress is to be calculated";

cin>>h;

float depth=0,stress=0;

for(i=1;i<=n;i++)

{

depth=depth+thk[i];

if(h>=depth)

{

if(Dw<depth && Dw>depth-thk[i])

stress= stress+y[i]*(Dw-depth-thk[i])+ysat[i]*(depth-Dw)-9.81*(depth-Dw);

if(Dw>=depth)

stress+=y[i]*thk[i];

if(Dw<=depth-thk[i])



stress+=ysat[i]*thk[i]-9.81*thk[i];

}

if(h<depth && depth-h<thk[i])

{

if(Dw<depth && Dw>depth-thk[i])

{

if(Dw>=h)

stress+=y[i]*(h-depth+thk[i]);

else

stress+=y[i]*(Dw-depth+thk[i])+ysat[i]*(h-Dw)-9.81*(h-Dw);

}

if(Dw>=depth)

stress+=y[i]*(h-depth+thk[i]);

if(Dw<=depth-thk[i])

stress+=ysat[i]*(h-depth+thk[i])-9.81*(h-depth+thk[i]);

}

}

cout<<"\n Effective stress at"<<i<<"th point (kN/m2):"<<stress+q;

}

getch();

}



Experiment-5

Aim: C++ program for determination of bearing capacity of soil for given soil and water table conditions.

// A PROGRAM FOR THE DETERMINATION OF ULTIMATE BEARING CAPACITY OF SOIL //


#include<conio.h>

void main()

{

clrscr();

float yav,q,Zw1,ysat,Zw2,Rw1,Rw2,Df,B,c,y,Dw,Nc,Nq,Ny;

cout<<"\n Enter the depth of ebedent of footing(m)";

cin>>Df;

cout<<"\n Enter the width of footing(m)";

cin>>B;

cout<<"\n Enter the effective cohesion of soil(Kn/sqm)";

cin>>c;

cout<<"\n Enter the unit weight of soil(Kn/cum)";

cin>>y;

cout<<"\n Enter the saturated unit weight of soil(Kn/cum)";

cin>>ysat;

cout<<"\n Enter the depth of water table";

cin>>Dw;

cout<<"\n Enter the bearing capacity factor \n Nc ";

cin>>Nc;



cout<<"\n Nq ";

cin>>Nq;

cout<<"\n Ny ";

cin>>Ny;

Zw1=Dw;

if(Zw1<Df || Zw1==Df)

{

Rw1=.5*(1+(Zw1/Df));

}

else

{

Rw1=1;

}

Zw2=Dw-Df;

if(Zw2<B || Zw2==B)

{

if(Zw2>0)

{

Rw2=.5*(1+(Zw2/B));

yav=((y*Zw2)+(ysat*(B-Zw2)))/B;

}

else

{

Zw2=0;

Rw2=.5*(1+(Zw2/B));



yav=ysat;

}

}

else

{

Rw2=1;

yav=y;

}

if(Dw<Df && Dw!=0)

{

y=((y*Dw)+(ysat*(Df-Dw)))/(Dw+(Df-Dw));

}

else if(Dw==0)

{

y=ysat;

}

else

{

y=y;

}

q=(c*Nc)+(y*Df*Nq*Rw1)+(.5*B*yav*Ny*Rw2);

cout<<"Bearing capacity of soil is= "<<q<<"kN/sqm";

getch();

}



Experiment-6

A C++ program for determination of horizontal and vertical hydraulic conductivities for flow through

anisotropic soils.

A PROGRAM FOR DETERMINATION OF RL OF POINTS BY HI METHOD //


#include<conio.h>

#include<math.h>

void main()

{

int no_s,n_tp,i,j,st_tp[20];

float RL[20],BS,FS,IS,HI;

cout<<"\n Enter the no. of station";

cin>>no_s;

cout<<"\n Enter the no. of turning point";

cin>>n_tp;

for(i=1;i<=n_tp;i++)

{

cout<<"\n Enter the station no of "<<i<<" turning point";

cin>>st_tp[i];

}

for(i=1;i<=no_s;i++)

{

if(i==1)



{

cout<<"\n Enter the RL of the BM";

cin>>RL[i];

cout<<"\n Enter the BS at station no."<<i<<" : ";

cin>>BS;

HI=RL[i]+BS;

}

if(i!=1 && i!=no_s)

{

for(j=1;j<=n_tp;j++)

{

if(i==st_tp[j])

{

cout<<"\n Enter the FS at station no. "<<i<<" : ";

cin>>FS;

RL[i]=HI-FS;

cout<<"\n Enter the BS at station no. "<<i<<" : ";

cin>>BS;

HI=RL[i]-BS;

goto end;

}

}

cout<<"\n Enter the IS at station no. "<<i<<" : ";

cin>>IS;

RL[i]=HI-IS;



}

if(i==no_s)

{

cout<<"\n Enter the FS at station no. "<<i<<" : ";

cin>>FS;

RL[i]=HI-FS;

}

end:

}

for(i=1;i<=no_s;i++)

{

cout<<"\nRL of "<<i<<"POINT = "<<RL[i];

}

getch();

}



Experiment-7

A C++ program for computation of SF & BM at any desired section of a simply supported beam for any .

loading conditions. UNIT 4 SF AND BM


#include<conio.h>

#include<math.h>

void main()

{

float w[20],x[20],l,RA,RB,p,t,BM;

int n,i;

clrscr();

cout<<"\t\t ****SHEAR FORCE AND BENDING MOMENT****\n\n");

cout<<"Length of Beam l= "<<"\n\t";

cin>>l;

cout<<"\n\tEnter the no.of points loads n ="<<"\n\t";

cin>>n;

for(i=1;i<=n;i++)

{

cout<<"\n\tEnter the value of loads w= "<<"\n";

cout<<"\t";

cin>>w[i];

}



for(i=1;i<=n;i++)

{

cout<<"\n\tEnter the positions of loads from A x= "<<"\n";

cout<<"\t";

cin>>x[i];

}

p=0;

for(i=1;i<=n;i++)

{

p=p+w[i];

}

cout<<"\tTotal magnitude of loads = "<<p<<"\n";

t=0;

for(i=1;i<=n;i++)

{

t=t+(w[i]*x[i]);

}

RB=t/l;

RA=p-RB;

for(i=1;i<=n;i++)

{

if(i==1)

{

BM=(RA*x[i]);



}

else

{

for(int j=1;j<=i-1;j++)

{

if(j==1)

{

BM=(RA*x[i])-(w[j]*(x[i]-x[j]));

}

else

{

BM=BM-(w[j]*(x[i]-x[j]));

}

}

}

cout<<"\n\tBending Moments at "<<" point"<<i<< "="<<BM<<"Kn-M \n";

}

cout<<"\tS.F. at A (RA) =";

cout<<RA<<"\n";

cout<<"\tS.F. at B (RB) =";

cout<<RB;

}

getch();

}



Experiment -8

A C++ program for design of simply supported RCC beam


#include<conio.h>

#include<math.h>

void main()

{

clrscr ();

float Q,b,S,Z,n,R,s,P,x,m,y,N,temp;

cout<<"enter discharge in m^3/s = ";

cin>>Q;

cout<<"\nenter bed width in m = " ;

cin>>b;

cout<<"\nenter bed slope in decimal = ";

cin>>S;

cout<<"\n enter mannings constant = ";

cin>>N;

cout<<" \n side slope vertical = ";

cin>>m;

for(y=0;y<20;y=y+.01)

{ R=((b+m*y)*y)/(b+2*y*pow((m*m+1),.5));

Z=pow(R,.667)*(b+m*y)*y;

temp=(Q*N)/pow(S,.5);



x=Z-temp;

if(x<=.01)

P=y;}

cout<<" normal depth of trapozoidal = " <<P <<" m ";

getch();}



Experiment-9

Aim: A C++ program for design of RCC column. #include<iostream.h>

#include<conio.h>

#include<math.h>

void main()

{

clrscr ();

float p,w,Xcc,Xsc,d,Ast,Ag,Ab;

int i,b,n,j,D;

cout<<"enter the load on column in KN ";

cin>>w;

cout<<"\nenter the permissible strees in steel N/sqmm ";

cin>>Xsc;

cout<<"\nenter the permissible strees in concrete N/sqmm";

cin>>Xcc;

cout<<"enter the percentage of steel";

cin>>p;

cout<<" %";

p=p/100;

Ag=(w*1000)/((Xcc*(1-p))+(p*Xsc));

Ast=p*Ag;

b=pow(Ag,.5);

cout<<"\narea of steel = "<<Ast<<" mm^2\n";



cout<<"\nenter dia of main bar in mm\n";

cin>>D;

Ab=(3.14*D*D)/4;

n=Ast/Ab;

cout<<"\nenter the dia of tie bar in mm";

cin>>d;

cout<<"\ngroosse area of col. = "<<Ag<<" mm^2\n";

cout<<"\nreq. width of col.= "<<b<<" mm ";

i=(b%50);b=b-i;if(i==0)b=b;

else

{b=b+50;}cout<<" say= "<<b<<" mm";

cout<<"\ndia of main bar in mm = "<<D<<"\n" ;

cout<<"\nreq no. of main bar = "<<n+1<<"\n";

cout<<"\ndia of tie of main bar= "<<d<<" mm\n ";

if(b<(16*d)&&(b<48*d))

j=b;

else if((16*d)<(48*d))

j=(16*D);

else

j=(48*d);cout<<"spacing of tie bar = "<<j;

i=(j%10);j=j-i;cout<<" say= "<<j<<" mm c\c";

getch();}


Computer applications in civil engineering lab

Engineering

Transcript of Computer applications in civil engineering lab