Complex functions C – Integration
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Transcript of Complex functions C – Integration
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1.6 Contour integration
(pp. 61-79; 86-88)
NotationA line in the complex plane can be
smooth
piecewise smooth
closed
* simple closed * not simple
closed
A contour is asimple closed curve with
apositive (counterclockwise) orientation.
Contour deformation: The process used
to remove singularities from inside acontour.
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A
B
A
B
A
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1.6.1 Contour integrals
If Cis a piecewise smooth curve in the
complex plane withz x jy= +
and
( ) ( ; ) ( ; )f z u x y jv x y= + , we use
( ) [ ( , ) ( , )]( C C
f z dz u x y jv x y dx jd= + +
The integral is called a complex lineintegral.
Example 1
Evaluate
2( 3 )C
z z dz+along Cwhere Cis
the curve shown in
the sketch.
1.6.2 Cauchys theoremIff(z) is an analytic function withderivativef'(z) that is continuous at all
2
2
2 + 2j2
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points inside and on a simple closed
curve C, then
( ) 0C
f z dz= No singularities in C!The integral is called a contour integral.
Example 2
Evaluatez
C
e dz
where Cis the curve in the sketch.
Example 3
Evaluate
2 5 6C
dz
z z +
where Cis the unit circle.
Cauchy integral theorem: p. 69USE PARTIAL FRACTIONS!Letf(z) be analytic within and on a
simple closed curve C. Then
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0
0
( )2 ( )
C
f zdz j f z
z z
=
0 0( ) ( )2 ( )C
f z dz z z jf z = forz0a simple pole and
( )
( )
01
0
( ) 2( )!
n
n
C
f z jdz f z nz z
+ =.
1 ( )
0 0( ) ( ) 2 ( )n n
Cf z dz z z jf z+ =
forz0a pole of ordern + 1.Example 4
Evaluate
2
z
C
edz
zfor each of the following contours.
a) Cis any contour enclosingz= 2
b) Cis any contour excludingz= 2
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Example 5
Evaluate
2(2 1)( 2)C
zdzz z +
for the given contourC.
a) C:1z =
b) C: 3z =Example 6
Evaluate3
3
(2 1)C
z zdz
z
+
+
where Cis the unit circle.
Example 7
Evaluate
2
4
( 1)( 2)C
z
dzz z + where Cis the curve
3z =
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1.6.4 The residue theorem: p. 73DONT USE PARTIAL FRACTIONS!
Iff(z) is an analytic function within andon a simple closed curve C, apart from a
finite number of poles, then
( )C
f z dz= 2j[sum of residues off(z) at the
poles inside C]Example 8
Evaluate
2( 1) ( 3)C
dz
z z where Cis the circle 2z =
Example 9
Evaluate
22 6
4C
z dzz
++
C:2z j =
.
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Example 10
Evaluate
2( 1) ( 3)C
dzz z
for each contourC.
a) C:
1
2z =
b) C:2z =
Example 11
Evaluate
3( 1) ( 1)( 2)C
dz
z z z+ where Cis the rectangle with vertices
jand 3 j .
1.6.5 Evaluation of definite real
integralsType 1: Infinite real
integrals
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- R - R
x
y
O
C
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-Cconsists of the real axis between R
andR, and the semicircle in the upper
half of the complex plane.
- In calculationsR is chosen to include
all poles in the upper half plane.
Example 12
Evaluate
2 2( 1)( 9
dx
x x
+ + using contour integration.Example 13
Evaluate
4,
1
dxx
x
+
Example 14
Evaluate
2 2 20 ( 1)( 4)
dx
x x
+ +
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Type 2: Integrals of trig. functions
Suppose (sin , cos )G G = is a function
containing sin and cos . To evaluate2
0Gd
, let , 0 2 .jz e =
Thus,
j
j
dz dz
dz je d d je jz
= = = .Furthermore, p.30
( ) ( )11 1
cos
2 2
j j
Ze e z = + = +
and
( ) ( )11 1
sin2 2
j j
Ze e z
j j
= =
Substitute these expressions and then2
0( )
C
Gd f z dz
=
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where Cis the unit circle.
Example 15Using contour integration, evaluate
2 cosC
d
+
Example 16
Show that
22 cosC
d
=
Work through every example from p 61
up to and including p 79. Then do the
exercises on p 71 (#53(b), 54(b), 56, 57,
58, 59), p 78 79 (#60 65) and pp 87 88 (#7, 8, 11 16,19 24).
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