Complex Functions Limit and Continuity
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Transcript of Complex Functions Limit and Continuity
Complex FunctionsLimit and Continuity
Mohammed Nasser Acknowledgement:
Steve Cunningham
Statistical Concepts/Techniques
Concepts in Vector space
Variance Length of a vector, Qd. forms
Covariance Dot product of two vectors
Correlation Angle bt.two vectors
Regression and Classification
Mapping bt two vector sp.
PCA/LDA/CCA Orthogonal/oblique projection on lower dim.
Relation between MM (ML) and Vector space
Math
ematical C
on
cepts
Mathematical Concepts
Covariance
Variance
Z
Basis
3f
2f
1f
0
f
Set of f1, f2, …, fn is linearly independent if α1 f1+ α2 f2 + …+ αn fn = 0 ,Holds only if each αi =0.Finite dimensional if there exist maximum n linearly independent elements ; Otherwise it is infinite-dimensionalBasis: can express every f in in the form
f = α1 f1+ α2 f2 + …+ αn fn
Linear manifold: αf1+βf2 in
Basis ( Continued)
Mathematical Concepts
Covariance
Variance
Some Vector Concepts
• Dot product = scalar
ii
iT yxyxyxyx
y
y
y
xxx
3
1332211
3
2
1
321yx
|| x || = (x12+ x2
2 + x32 )1/2
Inner product of a vector with itself = (vector length)2
xT x =x12+ x2
2 +x32 = (|| x
||)2
x1
x2 ||x||
Right-angle triangle
Pythagoras’ theorem
• Length of a vector
1
21 2
1
...n
Tn i i
i
n
y
yx x x xy
y
x y
|| x || = (x1
2+ x22)1/2
x1
x2
2 1
2 1
1 1 2 2
sin cos
sin cos
cos cos( ) cos cos sin sin
x ycos
x y cos
T
T
y yy y
x xx x
yx yx
x y
x y
x y
• Angle between two vectors
Orthogonal vectors: xT y = 0
x
y
=/2
||x||||y||
y2
y1
x
Some Vector Concepts
1
21 2
1
...n
Tn i i
i
n
y
yx x x xy
y
x y
Dot Product in Rn
; n nf R R R
XTy=yTx(aX+bZ)Ty=aXTY+bZTY
XTX=0 ↔ X=0
Real Inner product space
Inner product space: A vector space X over the reals R is an inner product space if and only if there exists a real-valued symmetric bilinear (linear in each argument)
map (.,.), that satisfies:
< , >: X X→R
1) <x,y>=<y,x>
2) <x,x>.≥0, and <x, x>=0↔ x=0
3) <x+z,y>=<x,y>+<z,y>
4) <kx,y>=k<x,y>
Show that R is itself an inner product space with inner product <x1,x2>=x1 x2
Complex Inner product space
Inner product space: A vector space X over the
reals C is an inner product space if and only if there
exists a real-valued symmetric bilinear (linear in
each argument) map (.,.), that satisfies:
< , >: X X→C
1) <x,y>=<y,x>
2) <x,x>.≥0, and <x, x>=0↔ x=0
3) <x+z,y>=<x,y>+<z,y>
4) <kx,y>=k<x,y>
Show that C/Z is itself an inner product space with inner product <z1,z2>=z1 z2
A vector space V on which an inner product is defined is called an inner product space.Any function on a vector space that satisfies the axioms of an inner product defines an inner product on the space. .
There can be many inner products on a given vector space
Inner product Space
Example 2Let u = (x1, x2), v = (y1, y2), and w = (z1, z2) be arbitrary vectors in R2. Prove that<u, v>, defined as follows, is an inner product on R2.
<u, v>= x1y1 + 4x2y2
Determine the inner product of the vectors (2, 5), (3, 1) under this inner product.Solution
Axiom 1:<u, v>= x1y1 + 4x2y2 = y1x1 + 4y2x2 =<v, u>
Axiom 2:<u + v, w>=< (x1, x2) + (y1, y2) , (z1, z2) >
=< (x1 + y1, x2 + y2), (z1, z2) .
= (x1 + y1) z1 + 4(x2 + y2)z2
= x1z1 + 4x2z2 + y1 z1 + 4 y2z2
=<(x1, x2), (z1, z2)>+<(y1, y2), (z1, z2) >
=<u, w>+<v, w>
Axiom 3:<cu, v>= <c(x1, x2), (y1, y2)> =< (cx1, cx2), (y1, y2) >
= cx1y1 + 4cx2y2 = c(x1y1 + 4x2y2) = c<u, v>
Axiom 4: <u, u>= <(x1, x2), (x1, x2)>= 04 22
21 xx
Further, if and only if x1 = 0 and x2 = 0. That is u = 0. Thus<u, u> 0, and<u, u>= 0 if and only if u = 0.
The four inner product axioms are satisfied,
<u, v>= x1y1 + 4x2y2 is an inner product on R2.
04 22
21 xx
The inner product of the vectors (2, 5), (3, 1) is
<(2, 5), (3, 1)>= (2 3) + 4(5 1) = 14
Example Consider the vector space M22 of 2 2 matrices. Let u and v defined as follows be arbitrary 2 2 matrices.
Prove that the following function is an inner product on M22.<u, v>= ae + bf + cg + dh
Determine the inner product of the matrices .
hg
fe
dc
bavu ,
Solution
Axiom 1:,<u, v>= ae + bf + cg + dh = ea + fb + gc + hd =<v, u>
Axiom 3: Let k be a scalar. Then
<ku, v>= kae + kbf + kcg + kdh = k(ae + bf + cg + dh) = k<u, v>
4)01()90()23()52( ,09
25
10
32
09
25 and
10
32
Cauchy–Schwarz Inequality
In an inner product space, |<x,y>|2≤ <x,x><y,y> and the equality sign holds in a strict inner product
space if and only if x and y are rescalings of the same vector.
Defining |x||=<x.x>1/2 we can make every inner product a normed space .
Using CSI we can introduce concept of angle, orthogonality, correlation etc into any innerproduct space
Projection theorem holds in this space
Angle between two vectors
In Rn we first prove C-S inequality
, then define cosθ
In R2 we first define cosθ, then prove C-S inequality
Definition Let V be an inner product space. The angle between two nonzero vectors u and v in V is given by
vu
vu,cos
The dot product in Rn was used to define angle between vectors. The angle between vectors u and v in Rn is defined by
(??)cosvu
vu
Angle between two vectors
Normed spacesDefine the notion of the size of f, an
element in , a vector space• Norm || f ||, || ||: →[0,∞)
1)||f||=0↔f=0
2) ||kf||=|k|||f||
3) ||f|+||g|| <=||f||+||g||
0,f 0 0f f
1 2 1 2f f f f 1 2 1 2,d f f f f
Both R and Z are normed spaces are spaces with | |
Both Rn and are normed spaces are spaces with Euclidean norm,|| ||
n mR
Norm of a Vector
Definition Let V be an inner product space. The norm of a vector v is denoted ||v|| and it defined by
vv,v
The norm of a vector in Rn can be expressed in terms of the dot product as follows
) , , ,() , , ,()() , , ,(
2121
22121
nn
nn
xxxxxxxxxxx
Generalize this definition:The norms in general vector space do not necessary have geometric interpretations, but are often important in numerical work.
Example Consider the vector space M22 of 2 2 matrices. Let u and v defined as follows be arbitrary 2 2 matrices.
It is known that the function <u, v>= ae + bf + cg + dh is an inner product on M22 by Example 2.
The norm of the matrix is
hg
fe
dc
bavu ,
2 2 2 2, a b c d || u || u u
Different Norms on C/Z
We have already seen mod, | | is norm on C.
Let | |max and | |tax be two functions defined as follow:
| z|max =max{|x|, |y|}, | z|tax =|x| +|y|,
Show that both are norms on C.
Show that | z|max =< |z|=<| z|tax =<2 | z|max
In fact, it can be shown that for a finite-dimensional space norms are equivalent
All norms are not generated from innerproduct.
Distance
Definition Let V be an inner product space with vector norm defined by
The distance between two vectors (points) u and v is defined d(u,v) and is defined by
vv,v
) ,( ),( vuvuvuvu d
As for norm, the concept of distance will not have direct geometrical interpretation. It is however, useful in numerical mathematics to be able to discuss how far apart various functions are.
Show that 1. || ||: →[0,∞) is a continuous function.
2. d(f,g)=||f-g|| is a metric on
Metric spaces
• Put some structure on our space defining nonnegative function d:χ→
2f
1f 1 2( , )d f f
1.d(f1,, f2)=d(f2,, f1), 2) d(f1,, f2)=0 if and only if f1=f2
3, d(f1,, f2)≤ d(f1,, f3) + d(f3,, f2)
f1
f2
f3
Why are metric spaces important?
• Allow us to define the distance between functions• Can be able to treat convergence in the space,and
limit and continuity of metric space valued functions on metric space.
• Completeness – no holes in the space• We want to look at spaces that are very similar to
Euclidean space
Can we talk about best approximations?
Can
We
Define
Rate
Of
Change??
Yes if
Can we get the best from data?
Mathematical Concepts
Covariance
Variance
Sequence
• Definition. A sequence of complex numbers, denoted , is a function f, such that f: N C, i.e, it is a function whose domain is the set of natural numbers between 1 and k, and whose range is a subset of the complex numbers. If k = , then the sequence is called infinite and is denoted by , or more often, zn . (The notation f(n) is equivalent.)
• Having defined sequences and a means for measuring the distance between points, we proceed to define the limit of a sequence.
knz 1
1nz
Meaning of Zn Z0
|zn-z0|=rn 0
Where rn=2 2
0 0( ) ( )
n nx x y y
, xn x0,,, yn y0
Zn Z0
I proved it in previous classes
Geometric Meaning of Zn Z0
zn tends to z0 in any linear or curvilinear way.
Limit of a Sequence
• Definition. A sequence of complex numbers is said to have the limit z0 , or to converge to z0 , if for any > 0, there exists an integer N such that |zn – z0| < for all n > N. We denote this by
• Geometrically, this amounts to the fact that z0 is the only point of zn such that any neighborhood about it, no matter how small, contains an infinite number of points zn .
1nz
.
lim
0
0
naszz
orzz
n
nn
Geometric Meaning of Zn Z0
zn tends to z0 in any linear or curvilinear way.
zN+1
zN+2
- -
z0
Example: Convergent Sequence
• Given , choose N=1/ , p=0
1/ or ( , ) 1/ or 1/n n np n d s s n z z n
10
Establish convergence by applying definitionNecessitates knowledge of p.
Cauchy Sequence
A sequence in a metric space X such that for every , there is an integer N such that if
{ }n
z
, ,m n N ,X n md s s 0
ns
A sequence in a complex field C such that for every , there is an integer N such that if0
, ,m n N n mz z
Example Cauchy Sequence
• Given , choose N=2/, p=0
1 /nnp n
10
Establish convergence by applying definitionNo need to know p
Theorems and Exercises
Theorem. Show that zn=xn+iyn z0=x0+iy0 if and only if xn x0, yn y0 .
Ex. Plot the first ten elements of the following sequences and find their limits if they exist:
i) 1/n +i 1/n
ii) 1/n2 +i 1/n2
iii) n +i 1/n
iv) (1-1/n )n +i (1+1/n)n
Topology
Topology studies the invariant properties ofobject under continuous deformations
For all > 0, there exists > 0 : |y-x| < ) |f(y)-f(x)| <
Topology
Topology studies the invariant properties ofobject under continuous deformations
For all S open, f-1(S) is open
S
f-1(S)
Limit of a Function
• We say that the complex number w0 is the limit of the function f(z) as z approaches z0 if f(z) stays close to w0 whenever z is sufficiently near z0 . Formally, we state:
• Definition. Limit of a Complex Sequence. Let f(z) be a function defined in some neighborhood of z0 except with the possible exception of the point z0 is the number w0 if for any real number > 0 there exists a positive real number > 0 such that |f(z) – w0|< whenever 0<|z - z0|< .
Limits: Interpretation
We can interpret this to mean that if we observe points w within a radius of of ww00, we can find a , we can find a corresponding disk about corresponding disk about zz00 such that all the such that all the points in the disk about points in the disk about zz00 are mapped into it. are mapped into it. That is, That is, any any neighborhood of neighborhood of ww00 contains all the contains all the values assumed by values assumed by ff in some full neighborhood in some full neighborhood of of zz00, except possibly , except possibly f(zf(z00))..
zz00 w
0
w = f(z)
z-plane w-planeu
v
x
y
Complex Functions : Limit and Continuity
f: Ω1 Ω2
Ω1 and Ω2 are domain and codomain respectively.
Let z0 be a limit point of Ω1 , w0 belongs to Ω2 .Let us take any B any nbd of w0 in Ω2 and take inverse of B, f-1{B}. f-1{B} contains a nbd of z0 in Ω1..
In the case of Continuity the only difference is w0 =f(z0)),
Properties of Limits
If as z z0, lim f(z) A, then A is unique
If as z z0, lim f(z) A and lim g(z) B, then
• lim [ f(z) g(z) ] = A B
• lim f(z)g(z) = AB, and
• lim f(z)/g(z) = A/B. if B 0.
Continuity
• Definition. Let f(z) be a function such that f: C C. We call f(z) continuous at z0 iff:
– F is defined in a neighborhood of z0,
– The limit exists, and–
• A function f is said to be continuous on a set S if it is continuous at each point of S. If a function is not continuous at a point, then it is said to be singular at the point.
)()(lim 00
zfzfzz
Test for Continuity of Functions
f: <S1,d1> <S2,d2> is continuous at s in S1.
For all sn s f(sn) f(s)
it is true in a general metric space but not
in general topological space.
Note on Continuity
• One can show that f(z) approaches a limit precisely when its real and imaginary parts approach limits, and the continuity of f(z) is equivalent to the continuity of its real and imaginary parts.
Properties of Continuous Functions
• If f(z) and g(z) are continuous at z0, then so are f(z) g(z) and f(z)g(z). The quotient f(z)/g(z) is also continuous at z0 provided that g(z0) 0.
• Also, continuous functions map compact sets into compact sets.
Exercises
• Find domain and range of the following functions and check their continuity:
i. f1(z)=z
ii. f2(z)=|z|
iii. f3(z)=z2
iv. f4(z)=
v. f5(z)=1/(z-2)
vi. f6(z)=ez/log(z)/z1./2/cos(z)
z
Test for Continuity of Functions
f: <S1,d1> <S2,d2> is continuous at s in S1.
For all sn s f(sn) f(s)
it is true in a general metric space but not
in general topological space.
Linear Map and Matrices
Vn is a finite-dimensional vector space. Let v belongs to Vn
v=x1v1+x2v2+--------+xnvn
(x1, X2, --------- xn)nR
Every Vn is isomorphic to Rn
nn RV Its
Significance??
This isom
orphism is basis
dep
end
ent
Linear Map and Matrices
Every Vnm is isomorphic to
nmnmnm RRV
Its Significance??
This isom
orphism is basis
dep
end
ent
VnWm
k1v1+k2v2
k1L(v1)+k2L(v2))
L
L(k1v1+k2v2)
Vnm, the set of all such L’s is a vector space of dimension nm
nmR
=
Example: Convergent Sequence
• Given , choose N=1/ , p=0
1/np n
10
Establish convergence by applying definitionNecessitates knowledge of p.
Convergent Sequence Properties
Cauchy Sequence
• A sequence in a metric space X such that for every , there is an integer N such that if ,m n N ,X n md p p
0 np
Example: Cauchy Sequence
• Given , choose N=2/, p=0
1 /nnp n
10
Establish convergence by applying definitionNo need to know p
Cauchy Sequences and Cauchy Sequences
• (Theorem 3.11 in Rudin)• (a) In any metric space X, every
convergent sequence is a Cauchy sequence.
• (b) If X is a compact metric space and if is a Cauchy sequence in X, then converges to some point of X.
• (c) In , every Cauchy sequence converges.
np np
k
Complete metric spaces
• A metric space in which every Cauchy sequence converges.
• Examples of complete metric spaces:
• All compact metric spaces
• All Euclidean spaces
• All closed subsets of complete metric spaces.
Home Task
Show that C/Z is completeWrite down diffrences between C and R2