Chapter 4 : Signal conditioning

52
1 BMCC 3743Signal Conditioning NH Chapter 4 : Signal conditioning 4.1 Introduction to signal conditioning 4.2 Bridge circuits 4.3 Amplifiers 4.4 Protection 4.5 Filters

description

Chapter 4 : Signal conditioning. 4.1 Introduction to signal conditioning 4.2 Bridge circuits 4.3 Amplifiers 4.4 Protection 4.5 Filters. Introduction. ELECTRICAL MEASUREMENT SYSTEM. WHY?. Easy to transmit signal from measurement site the data collection site - PowerPoint PPT Presentation

Transcript of Chapter 4 : Signal conditioning

Page 1: Chapter 4 :  Signal conditioning

1BMCC 3743Signal ConditioningNH

Chapter 4 : Signal conditioning

4.1 Introduction to signal conditioning4.2 Bridge circuits4.3 Amplifiers4.4 Protection4.5 Filters

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Introduction

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ELECTRICAL MEASUREMENT SYSTEM

WHY?

1. Easy to transmit signal from measurement site the data collection site2. Easy to amplify, filter and modify3. Easy to record the signal

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Signal conditioning• Used in factory or machine automation : to convert

sensor or transducer measurement signal levels to industry standard control signals

• Provide computer and control system manufacturers a common communication method to effectively receive and transmit measurement and control data

• Examples of measurement data : temperature or AC/DC voltage/current signals from various transducers

• Examples of control data : on/off signals for a heating element or proportional signals for a valve actuator.

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Signal conditioning

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Bridge circuits

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Bridge circuits

• Used to convert impedance variations into voltage variations

• Can be design so the voltage produced varies around zero

• Amplification can be used to increase voltage level for increased sensitivity to variation of impedance

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Wheatstone bridge• D : voltage detector

4123

4231

4123

42

4

31

3

RRRR

VRRRR

RRRRV

VRR

RV

VRR

RV

VVV

b

a

ba

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Exercise 1

Determine;1. R4 if a Wheatstone bridge nulls with

R1 = 1000 Ω, R2 = 842 Ω, and R3 = 500 Ω.

2. The voltage offset if the supply voltage is 10.0 V. The resistors in a bridge are

given by R1 = R2 = R3 = 120 Ω and R4 = 121 Ω.

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Galvanometer detector

GTh

ThG

Th

Th

RRVI

RRRR

RRRRR

VRRRR

RRRRV

42

42

31

31

4231

4123

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Exercise 2

A bridge circuit has a resistance of R1 = R2 = R3 = 2.00 kΩ and R4 = 2.05 kΩ and a 5.00 V supply. If a galvanometer with a 50.0 Ω internal resistance is used for a detector, calculate the offset current.

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Bridge resolution

• Resolution function of detector : to determine the bridge offset

• Resistance resolution : resistance change in 1 arm bridge that causes an offset voltage equal to detector resolution

• Detector can measure change of 100 µV

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Resolution

• The smallest discernible change in input; the smallest change in input that manifests itself as perceptible change in output that can be measured (example : 0.000 1 mm)

• Primary factor in deciding precision• Good resolution does not imply in good

precision

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Current balance bridge

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Current balance bridge• Used current to null bridge

5542

54

31

3

5542

54

542

54

IRVRRR

RRVRR

RV

IRVRRR

RRV

RRRRR

b

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Exercise 3

A current balance bridge has a 10 V supply voltage and resistors R1 = R2 = 10 kΩ, R3 = 1 kΩ, R4 = 950 Ω, R5 = 50 Ω and a high impedance null detector. Determine the current required to null the bridge if R3 increased by 1 Ω.

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Potential measurements using bridges

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Potential measurements using bridges

0

0

0

5

5542

54

31

3

42

4

31

3

IRV

IRVRRR

RRVRR

RV

VRR

RVRR

RV

VVVVVV

x

x

x

bc

axc

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Exercise 4

A bridge for potential measurement nulls when R1 = R2 = 1 kΩ, R3 = 605 Ω, and R4 = 500 Ω with a 10.0 v supply. Determine the unknown potential.

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Exercise 5

A current balance bridge is used for potential measurement. The fixed resistors are R1 = R2 = 5 kΩ, R3 = 1 kΩ, R4 = 990 Ω, and R5 = 10 Ω with a 10 V supply. Calculate the current necessary to null the bridge if the potential is 12 mV.

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Amplifiers

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Op amp characteristic

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Summing amplifier

2

3

21

1

2 VRRV

RRVout

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Noninverting amplifier

inout

outinin

VRRV

RVV

RV

II

1

2

21

21

1

0

0

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Exercise 7

Design a high impedance amplifier with a voltage gain of 42 if R1 = 1 kΩ is chosen.

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Differential amplifier

CMRRCMRAACMRR

VVV

cm

bacm

10log20

2

baout VVAV • The transfer function;

• Common mode rejection;

121

2 VVRRVout

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Voltage-to-Current converter

543

354

42531

31

2

RRR

RIVRR

R

RRRRR

VRRRI

m

sat

ml

in

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Current-to-Voltage converter

IRVout

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Exercise 8For a voltage-to-current converter using an op-amp, show that the relationship between current and voltage is given by

.in

31

2 VRRR

I R1 R2

R3

R4R5

RL

I

-+

Vin

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Integrator

tRCKV

dtVRC

V

dtdVC

RV

out

inout

outin

1

0

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Exercise 9

Use an integrator to produce a linear ramp voltage rising at 10 V per ms. Determine the R and C.

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Differentiator

dtdVRCV

RV

dtdVC

inout

outin

0

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Linearization

RVGV

VIRV

inout

outin 0

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Linearization

RIVV

VIVI

eincout

outout

0

0

log1log1exp

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Filters

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Filters• Filter : a circuit that is designed to pass signals with

desired frequencies and reject or attenuate others• 4 types of filters:

1. Low-pass filter: passes low frequencies and stops high frequencies

2. High-pass filter: passes high frequencies and rejects low frequencies

3. Band-pass filter: passes frequencies within a frequency band and blocks or attenuates frequencies outside the band

4. Band-reject filter: passes frequencies outside a frequency band and blocks or attenuates frequencies within the band

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Low-pass RC filter

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Low-pass RC filter

• Critical frequency:

• Output-to-input voltage ratio:RC

fc 21

2/1

1

cin

out

ffVV

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Exercise 10

A measurement signal has a frequency less than 1 kHz, but there is unwanted noise at about 1 MHz. Design a lowpass filter that attenuates the noise to 1% if a capacitor 0.01 µF has been used. What is the effect on the measurement signal at its maximum of 1 kHz?

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High-pass RC filter

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High-pass RC filter

• Critical frequency:

• Output-to-input voltage ratio:RC

fc 21

2/1

/

c

c

in

out

ff

ffVV

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Exercise 11

Pulses for a stepping motor are being transmitted at 2000 Hz. Design a highpass filter to reduce 60 Hz noise and reduce the pulses by no more than 3 dB.

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Design Methods

1. Determine critical frequency, fc

2. Select standard capacitor (µF – pF)3. Calculate required resistance (1 kΩ - 1 MΩ)4. Use nearest resistance standard value to

calculated value 5. Consider tolerance in resistors and capacitors

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Practical considerations

1. Very small resistance -> lead to large currents and loading effects -> avoid large capacitance (R= kΩ -MΩ, C= µF – pF)

2. The exact fc is not important, choose R and C of approximately to the fc

3. Isolation filter input/output with voltage follower4. Cascade RC filters to improved fc sharpness -> consider

loading

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Band-pass RC filter

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Band-pass RC filter• Critical frequency:

• Output-to-input voltage ratio:HH

L CRf

21

L

H

HLLH

H

in

out

RRr

ffrffff

ffVV

2222 1

LLH CRf

21

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Exercise 12

A signal conditioning system uses a frequency variation from 6 kHz to 60 kHz to carry measurement information. There is considerable noise at 120 Hz and at 1 MHz. Design a bandpass filter to reduce the noise by 90%. What is the effect on the desired passband frequencies if r = 0.01? Determine all the resistors and capacitors.

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Band-pass RC filter

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Band-reject RC filter

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Twin-T notch filter

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Twin-T notch filter• Critical frequency:

• Grounding resistor and capacitor:

cn ff 785.0 RCfC 2

1

cH ff 57.4cL ff 187.0

101RR

CC 10

1

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Exercise 13

A frequency of 400 Hz prevails aboard an aircraft. Design a twin-T notch filter to reduce the 400 Hz signal if 0.01 µF has been used and calculate the grounding resistor and capacitor. What effect would this have on voice signals at 10 to 300 Hz? Determine the higher frequency when the output is down by 3 dB.