Chapter 3.1 Pressure Presentation
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Transcript of Chapter 3.1 Pressure Presentation
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P = F/A
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Mass of liquid = Ahp P = pgh
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Pressure in liquid does not depends on
- the of the container.- the of the container.- the of its surface
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Pa = 0cmHgPb = 26cmHgPe = 76cmHgPf= 84 cmHg
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Figure shows a simplebarometer. Find theatmospheric pressure in theunit of cmHg
The atmospheric pressure,P = 76cmHg
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Pgas = Patm + PliquidPgas = Patm + hg
Pgas
= Gas PressurePatm = Atmospheric Pressureg = Gravitational Field Strength
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Figure shows a column ofmercury in a glass tube. Some airis trapped in the glass tube. If theatmospheric pressure is 76cmHg,what is the pressure of the gasinside the tube?
Patm = Pair + Pmercury(76) = Pair + 50Pair= 76 - 50 = 26cmHg
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