Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance...
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Transcript of Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance...
![Page 1: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/1.jpg)
Chapter 11
Hypothesis Testing IV (Chi Square)
![Page 2: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/2.jpg)
Basic Logic
Chi Square is a test of significance based on bivariate tables.
We are looking for significant differences between the actual cell
frequencies in a table (fo) and those
that would be expected by random
chance (fe).
![Page 3: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/3.jpg)
The relationship of homicide rate and gun sales
Low homicide
High homicide
Totals
Low gun sales
8 5 13
High gun sales
4 8 12
Totals 12 13 25
![Page 4: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/4.jpg)
Tables
Notice the following about these tables 1. Table must have a title 2. Independent vrble must go into columns and if percentaged, must percentage within columns3. Subtotals are called marginals.4. N is reported at the intersection of row and
column marginals.
![Page 5: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/5.jpg)
TablesTitle
Rows Column 1 Column 2
Row 1 cell a cell b Row Marginal 1
Row 2 cell c cell d Row Marginal 2
Column Marginal 1
Column Marginal 2
N
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Example of Computation
Problem 11.2 Are the homicide rate and volume of gun
sales related for a sample of 25 cities?
![Page 7: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/7.jpg)
Example of Computation The bivariate table showing the relationship
between homicide rate (columns) and gun sales (rows). This 2x2 table has 4 cells.
Low High
High 8 5 13
Low 4 8 12
12 13 25
![Page 8: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/8.jpg)
Example of Computation
Use Formula 11.2 to find fe.
Multiply column and row marginals for each cell and divide by N. For Problem 11.2
(13*12)/25 = 156/25 = 6.24 (13*13)/25 = 169/25 = 6.76 (12*12)/25 = 144/25 = 5.76 (12*13)/25 = 156/25 = 6.24
![Page 9: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/9.jpg)
Example of Computation Expected frequencies:
Low High
High 6.24 6.76 13
Low 5.76 6.24 12
12 13 25
![Page 10: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/10.jpg)
Example of Computation A computational table helps organize the
computations.
fo fe fo - fe (fo - fe)2 (fo - fe)2 /fe
8 6.24
5 6.76
4 5.76
8 6.24
25 25
![Page 11: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/11.jpg)
Example of Computation
Subtract each fe from each fo. The total of this column must be zero.
fo fe fo - fe (fo - fe)2 (fo - fe)2 /fe
8 6.24 1.76
5 6.76 -1.76
4 5.76 -1.76
8 6.24 1.76
25 25 0
![Page 12: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/12.jpg)
Example of Computation Square each of these values
fo fe fo - fe (fo - fe)2 (fo - fe)2 /fe
8 6.24 1.76 3.10
5 6.76 -1.76 3.10
4 5.76 -1.76 3.10
8 6.24 1.76 3.10
25 25 0
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Example of Computation Divide each of the squared values by the fe for that
cell. The sum of this column is chi square
fo fe fo - fe (fo - fe)2 (fo - fe)2 /fe
8 6.24 1.76 3.10 .50
5 6.76 -1.76 3.10 .46
4 5.76 -1.76 3.10 .54
8 6.24 1.76 3.10 .50
25 25 0 χ2 = 2.00
![Page 14: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/14.jpg)
Step 1 Make Assumptions and Meet Test Requirements
Independent random samples LOM is nominal
Note the minimal assumptions. In particular, note that no assumption is made about the shape of the distribution of the parameters. The chi square test is non-parametric.
![Page 15: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/15.jpg)
Step 2 State the Null Hypothesis
H0: The variables are independent Another way to state the H0, more
consistent with previous tests: H0: fo = fe
![Page 16: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/16.jpg)
Step 2 State the Null Hypothesis
H1: The variables are dependent Another way to state the H1:
H1: fo ≠ fe
![Page 17: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/17.jpg)
Step 3 Select the S. D. and Establish the C. R.
Sampling Distribution = χ2
Alpha = .05 df = (r-1)(c-1) = 1 χ2 (critical) = 3.841
![Page 18: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/18.jpg)
Calculate the Test Statistic
χ2 (obtained) = 2.00
![Page 19: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/19.jpg)
Step 5 Make a Decision and Interpret the Results of the Test
χ2 (critical) = 3.841 χ2 (obtained) = 2.00 The test statistic is not in the Critical
Region. Fail to reject the H0. There is no significant relationship
between homicide rate and gun sales.
![Page 20: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/20.jpg)
Interpreting Chi Square
The chi square test tells us only if the variables are independent or not.
It does not tell us the pattern or nature of the relationship.
To investigate the pattern, compute %s within each column and compare across the columns.
![Page 21: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/21.jpg)
Interpreting Chi Square Cities low on homicide rate were low in gun sales
and cities high in homicide rate were high in gun sales.
As homicide rates increase, gun sales increase. This relationship is not significant . The apparent pattern may be sampling error.
Low High
Low 8 (66.7%) 5 (38.5%) 13
High 4 (33.3%) 8 (61.5%) 12
12 (100%) 13 (100%) 25
![Page 22: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/22.jpg)
The Limits of Chi Square
Like all tests of hypothesis, chi square is sensitive to sample size. As N increases, obtained chi square
increases. With large samples, trivial relationships
may be significant.
Remember: significance is not the same thing as importance.
![Page 23: Chapter 11 Hypothesis Testing IV (Chi Square). Basic Logic Chi Square is a test of significance based on bivariate tables. We are looking for significant.](https://reader035.fdocuments.us/reader035/viewer/2022062516/56649dda5503460f94acfd70/html5/thumbnails/23.jpg)
Additional limits
If there are more than four categories in either variable, the use of chi square is questionable.
If one of the cells has a frequency less than 5 (as in our example), the use of chi square is questionable