Calculus, a technical project. And technicolor animation piece.
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Transcript of Calculus, a technical project. And technicolor animation piece.
Calculus, a technical project. And technicolor animation piece.
By David M. Toner, with great respect
Exercise #1, Part 1
Power Rule-By the power rule, the derivative of x^n=
nx^(n-1) 1. x^2= 2x
2.x^3= 3x^2
Exercise #1, Part 2
Quotient and Product rules-[(x^3-5)(x^2-1)]/(x^2+1) Becomes-
(x^5-x^3-5x^2+5)/(x^2+1) Becomes-(5x^4-3x^2-10x)/(x^2+1) Becomes-
(x^2+1)(5x^4-3x^2-10x)-(2x)(x^5-x^3-5x^2+5)Final
Answer-[(3x^6+4x^4-3x^2-20x)/(x^2+1)^2]
Exercise #2
The graph is not linear, and is infact quadratic. According to the 'rise over run'
approximation, using (2,4) and (3,9) the slope of this graph is 5/1, which is clearly not true.
The fault in this logic is that rise/run only works on linear graphs.
Exercise 3
Our input is (2+h)^3-2^3/hThe limit from Exercise 1 for 2,
(3(2)^2)=12, which is what this equation implies, so the two are in perfect agreement.
Input -.01 -.1 .01 .1
Output 11.94 11.41 12.06 12.61
Exercise 4, Part 1
To prove or disprove our third function, we've been given the following equation, [(x^3-5)
(x^2-1)]/x^2+1When x=2, y=1.8. When x=2.1, y=2.68
When placed into the equation to find the secant slope, it looks like this-
(2.68-2)/(2.1-2)=6.8
Exercise 4 Part 2
We then place this into the equation...equation.
y=1.8+6.8(x-2)b,A(b)=2.1, 2.48
Exercise 4 Part 3
According to the method I have been given, I should place SinX when x=0, as well as
Sinx=Pi/2, which make the following equations-Sin0, A(sin0)=0,5 and Sin(Pi/2),
A(Sin(Pi/2))=1,0
Exercise 4, Part 4
The slope equation now flows as such, (0-5)/(1-0)=-5
This means the equation of the line is-5+-5(x-0)=5+-5x.
Exercise 5
When give the equation, I find the derivative of the equation using the product rule-x(1-x) becomes x-x^2, which, using the power rule, becomes 1-2x. Using this, I can assume the
limit of this function will be .5. From here, I can plug in values near zero to
test the equation and my findings.
-.01 -.1 .01 .1
.51 .6 .49 .39
Exercise 5, Part 2
Based on the information we found in the table and using the derivative rules(power
and product), the limit is .5, as I hypothesized earlier.