Calculos Condensador Horizontal

8/10/2019 Calculos Condensador Horizontal

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SECUENCIA DE CALCULOS:

ROTAMETRO AL 80 %

1. Gasto Volumtr !o "#l a$ua al 100% &0.'1 l t(m )&. Gasto Volum#tr !o "#l a$ua la 80 % 1'.*88 l t(m )

Gv= 16.488 lit min

x 60 min1 hr

x 1m3

1000 lit = 0.988 m3

hr

+. Gasto masa "# a$ua:

a = (0.9888 m3hr ) x(996.59 kgm3 )= 985.4282 kghrG m a= Gv a

*. Gasto ,olumtr !o "#l !o)"#)sa"o #) 8 m )utos.

Gv vc= 4

d i2 z

[ m3

h ]Gva =

4

(0.385 m)2 0.04 m0.1333 hr

= 0.03492 m3

hr

-. Gasto masa "#l !o)"#)sa"o:

vc = (0.03492 m3hr ) x(996.59 kgm3 )= 34.8009 kghrGm vc = Gvvc

'. Calor $a)a"o o a sor "o /or #l a$ua:

Q a= Gm aCp t

Q a=(985.4292 kghr )(1 KcalkgC )(44 C 27 C )= 16752.2794 Kcalhr

. C l!ulo "#l !alor !#" "o /or #l ,a/or:

t1 & 2C

t& **2C


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Qv= Gm v v= 34.8009 kgh

541.5 kcalkg

= 18844.6873

8. Cal!ulo "# la #3! #)! a trm !a "#l #4u /o:

n=Q aQ v100 = 16752.2794

18844.6873100 = 88.89

5. C l!ulo "# la m#" a lo$ar6tm !a "# la " 7#r#)! a "# t#m/#raturas:

T ML= T 1 T 2

ln ( T

1

T 2 ) = C

T 1= T 1 t 1= T v t a = 96 C 27 C = 69 C

T 2= T 2 t 2 = T v t acaliente = 96 C 44 C = 52 C

T ML=69 C 52 C

ln

( 69 C

52 C ) = 60.0998 C

10.C l!ulo "#l r#a "# tra)s7#r#)! a "# Calor:

A= d e L

A= (0.0159 m) (1.5 m) (5 )= 0.3746 m2

11.C l!ulo "#l !o#3! #)t# $lo al "# tra)s7#r#)! a "# !alor.

! exp= Qa

A T ML=

16752.2794 kcalhr

(0.3746 m2) (60.0998 C )= 744.1031 kcal

m2 hrC


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1&.C l!ulo "# la ,#lo! "a":

v=Gv a

5 A"l#$%=

Gv a

5

4

d i2

=

0.9888 m3

hr

5

4

(0.01338 m)2= 1406.4890 m

hr

1+.Cal!ulo "# la t#m/#ratura m#" a:

tm=t 1+t 2

2= 27 C +44 C

2= 35.5 C

Nota: t 1 t a t& t a !al #)t#

1*.Co#3! #)t# "# /#l6!ula )t#r or 9 "atos "# las /ro/ #"a"#s 76s !as a lat#m/#ratura m#" a

55*.08;$(m +

< &.-5&;$(m=

> a$ua 0.-+ ->!al(=m2C

hi= 0.0225k di (di v& )

0.8

(Cp&k )0.33

hi=0.02250.53775 kcal

hmC 0.01338 m (0.01338 m1406.48 mh994.08 kg /m32.592 kg/mh )

0.8

( 1 kcalkg 2.592 kg/mh0.53775 Kcal /hmC )0.33

hi= 1855.6006 kcalh m2 C

1-.Cal!ulo "# la T 7

T " = T v 0.75 T "


4/5

T " = T v T

T =T v+T c +t a+t acalinete

4=

T 1 +T 2+t 1 +t 24

= 96 C +96 C +27 C +44 C 4

= 65.75 C

T " = 96 C 65.75 = 30.25 C

T " = 96 C 0.75 (30.25 C )= 73.3125 C

?ro/ #"a"#s 76s !a ala T7 5 -.88 >$(m +

< 1.+5'8 ;$(m=> 0.- +0&'

;!al(=m2C@ -*1.- ;!al(;$

1'.Co#3! #)t# "# /#l6!ula # t#r or.

he= 0.725 [ 2k 3 g

23de& T " ]

14 =[ kcalhCm 2 ]

he= 0.725

[ (975.88 Kg/m3)2(0.573026 kcalhm C )

3

541.5 kcalkg

127137600 mh2

52

3 (0.015875 m)(1.3968 kgmh)30.25 C ]14

= 6456.4938 kcal

h c m2

1 .Co#3! #)t# $lo al "# tra)s7#r#)! a "# !alor t#Br !o.


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! = 1de

hidi+ ede

K dm+ 1

he

dm=de+di

2 =0.01338 +0.0158

2 = 0.01463 m

# ! 0.00&*85 m

; *+.0&;!al(=m2C

! = 10.0158 m

(1855.6006 kcalChm 2)(0.01338 m)+ 0.002489 m0.0158 m(43.02 kcal /hmC )(0.01463 m)+

1

(6456.4938 kcalh c m 2)! = 1166.6944 kcal

hCm 2

18.D#s, a! B) /or!#)tual:

'( =! te% ! exp

! te%=

1166.6944 kcalhCm 2 744.1031

kcalm2 hrC

1166.6944 kcalh C m 2

x100 = 36.59

Calculos Condensador Horizontal

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