Bases de Diseño de Pilotes de Fundación
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Transcript of Bases de Diseño de Pilotes de Fundación
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Bengt H. Fellenius, Dr.Tech., P.Eng.2475 Rothesay Avenue, Sidney, British Columbia, V8L 2B9
TEL: (778) 426-0775 e-address: Web site: [www.Fellenius.net]
Basics of Design of Piled FoundationsA Course and Seminar
Santa Cruz, BoliviaApril 25, 2013
The primary intent of the course is to demonstrate that deep foundation design is a good deal more thanfinding some value of capacity. The course aims to show what data one must pull together and presentprocesses of analysis and calculations necessary for a design of a specific project. Aspects of negativeskin friction and associated drag load and downdrag are emphasized.
The presentation includes both broad generalities and in-depth details. Aspects of where to installinstrumentation, perform a test, and analyze the test data are addressed. Settlement analysis is of vitalimportance to the design of piled foundations, and the course addresses principles of settlement analysisand provides some of the mechanics of calculating settlement. A few aspects are included ofconstruction aspects as well as of Limit States Design, LSD (Ultimate Limit States, ULS, andServiceability Limit States, SLS, by Canadian terminology and Load and Resistance Factor Design,LRFD, by US terminology).
To simplify following along the flow of the presentation and taking notes, hand-out course notes areprovided, consisting of black-and-white copies of all Power Points slides, six to a page. Full-size colorcopies of the slides are also available on my web site [www.Fellenius.net]. These can be downloadedfrom the link [/Bolivia]. Note, the link is hidden and has to be typed into the command line ("commandribbon").
The slides contain only a minimum of text. For a background and explanation to much of thepresentations, I refer you to my text book "Basics of Foundation Design" also available for downloadingfrom my web site (the file is called 313 The Red Book_Basics of Foundation Design.pdf. Afterdownloading, the book can be viewed and read on-screen or be printed (color or black & white) withoutany restriction. The book contains a list of references pertinent to the material presented in the course.Copies of the referenced papers where I am the author or co-author are available for downloading at myweb site (click on the link "Download Papers").
I will be glad to respond to any e-mail with a question you might wish to put to me.
Sidney April 2013
Bengt H. Fellenius
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Basics of Design of Piled FoundationsA Course and Seminar
Bengt H. Fellenius, Dr.Tech., P.Eng.The course comprises four main lectures leading up to and presenting the essentials of the Unified Method of deepfoundations design for capacity, drag load, settlement, and downdrag for single piles, pile groups, and piledfoundations. The presentations are illustrated with case histories of testing and design analysis including how toevaluate strain-gage measurements from instrumented pile loading tests and to assess residual load. Settlementanalysis is of vital importance to the design of piled foundations, and the course addresses principles of settlementanalysis and how to calculate settlement of piles and piled foundations. Pertinent aspects of constructionprocedures and Load and Resistance Factor Design, LRFD are discussed.
08:00h Brief Background to Basic Principles Applicable to Piled Foundations
Stress distribution and interaction between adjacent foundations; Settlement analysis; Applications ofwick drains to piled foundations.
09:30h Coffee Break
09:45h Analysis of Load Transfer, Capacity, and Response to LoadLoad-movement response of foundations; Bearing capacity and load-transfer by beta, alpha, and lambdamethods, and by CPT and CPTu methods; Set-up and relaxation; Residual load; Results of predictionevents.
11:30h The Static Loading Test: Performance, Analysis, and Instrumentation
Methods of testing and basic interpretation of the results. How to analyze results from strain-gageinstrumented piles to arrive at resistance distribution along the pile shaft and the pile toe response.
12.00h LUNCH
13:00h The Static Loading Test: Resumed
Determining pile elastic modulus. The importance of residual load and how to include its effect in theanalysis. Principles of the bi-directional test (the O-cell test) and how to analyze the results of an O-celltest. Case histories of analyses on results of static loading tests on driven and bored piles.
14:30h Coffee Break
14:50h 4. Piles and Pile Groups Long-Term Behavior and how we know what we know; The Unified Design Method.
Important case histories presenting studies that demonstrated the actual long-term response of piles toload and observed settlement of piles and pile groups. The lessons learnt will be referenced to aspects ofdesign applying the Unified Method for Design of Piled Foundations considering Capacity, Drag Load,Settlement, and Downdrag for single piles, pile groups, and piled foundations.
1. Capacity (choice of factor of safety, and rules of LRFD and Limit States Design) and design forstructural strength (including drag load)
2. Settlement of single piles and pile groups due to load directly on the piles and due to influence fromadjacent activity (downdrag)
3. How to combine the various aspects for the design of an actual case with emphasis on foundationsettlement illustrated with examples
17:00h Questions and Discussions; End of Day
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1BASICS OF DESIGN OF PILED
FOUNDATIONSFOUNDATIONS
Bengt H. Fellenius
1
A short course
Santa Cruz, Bolivia, April 25, 2013
08:00h Brief Background to Basic PrinciplesApplicable to Piled Foundations
SCHEDULE
09:30h Break
09:45h Analysis of Load Transfer, Capacity and Response to Load
11.30h The Static Loading Test: Head-down and O-cell Tests
12.00h LUNCH
13.00h The Static Loading Test: Continued
14 00h Case Histories on Pile Analysis Drag Load Downdrag
2
14.00h Case Histories on Pile Analysis, Drag Load, Downdrag,Pile Groups, Piled Raft, Piled Pad
14.30h Break
14.50h The Unified Method of Design
17:00h Questions and Discussions and End of Day
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2www.Fellenius.net
Bolivia
To Download All COURSE SLIDES
Power Point Slides1 - Background Lecture 1.pdf2 - Analysis Methods Lecture 2.pdf3 - Static Loading Test Lectures 3a and 3b.pdf4 - Case Histories and Lectures 4a and 4b.pdf
Design Methods
4
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1
BASICS OF DESIGN OF PILED
FOUNDATIONS
Bengt H FelleniusBengt H. Fellenius
Background and Basic Principles
Bolivia, April 25, 2013
Some Fundamental Principles
22
Determining the effective stress is the key to geotechnical analysis
The not-so-good method:
h= '' = buoyant unit weight
33
)'(' hz = )1(' iwt =
It is much better to determine, separately, the total stress and the pore pressure. The effective stress is then the total stress minus the pore pressure.
)( h
44
)( hz = uz = '
Determining pore pressure
u = w hThe height of the column of water (h; the head representing the water pressure)is usually not the distance to the ground surface nor, even, the distance to thegroundwater table. For this reason, the height is usually referred to as thephreatic height or the piezometric height to separate it from the depth below
PRESSURE
55
the groundwater table or depth below the ground surface.
The pore pressure distribution is determined by applying the facts that
(1) in stationary conditions, the pore pressure distribution can be assumed to be linear in each individual soil layer
(2) in pervious soil layers that are sandwiched between less pervious layers, the pore pressure is hydrostatic (that is, the vertical gradient is unity)
SAND Hydrostatic distribution
CLAY Non-hydrostatic distribution, but linear
SAND Hydrostatic distribution Artesian phreatic head
GW
DEPTH
Distribution of stress below a a small load area
0LBqqz
=
The 2:1 method
66
)()(0 zLzBqqz ++
The 2:1-method can only be used for distributions directly under the centerof the footprint of the loaded area. It cannot be used to combine (add)stresses from adjacent load areas unless they all have the same center. it isthen only applicable under the area with the smallest footprint.
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2
The Boussinesq Method Derived from calculation of stress from
a point load on the surface of an elastic medium
33z
77
2/522 )(23
zrzQqz +=
Newmarks method for stress from a loaded area
Newmark (1935) integrated the Boussinesq equation over a finite area and obtained a relation for the stress under the corner of a uniformly loaded rectangular area, for example, a footing
CBAI +
88
40CIqqz ==
2222
22
112nmnm
nmmnA +++++=
12
22
22
++++=
nmnmB
++++= 2222
22
112arctannmnm
nmmnC
m = x/zn = y/zx = length of the loaded areay = width of the loaded areaz = depth to the point under the corner
where the stress is calculated
(1)
Eq. 1 does not result in correct stress values near the ground surface. To represent the stress near the ground surface, Newmarks integration applies an additional equation:
CBA +
99
40CBAIqqz
+==
For where: m2 + n2 + 1 m2 n2
(2)
Stress distribution below the center of a square 3 m wide footing
-2
0
) 0 15
0.20
0.25
CTO
R,
IEq. (1)
Eq. (2) Eq. (2)
1010
0 20 40 60 80 100-6
-4
STRESS (KPa)
DE
PTH
(m
0.01 0.10 1.00 10.000.00
0.05
0.10
0.15
m and n (m = n)
INFL
UE
NC
E F
AC
Eq. (1)
0
1
2
0 25 50 75 100
STRESS (%)
met
ers)
Boussinesq
Westergaard
0
1
2
0 25 50 75 100
SETTLEMENT (%)
met
ers)
Boussinesq
Westergaard
1111Comparison between Boussinesq, Westergaard, and 2:1 distributions
3
4
5
DEP
TH (
dia
2:13
4
5
DEP
TH (
dia
2:1
0
1
2
0 25 50 75 100
STRESS (%)
eter
s)
Westergaard
Boussinesq
0
1
2
0 25 50 75 100
SETTLEMENT (%)
met
ers)
Boussinesq
Westergaard
1212
2
3
4
5
DEP
TH (
diam
2:1
2
3
4
5
DEP
TH (
diam
2:1
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3/24/2013
3
0
1
2
0 25 50 75 100
STRESS (%)
amet
ers)
Westergaard
Boussinesq
0
1
2
0 25 50 75 100
SETTLEMENT (%)
amet
ers)
Boussinesq
Westergaard
1313
3
4
5
DE
PTH
(di
a
2:1 Characteristic Point; 0.37b from center
3
4
5
DEP
TH (
dia
2:1 Characteristic Point; 0.37b from center
Below the characteristic point, stresses for flexible and stiff footings are equal
Now, if the settlement distributions are so similar, why would we persist in using
Boussinesq stress distribution instead of the much simpler 2:1 distribution?
1414
Because a footing is not alone in this world; near by, there are other footings, and fills,
and excavation, etc., for example:
The settlement imposed outside the loaded
foundation is often critical
0
1
2
0 25 50 75 100
SETTLEMENT (%)
met
ers)
BoussinesqOutside Point Boussinesq
Center Point
1515
2
3
4
5
DEP
TH (
diam
Loaded area
The end result of a geotechnical design analysis
is
1616
Settlement
Stress-Strain
' (
KPa
)
=tM
1717
STRAIN (%)
STR
ESS,
Plotted as Strain-Stress
N (
%)
N (
%)
TIO
, e
Plotted as Void Ratio vs. Stress
1818
STRESS, ' (KPa)
STR
AIN
STRESS, ' (KPa)
STR
AIN
STRESS (KPa)
VOID
RA
T
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4
Stress-strain behavior is non-linear for most soils. The non-linearity cannot be disregarded when analyzing compressible soils, such as silts and clays, that is, the elastic modulus approach is not appropriate for these soils.
Non-linear stress-strain behavior of compressible soils, is conventionally modeled as follows.
11 'l'l C
1919
where = strain induced by increase of effective stress from 0 to 1Cc = compression indexe0 = void ratio0 = original (or initial) effective stress1 = final effective stressCR = Compression Ratio = (MIT)
0
1
0
1
0 'lg
'lg
1
CR
eCc =+=
01 eCCR c+=
Some use the term "Cc" for the "CR", creating quite a bit of confusion thereby
In overconsolidated soils (most soils are)
)''lg
''
lg(1
1 100 p
cp
cr CCe
++=
2020
where p = preconsolidation stressCcr = re-compression index
The Janbu Method
The Janbu tangent modulus approach, proposed by Janbu (1963; 1965; 1967; 1998), and referenced by the Canadian Foundation Engineering Manual, CFEM (1985; 1992), applies the same basic principles of linear and non-linear stress-strain behavior. The method applies to all soils, clays as well as sand. By this method, the relation between stress and strain is a function of two non-dimensional parameters which are unique for a soil: a stress exponent, j, and a modulus number, m.
2121
Janbus general relation is
])''()
''[(1 01 j
r
j
rmj
=
where: r = a reference stress = 100 KPaj = a stress exponent
m = the modulus number
The Janbu Method
Dense Coarse-Grained Soil j = 1
Cohesive Soil j = 0 1'
ln1 =
'1)''(1 01 == mm
'21)''(
21
01 == mm
in KPa
in ksf
2222
Cohesive Soil j = 0
Sandy or Silty Soils j = 0.5
0'ln m=
)''(51
01 = m
pm''(2 1 =
in KPa
in ksf
There are direct mathematical conversions
between m and the E and Cc-e0
For E given in units of KPa (and ksf), the relation between the modulus number and the E-modulus is
2323
m = E/100 (KPa)m = E/2 (ksf)
For Cc-e0, the relation to the modulus number is
cc Ce
Cem 00 13.2110ln +=+= And m = 2.3/CR
Typical and Normally Conservative Modulus Numbers
SOIL TYPE MODULUS NUMBER STRESS EXP.
Till, very dense to dense 1,000 300 (j=1)
Gravel 400 40 (j=0.5)
Sand dense 400 250 (j=0.5compact 250 150 _ " _loose 150 100 _ " _
Silt dense 200 80 (j=0.5)compact 80 60 _ " _loose 60 40 _ " _
This is where the greater value of the Janbu approach versus the MIT CR-approach comes in.
ClaysSilty clay hard, stiff 60 20 (j=0)
stiff, firm 20 10 _ " _Clayey silt soft 10 5 _ " _
Soft marine claysand organic clays 20 5 (j=0)
Peat 5 1 (j=0)
For clays and silts, the recompression modulus, mr, is often five to twelve times greater than the virgin modulus, m.
This is where the Janbu approach and the MIT CR-approach are equal in practicality.
Reference: Fellenius, B.H., 2012. Basics of foundation design, a text book.Revised Electronic Edition, [www.Fellenius.net], 385 p.
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3/24/2013
5
0.80
1.00
1.20
Voi
d R
atio
(- -
)
m = 12(CR = 0 18)
p'c
10
15
20
25
Stra
in (
%)
C
1/m
Slope = m = 12
Evaluation of compressibility from oedometer results
2525
0.40
0.60
10 100 1,000 10,000
Stress (KPa) log scale
V (CR = 0.18)
0
5
10 100 1,000 10,000
Stress (KPa) log scale
p 10p
Cc
Cc = 0.37
e0 = 1.01 p'c
p 2.718p
Void-Ratio vs. Stress and Strain vs. Stress Same test data
Note, if the "zero"-value -- the e0 -- is off, the Cc-e0 is off (and so is the CR) even ifthe Cc is correctly determined. Not so the "m" (if determined from the test results).
Comparison between the Cc/e0 approachand the Janbu method
0 10
0.15
0.20
0.25
0.30
0.35
PRES
SIO
N IN
DEX
, Cc
Do these values indicate a
compressible soil, a medium compressible
soil, a moderately ibl il
15
20
25
30
35
MO
DU
LUS
NU
MB
ER, m
2626
Data from a 20 m thick sedimentary deposit
0.00
0.05
0.10
0.40 0.60 0.80 1.00 1.20
VOID RATIO, e0
CO
MP compressible soil, or a
non-compressible soil?0
5
10
0.400.600.801.001.20
VOID RATIO, e0
VIR
GIN
The Cc-e0 approach (based on Cc) implies that the compressibility varies by 30 %.
However, the Janbu methods shows it to vary only by 10 %. The modulus number, m, ranges from 18 through 22; It would be unusual to find a clay with less variation.
Conventional Cc/e0
How many of these oedometer results indicate
(o) highly compressible clay
(o) compressible clay
( ) di ibl l20
30
40
50
OD
ULUS
NU
MB
ER, m
0 20 40 60 80 100WATER CONTENT, wn (%)
Janbu Modulus Number m
The Cc-values converted via the associated e0-values to modulus
numbers.
2
3
4
5
MPR
ESSI
ON
IND
EX, C
c
2727
(o) medium compressible clay
(o) non-compressible clay?
0
10
0.00 0.50 1.00 1.50 2.00 2.50 3.00
VOID RATIO, e0
VIRG
IN M
m < 10 ==> Highly compressible Oedometer test data from Leroueil et al., 1983
0
1
0.00 1.00 2.00 3.00
VOID RATIO, e0
CO
M
Stress produces strainLinear Elastic Deformation (Hookes Law)
= induced strain in a soil layer= imposed change of effective stress in the soil layer '
E' =
2828
p g y
E = elastic modulus of the soil layer (Youngs Modulus)
Youngs modulus is the modulus for when lateral expansion is allowed, which may be the case for soil loaded by a small footing, but not when the load is applied over a large area. In the latter case, the lateral expansion is constrained (or confined). The constrained modulus, D, is larger than the E-modulus. The constrained modulus is also called the oedometer modulus. For ideally elastic soils, the ratio between D and E is:
= Poissons ratio
)21()1()1(
+
=ED
Settlement is due to Immediate Compression, Consolidation Settlement, and Secondary Compression
Immediate Compression is the compression of the soil grains (soil skeleton) and of any free gaspresent in the voids. It is usually assumed to be linearly proportional to the change of stress Theimmediate compression is therefore often called 'elastic' compression. It occurs quickly and isnormally small (it is not associated with expulsion of water).
Consolidation (also Primary Consolidation) is volume reduction during the increase ineffective stress occurring from the dissipation of pore pressures (expelling water from the soilbody). In the process, the imposed stress, initially carried by the pore water, is transferred to the
il t t C lid ti i kl i i d il b t l l i fi i d
2929
soil structure. Consolidation occurs quickly in coarse-grained soils, but slowly in fine-grainedsoils.
Secondary Compression is a term for compression occurring without an increase of effectivestress. It is triggered by changes of effective stress. It does not usually involve expulsion ofwater, but is mainly associated with slow long-term compression of the soil skeleton. Somecompression of the soil structure occurs and it is then associated with some expulsion of water,but this is so gradual and small that pore pressure change is too small to be noticed. Sometimes,the term "creep" is used to mean secondary compression, but "creep" should be restricted toconditions of shear. Secondary compression is usually small, approximately similar in magnitudeto the immediate compression, but may over time add significantly to the total deformation of thesoil over time. Secondary compression can be very large in highly organic soils, such as peat.Theoretically, seconday compression occurs from the start of the consolidation (effective stresschange), but in practice, it is considered as starting at the end of the consolidation.
On applying load, the soil skeleton compresses and the soil grainsare forced closer to each other reducing the void ratio. Thecompression of the soil skeleton occurs more or less immediately incontrast to the reduction of the void volume which requiresexpulsion of water ("consolidation") and can take a long time.However, in soils containing gas bubbles, the load applicationcauses the bubbles to compress (and partially to go into solution in
Immediate Compression and Consolidation Settlement
3030
the pore water), which also occurs immediately. Then, as the porepressure dissipates during the consolidation process, the gasbubbles expand which slows down the settlement process. The"slow-down" is often mistaken for approaching the end ofconsolidation. The thereafter observed settlement is theninterpreted as a large secondary compression (addressed later on).
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3/24/2013
6
2H
Drainage Layer
Clay Layer (consolidating)
Drainage Layer
0
1uu
SSU t
f
tAVG ==
where UAVG = average degree of consolidation (U)St = settlement at Time tSf = final settlement at full consolidationut = average pore pressure at Time tu0 = initial average pore pressure (on application of the load at Time t = 0)
Basic Relations
UAVG
Consolidation Settlement
3131
vv c
HTt2
=where t = time to obtain a certain degree of consolidation
Tv = a dimensionless time coefficient: cv = coefficient of consolidationH = length of the longest drainage path
UAVG (%) 25 50 70 80 90 100
Tv 0.05 0.20 0.40 0.57 0.85 1.00
)1(lg1.0 UTv =
HOW TO HANDLE A MULTILAYERED PROFILE?
c/c
d
"Square" spacing: D = 4/ c/c = 1.13 c/c
"Triangular" spacing: D = (23)/ c/c = 1.05 c/c
Vertical Drains
3232
c/cBasic principle of consolidation process in the presence of vertical drains
hh Ud
DT = 11ln]75.0[ln
81
hh UdD
cDt = 1
1ln]75.0[ln8
2
and
hh c
DTt2
=
The Kjellman-Barron Formula
Walter Kjellman, inventor of the very first wick drain, the Kjellman Wick, a 100 mm wide, 3 mm thick, cardboard drain that became the prototype for
33
p ypall subsequent wick drains.
Walter Kjellman, 1950
Important Points
Build-up of Back Pressure
The consolidation process can be halted if back-pressure is let to build-up below the embankment, falsely implying that the process is completed
3434
Flow in a soil containing pervious lenses, bands, or layers Theoretically, vertical drains operate by facilitating horizontal drainage. However, where pervious lenses and/or horizontal seams or bands exist, the water will drain vertically to the pervious soil and then to the drain. When this is at hand, the drain spacing can be increased significantly.
Pervious seams (silt or sand) will dry faster than the main body of clay. The pervious seams can be observed in a Shelby sample during the drying process, as indicated in the photos.
3535
p
CPTU soundings with readings every 10 mm can also disclose the presence of sand and silt seams (if they are thicker than about 10 mm; which the illustrated small seams are not).
How deep do the wick drains have to be installed?
In theory, the drains do not need to go deeper than to where the applied stress is equal to the preconsolidation stress.
However in practice it is a good rule to always go down to a
3636
However, in practice, it is a good rule to always go down to a pervious soil layer (aquifer) to ensure downward drainage. But, if the surcharge is by vacuum treatment or combined with vacuum treatment, it is better to avoid having the drains in an aquifer, or they would "suck".
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3/24/2013
7
3737
The Kjellman wick, 1942 The Geodrain, 1972
3838
The Geodrain, 1976
Wick drain types
The Burcan Drain, 1978
The Mebra Drain 1984 (a development of the
Castleboard Drain 1979)
3939
0
5
10
15
20
25
30
35
40
0 100 200 300Pore Pressure (KPa)
Dep
th (
m)
Wick Drains Installed
m)
Settlement at center of a 3.6 m high embankment BangkokAirport. Wick drains at c/c 1.5 m were installed to 10 m depth.
PORE PRESSUREEnlarged
40
AVERAGE MEASURED SETTLEMENT
DESIGN CURVE FOR THISSURCHARGE (75 KPa)
1.0 m
FINAL HEIGHTOF FILL
SET
TLEM
ENT
(mm
)
200 days
FILL
HEI
GH
T (m
CalculatedTotalSettlements
Settlement and Horizontal Displacement for the 3.6 m Embankment
WICK DRAINS TO 10 m DEPTHWICK DRAINS TO 10 m DEPTH
Settlement was monitored in center and at embankment sides and horizontal displacement was monitored near sides of embankment
Note the steep slopes
4141
Time from start to end of surcharge placement = 9 monthsObservation time after end of surcharge placement = 11 months
1.0 m
2.0 m
WICK DRAIN
Moh and Lin 2006
Horizontal Displacement versus Settlement at Different Test Locations
OVE
MEN
T (c
m)
4242
HOR
IZO
NTA
L M
O
SETTLEMENT (cm)
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3/24/2013
8
Secondary Compression
1000
log1 t
te
C +=The value of the Coefficient of Secondary Compression, C, is usually expressed as aratio to the consolidation coefficient, Cc, ranging from 0.02 through 0.07 with an averageof about 0.05 (Holtz and Kovacs 1981). For example, in a soft clay with Cc of about 0.3
d f b t it (i d l b f 15) C ld b b t 0 01
4343
and e0 of about unity (i.e., a modulus number of 15), C, would be about 0.01.
The key parameter, however, it the t100 value, the time it takes for 100 % of consolidation (or 90 %, more realistically) to develop. Also when using wick drains, the 100-% should be the time for vertical drainage, not horizontal.
It is commonly assumed that secondary compression does not start until primary consolidation is completed; U = 100 %. However, the consensus amongst the experts is that secondary compression starts as soon as a change of effective stress has been triggered, i.e., it starts at at 0 % consolidation.
The purpose of calculating stresses is to calculate settlement. The following showssettlements calculated from the Boussinesq distribution. how stress applied to thesoil from one building affect the settlement of an adjacent existing 'identical'building loaded the same constructed about 5 years before.
EXISTING ADJACENT BUILDING
NEW BUILDING
WITH SAME LOAD OVER FOOTPRINT
AREA
The 2nd building was constructed five years after the 1st building. The 1st building had then settled about 80 mm (3 inches), which was OK albeit close to what was felt to be
4444The soils consist of preconsolidated (OCR = 2) compressible silt and clay
6.5 m6.5 m 4 m m
1st Building
2nd Building
was OK, albeit close to what was felt to be acceptable. Did the construction of the 2nd building add settlement to the 1st, and what was the settlement of the 2nd building?
(Because the buildings are on raft foundation, the characteristic point is the most representative point for the settlement calculations).
The settlement of the first building calculated using UniSettle Version 4
0 2 4 6 8 10YEARS
SETTLEMENT OVER TIME
4545
020406080
100120
0 2 4 6 8 10
SETT
LEM
ENT
(mm
)
2nd Building constructed
Calculations using Boussinesq distribution can be used to determine how stressapplied to the soil from one building may affect an adjacent existing building(having the same loading as the new building).
0
5
0 20 40 60 80 100
STRESS (%)
STRESSES UNDER AREA
BETWEEN THE TWO BUILDINGS
EXISTING ADJACENT BUILDING
NEW BUILDING
WITH SAME LOAD OVER FOOTPRINT
AREA
4646
10
15
20
25
30
DEP
TH (
m)
STRESSES ADDED TO THOSE UNDER THE FOOTPRINT OF THE ADJACENT BUILDING
STRESSES UNDER THE FOOTPRINT OT THE LOADED BUILDING
TWO BUILDINGS
Calculations by means of UniSettleThe soils consist of preconsolidated
moderately compressible silt and clay
6.5 m6.5 m 4 m m
Calculations using Boussinesq stress distribution can be used to determine howstress applied to the soil from one building may affect an adjacent existing building(having the same loading as the new building).
EXISTING ADJACENT BUILDING
NEW BUILDING
WITH SAME LOAD OVER FOOTPRINT
AREA
0
5
10
0 20 40 60 80 100
STRESS (%)
STRESSES UNDER THE AREA
BETWEEN THE TWO BUILDINGS
PRECONSOLIDATION MARGIN (Reducingwith depth)
4747The soils consist of preconsolidated moderately compressible silt and clay. The preconsolidation margin reduces with depth.
6.5 m6.5 m 4 m m
10
15
20
25
30
DEP
TH (
m)
CENTER STRESSES COMBINED
STRESSES UNDER THE FOOTPRINT OF THE LOADED BUILDING
STRESSES FROM LOADED BUILDING CALCULATED UNDER THE FOOTPRINT OF THE ADJACENT BUILDING
Settlement distributions (UniSettle Version 4)
0
5
10
0 20 40 60 80 100 120
SETTLEMENT (mm)
1st ONLY
Increase due to 2nd Bldng BOTHSand &
Gravel
Silty Clay
0
5
10
0 20 40 60 80 100 120
SETTLEMENT (mm)
Of ground due to 1st Bldng only
Due to 2nd Bldng
4848
15
20
25
30
35
DEP
TH (
m)
1st BUILDING
Soft Clay 15
20
25
30
35
DEP
TH (
m)
2nd BUILDING
-
3/24/2013
9
-83 KPa
105 KPa
34 KPa
85 KPa
105 + 34 + 85 = 224 - 83 141 KPa
110 m
38 m74 m
MORE ON SETTLEMENT
YEARYEAR
49
Briaud et al. 2007; Fellenius and Ochoa 2008
0
50
100
150
200
250
300
350
4001936 1946 1956 1966 1976 1986 1996 2006
YEAR
SETT
LEM
ENT
(m
m)
.
0
50
100
150
200
250
300
350
400
1 10 100
SETT
LEM
ENT
(mm
)
1936 1937 1940 1945 1950 1960 1975 2000
LINEAR PLOTLOWER SCALE
LOGARITHMIC PLOTUPPER SCALE
1936 1946 1956 1966 1976 1986 1996 2006
0
20
40
60
80
100
120
140
YEAR
WA
TER
DEP
TH (
m)
132a- 14m217 - 26m216a- 39m115 -153m209 -159m111 -161m501a-180m912 -206m114a-261m618 -267m606 -301m501b-365m132b-442m114b-480m
1925 1935 1945 1955 1965 1975 1985 1995 2005 2015
SHALLOW WELLS
DEEP WELLS
Water Depths Measured in Deep Wells
50
Monument and Well Locations
Well head at Burnett School, Baytown, Texas
YEAR
51
0
50
100
150
200
250
300
350
400
1 10 100
YEAR
SE
TTLE
ME
NT
(mm
)
1936 1937 1940 1945 1950 1960 1975 2000
DEPTH TO WATER TABLE
SETTLEMENT
0
25
50
75
100
125
DEP
TH T
O W
ATE
R T
AB
LE (
m)
San Jacinto MonumentSettlement and Measured Depths to Water in the Wells Plotted Together
1925
The lowering of the pore pressures due to mining of water and subsequent regionalsettlement is not unique for Texas. Another such area is Mexico City, for example.Here is a spectacular 1977 photo from San Joaquin, California.
52
1977
1955
Subsidence at San Joaqu in Valley, California
0.0
0.5
1.0
1920 1930 1940 1950 1960 1970 1980 1990 2000 2010
YEAR
ent
(m)
I II III IV
5353
1.5
2.0
2.5
Settl
eme
NEW ORLEANS 1924 - 1978
I. Initial Period of Pumping II. Increased Pumping III. Further Increased IV. Reduced Pumping
Data from Kolb, C.R. and Saucier, RT., 1982
Site Investigation Techniques
The SPT and the CPT/CPTu
-
3/24/2013
10
The SPTExample from Atlantic coast of South USA
0
5
10
15
0 20 40 60 80 100
SPT N-Indices (bl/0.3m)
0
5
0 10 20 30 40 50
SPT N-Indices (bl/0.3m)
5555
20
25
30
35
40
45
50
DEP
TH (
m)
East Abutment
10
15
20
25
DEP
TH (
m)
DETAIL
0
10
20
30
40
0 20 40 60 80 100
N-Index (bl/0.3m)
H (
m)
0
10
20
30
40
0 20 40 60 80 100
N-Index (bl/0.3m)
H (
m)
0
10
20
30
40
0 20 40 60 80 100
N-Index (bl/0.3m)
H (
m)
Example from Atlantic coast of
Canada
5656
40
50
60
70
80
DE
PT 40
50
60
70
80
DE
PT 40
50
60
70
80
DE
PT
SPT for design After problems arose
Forensics
0
10
20
30
0 20 40 60 80 100
N-Index (bl/0.3m)
m)
With all data points
5757
30
40
50
60
70
80
DE
PTH
(m
0.010
0.100
1.000
mv (
1/M
Pa)
30405060708090
100
Mod
ulus
(M
Pa)
Direct numerical use of the SPT N-index
5858
0.0011 10 100
N60-Index (bl/0.3m)
01020
0 10 20 30 40 50N60-Index (bl/0.3m)
(after Terzaghi, Peck, and Mesri 1996 from Burland and Burbidge 1985)
Determining pile Capacity from SPT-indices
0
5
10
15
0 10 20 30 40
SPT N-Index (bl/0.3m)
(m)
0
5
10
15
0 10 20 30 40
SPT N-Index (bl/0.3m)
(m)
0
5
10
15
0 10 20 30 40Cone Stress, qt (MPa)
(m)
5959
20
25
30
35
DEP
TH (
Estimated required depth
20
25
30
35
DEP
TH (
Potentially possible depth
Estimated required depth1
2
Pile 1 had a much smaller capacity than Pile 2!
20
25
30
35
DEP
TH (
N (bl/ft)
Pile 1 had a much smaller capacity than Pile 2!
2
1
Principles of the CPT and CPTU
The Cone Penetrometer
606060
Sleeve friction, fs
Pore PressureU2 position
Cone Stress, qc
U2 Position = pore pressure measured on the cone shouldercone shoulder
-
3/24/2013
11
616161 626262
6363 6464
Continuous cores samples obtained by pushing down a pipe having an inside plastic tube. On withdrawal and cutting the tube open, the soil sample is available in a better condition than a sample in a SPT-spoon.
Courtesy of Pinter and Associates, Saskatoon, SK.
0
10
0 10 20 30
INCLINATION ANGLE ()
(m)
0
10
0 2 4 6 8
RADIAL DEVIATION (m)
(m)
0
10
0.0 0.3 0.5 0.8 1.0
DEPTH DEVIATION (m)
(m)
The CPT sounding rod is never truly vertical, of course.
How much can it be off?
6565
20
30
40
50
AC
TUA
L D
EPTH
20
30
40
50
AC
TUA
L D
EPTH
20
30
40
50
AC
TUA
L D
EPTH
5
10
15
20
25
Y-D
irect
ion
(m)
20.6 m
PLAN VIEW
"Unfolded"
0
10
20
30
40
50
0 1 2 3 4
DEPTH DEVIATION (m)
EPTH
(m
)
0
10
20
30
40
50
0 5 10 15 20 25
RADIAL DEVIATION (m)
EPTH
(m
)
6666
-5
0
-5 0 5 10 15 20 25
X-Direction (m)
Example 2
60
70
80
90
100
DE
60
70
80
90
100
DE
Inclination plane
X-plane Y-plane
-
3/24/2013
12
0
5
10
15
0 10 20 30Cone Stress, qt (MPa)
TH (
m)
0
5
10
15
0 100 200
Sleeve Friction (KPa)TH
(m
)
0
5
10
15
0 100 200 300 400
Pore Pressure (KPa)
TH (
m)
0
5
10
15
0.0 1.0 2.0 3.0 4.0
Friction Ratio (%)
TH (
m)
CLAY CLAYCLAY
6767
20
25
30
DEP
T 15
20
25
30
DEP
T 15
20
25
30
DEP
T
20
25
30
DEP
T
SILT SILT SILT
SAND SAND SAND
Results of a CPTU sounding
Soil profilingApplications
6868The Begemann original profiling chart (Begemann, 1965)
1
10
100
Con
e St
ress
, qt
(MPa
)
4
56
7
8
9
10
11
12
Friction Ratio from 0.1 % through 25 %
6969
Profiling chart per Robertson et al. (1986)
01 10 100 1,000
Sleeve Friction (KPa)
C
12
3 25 %
7070Profiling chart per Robertson (1990)
1
10
100
Con
e St
ress
, qE
(MPa
) 5 1 = Very Soft Clays, or Sensitive or Collapsible Soils 2 = Clay and/or Silt 3 = Clayey Silt and/or Silty Clay 4a = Sandy Silt 4b = Silty Sand 5 = Sand to Sandy Gravel
3
4
7171
0.11 10 100 1,000
Sleeve Friction (KPa)
1 2
The Eslami-Fellenius profiling chart (Eslami 1996; Eslami and Fellenius, 1997)
Example of a CPTU sounding from a river estuary delta (Nakdong River, Pusan, Korea)
0
10
20
30
0 10 20 30Cone Stress, qt (MPa)
DEP
TH (
m)
0
10
20
30
0 200 400
Sleeve Friction (KPa)
DEP
TH (
m)
0
10
20
30
0 250 500 750 1,000
Pore Pressure (KPa)
DEP
TH (
m)
0
10
20
30
0 1 2 3 4 5
Friction Ratio (%)
DEP
TH (
m)
Profile
Mixed
CLAY
7272
The sand layer between 6 m and 8 m depth is potentially liquefiable.The clay layer is very soft.
The sand below 34 m depth is very dense and dilative, i.e., overconsolidated and providing sudden large penetration resistance to driven piles and relaxation problems.
30
40
50
30
40
50
30
40
50
30
40
50
SAN
Reduced pore pressure (dilation)
SAND
-
3/24/2013
13
1
10
100
one
Stre
ss, q
E (M
Pa)
5
3
4
7373
0.11 10 100 1,000
Sleeve Friction (KPa)
Co
1 2
The CPTU data of the Preceding Slide plotted in an Eslami-Fellenius Chart
The CPTU is an excellent and reliable tool for soil identification, but there is more to geotechnical site
investigation than just establishing the soil type.
And, the CPTU can deliver much more than soil profiling
7474
Liquefaction7.4 Magnitude Earthquake of August 17, 1999
Kocaeli, Adapazari, Turkey
7575
Photos courtesy of Noel J. Gardner, Ottawa
7676
Photo courtesy of Noel J. Gardner, Ottawa
dv
v rg
aCSR 'max65.0
=CSR = Cyclic Stress Ratio
For earthquakemagnitude of 7.5
An earthquake generates a Cyclic Stress Ratio, CSR
Assessment of liquefaction risk fromresults of a CPTU sounding
7777
amax = maximum horizontal acceleration at ground surface (m/s2)
g = gravity constant (m/s2)
v = total overburden stress (Pa)
'v = effective overburden stress (Pa)
rd = stress reduction coefficient for depth (dimensionless)
z = depth below ground surface (m)
CRR
The safety against liquefaction depends on the Cyclic Resistance Ratio, CRR, determined from the CPTU data
7878
CSRCRRFs = For earthquake magnitude of 7.5
-
3/24/2013
14
KPaqforqCRR cc 5005.0100833.0 11
-
3/24/2013
15
0
1
2
3
4
5
0 5 10 15Cone Stress (MPa)
TH (
m)
0
1
2
3
4
5
0 10 20 30 40 50Sleeve Friction (KPa)
TH (
m)
0
1
2
3
4
5
0 50 100 150 200Pore Pressure (KPa)
TH (
m)
0
1
2
3
4
5
0.0 0.1 0.2 0.3 0.4 0.5Friction Ratio (%)
TH (
m)
7 Days7 Days
Before
8585
6
7
8
9
10
DE
PT
6
7
8
9
10
DE
P
6
7
8
9
10
DE
PT
6
7
8
9
10
DE
PT
7 DaysBeforeBefore
Geometric average values of cone stress, sleeve friction, and friction ratios andmeasured pore pressures from CPTU soundings at Chek Lap Kok Airport beforeand seven days after the vibratory compaction.
Fs versus depth0
1
2
3
4
5
0.00 1.00 2.00 3.00 4.00 5.00
Factor of Safety, Fs (--)
PTH
(m
)
Before Compaction
7 Days after
CSRCRRFs =
8686
Factor of safety against liquefaction before and after vibratory compaction
6
7
8
9
10
DEP compaction
CPT and CPTU Methods
for Calculating the Ultimate
Resistance (Capacity) of a Pile
Schmertmann and Nottingham (1975 and 1978)
8787
Meyerhof (1976)
deRuiter and Beringen (1979)
LCPC, Bustamante and Gianeselli (1982 )
Eslami and Fellenius (1997 )
ICP, Jardine, Chow, Overy, and Standing (2005)
But we will save those methods for later
Vibrations from Pile Driving
v = 433 EhZ P
M g hr
= 433 EhZ P
M g hx2 + z2
V = vertical component of the ground vibration, m/sEh = hammer efficiency coefficientZP il i d N /
88
ZP = pile impedance, Ns/mM = hammer (ram) mass, NG = acceleration, m/s2H = hammer height-of-fall, m, taken as the equivalent
height-of-fall that corresponds to the kinetic energyat impact
z = pile penetration depth, mx = horizontal distance at the ground surface from pile
to observation point, m
Most ground vibrations are generated from the pile toe
6
8
10
12
14
16
18
20
brationVelocity,
v0(m
m/s)
89
0
2
4
0 5 10 15 20 25 30 35 40 45 50
Distancetopiletoe,r(m)
Vi
Vibrations from driving a long toe bearing pile: measured compared to calculated
-
3/24/2013
1
BASICS OF DESIGN OF PILED
FOUNDATIONS
Bengt H Fellenius
1
Bengt H. Fellenius
Load Transfer and Capacity of Piles
Bolivia, April 25, 2013 22Driving closed-toe pipe piles into fine sand about 2.5 m above the groundwater table
33Driving 12-inch precast concrete pile into clay for Sidbec in 1974
Head measured in aquifer below the clay layer
44Svrta River 1969
GW
What really is Capacity?
For piles, capacity is
what we determine in
55
define from
a loading test
?
e.g.: The Offset Limit Load (Davisson, 1972)
Do you agree that this pointon the curve represents thecapacity of the pile?
Qu
Qu
66
Rs
Rt
-
3/24/2013
2
NbNqNcr qcu '5.0'' ++=and for Footings?
The Bearing Capacity Formula
where ru = ultimate unit resistance of the footingc = effective cohesion interceptB = footing width b d ff ti t t th f d ti l l
77
q = overburden effective stress at the foundation level = average effective unit weight of the soil below the foundation
Nc, Nq, N = non-dimensional bearing capacity factors
The main factor is the
Nq
Nq
88
Nq
But what is the reality?
Results of static loading tests on 0.25 m to 0.75 m square footings in well graded sand (Data from Ismael, 1985)
400
500
600
700
D
( KN
)
1.00 m
0.75 m
0.50 m
0.25 m
1,000
1,200
1,400
1,600
1,800
2,000
S S
( K
Pa
)
Normalized
99
0
100
200
300
0 10 20 30 40 50
SETTLEMENT (mm)
L O
A D
MOVEMENT
0
200
400
600
800
,
0 5 10 15 20
MOVEMENT/WIDTH (%)
S T
R E
S
1.00 m
0.75 m
0.50 m
0.25 m
Normalized
0
2
4
0 5 10 15 20Cone Stress, qt (MPa)
0
2
4
0 100 200 300 400
Sleeve Friction, fs (KPa)
0
2
4
0 20 40 60 80
Pore Pressure (KPa)
0
2
4
0 1 2 3 4 5
Friction Ratio, fR (%)
SAND
CPTU PROFILE
Load-Movement for Five Footings on Sandat Texas A&M University Experimental Site.
J-L. Briaud and R.M. Gibbens, 1994, ASCE GSP 41,
10
6
8
10
12
14
16
DEPT
H (
m)
6
8
10
12
14
16
DEPT
H (m
)
6
8
10
12
14
16
DEP
TH (
m)
6
8
10
12
14
16
DEPT
H (m
)
SANDY CLAYEY SILT
Eslami- RobertsonFellenius
As before the data will tell usmore, if we divide the load withthe footing area (to get stress)and divide the movement withthe footing width, as follows.
Load-Movement of Four Footings on SandTexas A&M University Experimental Site
ASCE GSP 41, J-L Briaud and R.M. Gibbens 1994
8,000
10,000
12,000
N )
3.0 m
3.0 m 1,400
1,600
1,800
2,000
KPa
)
Texas A&MSettlement Prediction Seminar
11
0
2,000
4,000
6,000
,
0 50 100 150 200
MOVEMENT ( mm )
L O
A D
(
KN
1.5 m
1.0 m
2.5 m
0
200
400
600
800
1,000
1,200
0 5 10 15 20
MOVEMENT / WIDTH (%)
S T
R E
S S
(
Load-Movement of Four Footings on SandTexas A&M University Experimental Site
ASCE GSP 41, J-L Briaud and R.M. Gibbens 1994
8,000
10,000
12,000
N )
3.0 m
3.0 m1,600
2,000
)
e
QQ
=
2
1
2
1
e = 0.4
q-z curve:
We can also borrow from pileanalysis (Pile toe response) andapply a q-z function to the stress-movement data. The "Ratio" functionis applied here.
Texas A&MSettlement Prediction Seminar
12
0
2,000
4,000
6,000
,
0 50 100 150 200
MOVEMENT ( mm )
L O
A D
(
KN
1.5 m
1.0 m
2.5 m
0
400
800
1,200
0 5 10 15 20MOVEMENT/WIDTH, (%)
STR
ESS,
(KPa
)
-
3/24/2013
3
Lehane et al. 2008Settlement Prediction Seminar
200
250
300
350
400
450
500
OA
D (
KN
)
1.0 m 1.5 m
1.0 m
200
300
400
500
RES
S (K
Pa)
1.0 m
13
Lehane, B.M., Doherty, J.P., and Schneider, J.A., 2008. Settlement prediction for footings on sand. Conference on Deformational Characteristics of Geomaterials. S.E. Burns, P.W. Mayne, and J.C. Santamarina (Editors), Atlanta, September 22-24, 2008, Vol. 1, pp.133-150.
0
50
100
150
0 10 20 30 40 50
MOVEMENT (mm)
L
0
100
0 1 2 3 4 5 6 7 8
MOVEMENT / WIDTH (%)
STR
Footing, 1.5 mFooting 1.0 mFooting 1.0 m
Six footings on gravel
Caisson under air pressure to control water level.
GW//\\//\\//\//\\//\\ //\\//\\//\//\\//\\
14 m16 m
6,000
8,000
10,000
12,000
14,000
TRES
S (K
Pa)
0.3 x 0.3
14Kusakabe, O., Maeda, Y., and Ohuchi, M., 1992. Large-scale loading tests of shallow footings in pneumatic caisson. ASCE Journal of Geotechnical Engineering, 118(11) 1681-1695.
"SCORIA" = Sandy GRAVEL, trace fines. An "interlocked" and highly overconsolidated volcanic soil.
e0 = 1.2, wn = 40 %, = 1,800 kg/m3
``W
Footing test
!?
0
2,000
4,000
0 5 10 15 20 25 30 35 40
NORMALIZED MOVEMENT (%)
ST
0.3 x 0.30.4 x 0.40.7 X 0.71.3 X 1.30.4 X 1.20.4 X 2.0
8,000
10,000
12,000
14,000
ESS
(KPa
)
Considering the "Preloading"/"Reloading"/"Prestress" Effect
15
0
2,000
4,000
6,000
0 5 10 15 20 25 30 35 40
NORMALIZED MOVEMENT (%)
STR
E
0.3 x 0.30.4 x 0.40.7 X 0.71.3 X 1.30.4 X 1.20.4 X 2.0
Data from Kusabe et al. 1992
Plate loading tests on 0.55 m x 0.65 m and 1.10 m x 1.30 m rectangular slabs in silty sand at Kolbyttemon, Sweden
1,500
2,000
(KPa
)
TREND1 1m x 1 3m
16Fellenius (2011). Data from Bergdahl, U., Hult, G., and Ottosson, E. (1984)
0
500
1,000
0 1 2 3 4 5 6 7 8 9 10MOVEMENT (%)
STR
ESS
0.55m x 0.65m
1.1m x 1.3m
Ultimate Shaft Resistance
rs, RsUltimate Shaft Resistance
is a reality
1717
Ultimate Toe Resistance does not exist other than as a definition of load at a certain movement
rt, Rt
Ultimate Toe Resistance does not exist other than as a definition of load at a certain movement
Ultimate Toe Resistance is not
50
100
150
200
AG
E S
HA
FT S
HEA
R(K
Pa)
O-cell to GL3
GL3 to GL1Pile D2000
2,000
3,000
4,000
RA
GE
STR
ESS
AN
DSH
EAR
(K
Pa)
Toe Resistance
Pile D2000
Shaft and toe resistances from full-scale static loading tests on a 2,000 m diameter, 85 m long bored pile in silty clay
Shaft Resistance Toe Resistance
1818
0
50
0 20 40 60 80 100
MOVEMENT (mm)
AVE
R
0
1,000
0 20 40 60 80 100MOVEMENT (mm)
AVE
R S
Shaft resistances(repeated for reference)
The above curve shows the shape of theload-movement every toe resistance."Ultimate Toe Resistance" does not exist!
A pile toe reacts to load by a stiffnessresponse and failure does not occurhowever much the pile toe is moveddown.
-
3/24/2013
4
Pile capacity is the combined effect of shaft resistance and toe resistance.
Shaft resistance is governed by shear strength, which has an ultimate value. That is, shaft capacity is reality.
In contrast, toe resistance is governed by
1919
In contrast, toe resistance is governed by compression, which does not have an ultimate value. As the load is increased, a larger and larger soil volume is stressed to a level that produces significant compression, but no specific failure or peak value: Toe capacity is a delusion.
Analysis Methods for Determining Shaft Resistance, rs
The Total Stress Method
The Lambda Method
Th SPT M th d
2020
The SPT Method
The CPT and CPTU Methods
The Pressuremeter Method
The Beta Method
where rs = unit shaft resistance
u = undrained shear strength = reduction coefficient for u > 100 KPa
[ ]uusr ==
Piles in Clay
Total Stress Method
"Alpha analysis"
2121
The undrained shear strength can be obtained from unconfined compression tests, field vane shear tests, or, to be fancy, from consolidated, undrained triaxial tests. Or, better, back-calculated from the results of instrumented static loading tests. However, if those tests indicate that the unit shaft resistance is constant with depth in a homogeneous soil, dont trust the analysis!
2222
Clay adhering to extracted piles
Photo courtesy of K.R. Massarsch
The Lambda MethodVijayvergia and Focht (1972)
)2'( mms cr += where rm = mean shaft resistance along the pile
= the lambda correlation coefficientm = mean overburden effective stresscm = mean undrained shear strength
Piles in Clay
2323
Approximate Values of Embedment (Feet) (m) (-)
0 0 0.5010 3 0.3625 7 0.2750 15 0.2275 23 0.17
100 30 0.15200 60 0.12
The Lambda method was developed for long piles in clay deposits (offshore conditions)
{ } 'tan')/2()()(lg87.0)(016.02.28.0 2.042.0 zts bhOCRSOCRr +=where rs = unit shaft resistance
OCR = overconsolidation ratioSt = sensitivity
Piles in Clay
A method from fitting a variety of parameters to results from static loading tests
2424ICP (Imperial College Pile method)
Jardine, Chow, Overy, and Standing (2005 )
h = height of point above pile toe ; h 4bb = pile diameter = interface friction angle
-
3/24/2013
5
The SPT MethodMeyerhof (1976)
Rs = n N As D
where Rs = ultimate shaft resistance
n = a coefficient
N = average N-index along the pile shaft (taken as a pure number)
Piles in Sand
2525
g g p ( p )
As = unit shaft area; circumferential area
D = embedment depth
n = 2103 for driven piles and 1103 for bored piles (N/m3)[English units: 0.02 for driven piles and 0.01 for bored piles (t/ft3)]
For unit toe resistance, Meyerhof's method applies the N-index at the pile toe times a toe coefficient = 400103 for driven piles and 120103 for bored piles (N/m3)
[English units: 4 for driven piles and 1 for bored piles (t/ft3)]
CPT and CPTU Methods
for Calculating the Ultimate
Resistance (Capacity) of a Pile
Schmertmann and Nottingham (1975 and 1978)
2626
deRuiter and Beringen (1979)
Meyerhof (1976)
LCPC, Bustamante and Gianeselli (1982 )
ICP, Jardine, Chow, Overy, and Standing (2005)
Eslami and Fellenius (1997 )
caOCRt qCr =The CPT and CPTU Methods
where rt = pile unit toe resistance (NK = a dimensionless coefficient, ranging from 15
through 20, reflecting local experience = adhesion factor equal to 1.0 and 0.5 for
normally consolidated and overconsolidatedclays, respectively
An upper limit of 15 MPa is imposed for rt
k
cu N
qS =Stress method
LCPC Bustamante and Gianeselli (1982 )
cs qKr =cat qCr =
3030
C = toe coefficient ranging from 0.40 through 0.55qca = cone stress averaged in a zone 1.5 b above and
1.5 b below the pile toe plus filtering
rt = pile unit toe resistance < 15 KPa,
-
3/24/2013
6
Soil Type Cone Stress Bored Piles Driven Piles Maximum rtCLCPC CLCPC
(MPa) (- - -) (- - -) (MPa)
CLAY - - qc < 1 0.04 0.50 15
Coefficients and Limits of Unit Toe Resistance in the LCPC Method Quoted from the CFEM (1992)
3131
c
1 < qc < 5 0.35 0.45 15
5 < qc - - - 0.45 0.55 15
SAND - - - qc < 15 0.40 0.50 15
12 < qc - - - 0.30 0.40 15
Soil Type Cone Stress Concrete Piles Steel Piles Maximum rs(MPa) & Bored Piles
KLCPC KLCPC J
(- - -) (- - -) (KPa)
CLAY - - qc < 1 0.011 (1/90) 0.033 (=1/30) 15
1 5 0 025 (1/40) 0 011 ( 1/80) 35
Coefficients and Limits of Unit Shaft Resistance in the LCPC Method Quoted from the CFEM (1992)
3232
1 < qc < 5 0.025 (1/40) 0.011 (=1/80) 35
5 < qc - - - 0.017 (1/60) 0.008 (=1/120) 35
SAND - - - qc < 5 0.017 (1/60) 0.008 (=1/120) 35
5 < qc < 12 0.010 (1/100) 0.005 (=1/200) 80
12 < qc - - - 0.007 (1/150) 0.005 (=1/200) 120
The values in the parentheses are the inverse of the KLCPC-coefficient
cac
t qdbr )5.01( =
cJs qKr = ' b
ICP (Imperial College Pile method)Jardine, Chow, Overy, and Standing (2005 )
3333
tan)')()'(0145.0( 38.013.0 m
tr
zcJ h
bqK +=
bq
qqrz
rzccmc 01.0)]
'(10216.1)'(00125.00203.0(2[' 1
265.0 +=
Egtt qCr =Eslami and Fellenius
(1997 )
Ess qCr =rt = pile unit toe resistance
Ct = toe correlation coefficient (toe adjustment factor)equal to unity in most cases
Shaft Correlation Coefficient
Soil Type*) Cs
Soft sensitive soils 8 0 %
bCt 3
1=
bCt
12=
b in metre
b in inch
3434
qEg = geometric average of the cone point resistance over the influence*) zone after correction for pore
pressure on shoulder and adjustment to effective stress rs = pile unit shaft resistanceCs = shaft correlation coefficient, which is a function of soil
type determined from the soil profiling chartqE = cone point resistance after correction for pore pressure
on the cone shoulder and adjustment to effective stress
*) The Influence zone is 8b above and 4b below pile toe
Soft sensitive soils 8.0 %Clay 5.0 %Stiff clay andClay and silt mixture 2.5 %Sandy silt and silt 1.5 %Fine Sand and silty Sand 1.0 %Sand to sandy gravel 0.4 %
*) determined directly from the CPTU soil profiling
Unit shaft resistance as a function of cone stress, qc in Sandaccording to the LCPC method and compared to the Eslami-Fellenius method
100
120
140
ce, r
s (K
Pa)
Sandy Silt to silty Sand to sandy Gravel
Concrete
Range for the Eslami Fellenius method
3535
0
20
40
60
80
0 5 10 15 20 25 30 35 40
Cone Stress, qc (MPa)
Uni
t Sha
ft R
esis
tan piles
Steel piles
PILES IN SAND
Cone Stress, qc and qt (MPa)
Pile Capacity or, rather, Load-Transfer follows
principles of effective stress
3636
principles of effective stress and is best analyzed using the
Beta method
-
3/24/2013
7
the Beta method
Unit Shaft Resistance, rs zs
r '=where c = effective cohesion intercept
= Bjerrum-Burland coefficient'z = effective overburden stress
Effective Stress Analysis (Beta-analysis as opposed to Alpha analysis)
3737
dzcAdzrAR zssss )''( +==Total Shaft Resistance, Rswhere As = circumferential area of the pile at Depth z
(surface area over a unit length of the pile)
Shaft Resistance in Sand and in Clay
KMr ''tan =
vsr '=
3838
where rs = unit shaft resistance
M = tan / tan Ks = earth stress ratio = h / vv = effective overburden stress
vss KMr tan =
Approximate Range of Beta-coefficients
SOIL TYPE Phi Beta
Clay 25 - 30 0.20 - 0.35
Silt 28 - 34 0.25 - 0.50
Sand 32 - 40 0.30 - 0.90
Gravel 35 - 45 0.35 - 0.80
0.05 - 0.80 !
3939
Gravel 35 45 0.35 0.80
These ranges are typical values found in some cases. In any given case,actual values may deviate considerably from those in the table.
Practice is to apply different values to driven as opposed to bored piles, but ....
2.0
3.0
4.0
5.0
6.0
coef
ficie
nt i
n s
and
G
Trend line
4040
0.0
1.0
0 5 10 15 20 25 30
LENGTH IN SOIL (m)
-c
HK GEO (2005)CFEM (1992)
Gregersen et al. 1973
Beta-coefficient versus embedment length for piles in sand (Data from Rollins et al. 2005). Ranges suggested by CFEM (1993), Gregersen et al 1973, and Hong Kong Geo (2005) have been added.
1.00
1.50
2.00
2.50
OEF
FIC
IEN
T IN
SA
ND
Concrete piles
Open-toe pipe piles
Closed-toe pipe piles
Gregersen
4141
0.00
0.50
0 50 100 150 200 250 300 350
AVERAGE EFFECTIVE STRESS, 'z (KPa)
-C
O et al. 1973
Beta-coefficient versus average for piles in sand. (Data from Clausen et al. 2005).
1.00
1.50
2.00
2.50
FIC
IEN
T IN
SA
ND
Concrete piles
Open-toe pipe piles
Closed-toe pipe piles
4242
0.00
0.50
0.0 0.2 0.4 0.6 0.8 1.0 1.2
AVERAGE DENSITY INDEX, I D
-C
OEF
Beta-coefficient versus average ID for piles in sand. (Data from Karlsrud et al. 2005).
-
3/24/2013
8
0.20
0.30
0.40
0.50
0.60co
effic
ient
in
cla
y
Norway Japan Thailand Vancouver Alberta
4343
0.00
0.10
0 20 40 60 80
PLASTICITY INDEX, I P
-c
Beta-coefficient versus average IP for piles in clay. (Data from Karlsrud et al. 2005 with values added from five case histories).
c
CCI
CKr
vD
C eCe
K
tan'
ln100
10
24
302
=Where K = coefficient of earth stress at rest
I = density index (relative density)
The Beta-coefficient has a certain appeal to the academia it seems. This is what is proposed in a recent issue of the ASCE Journal.
44
ID = density index ( relative density )v = effective overburden stressr = reference stress = 100 KPa = triaxial-compression critical-state
friction angleC1 = a coefficient: 0.6< C1
-
3/24/2013
9
0
1
2
0 50 100 150
UNIT SHAFT RESISTANCE (KPa)
0
1
2
0 100 200 300 400 500 600 700 800
TOTAL SHAFT RESISTANCE (KN)
Pile CCPT-3
Calculations of unit and total shaft resistances for a pile driven into asaprolite (residual soil) in Porto, Portugal. The soil can be classified bothas a clay type and sand type.
Shaft resistance by CPT-methods
4949
3
4
5
6
DEP
TH (
m)
DutchSand
MeyerhofSand
LCPCSand
LCPCClay SchmertmannClay
Eslami-Fellenius
SchmertmannSand
DutchClay
TumayClaya
3
4
5
6
DEPT
H (
m)
Effective StressBeta = 1.00
DutchSand
MeyerhofSand
LCPCClay &Sand
SchmertmannClay
Eslami-Fellenius
SchmertmannSand
DutchClay
TumayClayb
0
1
2
0 200 400 600 800 1,000 1,200 1,400 1,600 1,800 2,000
CALCULATED PILE RESISTANCE (KN)
TumayClay
Eslami-Fellenius
SchmertmannClayDutch
Clay
LCPC
DutchSand
MeyerhofSand
Pile CCPT-3
Total resistance by CPT-methods
5050
3
4
5
6
DEP
TH (
m) Schmertmann
Sand
LCPCSand
LCPCClay
a
Lets look at a few case studies
Annacis/Lulu Island Tests, Vancouver,
BC
by UBC 1985
5151
Static loading tests on three 324 mm diameter pipe piles driven to depths of 14 m, 17 m, and 31 m into the Fraser River deltaic soils
0
5
10
15
20
0 5 10 15Cone Stress, qt (MPa)
PTH
(m
)
0
5
10
15
20
0 100 200
Sleeve Friction (KPa)
TH (
m)
0
5
10
15
20
0 500 1,000
Pore Pressure (KPa)
PTH
(m
)
0
5
10
15
20
0 1 2 3 4 5
Friction Ratio (%)
PTH
(m
)
PILES1 2 3 4
PROFILE
Eslami-Fellenius Robertson
CLAY CLAY
SANDSAND
SANDGRAVEL & SAND
CPT and CPTU analysis for capacity
5252
25
30
35
40
DEP
25
30
35
40
DEP
25
30
35
40D
EP
25
30
35
40
DEP
CLAY andSilty
CLAY
CLAY andSilty
CLAY
Annacis/Lulu Island Tests by UBC 1985
The results of the load-movement curves from all three tests combined in
600
800
1,000
1,200
OA
D (K
N)
Depth 16.8 mSet-up Time
85 days
Depth 31.1 mSet-up Time
38 days
5353Data from Lulu Island Tests
by UBC 1985
tests combined in one graph. (With offset limit lines and maximum load in the tests).
0
200
400
0 10 20 30 40
MOVEMENT (mm)
LO
Depth 13.7 mSet-up Time
197 days
Results of CPT and CPTU analysis compared tocapacity from the static loading tests
0
5
10
0 500 1,000 1,500 2,000
SHAFT RESISTANCE (KN)
Eslami-Fellenius
DutchLCPC
SchmertmannUniPile eff.stress
= 0 15
0
5
10
0 500 1,000 1,500 2,000
SHAFT and TOE RESISTANCEs (KN)
Eslami-FelleniusDutchLCPCSchmertmannUniPile eff. stressPile static tests
= 0.15
5454UniPile eff.stress is effective stress analysis matched to results of static tests
15
20
25
30
35
DEP
TH (
m)
= 0.15
= 0.20
= 0.15
15
20
25
30
35
DEP
TH (
m)
0.15 Nt = 7
= 0.20 Nt = 25
= 0.15 Nt = 3
Test too soon after EOID
-
3/24/2013
10
150
a)
O-cell to GL3 GL3 to GL2 GL2 to GL1O-cell to GL2 O-cell to GL1
Sunrise City Project, HoChiMinh City, Vietnam1,800 mm diameter bored piles constructed to 70 m depthUnit shaft resistances versus measured downward movement at depths of 50 m
150
Pa)
O-cell to GL4 GL4 to GL3 GL3 to GL2O-cell to GL3 O-cell to GL2 O-cell to GL1
SHAFT RESISTANCE
HoChiMinh
Ha Noi
Cai Mep Port
55
0
25
50
75
100
125
0 1 2 3 4 5 6 7 8 9 10
MOVEMENT (mm)
UN
IT S
HA
FT R
ESIS
TAN
CE
(KPa
TBP-1
Next reading was at 56 mm
= 0.14
0
25
50
75
100
125
0 1 2 3 4 5 6 7 8 9 10
MOVEMENT (mm)
UN
IT S
HA
FT R
ESI
STA
NC
E (K
P
TBP-2
= 0.13
Next reading was at 35 mm
No records were obtained during the sudden movement occurring at about 5 mm
0
500
1,000
1,500
2,000
2,500
0 50 100 150 200
MOVEMENT (mm)
UN
IT R
ESIS
TAN
CE
(KPa
)
TBP-1
Unit Toe Resistance
Unit Shaft Resistances
10% of diameter
TOE RESISTANCE
56
0
500
1,000
1,500
2,000
2,500
0 50 100 150 200
MOVEMENT (mm)
UN
IT R
ESIS
TAN
CE
(K
Pa)
TBP-2
TBP-1Unit Toe Resistance
Unit Shaft Resistances
The stiffness of the toe stress-movement is unusually soft for adense sand and typical of a pilehaving a layer of debris at the bottomof the shaft when the concrete wasplaced. A pile a few metre to the sidewas constructed using the samemethod and equipped with a coringtube. Coring through this pile toe intothe soil two weeks after constructionrevealed presence of about 30 mm ofsoft material between the pile and thesoil.
Core from the pile toe and into the soil below
57
Bridge over Panama Canal, Paraiso Reach, Republic of PanamaO-cell test on a 2.0 m (80 inches) diameter, 30 m (100 ft) deep shaft
drilled into the Pedro Miguel and Cucaracha formations, February 2003.
0
5
0 5,000 10,000 15,000 20,000 25,000 30,000
LOAD (KN)
0.30
0.45
5858
10
15
20
25
30
DEP
TH (
m) 0.30
___
1.20
O-cell Tests on an 11 m long, 460 mm square precast concrete pile driven in silica sand in
North-East Florida(Data from McVay et al 1999)
0
2
4
6
8
0 500 1,000 1,500 2,000 2,500 3,000
Shaft Resistance, Rs (KN)
(m
)
E-FLCPCSchmertmannDutchMeyerhofBetaTests
5959
(Data from McVay et al. 1999)
A study of Toe and Shaft Resistance
Response to Loading
10
12
14
16
18
20
DEP
TH
The foregoing analysis results are quite good predictions
They were performed after the test results were known
Such predictions are always the best!
So, what about true predictions?
6060
Lets see the results of a couple ofPrediction Events
p
-
3/24/2013
11
ULTIMATE R
Prediction Event at Deep Foundations Institute Conference in Raleigh, 1988
6161
44 ft embedment, 12.5 inch square precast concrete driven through compact silt and into dense sand
Capacity in Static Loading Test = 200 tonsRESISTANCE
TonsPREDICTORS (60 individuals)
1,500
2,000
2,500
ity (
KN
)
Orlando 2002 Predictions
Max LoadAvailable
6262
0
500
1,000
Predictors
Cap
ac
500
600
700
KN
)
0 20 40 60 80MOVEMENT (mm)
FHWA Washington, DC, 1986
273 mm diam. closed-toe pipe pile driven 9.1 m into hydraulic sand fill
6363
0
100
200
300
400
1 2 3 4 5 6 7 8 9 10PREDICTIONS
CA
PAC
ITY
( 800
1,000
1,200K
N)
0 2 4 6 8 10 12 14 16 18MOVEMENT (mm)
FHWA Baltimore, MD, 1980
Two 273 mm diam. closed-toe pipe piles driven 13.1 m into Beaumont clay
6464
0
200
400
600
800
PARTICIPANTS
CA
PAC
ITY
(K
1,500
2,000
2,500
3,000
3,500
OA
D (
KN
)
Singapore 2002
1,400
1,600
1,800
2,000
65
0
500
1,000
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33
L
400 mm H-Pile (168 kg/m) driven through sandy clay to a 15 m embedment
0
200
400
600
800
1,000
1,200
0 10 20 30 40 50MOVEMENT (mm)
LOA
D (
KN
)
Brazil 2004: Bored pile (Omega screw pile) 23 m long, 310 mm diameter
0
2
4
6
8
0 20 40 60 80
Water Content (%)
(m)
0
5
10
0 5 10 15 20 25N-Index (blows/0.3)
(m)
SPT 18at 23 m Pile
0
2
4
6
8
0 25 50 75 100
Grain Size (%)
(m)
SILT
SAND CLAY
Sandy SiltyCLAY (Laterite)
Sandy SILT
6666
10
12
14
16
18
20
DEP
TH
wnwP wLGW
15
20
25
DEP
TH
10
12
14
16
18
20
DEP
TH Sandy SILT
and CLAY
Sandy ClayeySILTGW
-
3/24/2013
12
Brazil 2004
Static Loading Test
on a 23 m 310 mm bored pile
Load-Movement Response
1,500
2,000
2,500
KN
)
Prediction Compilation
2,000
2,500PUSH L= 23m
0 5 10 15 20 25 30
MOVEMENT (mm)
6767
0
500
1,000
0 10 20 30 40
MOVEMENT (mm)
LOA
D (
K
0
500
1,000
1,500
PARTICIPANTS
LOA
D (
KN
)
Portugal 2004. Precast 350 mm diameter pile driven to 6 m depthin a saprolite, a residual soil consisting of silty clayey sand.
0
1
2
3
0 10 20Cone Stress, qt (MPa)
) 1 500
2,000
2,500
3,000
PAC
ITY
(KN
)
CAPACITY FROM STATIC LOADING TEST
Pile C1
6868
4
5
6
7
8
DEP
TH (
m
0
500
1,000
1,500
1PREDICTIONS
TOTA
L C
AP
0
OFFSET LIMIT LOAD
1,200
1,400
1,600
1,800
KN
)
Pipe-Pile
0 10 20 30 40MOVEMENT (mm)
Northwestern University, Evanston, Illinois, 1989.15 m embedment, 457 mm diameter closed-toe pipe piles driven in sand on clay.
6969
0
200
400
600
800
1,000
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
CA
PAC
ITY
(K
PREDICTIONS
Finno 1989
Edmonton, Alberta, 2011
Prediction of load-movement and capacity of a 400-mm diameter, 18 mlong, augercast pile constructed in transported and re-deposited glacial till.
2 000
3,000
4,000D
(KN
)E = 20 GPaE = 35 GPa
70
0
1,000
2,000
0 5 10 15 20 25 30 35 40 45 50
MOVEMENT (mm)
LOA
D
10 capacity predictions are at movements > 50 mm
7 mm (4 mm + b/120 mm)TEST RESULTS
Values
Rea
ltive
Fre
quen
cy
2
= Standard Deviation, = 833 = Mean, 1,923 / = Coefficient of Variation, COV = 0.43
Mean,
4
NORMAL DISTRIBUTIONEdmonton 2011
71
CAPACITY PREDICTIONS
T he area between - and + f ro m the mean value is 68% o f to tal areaT he area between -2 and +2 f ro m the mean value is 95% o f to tal areaT he area between -3 and +3 f ro m the mean value is 99% o f to tal area
0
100
200
0 10 20 30 40 50 60 70 80 90 100
PRED
ICTE
D L
OA
D =
100
MOVEMENT (mm)
NORMALIZED TO LOAD
Forthcoming Prediction Event in Bolivia April 2013
Four bored instrumented piles in sand tested in compression
0
5
2.9 m GW1.0 m
4.5 m
1.0 m
4.5 m
Groundsurface
TP1 TP2 TP3 TP4 "Std" FDP FDP "Std" +EB +O-cell +EB BH1 BH3 BH 4 BH2
0.0 m 400 mm 440 mm 400 mm 400 mm
72
5
10
15
20
25
DE
PTH
(m
)
1.2 m17.5 m 2.5 m
15.0 m
O-cell
EB EB
600 mm
5
7.5 m
10.5 m
13.5 m
16.5 m 15.8 m
4.5 m
7.5 m
10.5 m
13.5 m
Test Pile Configurations and Strain-Gage Levels
440 mm400 mm 600 mm
-
3/24/2013
13
0
2
4
6
8
10
0 10 20 30 40 50N (blows/0.3m)
PTH
(m
)
SPT1SPT2SPT3
0
2
4
6
8
10
0 5 10 15 20 25 30
WATER CONTENT (%)
TH (
m)
0
2
4
6
8
10
0 20 40 60 80 100
GRAIN SIZE (%)
TH (
m)
Fine to Medium Sand
Medium to Coarse SandFines
BH-1
Soil Profile
73
12
14
16
18
20
DEP
10
12
14
16
18
20
DEP
T 10
12
14
16
18
20
DEP
T Gravel
Zone of Clay and Clayey Sand (no samples)
Deadline for submitting a prediction is April 1I will be glad to email the details for how to submit one.
Pore Pressure Dissipation
0
5
10
0 100 200 300 400 500 600
PORE PRESSURE (KPa)
(m)
0
5
10
0 100 200 300 400 500 600
PORE PRESSURE (KPa)
(m)
0
5
10
0 100 200 300 400 500 600
PORE PRESSURE (KPa)
(m)
7474Paddle River, Alberta, Canada (Fellenius 2008)
15
20
25
DEP
TH
Before Driving
EOID
Total Stress
15
20
25
DEP
TH
30 Days after EOID 15 Days
after EOID
Before Driving
EOID
Total Stress
15
20
25
DEP
TH
4 Years after Driving
30 Days after EOID 15 Days
after EOID
Before Driving
EOID
Total Stress
800
1,000
1,200
1,400
1,600
D (
KN
)
Effective Stress Analysis
0
5
10
0 500 1,000 1,500 2,000
LOAD (KN)
(m)
4 Years after EOID
7575
0
200
400
600
0 10 20 30 40 50
MOVEMENT (mm)
LOA
Paddle River, Alberta, Canada
15
20
25
DEP
TH (
15 Days after EOID
30 Days after EOID
All three analyses apply the same coefficients coupled with the actual
pore pressure distribution
If we want to know the load distribution, we can measure it. But, what we measure is the increase of load in the pile due to the load applied to the pile head. What about the load in the pile that was there before
76
pwe started the test?
That is, the Residual load.
Normalized Applied Load
Load distributions in
static loading tests on
four instrumented
77
D E P T H
piles in clayS d
Example from Gregersen et al., 1973
0
2
4
6
8
0 50 100 150 200 250 300
LOAD (KN)
(m)
0
2
4
6
8
0 100 200 300 400 500 600
LOAD (KN)
(m) True
Residual
True minus Residual
78
B. Load and resistance in DA
for the ultimate load applied
Sand810
12
14
16
18
DE
PTH
(
Pile DA
Pile BC, Tapered
8
10
12
14
16
18
DE
PTH
(
A. Distribution of residual load in DA and BC
before start of the loading test
-
3/24/2013
14
FHWA tests on 0.9 m diameter bored pilesOne in sand and one in clay
(Baker et al., 1990 and Briaud et al., 2000)
0
2
4
0 10 20 30 40
Cone Stress and SPT N-Index(MPa and bl/0.3 m)
Silty Sand
0
2
4
0 10 20 30 40
Cone Stress (MPa)
ClaySilty
Sand Clay
79
6
8
10
12
DEPT
H (m
)
Sand
Pile 4
6
8
10
12
DEPT
H (m
)
Pile 7
N
qc Sand Clay
ANALYSIS RESULTS: Load-transfer curves
0.0
2.0
4.0
0 1,000 2,000 3,000 4,000 5,000
LOAD (KN)
m)
0.0
2.0
4.0
0 1,000 2,000 3,000 4,000 5,000
LOAD (KN)
)
True Distribution
0.0
2.0
4.0
0 1,000 2,000 3,000 4,000 5,000
LOAD (KN)
m)
Measured Distribution
0.0
2.0
4.0
0 1,000 2,000 3,000 4,000 5,000
LOAD (KN)
m)
True Distribution
Residual Load
80
6.0
8.0
10.0
12.0
DEP
TH (
m
PILE 4SAND
Measured Distribution6.0
8.0
10.0
12.0
DEP
TH (
m)
PILE 4SAND
Residual Load
Measured Distribution
6.0
8.0
10.0
12.0
DEP
TH (
m
PILE 7CLAY
6.0
8.0
10.0
12.0
DEP
TH (
m
PILE 7CLAY
Results of analysis of a Monotube pile in sand(Fellenius et al., 2000)
0
5
0 1,000 2,000 3,000
LOAD (KN)
Measured Resistance
Residual Load
81
10
15
20
25
DE
PTH
(m
)
True Resistance
Method for evaluating the residual load distribution
0
2
4
0 500 1,000 1,500 2,000
RESISTANCE (KN)
Measured Load
Shaft
82
6
8
10
12
14
16
DE
PTH
(m
)
Measured Shaft ResistanceDivided by 2
Residual Load
True Resistance
ExtrapolatedTrue Resistance
Resistance
0
5
10
15
20
0 500 1,000 1,500 2,000 2,500LOAD (KN)
(m)
Static Loading Testat Pend Oreille, Sandpoint, Idaho, for
the realignment of US95
406 m diameter,45 m long, closed-toe pipe pile
driven in soft clay
Determining True Resistancefrom Measured Resistance (False Resistance)
Cl
83
25
30
35
40
45
50
DEP
TH (
Fellenius et al. (2004)
driven in soft clay
200+ m
Clay
0
5
10
15
20
-500 0 500 1,000 1,500 2,000
LOAD (KN)
(m)
= 0.60
= 0.06
AS MEASURED,i.e. "FALSE RES."
A
= 0.09
0
5
10
15
20
-500 0 500 1,000 1,500 2,000
LOAD (KN)
(m)
= 0.60
= 0.09
= 0.09
AS MEASURED,i.e. "FALSE RES."
CPTu Eslami-Fellenius
B
84
Test on a strain-gage instrumented, 406 mm diameter,45 m long pile driven in soft clay in Sandpoint, Idaho
25
30
35
40
45
50
DE
PTH
= 0.06
"TRUE RES." RESIDUAL LOAD
AFTER 1st UNLOADING
25
30
35
40
45
50
DE
PTH
= 0.10
"TRUE RES." per CPTu
RESIDUAL LOAD
AFTER 1st UNLOADING
= 0.10
Extrapolated
-
3/24/2013
15
0
5
10
15
0 500 1,000 1,500 2,000 2,500 3,000 3,500
LOAD (KN)
PTH
(m
)
True Resistance
HEAD-DOWN AND FULL RESIDUAL LOAD
Residual Load
True Resistance
False Resistance
Silty Sand
Silty Clay
0
5
10
15
0 500 1,000 1,500 2,000 2,500 3,000 3,500
LOAD (KN)
PTH
(m
)
HEAD-DOWN AND PARTIAL RESIDUAL LOAD
True
False Resistance
Shaft Resistance
Typical Example: Table 7.3 in the Red Book
85
20
25
30
35
DE
P Resistance
Residual and TrueToe Resistance
Transition Zone
Silty Sand
Glacial Till
20
25
30
35
DEP
Residual Load
Resistance
Residual and TrueToe Resistance
Transition Zone
Resistance
The effect of residual load on an uplift test
0
5
10
-2,000 -1,500 -1,000 -500 0 500 1,000
LOAD (KN)
m)
True Resistance
TENSION TESTAND FULL RESIDUAL LOAD
Residual Load
0
5
10
-2,000 -1,500 -1,000 -500 0 500 1,000
LOAD (KN)
m)
Residual Load
True Resistance
TENSION TESTAND PARTIAL RESIDUAL LOAD
8686
15
20
25
30
35
DE
PTH
(m
False Resistance
Toe Resistancein an Uplift Test?!
15
20
25
30
35
DEP
TH (
m
False Resistance
Toe Resistancein an Uplift Test?
Combining the results of a head-down test with those of a tensions test will help determining the true resistance
0
5
10
15
0 500 1,000 1,500 2,000 2,500 3,000 3,500
LOAD (KN)
H (
m)
HEAD-DOWN AND PARTIAL RESIDUAL LOAD
FalseHead-down
True Shaft
False TensionTest
8787
20
25
30
35
DEP
TH
Residual Load
True Resistance
Residual and TrueToe Resistance
Transition Zone
True Shaft Resistance
Not directly useful below this level
Now you know why some claim that resistance in tension is smaller than that in compression
400
600
800
1,000
LOA
D (
KN
)
No Residual Load
Residual Load present
No Strain Softening
Presence of residual load is not just of academic interest
400
600
800
1,000
LOA
D (
KN
)
With Strain Softening
Residual Load present
No Residual Load
8888
0
200
400
0 5 10 15 20 25 30
MOVEMENT (mm)
L
OFFSET LIMIT LOAD
0
200
400
0 5 10 15 20 25 30
MOVEMENT (mm)
L
OFFSET LIMIT LOAD
"Residual Load " follows the same principle and mechanism as "Drag Load". The distinction made is that by residual load we mean the locked-in load present in the pile immediately before we start a static loading test. By drag load we mean the load present in the pile in the long-term.
Additional Comments on Residual load
8989
Residual load as well as drag load can develop in coarse-grained soil just as it does in clay soil.
Both residual load and drag load develop at very small movements between the pile and the
soil.