Airplane Performance and Design

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    © 2012 Randal Allen, PhD

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    AIRPLANE PERFORMANCE and DESIGN  

    Dr. Randal Allen

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    Phases of Airplane Design

    2

    Conceptual Design

    Preliminary Design

    Detail Design

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    Conceptual Design

    3

    Major drivers are

    Aerodynamics

    Propulsion

    Flight performance.

    The first-order question is… 

    Can the design meet the specifications?

    If so, then the next question is…  Is the design optimized, i.e. is it the best design that meets the

    specifications?

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    Preliminary Design

    4

    Serious structural and control system analysis and design take

     place.

    Substantial wind tunnel testing will be carried out, and major

    computational fluid dynamic (CFD) calculations of the completeflow field over the airplane configuration will be made.

    At the end of the preliminary design phase, the airplane

    configuration is frozen and precisely defined.

    The drawing process called lofting is carried out whichmathematically models the precise shape of the outside skin of

    the airplane, making certain that all sections of the aircraft

     properly fit together.

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    Detail Design

    5

    The airplane is now simply a machine to be fabricated.

    The precise design of each individual rib, spar, and section of

    skin now takes place.

    The size, number, and location of fasteners (rivets, welded joints,

    etc.) are determined.

    Manufacturing tools and jigs are designed.

    At this stage, flight simulators for the airplane are developed.

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    7 Pivot Points for Conceptual Design

    6

    Requirements

    Initial weight estimate of the airplane

    Critical performance parameters

    Maximum lift coefficient

    Lift-to-drag ratio

    Wing loading

    Thrust-to-weight ratioConfiguration layout (shape/size of the airplane on a drawing)

    Better weight estimate

    Performance analysis (does the airplane meet/exceed the req’ts?) 

    …iterate steps 3 to 6… Optimization (is it the best design?)

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    Requirement Aspects (1/4)

    7

    Remember thrust required  and power required  are associated

    with the airframe, while thrust available and power available 

    are strictly associated with the power plant (engine/motor).

    Range

    Propeller

    Takeoff distance

    0

    1ln

    W  L

     R cD W 

     

    2

    ,0.7

    1.44

     LO

     LO

     L MAX r V 

    W  s

     g SC T D W L   

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    Requirement Aspects (2/4)

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    Stalling velocity

    Endurance

    Propeller

    Maximum velocity

    ,

    2 stall 

     L MAX 

    W V 

    SC   

    3/2

    1 0

    1 12

    2

     L

     D

    C S  E 

    cC    W W 

      

    1/22

    ,0

    ,0

    4 D A A

     MAX MAX 

     MAX 

     D

    C T T W W 

    W S S W eARV 

     

      

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    Requirement Aspects (3/4)

    9

    Rate of climb

    Propeller

    Maximum turn rate

    Maximum turn radius

    3/ 2,0

    / 1

    ( / ) 0.8776 / MAX   MAX    D  MAX 

     P W S 

     R C  W C    L D

     

      

    ,

    2 /

     L MAX MAX 

     MAX 

    C n g 

    W S 

       

     

    min

    ,

    2

     L MAX 

    W  R

     gC S   

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    Requirement Aspects (4/4)

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    Maximum load factor

    Service ceiling

    Cost

    Reliability and maintainability

    Maximum size

    ,212

    /

     L MAX 

     MAX 

    C n V 

    W S   

     

    1/21/4

    ,0

    3/4

    0,0

    0.7436219,867ln

      D

     A  MAX 

    C W W  H 

    S  P    eAR  

           

       

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    Design of a Propeller-Dr iven Airplane  

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    Requirements

    12

    1. Maximum level speed at midcourse weight: 250 mph

    2. Range: 1,200 mi

    3. Ceiling: 25,000 ft

    4. Rate of climb at sea level: 1,000 ft/min

    5. Stalling speed: 70 mph

    6. Landing distance (to clear a 50-ft obstacle): 2,200 ft

    7. Takeoff distance (to clear a 50-ft obstacle): 2,500 ft

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    Initial (gross) Weight Estimate (1/2)

    13

    (empty: historical data for 19 propeller-driven airplanes)

    (fuel: see Anderson, section 8.3.2, pp. 400-405)

    Crew: 1 pilot at 170 lb

    Payload: 5 passengers (5 x 170 lb) and luggage (6 x 20 lb)

    0 0 01 / /crew payload  

     f e

    W W W 

    W W W W  

    0

    0.62eW 

    0

    0.159 f  W 

    170crewW   

    970 payload W   

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    Initial (gross) Weight Estimate (2/2)

    14

     Note: For each 1 lb increase in passenger weight, there is 4.525

    lb increase in gross weight

    Aviation gasoline

    Density

    Minimum needed fuel capacity

      0 0 0170 970 1140

    (1140 )(4.525) 51581 0.159 0.62 0.2211 / /

    crew payload  

     f e

    W W    lb lb lbW lb lb

    W W W W  

     

    0

    0

    (0.159)(5158 ) 820 f  

     f  

    W W W lb lb

    820145.4

    5.64 /

    lb gal 

    lb gal 

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    Critical Performance Parameters

    Maximum Lift Coefficient

    15

    Maximum lift coefficient

    5-digit NACA airfoils preferred over 4-digit NACA airfoils

     because the maximum camber is closer to the leading edge

    (0.15c), which implies a higherWings are usually thicker at the root then taper toward the tip

    While stall may occur at the root, the tips are still in the flow

    for effective aileron

    Assume root is NACA 23018

    Assume tip is NACA 23012

    Use the average

    To assist in takeoff and landing performance, trailing edge

    flaps are added

    , L MAX C 

    ,   1.6l MAX c  

    ,   1.8l MAX c  

    ,   0.9l MAX c  

    ,  1.7

    l MAX c  

    ,l MAX c

    ,  1.7 0.9 2.6

    l MAX c     , ,0.9 (0.9)(2.6) 2.34 L MAX l MAX C c

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    Critical Performance Parameters

    Wing Loading

    16

    Wing loading

    Wing loading plays a role in stall velocity, landing distance,

    and maximum velocity.

    Consider each requirement then determine based onstrongest constraint

    Stall velocity requirement (#5) of 70 mph = 102.7 fps… 

    (sea level)

    Landing distance requirement (#6) of 2,200 ft… 

    The stronger constraint is

    /W S 

    3 2

    2 2

    ,

    1 1(0.0023769 )(102.7 ) (2.34) 29.3

    2 2

     slug ft    lb stall L MAX    s ft ft 

    W V C 

      

    241.5  lb

     ft 

    229.3

      lb

     ft 

    2 2

    25159 17629.3 29.3lb lb

     ft ft 

    W lbS ft 

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    Critical Performance Parameters

    Thrust-to-Weight Ratio

    17

    Thrust-to-weight ratio

    Consider each requirement then determine the ratio based on

    strongest constraint

    Takeoff distance requirement (#7) of 2,500 ft… 

    Rate of climb requirement (#4) of 1,000 ft/min… 

    Maximum velocity requirement (#1) of 250 mph… 

    The stronger constraint is

    Recall for a propeller-driven aircraft, the power-to-weight

    ratio is the performance parameter and is often quoted as

     power loading (the reciprocal of power-to-weight ratio).

    /T W 

    119 P hp363 P hp

    303 P hp

    363 P hp

    363 0.075158

    hplb P hp

    W lb   14.2   lbhpW 

     P 

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    Maximum lift coefficient

    Maximum lift-to-drag ratio

    Wing loading

    Power loading

    Takeoff gross weight

    Fuel weight

    Fuel tank capacity

    Wing area

    High-lift device, single-slotted trailing-edge flaps

    Zero-lift drag coefficient

    Drag-due-to-lift coefficient

    Aspect ratio

    Propeller efficiency 0.8 Engine power, supercharged to 20,000 ft

    Summary

    Minimum Needed for Conceptual Design

    18

    ,   2.34 L MAX C   

    / 14 MAX 

     L D  

    2/ 29.3  lb

     ft W S  

    / 14.2   lbhp

    W P  

    0   5158W lb

    820 f  

    W lb

    145.4 gal 2176S ft 

    ,0  0.017

     DC   

    0.075 K  

    7.07 AR 

    363 P hp

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    Configuration Layout (1/4)

    Overall Configuration

    19

    The weight of 5158 lb is on the borderline of single- and twin-

    engine general aviation airplanes. We need 363 hp. Examining

    the available piston engines, we find the Textron Lycoming

    TIO/LTIO-540-Vis rated at 360 hp supercharged to 18,000ft.

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    Configuration Layout (2/4)

    Tractor Configuration

    20

    (+) The heavy engine is at the front, which helps to move the

    center of gravity forward and therefore allows a smaller tail for

    stability considerations.

    (+) The propeller is working in an undisturbed free stream. (+) There is a more effective flow of cooling air for the engine.

    (-) The propeller slipstream disturbs the quality of the airflow

    over the fuselage and wing root.

    (-) The increased velocity and flow turbulence over the fuselagedue to the propeller slipstream increase the local skin friction on

    the fuselage.

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    Configuration Layout (3/4)

    Pusher Configuration

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    (+) Higher-quality (clean) airflow prevails over the wing and

    fuselage.

    (+) The inflow to the rear propeller induces a favorable pressure

    gradient at the rear of the fuselage, allowing the fuselage to closeat a steeper angle without flow separation. This in turn allows a

    shorter fuselage, hence smaller wetted surface area.

    (+) Engine noise in the cabin area is reduced.

    (+) The pilot’s front field of view is improved.  (-) The heavy engine is at the back, which shifts the center of

    gravity rearward, hence reducing longitudinal stability.

    (-) Propeller is more likely to be damaged by flying debris at

    landing. (-) Engine cooling problems are more severe.

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    Configuration Layout (4/4)

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    Because we need a rather large, powerful reciprocating engine

    for our airplane, we wish to minimize any engine cooling

     problems. Therefore, we will be traditional and choose the

    tractor configuration.

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    Wing Layout (1/2)

    23

    Aspect ratio

    Wing sweep, subsonic therefore no need for swept wings

    Taper ratio

    (+) Smaller taper ratio implies a lighter wing structure (based oncentroid of the lift distribution)

    (-) Smaller taper ratio exhibits undesirable flow characteristics

    Compromise with which determines the geometry of the

    trapezoidal wingVariation of airfoil shape and thickness along the span, root

     NACA 23018, tip NACA 23012

    Geometric twist, unnecessary since aileron control is maintained

    Anhedral –  wings bent upDihedral –  wings bent down

      2176 7.07 35.27b S AR ft ft  

    / , 0 1t r c c  

    0.5  

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    Wing Layout (1/2)

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    High-wing: good for loading/unloading cargo; more stable re:

    lateral/rolling motion; dihedral also enhances lateral stability;

     possibly too much stability inhibiting rolling motion; anhedral

    Mid-wing: lowest drag because wing-body interference isminimized; structural disadvantages with support running

    through the fuselage; okay with passengers above and cargo

     below

    Low-wing: landing gear disadvantages; ground clearance neededfor propeller

    We choose a low-wing configuration due to structural and

    landing gear considerations.

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    Fuselage Configuration

    25

    Store the fuel in the wings

    Volume is given for the Lycoming engine, seating is referenced,

     baggage

     Note: Tapering should be less than 15 degrees to avoid flowseparation.

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    CG Location –  First Estimate

    26

    Used to locate the wing relative to the fuselage such that the

    mean aerodynamic center of the wing is behind the c.g. of the

    airplane for static longitudinal stability.

    Estimate the weight of the wing. 2 2 22.5 2.5 176 440lb lbwing   ft ft W S ft lb

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    Horizontal and Vertical Tail Size (1/)

    27

    Horizontal tail: longitudinal stability

    Elevator: provides longitudinal control and trim

    Vertical tail: directional stability

    Rudder: provides directional control

    Size may be based on stability and control analysis or historical

    approach.

    Horizontal tail volume sizing: (historically, )

    Vertical tail volume sizing: (historically, )

    0.7 HT 

    V   

    0.04VT V   

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    Horizontal and Vertical Tail Size (2/)

    28

    Tail types: Conventional, T-tail, Cruciform

    We choose the conventional tail for its light-weight structure

    and reasonable stability and control then calculate

    and . It makes no sense to use a cambered airfoil forthe tail, therefore, use symmetric airfoils, e.g. NACA 0012.

    Wings of lower AR, although aerodynamically less efficient,

    stall at higher angles of attack than wings with higher AR.

    Hence, if the horizontal tail has a lower AR then the wing, whenthe wing stalls, the tail still has some control authority.

    Select with the same taper ratio as the wings, .

    Then calculate wingspan, root chord and tip chord length, and

    mean aerodynamic chord for the horizontal tail.

    237.2 HT 

    S ft 2

    15.5VT S ft 

    4 AR    0.5  

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    Horizontal and Vertical Tail Size (3/3)

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    For the vertical tail, is typical. Choose .

    Then, calculate the height of the vertical tail, and with ,

    calculate the root chord and tip chord lengths as well as the mean

    aerodynamic chord for the horizontal tail.

    1.3 2.0VT 

     AR   1.5VT  AR  

    0.5  

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    Propeller Size (1/2)

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    Propeller efficiency is improved as the diameter of the propeller

    gets larger.

    1. Propeller tips must clear the ground when the airplane is on

    the ground. 2. Propeller tips speed should be less than the speed of sound to

    avoid compressibility effects.

    Two-blade (diameter in inches)

    Three-blade (diameter in inches)

    1/4

    22 D hp

    1/4

    18 D hp

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    Propeller Size (2/2)

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    With a two-blade: , the wing tip velocity is

    1,089 ft/s

    Add this vector to the forward velocity vector (250 mph = 367

    fps) to attain 1,149 ft/sThe speed of sound at sea level is 1,117 ft/s which is undesirable.

    With a three-blade: , the wing tip

    velocity is 889 ft/s

    Add this vector to the forward velocity vector (250 mph = 367fps) to attain 962 ft/s

    Therefore, we choose the three-blade propeller with

    (adjust to what is available off the shelf)

    1/4

    18 360 78.4 6.5 D in ft 

    1/4

    22 360 95.8 8 D in ft 

    6.5 D ft 

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    Landing Gear/Wing Placement (1/3)

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    Landing gear configurations: tricycle, tail dragger, and bicycle

    Tricycle: cabin is level when on the ground, forward visibility is

    improved, requires the c.g. to be ahead of the main wheels,

    enhanced stability during ground rollTail dragger: allows for a larger propeller, greater lift at takeoff,

    main wheels must be ahead of the c.g., unstable during a ground-

    roll turn

    Bicycle: useful for high wing airplanes, light-weight outriggerwheels are required near each wing tip

    We choose the tricycle configuration. (Complete texts are

    written on landing gear design.)

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    Landing Gear/Wing Placement (2/3)

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    The landing gear should be long enough to give the propeller tip

    at least 9 inches of clearance above the ground. (We choose 12

    inches or 1 ft.) The diameter of the propeller was determined to

     be 6.5 ft, so that the radius is 3.25 ft. The landing gear length

    should be at least 4.25 ft.

     Note: since the landing gear folds up into the wing, the wing

    location may have to be adjusted to distribute the loading on the

    wheels –  keeping the aerodynamic center behind the c.g. to

    maintain longitudinal stability.

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    Landing Gear/Wing Placement (3/3)

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    Tire sizing

    From a load analysis, the load on the main gear is 4,301 lb andthe nose gear is 857 lb. Therefore, the main wheels are 22.0

    inches in diameter and 7.8 inches wide; while the nose wheel is

    15.9 inches in diameter and 5.9 inches wide. (adjust according to

    what is available off the shelf) Note: Keep in mind the c.g. shifts as fuel is consumed.

    Therefore, a detailed analysis should be conducted to account for

    the range of the c.g.

    A  B 

    Wheel diameter (inches)  1.51  0.349 

    Wheel width (inches)  0.715  0.312 

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    Better Weight Estimate (1/3)

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    Reference: “Aircraft Design: A conceptual Approach” by Daniel

    Raymer, AIAA

    Wing weight = 2.5(Sexposed wing planform)

    Horizontal tail weight = 2.0(Sexposed horizontal tail planform)Vertical tail weight = 2.0(Sexposed vertical tail planform)

    Fuselage weight = 1.4(Swetted area)

    Landing gear weight = 0.057(W0)

    Installed engine weight = 1.4(Engine weight)

    All else empty = 0.1(W0)

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    Better Weight Estimate (2/3)

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    Wing weight = 370 lb

    Horizontal tail weight = 70.6 lb

    Vertical tail weight = 28.8 lb

    Fuselage weight = 428.8 lb

    Landing gear weight = 294 lb Installed engine weight = 765.8 lb

    2

    exp   148osed wing planformS ft 

    2

    exp  35.3

    osed horizontal tail planformS ft 

    2

    exp  14.4

    osed verticaltail planformS ft 

    2306.3wetted areaS ft 

    0  5158W lb

    547 Engine weight lb

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    Better Weight Estimate (3/3)

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    All else empty = 515.8 lb

    With this new we recalculate landing gear weight 0.057(W0)

    and all else empty 0.1(W0) and recalculate . Repeat until

    convergence occurs. Finally… 

    2474eW lb

    0   crew payload fuel emptyW W W W W  

    170crewW lb

    970 payload 

    W lb

    820 fuel W lb

    0   170 970 820 2474 4434W lb lb lb lb lb

    2308eW lb   652 f  W lb 0   4100W lb

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    Performance Analysis (1/8)

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    Updated performance parameters… 

    Wing loading

    Power loading

    Still assume… 

    22

    410023.3

    176

    lb

     ft 

    W lb

    S ft 

    410011.4

    360lbhp

    W lb

     P hp

    ,0  0.017

     DC   

    0.075 K  

    ,   2.34 L MAX C  

    / 14 MAX 

     L D  

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    Performance Analysis (2/8)

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    Power required and power available curves

    Plotted curves show

    Requirement #1: Maximum level speed at midcourse weight: 250

    mph

    437 298 ft  MAX    s

    V mph

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    Performance Analysis (3/8)

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    Rate of climb and ceiling

    Plots show with a ceiling of 33,300 ft

    Requirement #4: Rate of climb at sea level: 1,000 ft/min

    Requirement #3: Ceiling: 25,000 ft

      min/ 1572  ft 

     MAX  R C   

    f A i (4/8)

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    Performance Analysis (4/8)

    41

    Range

    Calculations show range meets the range requirement.

    Requirement #2: Range: 1,200 mi

    P f A l i (5/8)

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    Performance Analysis (5/8)

    42

    Stalling speed

    Requirement #5: Stalling speed: 70 mph

    2

    3,

    2 1 2 123.3 91.5 62.4

    0.0023769 2.34

     ft lb stall    s slug    ft 

     L MAX   ft 

    W V mph

    S C   

    P f A l i (6/8)

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    Performance Analysis (6/8)

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    Landing distance 

    Calculations show

    Requirement #6: Landing distance (to clear a 50-ft obstacle):

    2,200 ft

    1751landing  s ft 

    P f A l i (7/8)

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    Performance Analysis (7/8)

    44

    Takeoff distance

    Calculations show

    Requirement #7: Takeoff distance (to clear a 50-ft obstacle):

    2,500 ft

    761takeoff   s ft 

    Performance Anal sis (8/8)

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    Performance Analysis (8/8)

    45

    Clearly we meet all the performance requirements (in some

    cases considerably). This is due to the change from the initial

    weight estimate of 5,158 lb to a new weight estimate of 4,100

    lb. 

    Iterate

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    Iterate

    46

    …iterate steps 3 to 6… 

    There really is no reason to iterate on the design. But if you did,

    it’s best to have this information in MATLAB or an Excel

    spreadsheet for iterative purposes.

    Optimize

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    Optimize

    47

    Optimization –  Is it the Best Design?

    With the new, lighter weight, we could choose a less powerful,

    more light-weight engine. Hence the airplane will be less

    expensive.

    References

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    References

    48

    Aircraft Performance and Design, by John D. Anderson

    Aircraft Design: A Conceptual Approach, by Daniel P. Raymer