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Aim: Separation of variables: Divorce – Calculus style!
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Transcript of Aim: Separation of variables: Divorce – Calculus style!
Aim: Separation of Variables Course: Calculus
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Aim: Separation of variables: Divorce – Calculus style!
1
Use log differentiation to find : for
2x
dy
dx
y x
Aim: Separation of Variables Course: Calculus
Separation of Variables
When all x terms are collected with dx and all y terms are collected with dy on opposite sides of a differential equation.
original separated
2 3 0dy
x ydx
23 ydy x dx
sin ' cosxy x cotdy x dx
'2
1y
xy
e
1 2
1y dy dxe x
Aim: Separation of Variables Course: Calculus
Model Problem
4If and (0) 5 find an equation
for in terms of
dy xy
dx y
y x
4y dy x dx
4y dy x dx 2 2
2 21 22 2
2 2
y yC x C x C
2
25 252 0
2 2C C
22 25
22 2
yx
Separate, integrate, and solve for constant
Aim: Separation of Variables Course: Calculus
Model Problem
2If 3 and (0) 2 find an equation
for in terms of
dyx y y
dxy x
23dy
x dxy
Separate, integrate, and solve for constant
23dy
x dxy
3ln y x C 3x Cy e 1CC e
3xy Ce
Aim: Separation of Variables Course: Calculus
Model Problem
2If 3 and (0) 2 find an equation for in terms of
dyx y y y x
dx
3xy Ce302 2Ce C
3
2 xy e
Aim: Separation of Variables Course: Calculus
Model Problem – General Solution
Find a general solution of 2 4dy
x xydx
2 4x dy xydx
2 4
dy x dx
y x
2 4
dy x dx
y x
21
1ln ln 4
2y x C 2
1ln 4x C
1 12 24 4C Cy e x y e x
2 4y C x
differential form
separate variables
integrate both sides
general solution
1CC e
Aim: Separation of Variables Course: Calculus
Model Problem – Particular Solution
Find the equation of a curve that passes through (1, 3) and has a slope of y/x2 at the
point (x, y).
2
dy y
dx x y(1) = 3
2
dy dx
y x 2
dy dx
y x 1
1ln y C
x
11/ 1/x C xy e Ce 13 3Ce C e
1/ 1 /3 3 , 0x x xy e e e x
separate integrate antiderivative
solve for y
1CC e
Particular Solution
General Solution
Aim: Separation of Variables Course: Calculus
Model Problem
If the acceleration of a particle is given by a(t) = -32 ft/sec2, and the velocity of the particle is 64 ft/sec and the height of the particle is 32 ft at time t = 0, find: a) the equation of the particle’s velocity at time t; b) the equation for the particle’s height, h at time t; and c) the maximum height of the particle
dv
dt( ) 32a t
32dv dt 32dv dt
Aim: Separation of Variables Course: Calculus
Model Problem
If the acceleration of a particle is given by a(t) = -32 ft/sec2, and the velocity of the particle is 64 ft/sec and the height of the particle is 32 ft at time t = 0, find:
a) the equation of the particle’s velocity at time t; 32dv dt
32v t C
64 32 0 64C C
32 64v t
Aim: Separation of Variables Course: Calculus
Model Problem
If the acceleration of a particle is given by a(t) = -32 ft/sec2, and the velocity of the particle is 64 ft/sec and the height of the particle is 32 ft at time t = 0, find:
b) the equation for the particle’s height, h at time t; dh
dt32 64v t
32 64dh t dt
32 64dh t dt 216 64h t t C
232 16 0 64 0 C 32C
216 64 32h t t
Aim: Separation of Variables Course: Calculus
Model Problem
If the acceleration of a particle is given by a(t) = -32 ft/sec2, and the velocity of the particle is 64 ft/sec and the height of the particle is 32 ft at time t = 0, find: c) the maximum height of the particle
032 64v t 0dh
dt
216 64 32h t t
2t
216 2 64 2 32h 96h
Aim: Separation of Variables Course: Calculus
Model Problem
A city had a population of 10,000 in 1980 and 13,000 in 1990. Assuming an exponential growth rate, estimate the city’s population in 2000.
dy
dtky
Separate dy
k dty
dyk dt
y ln y kt C
kt Cy e
1CC ekty Ce
integrate
Aim: Separation of Variables Course: Calculus
Model Problem
A city had a population of 10,000 in 1980 and 13,000 in 1990. Assuming an exponential growth rate, estimate the city’s population in 2000.
kty Ce
1980: t = 0 1990: t = 10 2000: t = 20
solve
1ln1.3 0.262
10k
0.026210000 ty e
010000 kCe 1013000 kCe
16,900 - population in 2000y
1013000 10000 ke
Aim: Separation of Variables Course: Calculus
Model Problem – Particular Solution
Find a particular solution given y(0) = 1 of
2 2 1 0xxydx e y dy
2
2 2 1 0x
xexydx e y dy
y
22 1
0xy dy
e x dxy
22 1
xy dy
e x dxy
22 1
xy
dy e x dxy