Acceleration due to Gravity CCHS Physics. Historical Background.

13
Acceleration due to Gravity CCHS Physics

description

Galileo attempts to prove Aristotle’s hypothesis wrong… He drops objects of various weights from the Leaning Tower of Pisa and compares the falls. He thinks that light and heavy objects will fall at the same rate. We’ll find out who is correct with a demonstration…

Transcript of Acceleration due to Gravity CCHS Physics. Historical Background.

Page 1: Acceleration due to Gravity CCHS Physics. Historical Background.

Acceleration due to Gravity

CCHS Physics

Page 2: Acceleration due to Gravity CCHS Physics. Historical Background.

Historical Background

Hypothesis:Objects fall at

speeds proportionalto their weights

Natural Motion-Results from the "nature" of objects

Objects strive to get to their proper placeEX- clay vs. smoke vs. feather

Summary-All motion results from the

nature of the moving object or froma sustained push or pull

Violent Motion-Results from pushing or pulling forces

Externally caused- outside force requiredEX- pushing a cart, tugging a rope

Aristotle (Greek philosopher/scientist)divided motion into two main classes:

Page 3: Acceleration due to Gravity CCHS Physics. Historical Background.

Galileo attempts to prove Aristotle’s hypothesis

wrong…• He drops objects of various weights

from the Leaning Tower of Pisa and compares the falls.

• He thinks that light and heavy objects will fall at the same rate.

• We’ll find out who is correct with a demonstration…

Page 4: Acceleration due to Gravity CCHS Physics. Historical Background.

Let’s See The Real Thing

QuickTime™ and aSorenson Video decompressorare needed to see this picture.

Page 5: Acceleration due to Gravity CCHS Physics. Historical Background.

So who’s right?• Both- why?• In the absence of air resistance, all objects

accelerate towards Earth at the same rate.• We call this “free-fall” acceleration- meaning

gravity is the only force acting on an object.• Because we use this value so often we’ll give

it a name- g• What do you think g depends on?

Page 6: Acceleration due to Gravity CCHS Physics. Historical Background.

For an object in free-fall, g depends on…

• Mass of the planet object is near• Distance from object to the center of the

planet

• (G = universal gravitational constant) • Near the surface of the Earth, g = -9.8 m/s2

g =GMr2

Page 7: Acceleration due to Gravity CCHS Physics. Historical Background.

Free Fall

• Motion of a body when only the force of gravity is acting on the body

• The acceleration of an object in free fall is called the acceleration due to gravity, or free fall accleration

• Free fall acceleration is denoted by the symbol g

Page 8: Acceleration due to Gravity CCHS Physics. Historical Background.

Free Fall Movie

Page 9: Acceleration due to Gravity CCHS Physics. Historical Background.

Handy Chart

Page 10: Acceleration due to Gravity CCHS Physics. Historical Background.

Velocity and Acceleration Movie

Page 11: Acceleration due to Gravity CCHS Physics. Historical Background.

Let’s try some examplesEstimate the following:

• A stone is dropped off a cliff. What is its velocity 5 seconds later?

• A ball is tossed straight up at 30 m/s. How long will it take to land? (It returns to same height.)

a =vf −vi

t−10 =

v f − 05

⇒ v f = −50 m/s

a =vf −vi

t−10 =

−30 − 30t

⇒ t = 6 s

Page 12: Acceleration due to Gravity CCHS Physics. Historical Background.

Let’s try some more … a little harder though

• Ms. Clark throws a ball straight down off a building with an initial speed of 10 m/s. It lands 3 seconds later. How high was the building?d =

12at2 +vit

d =12

−10( )32 + −10( )3

d =−75 m

h=75 m

Page 13: Acceleration due to Gravity CCHS Physics. Historical Background.

One More Example• Jason hits a volleyball so that it moves with an initial

velocity of 6 m/s straight upward. If the volleyball starts from 2 m above the floor, how long will it be in the air before it strikes the floor?– Choose origin to be initial position of ball– The displacement of the ball is -2 m

d =12at2 +vit

−2 =12

−9.8( )t 2 + 6t

t = 1.5s or t = −0.27s