Acceleration due to Gravity CCHS Physics. Historical Background.
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Acceleration due to Gravity
CCHS Physics
Historical Background
Hypothesis:Objects fall at
speeds proportionalto their weights
Natural Motion-Results from the "nature" of objects
Objects strive to get to their proper placeEX- clay vs. smoke vs. feather
Summary-All motion results from the
nature of the moving object or froma sustained push or pull
Violent Motion-Results from pushing or pulling forces
Externally caused- outside force requiredEX- pushing a cart, tugging a rope
Aristotle (Greek philosopher/scientist)divided motion into two main classes:
Galileo attempts to prove Aristotle’s hypothesis
wrong…• He drops objects of various weights
from the Leaning Tower of Pisa and compares the falls.
• He thinks that light and heavy objects will fall at the same rate.
• We’ll find out who is correct with a demonstration…
Let’s See The Real Thing
QuickTime™ and aSorenson Video decompressorare needed to see this picture.
So who’s right?• Both- why?• In the absence of air resistance, all objects
accelerate towards Earth at the same rate.• We call this “free-fall” acceleration- meaning
gravity is the only force acting on an object.• Because we use this value so often we’ll give
it a name- g• What do you think g depends on?
For an object in free-fall, g depends on…
• Mass of the planet object is near• Distance from object to the center of the
planet
• (G = universal gravitational constant) • Near the surface of the Earth, g = -9.8 m/s2
g =GMr2
Free Fall
• Motion of a body when only the force of gravity is acting on the body
• The acceleration of an object in free fall is called the acceleration due to gravity, or free fall accleration
• Free fall acceleration is denoted by the symbol g
Free Fall Movie
Handy Chart
Velocity and Acceleration Movie
Let’s try some examplesEstimate the following:
• A stone is dropped off a cliff. What is its velocity 5 seconds later?
• A ball is tossed straight up at 30 m/s. How long will it take to land? (It returns to same height.)
a =vf −vi
t−10 =
v f − 05
⇒ v f = −50 m/s
a =vf −vi
t−10 =
−30 − 30t
⇒ t = 6 s
Let’s try some more … a little harder though
• Ms. Clark throws a ball straight down off a building with an initial speed of 10 m/s. It lands 3 seconds later. How high was the building?d =
12at2 +vit
d =12
−10( )32 + −10( )3
d =−75 m
h=75 m
One More Example• Jason hits a volleyball so that it moves with an initial
velocity of 6 m/s straight upward. If the volleyball starts from 2 m above the floor, how long will it be in the air before it strikes the floor?– Choose origin to be initial position of ball– The displacement of the ball is -2 m
d =12at2 +vit
−2 =12
−9.8( )t 2 + 6t
t = 1.5s or t = −0.27s