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GCE TEACHERS’ GUIDE New Specifications: for teaching from September 2008 Physics

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GCE TEACHERS’ GUIDENew Specifications:for teaching from September 2008

Physics

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GCE AS and A PHYSICS Teachers' Guide 1

ContentsGCE AS and A Level Physics Teachers’ Guide

Page 1. Introduction 2 1.1 - Overview of New Specification 3 1.2 - Changes for teaching from September 2008 4 2. Delivering the specification 2.1 - Pathways through the Specification 5 3. Support for Teachers 6 3.1 - Generic Resources 3.2 - NGfL Cymru 3.3 - General Websites 4. Unit Guides 4.1 - PH1 : Motion, Energy & Charge 8 4.2 - PH2 : Waves & Particles 10 4.3 - PH3 : Practical Physics 31 4.4 - PH4 : Matter, Forces and the Universe 33 4.5 - PH5 : Electromagnetism, Nuclei & Options 45 4.6 - PH6 : Experimental & Synoptic Assessment 86 Contributors to the Teachers’ Guide 87

Issued January 2008

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GCE AS and A PHYSICS Teachers' Guide 1

1 INTRODUCTION The WJEC AS and A2 PHYSICS specification has been modified and updated for delivery from September 2008. The first AS awards will be made in Summer 2009 and the first A level awards in summer 2010. For the first availability of units, see page 2 of the specification. The specification can be delivered and assessed in centres throughout the UK. The revised subject criteria for GCE PHYSICS issued by the regulators have necessitated a change in the course structure from the current 3 externally assessed units at each of AS and A2 to 2 externally assessed theory units plus 1 internally assessed practical unit per stage.

This Guide is one of a number of ways in which the WJEC provides assistance to teachers delivering the new specification. Also essential to its introduction are the Specimen Assessment Materials (question papers and marking schemes) and professional development (INSET) conferences. Other provision which you will find useful are:

• Examiners’ reports on each examinations series • Free access to past question papers via the WJEC secure website • Easy access to specification and other key documents on main website • Easy access to study materials on the main website • Itemised feedback on outcomes for candidates at question level • Regular INSET delivered by Chief Examiners • Additional materials on the National Grid for Learning Wales (NGfL Cymru) • Easy access to both the Subject Officer (a physics specialist) and to administrative sections

Contact Points for GCE PHYSICS are as follows: Gareth Kelly, [email protected], 029 2026 5081 (Subject Officer) Fran Plumb, [email protected], 029 2026 5140 (Administrative Support Officer) Subject page www.wjec.co.uk INSET Section [email protected] www.wjec.co.uk/professionaldevelopment

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GCE AS and A PHYSICS Teachers' Guide 2

1.1 Overview of the Specification The specification is divided into a total of 6 units: 3 AS units and 3 A2 units. Weightings noted below are expressed in terms of the full A level qualification. AS (3 units)

PH1 20% 1¼ hour Written Paper 80 marks[120 UM] Motion, Energy & Charge Approx 7 structured questions. No question choice. No sections. PH2 20% 1¼ hours Written Paper 80 marks [120 UM] Waves & Particles Approx 7 structured questions. No question choice. No sections. PH3 10% Internal Assessment 48 marks [60 UM] Practical Physics Experimental tasks, performed under controlled conditions, based upon experimental techniques developed in the AS course.

A LEVEL (the above plus a further 3 units)

PH4 18% 1¼ hour Written Paper 80 marks [108 UM] Oscillations & Fields Approx 7 questions. Includes synoptic assessment. No question choice. No sections. PH5 22% 1¾ hour written paper 100 marks[132 UM] Electromagnetism, Nuclei and Options Section A: Approximately 5 questions on the compulsory content of the unit. 60 marks Section B: Case Study, synoptic in nature, based upon open-source material distributed by the board. 20 marks Section C: Options: Alternating Currents, Revolutions, Materials, Medical Physics, Energy. 20 marks PH6 10% Internal Assessment [UMS = 60] Experimental & Synoptic Assessment An experimental task (25 marks), and a data-analysis task (25 marks) performed under controlled conditions, both synoptic in nature.

• Assessment units PH1, PH2 and PH4 are available in the winter examination series. All units

are available in the summer examination series. • Internally assessed units PH3 and PH6 are timetabled for April and March respectively. • Synoptic assessment is included in PH4 and PH5. It is inherent in the internal assessment

PH6.

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GCE AS and A PHYSICS Teachers' Guide 3

1.2 Changes to the specification for delivery in September 2008 60% of the content of the AS and A2 specifications is prescribed in the GCE Physics criteria, or core. This material is common to all the examination specifications with the title Physics. The content of the core is little changed from the previous version. The changes mainly affect the positioning of topics within the specification, i.e. AS or A2. “Energy concepts,” for example, has been moved from A2 to AS – this allows it to sit nicely against kinematics and electrical power, giving scope for questions on electrical power generation. There are also changes between units at the two levels for more logical development of concepts – waves now sits alongside quanta to make PH2 a unit which deals exclusively with waves and particles. Significant changes to the theory assessments:

the introduction of novel and contemporary material in AS – leptons and quarks, lasers and stellar spectra as a means of understanding the composition of stars.

the introduction of novel and contemporary material into the compulsory part of A2 – the

application of gravitational and circular motion theory, via the Doppler Effect, to the study of extra-solar planets and the hypothetical dark matter in galaxies.

the introduction of options into A2 – as part of the PH5 unit, candidates will study one of:

Further electromagnetism & Alternating Current Revolutions in Physics Materials Biological Measurement & Medical Imaging Energy Matters All these options are designed to build upon the compulsory core material in AS and A2 and lend themselves in part to directed self study.

The Case Study. Candidates will be issued with an article on a contemporary topic. They will be expected to study it and to answer questions stimulated by the article as part of the PH5 examination.

Changes to the assessment of practical work The regulatory authorities required practical work to be assessed internally. Following detailed consultation with teachers, the assessments at both AS and A2 will take the form of WJEC-set tasks. These will be timetabled and detailed instructions for supervisors will be sent out in advance to allow them to assemble the necessary apparatus and materials. This will be marked in the centre and samples of work submitted for moderation. As these assessments come under the Internal Assessment criteria there are no inter-board agreed dates for these activities. In order to separate the AS and A2 assessments, to allow as long as possible for AS candidates to develop practical skills and to allow centres time to send in samples and marks by mid May, the tasks will be timetabled as follows:

PH3 Late April PH6 Mid March

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2. DELIVERING THE SPECIFICATION The specification was designed for and by physics teachers. The extent and depth of the content in each of the theory units – PH1, 2, 4 & 5 – was chosen to allow it to be taught in approximately 60 hours. This time includes individual and demonstration practical work required for the examination of the content of each unit. Time will also need to be devoted to a systematic development of candidates’ experimental and investigatory skills in preparation for assessment units PH3 and PH6. 2.1 Pathways through the specification The specification is unitised and there is no requirement for candidates to take units in a particular sequence. The following models are supported: (a) Fully sequential

Time Unit taken January year 12 PH1 April year 12 PH3 May/June year 12 PH2 January year 13 PH4 March year 13 PH6 June year 13 PH5

(b) Linear AS and unitised A2

Time Unit taken April year 12 PH3 May/June year 12 PH1 & PH2 January year 13 PH4 March year 13 PH6 June year 13 PH5

(c) Linear A level

Time Unit taken March year 13 PH6 April year 13 PH3

May/June year 13 PH1, PH2 PH4, PH5

These assessment models are not exhaustive and all units may be retaken on any number of occasions prior to cashing in.

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3, SUPPORT FOR TEACHERS The most immediate support for teachers is from the Subject Officer, an experienced teacher of Physics with 25 years experience of preparing candidates for A level Physics. The contact details are given on page 2 of this guide. In addition, the physics examining team consists of teachers and academic with a wide range of subject expertise and experience. No single text book is recommended for the WJEC physics course. The matter of a textbook is one of personal taste and most of the contents of the specification are well covered in a range of textbooks. Some topics, within the specification are not found in other specifications. Others, though generally covered, often cause confusion for A level Physics students. This guide is intended to cover these gaps. In particular the following topics are covered: Topic Unit Comments Photoelectric effect

PH2 This topic is to be found within the national core. It is however, conceptually difficult and the notes are intended to provide guidance for teachers as to the level required.

Lasers PH2 The concept of atomic energy levels and the spontaneous absorption and emission of photons is part of the legacy specification and, although numerical questions are generally well, there is often confusion at a qualitative level. It is expected that the increased exposure to the concepts, with the introduction of lasers, will reduce the difficulty. The notes are intended to introduce teachers to this new topic.

Leptons and quarks

PH2 The coverage of the Standard Model expected is restricted to that of the 1st generation of particles.

The analysis of stellar spectra

PH2 Intended to show students how the study of spectra allows astronomers to develop an understanding of stellar conditions and processes. The basic physics of black body radiation and absorption spectra is standard but the application is one which is not well covered in text books.

Uncertainty analysis

PH3 & PH6

The understanding of the limitations of physical measurements is fundamental to an appreciation of the degree of trust which can be placed on the results of investigations. This is introduced in the AS course and developed in the A2.

Orbital mechanics

PH4 This is the most up-to-date topic in the specification. It deals with the way in which the study of orbital motion, using Doppler measurements on spectral lines has enabled the masses of binary stars to be determined, extra-solar planets to be detected and the existence of Dark Matter within galaxies to be inferred. The treatment is quite mathematical.

A.C. Theory PH5 Option A

A traditional topic for WJEC specifications, this has been left out of some other exam boards’ material and is not always covered in text books.

Revolutions PH5 Option B

An innovative unit which traces the history of scientific understanding in electromagnetism through the nineteenth century, culminating in the theory of Special Relativity. In addition to a synopsis for teachers in this guide, an exhaustive comprehensive pupil reader is available on the WJEC website.

Materials PH5 Option C

In addition to teacher guidance notes in this document, a student reader on the development of single crystals for use in turbine blades is available on the WJEC website.

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Topic Unit Comments Biological measurement & medical imaging

PH5 Option D

Although well covered in text books, there is often a degree of confusion as to the detail required. These notes clarify the depth and breadth which ill be expected.

Energy Matters

PH5 Option E

Many of the areas in this option are covered in the AS part of the specification. The guidance notes indicate how they will be treated at A2 and integrated with the A2 topics of thermodynamics and nuclear energy.

Student Guidance notes and worksheets: As the table indicates, two areas of the specification have publications for students in addition to those intended for teachers. There are also on the website several documents which will help students and their teachers in preparing for examinations. These documents cover, amongst other topics: Thermodynamics – specifically the 1st Law Ductile deformation of metals. It is the intention to add to these documents and an up to date list can be found on the A level Physics page of the WJEC website. School Physics The website www.schoolphysics.co.uk covers most of the areas of the WJEC specifications at both A level and GCSE. It also provides links from specification topics to the relevant resources. Whilst this is not a WJEC resource, it is a useful one. Other websites There are many websites which are of use in the study of Physics to A level. Unfortunately the URLs of websites change and some are withdrawn. For a list of suggested websites see the document Physics Websites of the WJEC website. Suggested textbooks include:

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4. UNIT GUIDES AS

4.1 PH1 – Motion, Energy & Charge General PH1 is intended as a general introduction to the AS/A Physics course. It is designed to provide:

• a gentle transition from GCSE, assuming that candidates have previously covered the content of GCSE Science and GCSE Additional Science;

• topics which lend themselves to developing students’ practical and investigatory skills;

• topics which are drawn upon in the remainder of the course. PH1.1 – Basic Physics This section includes the idea of units and dimensions, scalar and vector quantities, forces and their combination, density and moments. Previously, density was not covered until A2 when it suddenly appeared in the kinetic theory of gases. Placing it in PH1.1 will enable candidates to develop a feeling for the concept in less conceptually-demanding contexts. It also provides a useful introduction to the uncertainties associated with individual measurements and the uncertainties in quantities which are derived from combinations of measurements. With the exception of density, previous examination questions can be found in past PH1 papers of which there are over 10. PH1.2 – Kinematics This section is essentially unchanged from the previous specification. It is very adequately covered in standard A-level textbooks and there is no intention to produce guidance notes. Previous examination questions can be found in past PH1 papers. PH1.3 – Energy Concepts This topic has been moved from A2 to its more logical home of AS. The concepts of work, power and energy form a straightforward development of the concepts in the GCSE specification. This is especially true of work [extended to include the cos θ term], kinetic energy, gravitational potential energy, power and efficiency. Work as the area under the force-distance graph is included and elastic potential energy in hookean systems introduced. Previous examination questions can be found in past PH4 papers but caution should be exercised as the level of demand of these questions is appropriate for A2. Past WJEC GCSE Physics papers are a rich seam of source material with a similar warning about level of demand.

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PH1.4 – Conduction of Electricity PH1.5 – Resistance PH1.6 – D.C. Circuits This topic area was previously in PH2. Its position here enables centres to commence early in the AS year on electrical practical and investigatory work. Some minor adjustments to content have been made:

• Electric charge has been introduced. This topic is no longer covered in the GCSE Physics course. Its treatment is restricted to charging by rubbing, positive and negative charges, attraction and repulsion of charges and current as the rate of flow of charge.

• Temperature coefficient of resistance is no longer covered, though the qualitative variation of resistance with temperature for metal wires and the experimental investigation of variation are on the specification. Examination questions in which candidates interact with data are still possible.

4.2 PH2 – Waves and Particles General PH2 takes the student into new and, we hope, exciting territory. The main ‘blocks’ in PH2 are Waves and Photons. Having these re-united in the same module means that the nature of light becomes an important theme of PH2.

The old PH2 section on energy levels and line spectra is now seen to have interesting applications: it has been extended to include a treatment of lasers, while line absorption spectra are shown to give us information about the atmosphere of stars. In fact, there is a small section devoted to the physics of stars. It mainly concerns what we can learn about them from the radiation they emit.

In an extension to the old PH2 section on nuclear structure, the basic constituents of matter are acknowledged to be quarks and leptons. The four fundamental forces are also introduced in this section. One teaching strategy would be to generate interest by starting PH2 here, as the ideas are quite modern, new to most students, and raise tantalising issues.

PH2.1 – WAVES Most of the content of the Waves and Light sections of the old PH1 is included here. To make way for new material elsewhere, some gentle pruning has been done. Beats have disappeared. So has the relationship between intensity and amplitude. Students are no longer required to describe experiments showing diffraction or interference of water waves, sound and microwaves, though they are required to be familiar with such experiments; an examination question could probe understanding of a set-up given in the question. Students do still have to be able to describe a version – any they please – of a two-slits experiment for light.

Waves are well covered in standard textbooks.

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GCE AS and A PHYSICS Teachers' Guide 9

PH2.2 – REFRACTION OF LIGHT What is required has been spelt out in the specification in rather more detail than previously. The Snell’s Law equation is written in such a way as to emphasise symmetry.

The only application of total internal reflection now required to be learnt is the step-index multimode (‘thick core’) optical fibre. Step-index means simply that the core is glass of one refractive index and the cladding is glass of a lower index (students need to know why it has to be lower), with an abrupt change in index at the interface.

While such fibres are fine for conveying light for illumination, students need to know that they can’t be used for transmitting a rapid sequence of data over a long distance. Multimode dispersion is the problem. Light travelling at an angle to the axis of the fibre (ray A in the diagram) will travel further for a given axial length of fibre, than light (such as ray B) travelling parallel to, or at a smaller angle to, the axis, and so will arrive later. Thus the arrival time of an element of data encoded in the light is smeared out. The element could start to arrive (by the shortest route) earlier than the previous element has finsished arriving by its longest route. Even worse confusion can occur.

There are two ways round the problem of multimode dispersion…

• Make fibres with graded index cores. This means cores which have a progressively lower index as we go out from the axis towards the interface with the cladding. The lower the index the faster the light travels so, if the grading is correctly calculated, the longer, more zigzaggy, paths cash in on the ‘faster medium’ and take no longer than the short, axial, route. Clever stuff, but note that graded index fibres are not in the WJEC specification.

• Make the core very thin. Its diameter must be no more than a few wavelengths of the light (or infrared) being carried. Such fibres are monomode. Light travels parallel to the axis. There are no zigzag modes. Students are required to know this. They are not required to know why very thin fibres are monomode. This is just as well, because it cannot be shown by ray optics, nor even by simple application of Huygens Principle. Electromagnetic wave theory is needed.

The website http://www.techoptics.com/pages/Fiber%20Optics%20-%20Optical%20Fiber.html gives an excellent summary of fibres for data transmission, with some facts and figures. PH2.3 – PHOTONS This is a heavily modified, and, we hope, more satisfying, version of the ‘Quantum Physics’ section of the previous specification. Particles behaving as waves, and the electron diffraction demonstration have disappeared. The electron-volt will not be used in PH2. The origin of the continuous and line X-ray spectra will not be tested.

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GCE AS and A PHYSICS Teachers' Guide 10

The photo-electric effect is still arguably the most direct and easily understood evidence for photons. Although the wording of our requirements [new PH2.3(a)-(d)] has been re-thought, the same ground is covered, except that Millikan’s role need not be mentioned. This should discourage students from spending valuable time in the examination drawing elaborate diagrams of Millikan’s ‘laboratory in a vacuum’. Students find the photoelectric effect difficult, especially the experimental determination of KEmax. We have therefore written a detailed account – below – of the material to be tested, so that the level of approach required is as clear as we can make it. The section on atomic energy levels and line spectra now culminates in a treatment of lasers. Detailed notes follow the photoelectric notes.

PH2.3 (a)-(d) Detailed notes on Photons and the Photo-electric Effect

Photons Everything in nature seems to come in lumps or quanta (singular: quantum). For example, ordinary matter is made of atoms, and electric charge comes in units of e. This lumpiness was only becoming fully accepted a hundred years ago. But in 1905 Einstein made the bold suggestion that light, too, was ‘lumpy’. Light quanta are now called photons.

A photon is a discrete packet of electromagnetic radiation energy. The energy of a photon is given by

Ephoton = hf

In which f is the frequency of the light and h is a constant called Planck’s constant. [h = 6.6 = 10-34 Js] [This is given in the WJEC list of constants.]

[For interest only… The constant h had first arisen in the earlier (1900) work of Max Planck on the radiation inside a cavity with hot walls. Planck had shown that the energies of oscillating particles in the wall seemed to be quantised.]

Einstein suggested some experiments in which the quantisation of light should reveal itself. The simplest to understand involved the photoelectric effect, a phenomenon known about since the late 1880s.

The Photo-electric Effect

When electromagnetic radiation of high enough frequency falls on a metal surface, electrons are emitted from the surface.

For most metals, ultraviolet is needed. For some (including sodium, potassium, caesium), light towards the violet end of the spectrum) will release electrons.

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GCE AS and A PHYSICS Teachers' Guide 11

Demonstrating the Photo-electric Effect

EITHER Using a zinc plate with a gold leaf electroscope (or a coulombmeter)…

• Clean a zinc plate with fine emery paper or steel wool. • Attach the plate to the top disc on a gold leaf electroscope, so there is good electrical

contact. • Charge the zinc plate and inner assembly of the electroscope negatively1, e.g. by rubbing

the zinc plate with a polythene rod which has been rubbed with wool or fur. [Charging by induction using a perspex rod is more reliable, but might be considered too confusing!]

The leaf should now be raised, because the leaf and the back plate are both charged negatively and repel each other. The leaf should temporarily rise further if the charged polythene rod is brought near the zinc plate.

• Place an ultraviolet lamp near the zinc plate. Switch it on. The leaf should be seen to fall. [Safety note: Don’t look at the ultraviolet lamp (when it’s turned on!)] Clearly the plate (and inner assembly of electroscope) is losing charge.

• Repeat the procedure, but charging the zinc plate and inner assembly of the electroscope positively, e.g. by rubbing the plate with a charged perspex rod.

This time the ultraviolet does not affect the leaf. Charge is not lost. The simplest explanation is the correct one… The ultraviolet causes electrons to be emitted from the zinc plate. If the plate is charged positively, the electrons are attracted back again. If the plate is charged negatively the emitted electrons are repelled and lost from the plate for ever.

1 Note that it is also possible to charge up the electroscope using an EHT power supply. It is imperative that the output with the current-limiting resistance [usually several MΩ] is employed if doing this. 11

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GCE AS and A PHYSICS Teachers' Guide 12

OR Using a vacuum photocell… • The apparatus can be supplied by Philip

Harris (Unilab division). • Note the polarity of the power supply.

Any electrons emitted from the caesium surface will be collected by the ‘collecting electrode’.

• If the photocell is covered the current is zero; if light falls on the caesium electrode there is current.

Photo-electric Puzzles Before 1905, the energy of a beam of light was thought of as distributed uniformly across broad wavefronts. Calculations showed that it should take some time before an electron in a metal surface could absorb enough energy from the light to escape from the surface. Yet emission is observed as soon as the light falls on the surface.

Another puzzle was why, for a given surface, we find that light of frequency below a certain value (the threshold frequency) causes no electron emission at all.

Einstein’s theory of the photo-electric effect solves both these problems… Einstein’s Photo-electric Equation Although the free electrons in a metal have no allegiance to particular atoms, there are forces ‘bonding’ them to the lattice of ions as a whole. In order to escape from the metal an electron has to do work against these forces. Some have to do more work than others, but there is a certain minimum quantity of work to be done, so no electron can escape unless it is given a certain minimum energy.

The work function, φ, of a metal is the minimum energy needed by an electron in order to escape from the surface.

Einstein’s key idea was that any electron which leaves the surface is ejected by the action of a single photon. Photons don’t co-operate in the process.

Recall that a photon of light of frequency f has energy hf.

Suppose that a photon gives its energy hf to an electron, and that the electron is able to escape. The minimum energy used in escaping is φ, so the maximum kinetic energy the escaped electron can have is what’s left over of the photon’s energy. So we have the simple equation…

KEmax = hf – φ

This assumes that the photon energy is greater than (or equal to) the work function; in other words that hf ≥ φ , so f ≥ φ / h.

If f < φ / h, the photon energy will be less than the work function so no electrons at all can escape – a simple explanation of the phenomenon of threshold frequency.

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The threshold frequency, f0, for a metal is the minimum frequency of electromagnetic radiation needed to produce electron emission from the surface.

From the argument just given, f0 = φ / h.

This relationship can also be deduced from Einstein’s equation (without using ‘≥’ or ‘<’ signs!)… At the threshold frequency even the most energetic electron will only just manage to escape, so KEmax = 0, and therefore 0 0hf φ− = ∴ f0 = φ / h.

Provided that the light is above the threshold frequency, as soon as it falls on the metal surface electrons will start to be emitted, as emission results from individual photon ‘hits’, and is not a cumulative process as supposed before Einstein. Experimental test of Einstein’s Equation We use the arrangement with the vacuum photocell given earlier for demonstrating the photoelectric effect, but with the power supply polarity reversed.

• Use white light with a coloured filter, or a light emitting diode, to illuminate the caesium surface with approximately monochromatic light. [Its wavelength can be found using a diffraction grating, hence its frequency, using f = c / λ.]

• Increase the p.d. between the collecting electrode and the caesium surface until the current drops to zero.

At this point the p.d. is called the stopping voltage, Vstop, because it sall emitted electrons, even those with the most K.E., from reaching the collector electrode.

tops

• The maximum K.E. of the emitted electrons is simply given by

[How do we justify this? Because of the applied voltage, emitted electrons are subject to repulsion by the positive collector electrode and attraction by the emitting surface, hence to a resultant force towards the emitting surface. The electrons therefore get slower and slower as they cross the gap. When the stopping voltage is applied, even the most energetic of emitted electrons have no K.E. left when they have made it across the gap. The K.E. lost is equal to the P.E. gained for these electrons. That’s what the equation states.

KEmax = e Vstop

It is just like finding the K.E. of a ball thrown upwards in the Earth’s gravitational field by measuring the its maximum height, and using the energy conservation equation K.E. lost = mgh]

• Repeat the process using two or three more frequencies of light.

• Plot a graph of KEmax against frequency, f. If Einstein’s equation is correct it should have a positive slope equal to h and a negative intercept, equal to −

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GCE AS and A PHYSICS Teachers' Guide 14

We can see this by comparing Einstein’s equation with y = mx + c.

A sample graph is presented below.

Graph of KEmax against frequency of light for a caesium surface

It is useful practice to find from the graph… • a value of Planck’s constant, • the threshold frequency for caesium, • the threshold wavelength for caesium • the work function for caesium [In practice it is difficult to obtain a good value for h or φ using a commercially available vacuum photocell. Slight impurities on the caesium surface (e.g. a thin oxide film), and unwanted electron emission from the collector electrode, both affect the stopping voltage.]

The first convincing verification of Einstein’s photo-electric equation, leading to an accurate value of the Planck constant was completed in 1916 by R.A. Millikan, working in the United States. The secret of his success was a remotely operated knife working in the vacuum to skim off surface layers from the caesium surface as they became contaminated.]

[For interest only: http://focus.aps.org/story/v3/st23]

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GCE AS and A PHYSICS Teachers' Guide 15

Effect of changing the Light Intensity If we bring a monochromatic light source towards a surface we increase the light energy falling on the surface, per m2, per s. We are said to be increasing the intensity of the light. Clearly we can apply the same idea to ultraviolet or any other electromagnetic radiation. We find that…

(1) For light or ultraviolet of a given frequency, changing the intensity has no effect on the maximum K.E. of the emitted electrons.

This is exactly what Einstein’s theory predicts. The energy given to individual electrons comes from individual photons, and a photon’s energy, hf, depends only on the frequency (or, equivalently, the wavelength) of the radiation. It doesn’t, then, depend on its intensity (provided we don’t change the frequency).

(2) For light or ultraviolet of a given frequency, increasing the intensity increases the number of electrons emitted per second.

Again, this is just what we’d expect from Einstein’s theory. Increasing the intensity means increasing the number of photons arriving at the surface, per m2, per s. Naturally this means that more electrons will be emitted. [Each identical photon has the same probability of emitting an electron.]

We can show the effect with the same vacuum photocell arrangement used for demonstrating the photoelectric effect. Note that the polarity of the power supply is arranged to encourage electrons to cross the gap.

• Use a monochromatic light source to illuminate the caesium surface.

• Check that increasing the p.d. does not affect the current, I. This means that all the electrons emitted per second are being collected.

• Bring the light source closer and observe the effect on I.

• I is the charge flowing per second, so the number of electrons emitted per second is I/e in which e is the charge on each electron.

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PH2.3 ( l)-(t) Detailed notes on Laser Physics

Raison d’être Lasers, by now, are in nearly every household as they were once in every self-respecting science fiction film. Although, the death ray mystique will appeal to most A-level students there is real value in studying the physics which forms the foundation of laser construction. Unlike other subjects such as relativity or nuclear physics which can only be touched upon within an A-level course, the essential physics underpinning lasers can be taught reasonably well in a few lessons. Also, these fundamentals of lasers can be taught at the right level while not oversimplifying the subject. Summary (l)-(q) in the syllabus are related to the theory and construction of a simple laser. The new concepts here are:

1. Stimulated emission of radiation. 2. Lifetime of energy levels. 3. Population inversion. 4. 3 and 4-level laser systems. 5. Basic construction of a laser.

(r)-(t) are related to semiconductor lasers and their uses. Note: some of the content has been put in for general interest but will not be examined. Those details in square brackets or small print will not need to be learned and will not be examined.

LASER is an acronym and stands for Light Amplification by Stimulated Emission of Radiation. Which leads us nicely onto what is stimulated emission? The Three Important Atomic Processes These three processes [two of which are already known from 2.3(j)] are:

1. Absorption of light 2. Spontaneous emission of light 3. Stimulated emission of light

Absorption of light by an atom is shown in the diagram below – a photon of the correct energy is absorbed by the atom and an electron gains enough energy to move from the ground state to the excited state (Note: for the moment we are only considering the ground state and the first excited state only). Excited state

Ground state

Photon absorbed

Electron excited to higher energy

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Spontaneous emission is the reverse process – an electron drops spontaneously (and randomly) from the excited state to the ground state and emits a photon of the same energy. These photons have random phase and random direction.

Excited state

Photon emitted

Ground state

Electron drops to Lower energy

However, there is also a third process [which was originally proposed by Einstein in 1917]. This process is known as stimulated emission – an electron is ‘stimulated’ to drop from its excited state by an incoming photon.

Incoming photon and emitted photon exit in phase and in the same direction

Excited state

Ground state

Electron stimulated to drop by photon

The reason that the electron is stimulated to drop is that the incoming photon is an electromagnetic wave and its e-m field will exert an oscillating force on the excited electron. If the incoming photon is of the correct frequency, this oscillating force will cause the excited electron to drop and both photons will exit with the same frequency, phase and direction. Note: again, the incoming photon needs to be of the correct energy. Inverting The Population In order to get as much light out of a system as is possible we need to get as many atoms excited as is possible. Obviously, the more electrons we have in an excited state the more will drop and emit photons (either spontaneously or through stimulation). However, there is one serious problem that arises when we produce a lot of light – the very photons that we produce are the actual photons that can be absorbed (they have the correct energy to produce both effects). If we have photons being absorbed all the time then our laser beam isn’t getting any stronger. Forget, for the moment about spontaneous emission (we are allowed to but we’ll explain why later). When a photon arrives at an atom one of three things can happen:

1. It can pass by and do nothing. 2. It can be absorbed (if the atom is in the ground state). 3. It can cause stimulated emission (if the atom is in the excited state).

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When it comes to producing a laser beam with a high intensity the three options above will have the following effect on the beam.

1. No change in the beam. 2. Net loss of one photon from the beam. 3. Net gain of one photon in the beam.

We need to arrive at a situation where stimulated emission is more likely than absorption so that the laser beam increases in intensity. Since stimulated emission occurs if the electrons are in the upper level and absorption when electrons are in the lower level we need to get more electrons into the upper, excited level. This is called population inversion (or N2 > N1 as stated in the syllabus, where N2 and N1 are the number of electrons in the excited state and the ground state respectively). Unfortunately, this goes against what happens in nature – lower energy levels are always more heavily populated than higher energy levels when we have thermal equilibrium (as we go up 1eV to higher energy levels the probability of occupation of the level drops by a factor of 1017). There’s only one thing for it – get rid of this thermal equilibrium. How do we do this? We continue to pump energy into exciting electrons to higher energy levels to maintain a population inversion and to break the conditions of thermal equilibrium. Population inversion is not usually possible if we only have two energy levels (if pumping is carried out by light). As we start to pump our system we have the following situation:

(N2 = 0) Excited state

Ground state (N1 = 8) Pumping light

Many electrons will be promoted to the higher energy and all seems fine. Unfortunately, if we succeed in exciting half the electrons we are now in the following situation:

Excited state (N2 = 4)

Ground state (N1 = 4) Pumping light

In this situation the incoming flood of photons is just as likely to cause an electron to drop (stimulated emission) as it is to cause an electron to rise (absorption). The best we can achieve here is N2 = N1 which is not quite good enough.

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The 3 Energy Level Laser System 1 Pumping. Electrons are promoted from the

ground state (E1) to E3 usually by using an external light source or by electron collisions.

1

2

3

E3

E2

E1

2 Electrons drop quickly (because E3 is chosen to have a short lifetime of the order of anoseconds) to the metastable (E2). Calling E2 metastable means that it has a long lifetime and electrons stay there for a long time (not that long really around a millisecond but that’s a very long time for an electron).

3 This is the transition that produces the laser photons so we must have N2 > N1. Note that, although stimulated emission still reduces our population inversion, the pumping is at a different wavelength. We have to make sure that the pumping [1] exceeds the stimulated emission [3] to maintain a population inversion.

Other things to note:

• E3 (to E2) has to have a short lifetime because E3 cannot start to fill up – pumping won’t then be possible. Also, we don’t want the electrons to stay in E3 and have them stimulated to drop back to E1 by the pumping light – that’s back to the 2-level system again which wasn’t quite good enough.

• More than half the electrons from E1 must be pumped to E2 (via E3) in order to obtain a population inversion – that’s a lot of electrons!

The 4 Energy Level Laser System 1 Pumping again. 2 Quick drop to the metastable state E3. 3 This is the laser light producing transition so this

time N3 > N2. However, because E1 is the ground state, E2 is practically empty initially so obtaining population inversion is far, far easier (definitely no need to pump half the electrons!).

4 Another quick transition so E2 has a short lifetime. This is because we want E2 to be empty so that we have a population inversion (if N2 is small it’s easier for N3 to be larger than N2).

1

2

3

E4

E3

E2

E1

4

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Laser Construction

Amplifying medium

Mirror: approximately 99% reflecting (approx. 1% gets transmitted)

100% reflecting mirror

Laser beam

In order to ensure that the laser produces light of a high enough intensity, the above set up is used. The amplifying medium is the region where the population inversion exists. This means that the conditions are right in the amplifying medium for stimulated emission. Under these conditions one photon has the potential to produce two photons and these can produce 4 photons, then 8 photons etc. Like a chain reaction, this process will lead to an exponential increase in output energy. Laser physicists aren’t happy with this, they go even further – they use mirrors to ensure that this exponential increase happens many times. Because only 1% of the light exits each time it reflects back and forth between the mirrors, on average, the beam will pass through the amplifying medium a hundred times before it exits. Now, considering that each time the beam passes through the amplifying medium it is increasing exponentially, this factor of 100 makes an enormous difference. [Try calculating e0.1 and then e10 on your calculator and see the difference!] This all leads to very high light intensities inside the amplifying medium and this is why (as was said earlier) we can forget about spontaneous emission. Imagine that you’re an excited electron sitting happily in your higher energy level. Normally, you’ll just drop down spontaneously when your time is up. But, inside a laser, there’s so much light that you never drop spontaneously because before your time’s up you’ve been disturbed by another photon, stimulated to join in with all the other light and join in coherently as well! Efficiency Usually, lasers are very inefficient beasts. Because of the large energies required to maintain a population inversion, their efficiencies are generally far below 1%. Some reasons for this:

• The pumping energy (see [1] in the 3 and 4 level systems) is considerably larger than the output photon energy.

• High intensity pumping combined with the high intensity of the laser beam means that the amplifying medium will get very hot. So, there will be large heat losses. To make this matter worse, we need to cool the amplifying medium usually so that it, or its container, doesn’t melt. By cooling the system we just transfer more heat and increase our losses but better this than destroy a £50 000 laser!

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Semiconductor Lasers The basic structure of a standard ‘edge emitting’ semiconductor laser is shown below. The whole block shown below is a semiconductor chip with dimensions approximately 0.5mm x 0.5 mm × 1 mm.

‘sandwich’ of area with population inversion i.e. amplifying medium

ission

not silicon, usually gallium arsenide. This surface and its opposite are mirrors due to the air-solid boundary

below also

metal contact

light em

metal contact

[Although the chip itself has dimensions approximately 0.5mm x 0.5mm x 1mm, the beam has an approximate cross sectional area of 30µm x 5µm and passes along the ~1 mm length of the chip.]

The above laser fits the basic shape of a normal laser (shown below).

Amplifying medium

mirror Mirror The mirrors, however, are far from the 100% and 99% reflecting ideals discussed earlier. The mirrors are simply due to the semiconductor-air boundary at the edges of the chip. [This in fact gives 40% reflection only (at both sides).] This would be disastrous for highly inefficient gas lasers but not for our semiconductor laser. The reason why:

• The population inversion inside the semiconductor sandwich area is millions of times higher than in gas lasers [~1025 electrons/m3].

• The exponential increase in light intensity (i.e. 1 photon becoming two, becoming four etc.) occurs far more quickly because of the higher population inversion.

• So the fact that we lose 60% of the light at each reflection is compensated for by having huge gains between the mirrors.

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How can a population inversion be set up just by applying ~3 V d.c. voltage? [You don’t need to know this but you might find it interesting] Some of this next part used to be in the A-level syllabus many years ago. It shows a couple of band diagrams of a p-n junction in a very highly doped semiconductor.

Note: This is a diagram for a horizontal p-n junction but the junction in the laser diode diagram is vertical.

p-type semiconductor

n-type semiconductor

Electrons

Holes

After a small (~3 V) p.d. has been applied, we get: Can you see the area of population inversion? If you look carefully, there’s a small region in the middle between the p-type and the n-type where we have a high concentration of electrons above holes. These are the electrons that can be stimulated to drop and provide laser light.

Holes

Electrons

−ve +ve

Advantages and Uses of Laser Diodes These are straightforward and can be summarised as follows:

Advantages: Some Uses:

• Cheaper • Smaller • More efficient • Easy to mass produce

• Inside DVD and CD players • Barcode readers • Telecommunications (via optical

fibres) • Image scanning • Laser surgery

The usefulness of laser diodes is ‘reflected’ in the number of them produced annually – around 1 billion (109) laser diodes are produced worldwide per year!

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For more than enough further reading see: http://members.aol.com/WSRNet/tut/ut1.htm Physics PH6 written paper 2007, comprehension question. Wikipedia http://en.wikipedia.org then type ‘laser’ or ‘semiconductor laser’ Google http://www.google.co.uk/ then search ‘laser theory’ PH2.4 – MATTER, FORCES AND THE UNIVERSE We start in familiar territory. PH2.4(a) deals with the simple model of the atom as nucleus with orbiting electrons, in which the nucleus is composed of nucleons (protons and neutrons).

XAZ notation is required. The rest of PH2.4 is devoted to the modern quark and lepton picture, with a short review of the fundamental forces. PH2.4 ( b)-(g) Detailed notes on Quarks, Leptons and Fundamental Forces Nucleons have structure This section, until a third of the way down the next page, is non-testable background material which could provide a lead into PH2.4 (b). 1. Although electrons are point-like at scales of 10-18 m, nucleons have diameters of the

order of 10-15 m. Nuclear radius varies approximately as

13A – electron diffraction experiments – so

nuclear volume is proportional to A, showing that the volume of each nucleon is, at least approximately, the same.

Exercise: Radii of nuclei in fm: 6 28 56 120 208C 3.16, Si 3.93, Fe 4.85, Sn 5.99, Pb 7.1613AShow that r ∝ , and determine the density of nuclear material. [An A2 exercise would be to use

a log-log plot - and then go on to determine g at the surface of a 10 km diameter neutron star!]

2. Free neutrons decay into protons with a half-life of about 10 minutes.

The equation is 1 1 00 1 1n p e ν−→ + + e and is clearly energetically favourable, as the rest mass

of the neutron is greater than the combined rest masses of the proton and the electron. This is suggestive of a structure for at least the neutron and therefore the proton. [The very similar masses of the neutron and proton suggests that the particles are closely related – hence the use of the generic term nucleon.]

3. The Stanford/MIT Experiment of 1968 • 20 GeV Stanford Linear Accelerator (SLAC) in 1968 • Electrons fired down 2 km long accelerator tube • Target was a 7 cm container of liquid hydrogen. • Looked at interactions between the incident electrons and the protons in the hydrogen,

in which there was a large momentum transfer, shown by a large scattering angle for the electrons (looked at 10° and 6° which are quite large in these experiments.)

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• Results A large number of interactions was observed at these angles (just like the Geiger-Marsden-Rutherford α-particle scattering experiment). More technically, the distribution of scattered electrons was similar to that in the α-particle scattering, suggesting a point charge distribution. In other words – just as in the Geiger-Marsden experiment – the apparently solid object was in fact a collection of tiny ones. These large momentum-transfer interactions resulted in the production of new particles – typically the π0 meson.

The model of nucleon structure which best fits these and other results is the quark model, proposed by Gell-Mann and Zweig in 1964, in which nucleons are composed of three quarks bound together by the strong (nuclear) force. The work of Richard Feynman was instrumental in this interpretation. Quarks, antiquarks and quark combinations There are two types of quark in everyday matter – the so-called up quark (u) and down quark (d). The properties of these quarks are:

quark charge / e

u 23+

d 13−

Note that there is a potential confusion between the down quark (d) and the deuteron (d) i.e

– their symbols are the same. The distinction is usually clear from the context, but care will be taken over the framing of examination questions.

21H

Every particle has an antiparticle, which is identical to its corresponding particle apart from having opposite charge. Particles and corresponding antiparticles annihilate. In general the antiparticle has the symbol of the particle, but with a bar over it. Thus for quarks we have:

antiquark charge / e

u 23−

d 13+

Quarks are bound together into composite particles called hadrons. These are further classified…

Combinations of 3 quarks are called baryons [meaning ‘heavy ones’]. Neutrons and protons are baryons. A proton is composed of uud, and a neutron udd. The order of the letters doesn’t matter – it carries no information. [Check charges!] u u

d

proton u d d neutron

What would be the composition of (i) an antiproton, p (ii) an antineutron, n ?

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There does exist a family of four very short-lived baryons also composed of up

and down quarks: the Δ particles (delta particles). They are designated Δ++, Δ+, Δ0, and Δ−. The Δ+ and Δ0 have familiar sets of quarks – these two particles are essentially higher energy (excited) states of the proton and neutron respectively. What are the quark constituents of the Δ++ and Δ− ?

A combination of a quark and an antiquark is called a meson. A family of mesons that consists of only 1st generation quarks is the pions: π+, π0 and π−. These contain only up or down quarks and their antiparticles. So the charged pions must, have these quark structures…

u u d

π− π+ d

The composition of π0 is ambiguous. It could be either uu or dd .

It is actually – not for examination – a mixture of the two! Why don’t the uu and the dd self-annihilate? They do! The lifetime of the π0 is much smaller than that of the charged pions.

No such thing as a free quark

Our evidence for quarks is indirect, in the sense that it appears impossible to obtain a free quark, i.e. a quark by itself. Within a hadron, indeed within the nucleus, the quarks can move around, but they are bound together by the so-called strong force which does not decrease if the separation between the quarks increases. [Contrast the electromagnetic force between charged particles.] Hence the impossibility of obtaining free quarks.

Instead of freeing the quarks, when the bond between quarks is sufficiently stretched, a quark-antiquark pair is created using the potential energy in the stretched bond, and a new particle, a meson is formed. This is what happens in a so-called inelastic collision when a high [kinetic] energy particle is fired at a nucleon. For example…

Key up quark down quark

[π0]

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Students will not be expected to recall a host of different hadrons, but could be asked to work out the quark constituents of specified hadrons using the table below, which will be available in the examination. For example, a student could be asked to determine the composition at quark/antiquark level of the π+, given that is a meson, or of the Δ− , given that it is a baryon. [Students are expected to know that individually observable particles (i.e. excluding quarks) have charges in units of e.] Leptons The up and down quark are the so-called first generation of quarks. The first generation of leptons consists of the electron, e- and the electron neutrino, νe. ‘Lepton’ means ‘light one’ [The literal meaning of ‘meson’ is now easily guessed!] The table contains the first generation of quarks and leptons.

Leptons Quarks

particle (symbol) electron (e−) electron neutrino

(νe) up

(u) down

(d) charge / e − 1 0 2

3+ 13−

Lepton number +1 +1 0 0

There is also a second and third generation, each with two quarks, one charged lepton and one uncharged lepton. No questions will be set involving generations higher than the first. The electron’s antiparticle is the positron, e+. [Note that, for historical reasons, we don’t use the bar notation in this case.]

The electron was the first fundamental particle to be discovered [in 1896-7 by J J Thomson]. A-Level students should need no introduction to the electron. It is probably a different matter for the electron neutrino – or neutrino for short... Historically, the evidence for the existence of neutrinos was indirect and arose from the fact that, unlike α-particles, β-particles have a range of energies – suggesting that another particle was present which shared the energy in a random way. This evidence is not available in AS physics as it relies on the application of both mass/energy and momentum which are not available until the A2 course. Nonetheless this cloud chamber photograph of a 6He disintegration (beta decay) – see photo below – is highly suggestive.

The photograph [from a cloud chamber], shows paths of charged particles produced from the decay of a 6He nucleus at X. The short fat track is that of the daughter 6Li nucleus. The thin curved track is the electron (β- particle). Clearly something must have been ejected upwards and to the left…… Further evidence comes from a consideration of the β- energies [more in A2!]

Source: Sang 1995

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Lepton number

The electron and the (electron) neutrino are each assigned a lepton number of 1. Their antiparticles, the positron and the antineutrino, eν , are each assigned a lepton number of –1.

The point of doing this is that we find lepton number to be conserved. Thus in any interaction the sum of the lepton numbers before is equal to the sum of lepton numbers afterwards.

For example, the beta decay of the 6He nucleus is 6 62 3He Li e ν−→ + + e

The lepton numbers add to zero on the right. The lepton number is clearly zero on the left.

[Note also the conservation of charge, another infallible conservation law.]

In this interaction, a neutron in the nucleus is replaced by a proton. So we could write the beta decay as n → p + e− + eν

Or, at an even more fundamental level, recalling that a proton is uud and a neutron is udd, we could write the beta decay as d → u + e− + eν

Again, check charge and lepton number conservation.

Although the n, p version of the beta decay equation is fine for demonstrating the conservation laws, it should not be taken as meaning that beta decay involves one neutron decaying in isolation. We know that the neutron’s nuclear environment is involved, because different unstable nuclei have different half lives for beta decay. A similar remark applies even more strongly to the quark version: an isolated neutron has a half life of about 10 minutes, whereas a proton is to all intents and purposes completely stable – no tendency for its d to undergo the change shown. So the intra-nucleon environment matters. These subtleties will not be tested.

Exercise on applying Charge and Lepton number conservation Over the past 30 years, scientists have detected neutrinos from the Sun by their interactions with dry-cleaning fluid: specifically their interactions with a neutron in 37Cl nuclei. 37 3817 e 17Cl ν Ar X+ → + [X is unidentified for the moment.] This equation could be written at the nucleon level:

n + νe → p + X. It could also be written at the quark level:

d + νe → u + X.

Candidates could be asked to identify particle X. Solution: In order to balance with the other particles, it has to have a charge of −1 and a lepton number of +1, which means that it is an electron. Note that we could also say that it cannot be a baryon, because baryon number is also conserved, but that is not a requirement of the specification so it will not be asked.

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The four forces or interactions experienced by particles

Interaction Experienced by Range Comments

Gravitational all particles infinite Extremely weak – negligible except in the context of large objects such as planets and stars Not considered here

Weak all particles very short range

A very weak interaction – only significant in cases where the electromagnetic and strong interactions do not operate. Interaction governed by this are of low probability [in the case of collision interactions] or of long life-time [in the case of decays]. Governs any interactions including both hadrons and leptons, e.g. β decay and the p-p part of the p-p chain (see PH2.5).

Electromagnetic all charged particles infinite

Much stronger [and therefore more likely / shorter lifetime] than the Weak. Governs interactions composed entirely of charged particles and photons [N.B. Also experienced by neutral hadrons because they are composed of quarks]. Responsible for electric attraction and repulsion.

Strong quarks short range

The strongest interaction – only experienced by quarks and particles composed of quarks (i.e. hadrons). Responsible for the production of new particles from nucleon-nucleon interactions.

Examples of interactions – which interaction is responsible for each? • Neutron decay: en p e −→ + + ν

Governed by the weak interaction because, (i) includes neutrino, which is not affected by the strong or electromagnetic interactions, and (ii) it has a long lifetime [~ 10 minutes, which is long in particle terms, so the probability of the interaction is low.]

• Proton – proton collision: p p p p 0+ → + + π : Governed by the strong interaction because all the particles present are hadrons [consist of quarks]. Given enough energy to create a π0 this interaction is almost certain to occur, although p p p n ++ → + + π is also a good possibility.

• Electron-electron repulsion: e e e e− − − −+ → + Governed by the electromagnetic interaction because (i) the strong doesn’t affect leptons and (ii) although it would be possible to occur via the weak interaction, this is so much less likely.

• Proton-proton fusion: Governed by the weak interaction. Given the presence of the neutrino it is the only candidate. Also the fact that the average lifetime of a proton in the centre of the Sun is ~ 109 years, means that the process is very unlikely in any individual collision.

ep p d e ++ → + + ν

• π0 decay: [i.e. decays into two photons] Governed by the electromagnetic interaction because, (i) the pion is composed of a charged quark and a charged antiquark, which both feel the electromagnetic interaction, and (ii) neither the strong nor the weak interactions affect both quarks and electromagnetic photons. The lifetime of a π0, at 10-12 s, is very short compared to the charged pions which decay by a slower [less likely] weak process, e.g.

0π → γ + γ

ee ν− −π → + [lifetime ~10-8 s], because there is no electromagnetic process available.

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Useful websites These are written at an appropriate level for AS/A students: Standard Model: http://en.wikipedia.org/wiki/Standard_Model from the bbc. : http://www.bbc.co.uk/dna/h2g2/A666173 Particle adventure: http://particleadventure.org/frameless/standard_model.html The following site is worth it for one memorable sentence in brackets: http://engr-sci.org/pnu/1990/physnews.004.htm These sites contain a plethora of information – for self-motivated students only: http://hypernews.slac.stanford.edu/slacsite/aux/HiPPP/scattering/ http://www.physics.ox.ac.uk/documents/PUS/dis/index.htm http://physics.nmt.edu/~raymond/classes/ph13xbook/node194.html

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PH2.5 – USING RADIATION TO INVESTIGATE STARS This section of the specification is traditional 19th century physics applied to a current research area. The emphasis is on the use of spectra to investigate stars – the idea that some, in principle, very simple observations are enough to pin down important characteristics of stars including their surface temperature, power output and composition. The line spectra aspects of this unit are designed to fit in with section PH2.3 and so could be taught as a continuation of that section. The proton-proton chain section introduces the idea of remote sensing via subatomic particles and ties in well with section PH2.4. The black-body section is free standing. Detailed notes follow.

Detailed notes on PH2.5: Using radiation to investigate stars A star’s spectrum consists of a continuous spectrum, from the dense gas of the surface of a star, and a line absorption spectrum from the passage of the emitted electromagnetic radiation through the tenuous atmosphere of the star.

We start with some background material to assist in the interpretation of the continuous spectrum.

PH2.5 (b), (c) The Black Body Spectrum Good absorbers of radiation (of a given wavelength) are also good emitters (of that wavelength). A black body is the name physicists have given to an ideal surface which absorbs all the radiation that falls on it. Matt black surfaces approach this ideal. No surface at a given temperature can, purely because it is hot, emit more radiation, at any wavelength, than a black body.

The power emitted, per unit interval of wavelength, per m2 from a black body depends on the wavelength as shown by the curves for various temperatures of the body.

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Two of the most important laws that we find to apply to black body radiation are… Stefan’s Law The total power P of electromagnetic radiation emitted from area A of a black body at (kelvin) temperature T is given by P = σ A T4

In which σ is a constant called the Stefan constant. Its value is 5.67 × 10-8 W m-2 K-4.

P is the total of the power emitted at all wavelengths. It is proportional to the area under the curve for the particular temperature.

Wien’s Displacement Law

The wavelength, λp, at which the maximum power is emitted by a black body is inversely proportional to the temperature of the black body.

That is λp = W

T In which W is a constant called Wien’s constant. We find W = 2.90 × 10-3 K m. Three straightforward exercises 1. Use data from the curves to check Wien’s displacement law.

[The easiest way is to multiply λp for each curve by the temperature of the black body. Similar results, close to the accepted value of Wien’s constant, emerges each time.]

2. Draw vertical lines on the graph grid to show the extremes of the visible region of the electromagnetic spectrum. Hence explain why the black body at 3000 K appears yellowish compared with the body at 5000 K (even though the black bodies at all three temperatures shown are loosely described as ‘white hot’). What would be the appearance of a black body at 1000 K? What would be the appearance of a black body of a body at 8000 K?

3. A white hot lamp filament approximates to a black body. On this basis, estimate its temperature if the wavelength for peak emission is 1.16 × 10-6 m.

[Re-arranging Wien’s displacement law… T = W / λp = 2.90 × 10-3 K m / 1.16 × 10-6 m = 2500 K.] Estimate the surface area of the filament if the bulb emits radiation at a power of 70 W. [To estimate the surface area of the filament we will assume that the filament is a black

body at 2500 K. So, re-arranging Stefan’s Law… A = P / σ T4 = 70 / (5.67 × 10-8 × 25004) = 3.2 × 10-5 m2.] [Note that most of this radiation will be in the infrared (see curves) and is therefore, from

the point of view of illumination, wasted. What is more, the electrical power input to the lamp would have to be more than 70W, as some energy is lost as heat conducted along the wires from the filament and as heat convected from the filament by the inert gas surrounding it. Hence the phasing out of filament lamps as energy wasters.]

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PH2.5 (d) A Star’s Continuous Spectrum Using a telescope, a special diffraction grating, and a detector sensitive across a wide range of ultraviolet, visible and infrared wavelengths we can study the way in which a star’s radiation is distributed among different wavelengths. [Allowances have to be made for selective absorption by the Earth’s atmosphere.] None of the experimental method is required, but students need to know the result: a star has a continuous spectrum almost identical to that of a black body. We can usually assume that a star radiates as a black body.

On this assumption we can find out some key information about a star light years away by studying its continuous spectrum. We need to extract two figures: (i) the total power (across all wavelengths) reaching the vicinity of the earth, (ii) λp, the wavelength of peak power. How we could proceed is best shown by an example. This also illustrates the level at which we feel it would be reasonable to ask examination questions…

Example Consider the following observational data, which relates to Arcturus, a bright reddish star in the constellation of Boötes: Wavelength of peak emission in continuous spectrum = 674 nm Power received per m2 at the Earth = 3⋅09 × 10-8 W m-2 Distance from Earth = 36⋅7 l-y [= 3⋅47 × 1017 m]

a. Sketch the continuous spectrum – a nice easy intro. b. Calculate the Kelvin temperature. c. Calculate the total power emitted [This called the star’s luminosity.] d. Calculate the radius of Arcturus. (b) To find the Kelvin temperature: use Wien’s law:

3

9max

2 898 10 m K 4300K[3s.f.]674 10 m

WTλ

⋅ ×= = =

×

(c) To find the total power emitted, consider that, at the distance of the Earth, the power is spread out over the surface of a sphere of radius 3⋅47 × 1017 m, so that the total power is given by:

2 84 3 09 10 W 4 68 10 WP rπ −= × ⋅ × = ⋅ × 28

4

.

[Note that the total Solar power output is 3⋅90 × 1026 W, so that Arcturus is ~ 120 × as

powerful as the Sun on these data.] (d) To find the radius use Stefan’s Law: 24P r Tπ σ= , where r is the stellar radius this time.

2810

4 8 4

4 68 10 1 38 10 m4 4 5 67 10 4300

PrTπσ π −

⋅ ×= = = ⋅ ×

× ⋅ × ×

[ i.e. 13⋅8 million km, approx 20 × that of the Sun.] Additional remarks on PH2.5 (a) – (d) “How science works” and the 19th century ‘ultra-violet catastrophe’ suggest themselves as discussion topics. Students will not be tested on the ‘ultra-violet catastrophe’! The cosmic microwave background radiation is an almost perfect black body spectrum. We should really have mentioned it in the specification. We didn’t – but that doesn’t mean it couldn’t be included in questions, given sufficient - background - information. It fits well in PH5 in the comprehension passage….. 32

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PH2.5 (e) (f) A Star’s Line Absorption Spectrum Dark lines cross a star’s continuous spectrum. These co-incide in wavelength with the known emission lines of particular elements. [Allowances may need to be made for Doppler shifts, but this is not to be tested in PH2 examinations.] The implication is that these elements are present in the tenuous outer ‘atmosphere’ of the star, and absorb specific wavelengths from the continuous spectrum of light passing ‘outwards’ through this atmosphere.

This ties in with PH2.3 (h), (j). It would now be fair to test the work on absorption spectra in this stellar context. For example, students could be given wavelengths of a dark lines, and simplified atomic energy level diagrams, and asked to make reasoned deductions about element(s) present in the star’s atmosphere.

http://casswww.ucsd.edu/public/tutorial/Stars.html (up to, but not including, ‘spectral classification’) presents some useful pictures and diagrams.

http://jersey.uoregon.edu/vlab/elements/Elements.html lets you click on lines to find their wavelengths.

Almost two hundred years ago Joseph Fraunhofer made a study of dark lines crossing the Sun’s spectrum, and in particular noted dark lines at exactly the same places in the spectrum as the yellow [sodium] lines in a candle flame. Although he couldn’t explain what was going on, he had made an exceedingly important discovery: up to that time no-one had the slightest idea that the Sun’s composition shared anything in common with that of the Earth. For interest only, go to

http://astronomy.neatherd.org/Fingerprints%20of%20light.htm

Analysis of stellar spectra reveals that 75% of the universe by mass is Hydrogen, and 24%, helium, with very small quantities of the other elements.

The question naturally arises: where have the other elements come from? This is not required to be learnt, but for those interested, a very readable account is given in

http://fire.biol.wwu.edu/trent/alles/Origin_of_Elements.pdf .

PH2.5(g) Source of the Sun’s Energy In a star like the Sun, energy is transferred from the Sun’s core to its surface layers by a combination of radiation and convection. But what happens in the core? Energy is ‘produced’ through fusion reactions. The released energy is in the form of gamma ray photons, neutrinos and kinetic energy of the product nuclei, quickly randomised by collisions to random internal energy,

We require recall of the main branch (p-pI) of the proton-proton chain, which is the main energy production mechanism in stars like the Sun. There are 3 steps…

21

32

3 3 42 2 2

+ep p d e (where d deuteron H)

p d He γ (where γ photon)

He He He p p

ν+ → + + =

+ → + =

+ → + +

It helps to remember that at each step the nucleus acquires one more nucleon.

Neutrinos from the first step occurring in the Sun’s core are detected on Earth. Their release indicates that the weak force is involved. This means that the probability of the step occurring is very low for a given proton. That’s why the Sun doesn’t emit radiation at a greater rate than its miserly 3⋅90 × 1026

W, and is expected to survive for thousands of millions of years.

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Information on various sub-branches of the p-p chain [ppII and ppIII] might be used as examples in questions, as might the CNO cycle (important in stars heavier than the Sun). The ppII chain, which accounts for ~14% of the helium produced takes over at the last step of the ppI chain. The ppII chain is: 3 4 72 2 47 74 37 1 4 43 1 2 2

He He Be

Be e Li

Li He He He

+ → + γ

+ → + ν

+ → +e

Candidates would not be expected to recall this chain, nor even its existence, but could be expected to, say, infer that step 1 is governed by the electromagnetic interaction, and step 2 by the weak process, or to write step 2 at the level of quarks eu e d−⎡ ⎤+ → + ν⎣ ⎦

Useful Websites Note: Googling “proton-proton chain” gives a plethora of sites, many of which give far too much detail, but the following are interesting: P-p chain : http://csep10.phys.utk.edu/astr162/lect/energy/ppchain.html From Wikipedia http://en.wikipedia.org/wiki/Proton-proton_chain_reaction Nice – with animations: http://burro.cwru.edu/Academics/Astr221/StarPhys/ppchain.html Another animation http://www.physics.mun.ca/~jjerrett/protonproton/pp.html Part of a whole course on stellar physics: http://www.shef.ac.uk/physics/people/vdhillon/teaching/phy213/phy213_fusion3.html Dry, but links the production of solar neutrinos to their detection using Chlorine [they put the dry into dry-cleaning fluid]. http://www.sns.ias.edu/~jnb/Papers/Popular/Scientificamerican69/scientificamerican69.html [nice diagram of neutrino energies from the different branches of the p-p chain – this then related to the possibility of detecting using Cl-37]. If it’s not on this site, you didn’t want to know it – that goes for much of the material that is on the site too!

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4.3 PH3 – Practical Physics The attention of centres is drawn to the specification of this unit and the internal assessment guidelines on pages 24 and 57 of the GCE Physics specification. The focus of this unit is undertaking measurements and observations and an appreciation of the uncertainties inherent in these observations. Reference should be made to the Guidelines on the Treatment of Uncertainties <link to be inserted> on the WJEC website. Administration of the Internal Assessment. Based upon the preliminary entries which centres make in October, centres making entries will receive in February of each year a document entitled Confidential Instructions for Supervisors. This will contain general instructions for the administration of the assessment and a detailed description of the apparatus needed for each task. The questions will not be included with this mailing. Well before the scheduled time for the assessments, centres should assemble the required apparatus. The subject officer is available to answer any questions and deal with problems that may arise in doing this. The scheduled sessions for the assessment will be in two consecutive days in the last week in April. Centres are expected to enter candidates on the first day and only use the second day if candidates cannot be conveniently accommodated in one day. As the duration of the assessment is only 1½ hours, there is ample time for 2 or 3 sessions on each day. Centres which need to use more than one session may opt to use session 1 on day 1 and session 1 on day 2 rather than using two sessions on the same day. The assessment will come in two versions: version I is to be used on the first day and version II on the second. The structure of the assessment lends itself to accommodating candidates in multiples of six; at any one time, three of them would be undertaking Section A and three would be working on section B. For centres with large numbers of candidates, a possible arrangement is to have 18 candidates split between 2 communicating laboratories. Of course, 12 in each laboratory would also be possible, given sufficiently large laboratories. Centres will receive copies of the assessment questions and mark schemes in good time. In addition to the multiple copies of the assessment papers, centres will receive a containing a single copy of the assessment tasks which may be opened a week in advance. Supervisors should work through the tasks and ensure that the apparatus and questions work as intended. Following the completion of the tasks, supervisors should mark the work using the marking scheme provided. Moderation samples and marks should be despatched in accordance with the WJEC Internal Assessment Manual for that year.

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4.4 PH4 – Oscillations & Fields PH4.1 – Vibrations This section includes circular motion, simple harmonic motion, damping and resonance. It is essentially unchanged from the equivalent sections in the legacy specification. All its contents are adequately covered in many A-level Physics textbooks and there is no current intention to publish guidance notes. For examples of examination questions, see previous PH4 papers. PH4.2 – Momentum concepts This short section has been augmented by the introduction of the concept of photon momentum and hence of radiation pressure. This draws upon the photon ideas in PH2 and presents the opportunity for synoptic questions. The obvious application is the “light sail” which is proposed as a method of interplanetary propulsion. No equations in addition to

h hcp

fλ= = will be required. Questions could probe the difference between cases in which

photons are absorbed and those in which they are reflected [giving twice the momentum transfer]. The concept of elastic and inelastic collisions draws upon energy from PH1. For examples of examination questions, see previous PH4 papers. PH4.3 – Thermodynamics Statements PH4.3(a)–(g) deal with the behaviour of ideal gases. They include a simple treatment of the kinetic theory of gases, including the concept of the mole. It too is essentially unchanged from the previous specification. Statements PH4.3(h)–(p) cover the concepts of thermodynamics: heat, work and internal energy. The 1st Law of Thermodynamics is also included. In spite of its presence in the current specification, it is a section which many students find obscure and accordingly a set of notes is provided: go to the WJEC website, www.wjec.co.uk , select Physics and GCE AS/A under “Find resources” and “view the full list of documents” under Related Information. For examples of examination questions, see previous PH4 papers. PH4.4 – Electrostatic and Gravitational Fields of Force These two fields of force are treated together, in view of their mathematical similarity. The field line is introduced as indicating the direction of the force upon a test object [charge or mass, respectively] and leads on to its mathematical expression in the concept of the vector quantity of field intensity. The scalar potential in a field is defined in terms of the work required to be done [by an external agent] in bringing a unit test object from a point of zero potential – infinity for mathematical convenience. There are many similar equations and candidates will be helped to avoid their misapplication by the equation sheet included in the question paper.

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The only introduced concept in this section is that the gravitational field outside a spherically-symmetric body is identical to that of an identical point mass situated at the centre of the body. The point of introducing this statement [essentially Gauss’s Law] is to allow for the application of Newton’s Law of Gravitation to approximately spherical planets, moons and stars and, in the next section, to the hypothetical dark matter in which galaxies are supposed to be embedded. It is not explicitly stated, but the other aspect of Gauss’s Law will be assumed, i.e. that the net contribution to gravitation field by those parts of a spherically symmetric mass distribution lying outside the radius of the point in question is zero. For examples of examination questions, see previous PH5 papers. PH4.5 – Application to Orbits in the Solar System and the Wider Universe. This section of the specification contains traditional kinematics and application of Newton’s Laws of Motion. Much the theory is covered in A level text books. The section on mutual orbits is an exception. The applications to missing matter in galaxies and the detection of extra-solar planets (ESOs) require very little additional theoretical input. Statements PH4.5 (a) – (d) deal with the application of Kepler’s Laws of Planetary Motion and Newton’s Law of Gravitation to the orbit of objects around a massive central object. With the exception of the statement of Kepler’s Laws, this work could have been examined under the legacy specification. Suitable statements of Kepler’s Laws are:

K1: The planets orbit in ellipses with the Sun at one focus. K2: The radius vector sweeps out equal areas in equal intervals of time. K3: The square of the period of orbit is directly proportional to the cube of the semi-

major axis. The whole of PH4.5 will concentrate on circular orbits. Very little work will be set on the elliptical aspects. Candidates should be qualitatively aware of the ellipse. [eccentricity will not be explored quantitatively] and the meaning of “semi-major axis.” The implication of K3, that the period of orbit of an object in circular orbit is the same as that of an object in an elliptical orbit with the same semi-major axis, should be understood. An example of where this is important is the Transfer Orbit. Transfer Orbits Consider a satellite being carried on the upper stage of its launch rocket. It is currently in a low circular orbit – say an altitude of 500 km [radius of orbit ~ 7000 km]. It needs to be transferred to a geosynchronous orbit [radius ~42000 km].

A

geosynchronous orbit

transfer orbit

low earth (parking) orbit

B

The major axis of the transfer orbit is 7 000 + 42 000 = 49 000 km, so the semi-major axis is 24 500 km. The time taken to transfer can then be worked out because the time taken to 37

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complete half an orbit [the dotted line] is the same as the time for half a circular orbit of radius 24 500 km. Interestingly, though this is not required knowledge, the energy of the satellite in the transfer orbit is also the same as if it were in a circular orbit of the same radius, so we can calculate the additional energy [and therefore the impulse] needed to be given at A and at injection at B. “Derivation” of Kepler’s 3rd Law

This follows from Newton’s Law of Gravitation, 1 22

m mF G

r= , and the ideas of centripetal

force developed in section PH4.1. Consider an object of mass m in a circular orbit of radius r about a much more massive object of mass M. This could be satellite – natural or artificial - in orbit about a planet, a planet about a star or a star about the supermassive black hole in the centre of our galaxy. The centripetal force necessary for the [accelerated] circular motion is given by: 2F mrω= ,

or equivalently by 2

2

4F mrTπ

= , where T is the orbital period.

So we can write: 2

2 2

4GMm mrr T

π=

Dividing by m and rearranging, we have: 2 3

2 4 rTGMπ

= .

i.e the orbital period squared is proportional to the radius cubed, which is K3 for a circular orbit. Note that, we have assumed that the central body is a point mass, which it will certainly not be, but it is also correct if the central object is spherically-symmetric [see above]. Note also that, historically, the derivation was done in the opposite direction, with Kepler’s 3rd Law being the evidence for the inverse square relationship. Weighing the Earth Experiments to determine G, the universal constant of gravitation, used to be described as weighing the Earth. This is because a knowledge of G and the orbital radius and period of the Moon enables us to calculate the mass of the Earth. Data: Radius of Moon’s orbit = 3⋅844 × 108 m [380 000 km]. Period of Moon’s orbit = 27⋅32 days = 2⋅36 × 106 s. G = 6⋅673 × 10−11 N m2 kg−2.

2 32

E

4 rTGMπ

= , so 2 3

E4 rM

= = 6⋅04 × 1024 kg.

Note that, in this analysis, we have assumed that the mass of the moon is negligible and that the moon orbits about the centre of the Earth. In fact ME ~ 81 MM so the assumption leads to some inaccuracy albeit small [~1%].

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This type of analysis is very useful in obtaining information about remote objects in the universe. For example, we can “weigh” other planets and determine their mean densities, furnishing data which is useful for developing models of their composition. We can also weigh stars, black holes and whole galaxies using the same technique, see e.g. “how to measure the mass of a black hole” on the Physics page of the WJEC website. The relationship between T and r furnishes data which is useful for developing candidates’ graphical skills. Data on Jupiter’s satellites for example can be used in a log-log plot to establish the power law relationship. Students could also plot, say,

23T against a and use the

gradient to determine MJ. Alternatively, T against 32a is a possibility. Note that it is

unproductive to plot T2 against a3 as, whereas most of the points are almost at the origin a

couple are a long way out. Often the speed of an orbiting object is measured directly, e.g. using Doppler shift [see below] in which case we could use the following analysis to determine the central mass M.

2

2

GMm mvr r

=

Dividing by m and simplifying: 2 GMvr

= . Dark Matter and he motion of objects in galaxies. Spiral galaxies are flattened assemblages of stars which all rotate in the plane of the galaxy around the centre in its gravitational field. In additional to stars, spiral galaxies contain large quantities of gas and dust from which new stars form. Details of the structure of spiral galaxies will not be examined. Consider the following observed [simplified] rotational speed curve for a typical spiral galaxy: [The low radius part of the curve is obtained from observations of stars and gas clouds in the visible part of the disc. The observed speeds beyond the visible galactic disc are from orbiting clouds of neutral hydrogen which emit a characteristic 21 cm line in the microwave region of the spectrum.]

50 000 100 000 Distance from centre (light years)

Rotational speed (km s-1)

200

100

calculate

extent of visible disc

central galactic bulge

observed [N.B. the inner ellipse is my crude attempt using “Draw” to represent the central galactic bulge] The “calculated” curve is that predicted by taking into account the observed normal or “baryonic” matter in the galaxy. N.B. “Observed” doesn’t only mean “light-emitting” – it also includes dark gas clouds, whose speeds we can detect by their absorption lines in the light of more distant object which we view through them.

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A useful equation in investigating these curves is 2 GMvr

= , where r is the orbital radius, v is

the orbital speed and M is the total mass within the orbit [assuming a spherically-symmetric distribution] It is worth highlighting two regions of the curves:

(a) The low-radius part of the curves. Here the curves coincide and the speed is roughly proportional to the orbital radius. In other words, the wholes central region of the galaxy rotates with roughly the same angular velocity. This implies that the density of matter is constant within this region: For a constant density, ρ, the mass within an orbit of radius r = 34

3 rπ ρ .

So, using the equation above: 34

2 23 43

rv G G rr

π ρπρ= = , so v r∝ .

So we can see that, for the central regions of a galaxy, coinciding with the galactic bulge, the observed rotational velocity is consistent with the observed constant density of matter and the value of the matter density is consistent value of the rotational speeds.

(b) The high-radius part of the curves. The approximately constant orbital velocity is explicable if the density of the material falls off roughly as : 2r −

If , the total mass within the orbit, 2krρ −= ( )2 24 4M r kr dr krπ π−= =∫

So ( )2 44

G krv

π= = Gk , i.e. v is a constant

If we imagined a gas cloud orbiting at, say, 75 000 light years from the centre of the galaxy, it is doing so in the combined gravitational field of all the matter closer to the centre. In the case of a spherically-symmetric object we can for such purposes consider it as a point mass with its whole mass concentrated at its centre. Clearly the visible galaxy is not spherically symmetric, but it is not a bad approximation to consider it so for great distances. Beyond the visible disc, where the observed matter density is very low, we’d expect the orbital speed, v, to fall off approximately as 1

2r − , the same relationship as we observe for the planets in the Solar System. The observation that, beyond ~ 50 k l-y, the rotational speed is ~ constant implies that the material of the galaxy extends well beyond the observed galaxy, i.e. the visible galaxy is embedded in an unobserved cloud of material and also than the whole galaxy has a much greater mass [~ 10 times] than that of the observable matter.

N.B. It is worth emphasising that using “Dark Matter” to explain the discrepancy

between the observed and calculated orbital speeds is a hypothesis, albeit one which is widely supported in the theoretical cosmological community. Some theoretical cosmologists have proposed modifications to the law of gravitation to account for the observations. The modifications take into account the fact that, at the scale of the Solar System, the inverse square law works very well. In one such model, by Milgrom, the modification takes effect at gravitational accelerations of less than 10-9 m s-2 [i.e. ~10-10 g] and for these accelerations the gravitational force falls of as inverse r rather than inverse r2]. This is a classic example of “watch this space” or “How Science Works.”

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Objects in mutual orbit, leading up to the discovery of Extra-solar Planets. Centre of Mass We normally think that planets orbit stars and, to a good approximation, this is true because the planet is so much less massive than the star. For example, the MEarth = 6 × 1024 kg and MSun = 2 × 1030 kg. For precise work or for situations where the two orbiting bodies are of similar mass, such as a binary star or the Pluto-Charon system, we need to refer to the Centre of Mass. Both bodies orbit around a point which, in the absence of externally-applied forces, is stationary [or, more strictly, moves with constant velocity]. This point is called the centre of mass. Let us consider two spherically-symmetric objects, of comparable mass, orbiting about their centre of mass. Before we do any algebra, we can infer three things about the system:

1. Symmetry considerations tell us that that the centre of mass must be on the line joining the centres of the two objects.

2. The centre of mass must be between the objects as the direction of the centripetal acceleration must be towards it.

3. The angular velocities of the objects must be identical – if this were not the case, the objects would sometimes be on the same side of the Centre of Mass, which clearly contradicts point 2.

Time for some algebra: Consider two bodies, of mass m1 and m2 orbiting around their Centre of Mass, C. Each body exerts an attractive force upon the other and, by Newton’s 3rd Law, these are equal and oppositely directed.

So, we can write 2 21 1 2 2m r m rω ω=

So, dividing by ω , 1 1 2 2m r m r= Substituting for r2 1 1 2 1( )m r m d r= −

∴ 21

1 2

mr dm m

=+

Similarly 12

1 2

mr dm m

=+

The orbits of two massive objects, e.g. a binary star system: Now that the position of the centre of mass is sorted out, we can use Newton’s Law of Gravitation to work out the orbital characteristics of the binary system as follows: Consider the orbit of body 1 about the centre of mass. The centripetal force is provided by the gravitational attraction of body 2 upon body 1.

d

C1m 2m 2r

1r

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GCE AS and A PHYSICS Teachers' Guide 42

So we can write 2 1 21 1 2

Gm mm rd

ω =

Substituting for r1: 22 11 2

1 2

m Gm dm m d

ω =+

2m m

Dividing by m1m2 and rearranging: ( )1 223

G m md

ω+

=

∴as 2T πω

= ( )

2 32

1 2

4 dTG m m

π=

+ or

( )3

1 2

2 dT G m m

π=+

Consider the case of the Earth-Sun system. The Earth-Sun distance is 149⋅6 million km. With the masses given above, the distance of the centre of mass of the two bodies from the centre of the Sun is given by:

248

30 24

6 10 1 496 10 km 450 km2 10 6 10

r ×= × ⋅ × =

× + ×

In this calculation, clearly the mass of the Earth in the denominator is quite insignificant. The figure of 450 km compares to a radius for the Sun of 700 000 km – so not large!

246Earth

Sun Earth30

6 10 3 102 0 10

vv v−× ×= = ×

⋅ ×.

As the two bodies take the same time, T, to orbit the Centre of Mass:

Earth Sun

2 2Earth Sunr rTv vπ π

= =

So 11

Sun6

Earth Earth

22 1 496 10 m3 10

rv v

ππ−

× ⋅ ×=

×

So rSun = 440 km

which agrees to within the accuracy of the data. Can you spot the approximation? We’ll return to the idea of using momentum conservation when we analyse extra-solar planetary systems.

Aside: In fact, we could come up with this figure without the above analysis, just by using the idea of Conservation of Momentum. The argument could go as follows. Let the speed of the Earth in its orbit be vEarth, so its [linear] momentum is given by:

pEarth = 6 × 1024 kg × vEarth Assuming the momentum of the Earth-Sun system is zero, it follows that the momentum of the Sun is the same, in the opposite direction. So the orbital speed of the Sun is given by:

Question 1: If the mass of the Earth were 100 times as great [6 × 1026 kg], what would be the effect on: 1. the length of the year; 2. the position of the centre of mass of the Earth-Sun system; 3. the orbital speed of the Earth; 4. the orbital speed of the Sun.

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GCE AS and A PHYSICS Teachers' Guide 43

Question 2: The dwarf planet, Pluto, has a mass of 1⋅27 × 1022 kg. Its moon, Charon has a mass of 1⋅9 × 1021 kg. The mean separation of their centres is 19 640 km. Use these data to determine: Nice pic of Pluto,

Charon and the recently discovered Nix and Hydra

1. the position of their centre of mass; 2. the orbital period of the two bodies; 3. the orbital speeds of the two bodies.

Measuring speeds using the Doppler Effect. Many objects that we study, including stars and gas clouds, have emission and/or absorption spectra with identifiable lines. If such an object is moving towards or away from us, the wavelength of the radiation which we receive is shifted. This shift is towards longer wavelengths [red shift] if the object is moving away from us and towards shorter wavelengths if it is moving in our direction. We shall only use the low-velocity approximation for the Doppler shift,

i.e. vc

λλ

Δ= .

The velocity v in this equation is the component of the objects velocity relative to the observer along the line joining the observer to the object. This is known as the radial velocity, which can be slightly confusing, if we are considering an object in orbital motion about another]. In this low-velocity approximation [“low velocity” is relative to c, the speed of light, so speeds up to (say) 107 m s-1 would be considered “low”], any motion at right angles to the line of sight produces a negligible Doppler shift. Sign convention: In the equation above, Δλ will be positive if v is positive, so we measure v away from the observer. Alternative forms of the equation: Because the frequency of radiation, f, is inversely proportional to λ, the same equation holds, with the slight complication that there is now a minus sign:

f vf c

Δ= − .

Of course, if you are happy to remember that a positive v produces a smaller f you can forget about a sign convention. Information about stars from the Doppler Effect. Suppose we observe a star which has a massive star in orbit or, more correctly, a star and massive planet in mutual orbit. Normally, we would not be able to see the planet, but we would infer its presence from data about the speed of the star. In questions we would always assume that we see such a system edge-on. In reality, the situation is more complicated. All candidates might be asked to consider is what effect it would have on our observations if the system were tilted.

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GCE AS and A PHYSICS Teachers' Guide 44

Such a system might look as follows:

star orbit

light from the star to observers

on the Earth

massive planet

For such a system the data could be presented graphically, e.g. variation in the received wavelength of the sodium D2 line which has a laboratory wavelength of 589⋅00 nm.

589⋅00

λ / nm

0 0⋅5 1⋅0 1⋅5 20 Time /days 588⋅50

589⋅5

From this graph, you can determine: (a) the mean radial speed of the star system, from the mean wavelength [~589⋅1 nm]; (b) the star’s orbital speed, from the amplitude of the wavelength variation [~0⋅2 nm]; (c) the period of the orbit. Notice here the use of the word “radial”. Question (a) asks you to find the component of the binary system’s velocity in the direction directly away from the Earth. N.B. It is not only the wavelength [and frequency] of the radiation itself which undergoes Doppler shift. Recently astronomers noticed that the period of the pulsations from a pulsar [a neutron star] vary in a periodic way. This is attributable to the effect of an orbiting planet or companion star. They used the Doppler equation in the form:

T vT c

Δ= ,

where T = period of the pulsations, in the same way as the wavelength in the example above to work out the orbital parameters and the masses involved.

Where it all comes together: Most of the information about the masses of stars and the evidence for the existence of extra-solar planets has come from Doppler measurements in orbiting systems.

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GCE AS and A PHYSICS Teachers' Guide 45

For the case of Extra-solar planets we can assume that [where mp is the mass of the planet and mS is the mass of the star]. With this approximation, the equation for the period of the mutual orbit reduces to:

Pm mS

3

S

2 dTGm

π= (1)

Algebraic manipulation gives the following approximations for the orbital speeds:

S PS

Gv mm d

= (2) and

SP

Gmvd

= (3)

For a given star system, normally we would know the mass of the star, mS, from our knowledge of stellar models and the observations would be the received wavelength of a spectral line against time. For an edge-on system this variation would be sinusoidal and we can undertake the following steps: 1. From the graph, determine the orbital period, T. 2. From the amplitude of the observed Δλ, determine . Sv 3. Use equation (1) to determine the separation of the star and planet, d. 4. Use equation (2) to determine the planetary mass and (3) to determine its speed. Pm 5. If the planet occults the star [passes in front of it – if it’s a true edge-on system it

should do but many will just miss occulting the star], we can further estimate the planet’s diameter from the period of occultation and its speed and the ratio of the stellar to planetary diameters from the fractional decrease in the observed light.

The data needn’t be presented graphically, e.g.: Example The wavelength of the Hβ line which, in the laboratory has a value of 486⋅1 nm, in the radiation emitted from a star is observed to fluctuate with an amplitude of ± 1⋅05 × 10-3 nm with a period of 1⋅25 × 106 s. The mass of the star is 3⋅0 × 1030 kg. Assuming that this behaviour is caused by an orbiting planet and that we observe the system edge-on: 1. calculate the distance of the planet from the star; 2. calculate the mass of the planet and its orbital speed. STOP PRESS: Astronomers studying this star have noticed that its brightness drops by ~1% once in every orbit of the planet. This dimming lasts for 4⋅54 hours. They suggest that this dimming is caused by the planet blocking of the light from the star as it passes in front as seen from the Earth. 3. Use this information to estimate the diameter of the star and that of the planet. Calculate

also the planet’s density. Binary Star Systems Most information about stellar masses comes from a study of binary star systems, i.e. a pair of stars in mutual orbit. Because both objects in such a system emit light, the orbital velocities of the two stars can be found directly and so the masses can be calculated. Consider the following graphs of the radial speeds to two stars in close mutual orbit:

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GCE AS and A PHYSICS Teachers' Guide 46

What information can we glean from this without any algebra? • The mean radial velocity is + 40 km s-1, i.e. the binary system is receding from

us at this speed. • Assuming we see the system edge on, the speeds of the two components are

75 km s-1 and 25 km s-1 [these are the amplitudes of the speed variations]. • The period of the orbit is 17⋅6 days [1⋅52 × 106 s]

We can do some sums before we need to apply complicated theory: 1. The ratio of the masses is 3:1, i.e. one component [the faster one] has ¼ of the total

mass of the system and the other has ¾ of the total mass. This comes from momentum considerations: in the frame of reference in which the centre of mass is at rest, the momentum of each component must be equal and opposite. The speeds are in the ratio 1:3 so the masses must be in the ratio 3:1. Another way of looking at this idea is as follows: The gravitational forces on the components are equal: i.e. 2 2

1 1 1 2 2 2m r m rω ω= . Dividing by ω: 1 1 1 2 2 2m r m rω ω= , i.e. 1 1 2 2m v m v=

2. We can work out the circumference [and then the radius] of each of the orbits: e.g. The slower [more massive] component:

-1 6

circumference orbital speed orbital time25kms 1 52 10 s38 million km

= ×

= × ⋅ ×=

So the radius of the orbit is calculated at 6⋅04 million km [circumference = 2πr] Likewise the orbital radius for the faster component is 18⋅14 million km.

3. From the two orbital radii, we can infer that the separation of the stars, d, is 24⋅2 million km [the sum of their orbital radii].

Now the earlier formulae click in:

4. We can apply the formula ( )

3

1 2

2 dTG m m

π=+

to find the total mass, m1 + m2, of

the system – which comes out at 3⋅6 × 1030 kg, so the combined mass of the stars is roughly twice that of the Sun.

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GCE AS and A PHYSICS Teachers' Guide 47

5. From this, we can work out that the masses of the individual stars are 0⋅9 × 1030 kg and 2⋅7 × 1030 kg [remember the 3:1 ratio].

More or less useful references for gravity, spectra and mutual orbits Check out the applets on: http://www.ioncmaste.ca/homepage/resources/web_resources/CSA_Astro9/files/html/applets.html - more GCSE than GCE for Stars, Spectra and Kepler’s Laws On http://jersey.uoregon.edu/vlab/elements/Elements.html you can find the wavelengths of spectral lines [put the mouse cursor on the line and click] Doppler spectroscopy: http://en.wikipedia.org/wiki/Doppler_spectroscopy An example of a radial velocity curve: http://www.howstuffworks.com/planet-hunting2.htm Mutual orbit simulation: http://www.howstuffworks.com/framed.htm?parent=planet-hunting.htm&url=http://exoplanets.org/doppler.html This site also has mutual orbit simulation and a plethora of other applets: http://phet.colorado.edu/new/simulations/sims.php?sim=My_Solar_System Data for 51Peg: http://zebu.uoregon.edu/51peg.html Overview of detecting ESOs: http://astro.unl.edu/naap/esp/detection.html Another overview : http://www.esa.int/esaSC/SEMYZF9YFDD_index_0.html

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GCE AS and A PHYSICS Teachers' Guide 48

4.5 PH5 Magnetism, Nuclei & Options General PH5 is intended as a terminal unit, though the regulations do not require A level Physics to be cashed in at the same time as PH5 is taken. The 1¾-hour examination paper has 3 sections:

Section A This is a 60-mark section based upon the core content of PH5.1 – PH5.5. It is designed to be answered in about 60 minutes.

Section B This section carries 20 marks and contains a series of questions relating to the Case Study. It is designed to be answered in about 20 minutes.

Section C This section consists of 5 questions, 1 on each of the Optional Topics. The questions each carry 20 marks and are designed to be answered in about 20 minutes. Candidates will answer 1 question only.

SECTION A – Core content In line with the other units of this specification, PH5 is designed to require a teaching time of approximately 60 hours, of which ¾ should be devoted to the study of the compulsory core content. PH5.1 – Capacitance This topic is part of the national core and follows on from the electrostatic fields section of PH4. It also draws on energy and electrical circuits concepts. The equation for the decay of a capacitor is of the same form as that for radioactive decay. It is a good topic for the introduction of semi-log graphs for the determination of the time constant of the decay and hence the capacitance. There are many examination questions in past PH4 papers and the topic is well covered in most A-level physics textbooks. PH5.2 – B-fields This section deals with the concept and definition of magnetic fields, their effect on moving charges (in wires and in free space), their production and application in particle accelerators. This traditional topic is well covered in A-level text books and there are many examination questions to be found in past PH5 papers. PH5.3 – Electromagnetic Induction In addition to magnetic flux (linkage) and the laws of electromagnetic induction, this topic is linked via rotating coil generators to the basic concepts of alternating current electricity – frequency, period, peak values, r.m.s. values. The relationship between peak and r.m.s. values for a sinusoidally varying quantity and the use of r.m.s. current and voltage in power calculations are explored. Candidates will be expected to have used oscilloscopes to measure voltages and currents [by the p.d. across a resistor] and frequencies. This traditional topic is well covered in A-level text books and there are many examination questions to be found in past PH5 papers.

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GCE AS and A PHYSICS Teachers' Guide 49

PH5.4 – Radioactivity and Radioisotopes This core topic is largely unchanged from the previous specification and is well covered in A-level text books. Candidates will be expected to handle logarithm and exponential functions. Calculations on decay can be expressed via the exponential function te λ− or 2 x− , where x is the number of half-lives. This topic area lends itself to synoptic questions which combine concepts of relative atomic mass and the mole with the decay equations to calculate the activity of a given mass of material of known decay constant. Past PH5 papers contain many examination questions of an appropriate level. PH5.5 – Nuclear Energy This core topic is largely unchanged from previous specifications. As with radioactivity, the mole concept will be used in estimating the energy release from macroscopic quantities of reacting materials – the electron volt is also a concept from AS which is of use here. Conservation of mass/energy s introduced, using E = mc2. This concept can be applied generally and not only in particle interactions – e.g. calculate the Sun’s power output, and hence the Solar Constant, given that its mass loss per second is 4 million tonnes. A useful concept is the energy equivalence of 1 u. 1 u = 1.6604 × 10−27 kg. The energy of this mass is 1.6604 × 10−27 × c2 = 1⋅491 × 10-10 J = 931 MeV. The use of neutrino energy in neutrino detectors is possible. The common reaction used in detectors is:

37 38 117 e 17 0Cl ν Ar e−+ → +

The masses of the particles are: Cl: 36.96590 u νe: 0 [at least negligible] Ar: 36.96677 e: 0.000548 u

The gain in mass in the interaction Δm = 36.96677 + 0.0005 − 36.96590 = 0.00142 u ≡ 1.32 MeV. This means that only neutrinos with a kinetic energy of more than 1.32 MeV can cause this interaction. The mean neutrino energy produced by the first step in the proton-proton chain is only 0.26 MeV, so most of these are not detected. SECTION B – the Case Study Centres with candidates for PH5 will receive, in February of the relevant year, multiple copies of a printed passage based upon a physics topic of contemporary interest. The topic will be chosen to relate to previously studied areas of the AS and A2 specification. It will be assumed that candidates have covered the whole of the AS specification and PH4 at least. The passage should be given to candidates for study and teachers are encouraged to discuss its contents with them, drawing their attention to the relevant areas of the specification and considering the sorts of questions which could arise from its contents. Candidates will be provided with a clean version of this passage in the PH5 examination and will not be permitted to take notes into the exam.

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GCE AS and A PHYSICS Teachers' Guide 50

Previous PH6 examinations contain similar passages with the difference that, in the legacy specification, candidates had not previously seen the passage and were expected to read it in the examination. Nevertheless, these passages form a good resource for introducing this section of the paper. Because candidates will be expected to have studied the passage prior to the examination, no allowance for reading is built into the duration of PH5, which is 105 minutes. SECTION C – Options There are 5 optional topics:

A Further Electromagnetism and Alternating Currents B Revolutions in Physics C Materials D Biological Measurement and Medical Imaging E Energy Matters

Each topic is designed to be studied in approximately 15 hours of teaching time. They could all be taught at the end of PH5. They fit in with the rest of the specification in different ways, which suggests that different teaching strategies are appropriate: Option A follows on immediately from the electromagnetism and A.C. material in PH5. The filters section relates also to the potential divider ideas in PH1. The Electromagnetic Revolution aspect of Option B, which will be the setting for questions for the first 3 years, relates in the early stages to the optics material in PH2, the electrostatics in PH4 and the electromagnetism in PH5. There is a strong case, if this option is to be offered, for incorporating its ideas throughout the teaching of the rest of the course, Option C, materials, consists of ideas which were previously in the compulsory specification and are now optional. There are few strong links with other sections of the specification. Option D, Biological Measurement and Medical Imaging, has links to PH2 and PH5. Option E, Energy Matters, links to PH1, PH2 and PH4 and so a possible approach would be introduce the content throughout the course. Guidance notes on each of the options follows:

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GCE AS and A PHYSICS Teachers' Guide 51

Unit PH5 Option A – Further Electromagnetism and Alternating Currents The majority of this option unit is taken from the legacy specification where it was compulsory content. This historical material divides into 3 parts: 1. Mutual induction and its application to transformers. This treatment is largely qualitative,

except for the treatment of the ideal transformer in terms of turns ratio and the equality of input and output powers.

2. Self inductance and inductors. 3. Phasor analysis of series RC, RL, LC and RCL circuits. This material is adequately covered in text books and PH5 papers. Questions on transformers also appear in past GCSE Physics papers. It is not the current intention to produce teacher guidance notes on these aspects of Option A. Statements (p) – (r) deal with the sharpness of a resonance curve (Q- factor) and the application of the RC potential divider to high pass and low pass filter circuits. These topics are well dealt with in Electronics text books and past GCE Electronics papers [ET4] of WJEC but have not been dealt with in previous WJEC GCE Physics specifications. The Quality factor (Q) of a resonant circuit The quality (Q) factor of a LCR circuit is related to the sharpness of the resonance curve. A high Q factor gives a sharp resonance curve while a low Q factor gives a broad resonance curve (see the diagram below with Q = 8 and Q = 2).

The main component in determining the Q factor of the circuit is the resistance of the circuit because it is the resistance that dissipates energy away from the circuit. This is similar to pushing a swing back and forth – if there is a lot of friction taking energy away from the swing it’s difficult to achieve a high amplitude and ‘sharp’ resonance. The easiest way to define the Q factor is as follows

r.m.s. pd across inductor r.m.s. pd across resistor

Q =at resonance

at resonance

As the capacitor and inductor have equal reactance at resonance, the Q factor can also be written:

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GCE AS and A PHYSICS Teachers' Guide 52

r.m.s. pd across capacitor r.m.s. pd across resistor

Q =at resonance

at resonance

These definitions lead to the equations

0 0I L LQ

IR Rω ω

= = and also 0

0 1Q

IR CR

IC

ω

ω= =

If we also incorporate the expression for the resonant frequency, 0

1LC

ω = , then

0

11

LL LLCQR R R

ω= = =

⎛ ⎞⎜ ⎟⎝ ⎠

C

So we have three expressions for the Q factor.

0

0

11L LQ

R RCRω

ω= = =

C

Note that, in the expressions for the Q factor, we can eliminate L, C and ω0 but we cannot eliminate R – it is in all 3 expressions. Note also that the Q factor is a ratio and it has no units. Now consider this circuit:

~10 V

10 mH 10 nF

10 Ω These values for R, C, L make our arithmetic reasonably easy. They give us the following figures:

5 -10 2 8 10

1 1 110 s

10 10 10LCω

− − −= = = =

×

and 5 2

0 10 10100

10L

QR

ω −×= = =

We can also calculate the current flowing at resonance because the whole of the supply p.d. is across the resistor at resonance (p.d.s across the inductor and capacitance are equal and opposite, so cancel).

101 A

10V

IR

= = =

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GCE AS and A PHYSICS Teachers' Guide 53

All seems nice and straight forward until we look at the p.d. across the capacitor or inductor.

( )5 20 CL 1 10 10 1000 VI L VV ω −= × × = ==

How can we have 1000 V across the inductor (and capacitor) when the supply voltage is only 10 V? There is no simple answer to this question but a better understanding can be drawn from considering another type of resonance. Again, consider a swing with very little friction. You only need to provide a small push regularly in order to obtain a large amplitude – you might only be pushing the swing for a distance of 30 cm but the amplitude of oscillation could easily be 2 m. Understanding how a series LCR circuit can be used to select frequencies We know now that LCR circuits with high Q factors can increase the p.d. in an a.c. circuit. This can be used in the design of a simple radio. The circuit below can be used as the detection part of a simple radio. It consists of an antenna (long wire), inductor, variable capacitor and earth connection. If you look at the loop in the above circuit, you’ll notice that there is no resistor. It is an LC circuit without the R. Why is this? Remember that we want a high Q factor and one of the ways that this is achieved is to keep the resistance low. Does this mean that the resistance in the LC loop is zero? Obviously the resistance cannot be zero because the connecting wires aren’t made of superconductors. But the main source of resistance in the LC loop is the inductor. Remember that an inductor is a long wire wound into a coil. In order to make a large number of loops we need a thin wire and this increases the resistance of the inductor (a bit of a Catch 22 situation). A simplified way of analysing the performance of the detecting circuit above is to consider it as follows:

A good application of synoptic physics: Remember that radio waves are electro-magnetic waves and have oscillating electric (and magnetic) fields. These oscillating fields will cause electrons to move in the metal antenna. The moving electrons will give us an alternating current and an alternating p.d. (due to the resistance of the antenna).

earth

~

VOUT

antenna

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GCE AS and A PHYSICS Teachers' Guide 54

i.e. we have a series LCR circuit and the voltage across the variable capacitor is the output voltage. Note also that we have redrawn the inductor as a resistor and inductor in series because of the inherent resistance of the wires of the inductor. If we have resonance in the LCR circuit we know (from the definition of the Q factor) that the p.d. across the capacitor will be Q times the supply p.d. Hence, we can amplify the input p.d. by a factor of Q. Also, because of the shape of the resonance curve we only amplify the frequencies around the resonance frequency, so we have selectivity. So why do we use a variable capacitor? This is because we can vary the resonance frequency by varying the capacitance. We obtain the resonance frequency from the equation below.

00

12 2

fLC

ωπ π

= =

So, the above simple circuit does three things:

1. Amplification - it amplifies our signal 2. Tuning - it can tune to a particular resonance frequency (by changing C) 3. Selectivity - it amplifies only those frequencies around the resonance frequency.

If you would like to see this tuning circuit in operation there is a reasonably priced kit available from Maplins - N51FL crystal radio £5.99. Alternatively, it is possible to design and build your own radio using instructions available from many internet sites e.g. http://www.midnightscience.com/cigar.html, http://journeytoforever.org/edu_radio.html, http://www.electronics-tutorials.com/receivers/crystal-radio-set.htm .

~

0.15 mH

10 Ω

Example This circuit is used in a simple radio.

(i) Calculate the Q factor when C = 6 pF and when C = 600 pF. 6 − 600 pF

(ii) Calculate the range of frequencies to which the circuit can tuned.

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Using CR circuits as Low Pass and High Pass Filters NOTE: One thing you must beware is that you cannot simply add the rms p.d.s across the resistor and capacitor in either of these a.c. filter circuits. Remember always, for r.m.s. p.d.s , 2 2VIN C RV V= + and that (in general)

IN C RV V V≠ + Low pass filter: Compare with The easiest way to explain how the above circuit behaves as a low pass filter is to compare it with a voltage divider. In the circuit on the right, the supply voltage is shared between the two resistors. In the low pass filter, on the left, the voltage is divided between the capacitor and the resistor.

Remember that the reactance of the capacitor is given by: C1XCω

=

From the above equation, at low frequencies XC will be very large. So at low frequencies we have a voltage divider with a very large “resistance” in the R2 position. This means that nearly all the supply voltage will be across the capacitor at low frequencies. At high frequencies XC will be very small. So at high frequencies we have a voltage divider with a very low “resistance” in the R2 position. This means that nearly all the supply voltage will be across the resistor at low frequencies i.e. there will be a very low p.d. across the capacitor. If we were to draw a graph of Vout/Vin against frequency we would get:

~ Vin

Vout

R

C R2

R1

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0

0.2

0.4

0.6

0.8

1.0

100 102 104 106

Frequency/Hz

Vou

t/Vin

Low pass filter output

Note that Vout/Vin is usually called the gain and that it starts at 1 and drops to zero (this is because Vout = Vin at very low frequencies and Vout = 0 at very high frequencies). Example

1. Calculate the frequency when the rms p.d.

across the resistor is equal to the rms p.d. across the capacitor.

2. Calculate the rms p.d. across both the resistor and the capacitor at the frequency of Q1.

Answers 1 Equating the p.d.s across the capacitor and resistor we get:

CIX I= R . Cancelling I gives us: CX R=

But C1XCω

= , hence 1 RCω

= and rearranging we get 1CR

ω = .

Using 2 fω π= , we get: 9

1 1 159 kHz2 2 2 10 1000

fCR

ωπ π π −= = = =

× ×.

Beware: There are 3 pitfalls to avoid if you want to obtain the correct answer even after you’ve

obtained the equation 12

=CR

.

• First, you must remember that kΩ means 1000 Ω. • Second, you must remember that nF means 10-9 F. • Third (but this only applies if you have an EXP button on your calculator and if

you’re too lazy to do the powers of 10 in your head!), when putting 10-9 in your calculator you cannot type 10 exp -9 because this is the same as 10×10-9. You must type (and this might seem strange until you think about it carefully) 1 exp -9 because this is 1×10-9.

10V ac supply

~ V

1kΩ

Vout 1nF

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2 There are many ways of obtaining the correct answer

e.g.using 2C

2Z X R= + and VIZ

= etc.

but it is probably more direct and simple to do as follows: Remember that and that 2 2

S C RV V V= + 2RCV V= from question 1.

So , ∴ 2 2S C2V V=

22 S

C 2VV = and hence S

C10 7 07 V

2 2VV = = = ⋅

So the correct answer is that the p.d. across both the capacitor and the resistor is 7.07 V. Beware: Do not fall into the trap of saying that both rms p.d.s must be 5V so that they add up to 10V. Although this sort of argument applies to instantaneous p.d.s it is completely wrong for obtaining rms p.d.s because the p.d. across the capacitor is out of phase with the p.d. across the resistor. High pass filter: In the low pass filter of the previous section we noted that when the p.d. was low across the capacitor the p.d. was high across the resistor. If we now swap our capacitor and resistor, the output p.d. will be the p.d. across the resistor instead of the capacitor (see below left). In this circuit we will have a high output where we previously had a low output and a low output where we previously had a high output. See the graph at the bottom of the page and compare it with the previous low pass filter graph. The graph at the bottom of this page is characteristic of a high pass filter. Compare with

R R2

R1

~ Vin

Vout

C Again, the easiest way to explain how the above circuit behaves as a high pass filter is to compare it with the voltage divider (on the right). In the circuit on the right, the supply voltage is shared between the two resistors. In the high pass filter, on the left, the voltage is divided between the capacitor and the resistor.

Again, remember that the reactance of the capacitor is given by: C1XCω

=

From the above equation, at low frequencies XC will be very large. So at low frequencies we have a voltage divider with a very large “resistance” in the R1 position. This means that the output voltage across the resistor at low frequencies will be close to zero.

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At high frequencies XC will be very small. So at high frequencies we have a voltage divider with a very low “resistance” in the R1 position. This means that nearly all the supply voltage will be across the resistor at high frequencies. If we were to draw a graph of Vout/Vin against frequency we would now get:

0

0.2

0.4

0.6

0.8

1.0

100 102 104 106

Frequency / Hz

Vou

t / V

inHigh pass filter output

Note: Filters are usually drawn in the following manner:

C

R VIN

0 V

VOUT This makes it easier to draw higher order filters (i.e. one filter feeding into another to provide more filtering). This notation has not been used here so that students can compare the circuit more easily with a potential divider. However, the above notation may well be used in an examination.

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Unit PH5 Option B – Revolutions in Physics

OPTION B: REVOLUTIONS IN PHYICS ELECTROMAGNETISM AND SPACE-TIME

1. Lifetime of the Electromagnetism and Space-time material When a History of Physics option was proposed, two periods of revolutionary change immediately suggested themselves for study: the century of Kepler, Galileo and Newton, and the century of Young, Faraday and Maxwell. Rather more interest was expressed in the second of these, and only the Electromagnetism and Space-time revolution will be examined in 2010, 2011 and 2012. After the new A-Level has been running for a year or two, teachers will be consulted on whether or not a change should be made for examinations in 2013 and beyond.

2. Content One of the most exciting things in Physics is to discover relationships between phenomena which are seemingly very different in nature. What happened in electromagnetism in the nineteenth century is a wonderful example. In the year 1800 there were only the vaguest indications that magnetism had anything to do with moving electric charges, and no evidence at all that light had anything to do with electricity or magnetism. By 1900 magnetism and electricity had been firmly linked, and light had been shown to be an electromagnetic wave.

The seemingly obvious need for electromagnetic waves to have a propagation medium (the ether) created problems. These were resolved in a very radical way by Einstein’s Special Theory of Relativity.

The structure of the course is shown in a little more detail in the diagram below. The first main ‘block’ deals with events leading to the acceptance of the wave theory of light, starting with a careful look at Thomas Young’s description of his two slits experiment. Electromagnetism is the subject of the next main block, starting with Ørsted’s discovery of the magnetic effect of a current, and considering at some length the subsequent work of Ampère and Faraday.

Maxwell arrived at the conclusion that light was an electromagnetic wave using what we would now call a mechanical model of electric and magnetic fields. How he made the synthesis is looked at in some detail, as are the beautifully simple confirmatory experiments of Hertz. The Michelson-Morley experiment is then outlined, as are responses to its failure to yield the expected evidence for the ether. Finally there is a small taste of Special Relativity theory (a simple treatment of time dilation)

A brief survey of light, electricity and magnetism before 1800

(NEWTON, HUYGENS, GILBERT, GALVANI, VOLTA) YOUNG

FRESNEL

ØRSTED

AMPÈRE

FARADAY

synthesis

MAXWELL

HERTZ

MICHELSON

EINSTEIN

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3. Serving Suggestions All the material to be tested in the examination is contained in the 34 sides of WJEC notes, which are available in electronic form from the Physics section of the WJEC website <link to be inserted> or as hard copy from the WJEC subject officer.

The notes contain many self-test questions and could be used by a student for self-study. They are also peppered with links to websites which help to bring the basic material of the option alive and make it easier to learn. The sites often contain pictures and diagrams.

The first half of the course (Young, Ørsted, Ampère, Faraday) deals largely with concepts in light and electromagnetism which are key parts of the non-optional A-level specification, but comes at them from a different angle, adding ‘human interest’, and (obviously) a historical perspective. The result should be reinforcement. A possible teaching strategy is to integrate the material of the first part of this option with the normal teaching of the relevant topics. The second half of the material might lend itself to self-study with lessons on specific topics, such as time dilation. 4. Extracts from writings of Young, Faraday, Maxwell, Hertz, Einstein The extracts contained in the WJEC notes are short but they do give the student something approaching direct contact with great physicists of the past. They are supported by explanatory notes and self-test questions to help with understanding. In the examination, part of the Option B question might present the student with a snippet from one of the extracts and ask him or her to explain certain points, or to put the extract in its historical context.

Those who associate studying history with the enforced learning of dates need not have too many fears about this option. Placing discoveries in the right half decade will suffice. 5. Books Two thinnish and very readable books which provide good support are…

Michael Faraday and the Royal Institution: by John Meurig Thomas (ISBN 0-7503-0145-7).

Relativity and its Roots: by Banesh Hoffmann (ISBN 0-486-40676-8). Chapter 4 tells pretty much the same story as this course, but, as the book’s title makes clear, Hoffmann has a special agenda, and his emphases are different.

Examination questions are restricted, however, to the material in the WJEC notes (though the student will be assumed to have tackled the embedded self-test questions – which occasionally call for him or her to find facts elsewhere).

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Unit PH5 Option C – Materials General The optional unit is designed to provide students with a sound understanding of the behaviour of materials. Emphasis is placed on understanding the relationship between the physical and mechanical properties of metals, glasses ceramics, polymers and composites and the microstructure of these materials. The unit also touches upon the use of advanced materials such as superalloys and carbon fibre reinforced plastics and their applications. It is hoped that the unit will provide students who have an interest in pursuing a career in engineering or material science with an increased technological awareness of the field of materials and to alert them to the possibilities that the future holds in this rapidly advancing and increasingly important field. Much of the unit is covered in sufficient depth in standard A-level texts. This coverage is dealt with in Table 1. The text books referred to are detailed below the table. Further useful material is to be found in the following:

1. Cooke (B) and Seng (D) (1989). Physics of Materials for A-level students (2nd ed). Leeds. University of Leeds.

2. Advanced Physics project for independent learning (APPIL) – unit: Behaviour of matter. John Murray.

3. Easterling (K) (1990). Tomorrow’s materials. London Bourne Press. 4. Gordon (J.E.) 1978. Structures, or living things don’t fall down. Great Britain.

Penguin Books. 5. Gordon (J.E.) 1976. The New Science of Strong materials or why you don’t fall

through the floor. Great Britain. Penguin Books. Useful web pages. The links are active in the electronic version of these guidance notes and every attempt will be made to ensure their current validity.

1) The Macrogalleria- a cyberwordland of polymer fun. www.pslc.ws/mactest/index.htm 2) Stress-Strain curves. www.shodor.org/~jingersoll/weave/tutorial/tutorial.html 3) www.s-cool.co.uk 4) www.antonine-education.co.uk (Follow links to AS Physics and then to Module 3, Topic 6 – elastic properties of solid materials). 5) www.schoolphysics.co.uk

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Table 1. Selected Book Reference Specification Reference

Adams & Allday Duncan Advanced Physics for You

Muncaster

a 10.3 p. 17 – 19, 24 p. 288 – 289, 291

9.10 (p. 147 – 151)

b 3.8 (p.60 – 61) p. 282 c 10.1 p. 29 p. 284 – 285 11.2 (p. 182) d p. 30 p. 286 p. 183 – 184 e p. 39 p. 287 11.5 (p. 184 –

185) f 10.2 (p. 440 –

441)

g* 10.2 (p. 440 – 441)

p. 28 – 29

h* 10.6 (p. 448) p. 31 – 34 11.12, 11.13 (p. 192 – 193)

i* j 10.11 (p. 458 –

459) p. 35 – 36 p. 290 11.10, 11.11

(p.191) k* 10.6 (p. 448) p. 33 p. 289, 290 11.3 (p. 193) l 10.2 (p. 441) p. 28 – 29 p. 190 m* 10.10 (p. 456 –

457) p. 34 – 35 p. 290

n 10.7 (p. 450) p. 291 o* 10.8 (p. 452 –

453) p. 41 p. 291 11.8, 11.9 (p.

189 – 190) p* 10.8 (p. 452 –

453) p. 41 p. 291 p. 189

q 10.9 (p. 454 – 455) 10.10 (p. 456 – 457)

p. 37 p. 293

r p. 38 p. 294 * Further guidance given in the Teacher Guidance Notes or in associated documents. Texts referred to in the Table:

1. Duncan G.T. (1987) Physics, A textbook for Advanced Level Students (2nd ed). London. John Murray Ltd..

2. Adams (S) and Allday (J) (2000). Advanced Physics. Oxford. O. U. Press. 3. Johnson (K) et al (2000). Advanced Physics for You. U. K. Nelson Thornes. 4. Muncaster (R) (1993). A-level Physics. Cheltenham. Stanley Thornes.

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Detailed guidance Specification references (a) – (f), (j). (l), (n), (q) and (r) are treated in sufficient detail in standard A level text books to obviate the need for guidance in this document. Elastic and Plastic Strain The process of deformation of ductile materials, including the movement of edge dislocations, is treated at the molecular level in the WJEC document: The plastic behaviour of ductile metals. SUPERALLOYS Statement (i) draws upon statements (h) and (j). Candidates should have an understanding of the effects of dislocations at the molecular level, and the strengthening and stiffening of materials by the introduction of dislocation barriers such as foreign atoms, other dislocations and grain boundaries (specification statement (h)). Candidates should also be able to describe failure mechanisms in ductile materials and have an understanding of creep and fatigue (specification statement (j)). Introduction Aircraft jet engines are required to operate within extreme conditions of temperature and pressure. Jet engine turbine blades rotate at a typical speed of 10,000 rpm for long periods in an environment of combustion products at working temperatures of 1250ºC (though the inlet temperatures of high performance engines can exceed 1650ºC); non aviation gas turbines operate at approximately 1500˚C. The blades must be able to withstand impact and erosion from debris drawn in with the air stream. In addition, different parts of the blade may be at different temperatures and they will be subjected to large and rapid temperature changes when the engine is started up and turned off. The following is a list of the properties required of the material from which the blades are made: • Creep Resistance

Centripetal forces acting on the blade at high rotational speeds provide a considerable load along the turbine blade axis. Over prolonged periods of time this can cause creep. It becomes increasingly pronounced as temperature increases. Creep could cause a turbine blade to deform sufficiently that it might touch the engine casing.

• Corrosion Resistance Iron corrodes to form rust. At high temperatures, the presence of carbon dioxide, water vapour and other products of the combustion of fuel constitute a highly corrosive environment.

• Toughness The blades must resist impact with debris passing through the engine. In addition, stresses generated by expansion and contraction, between different parts of the blade at different temperatures, must not give rise to cracking.

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• Mechanical and Thermal Fatigue Resistance Variations of gas pressure and temperature on different parts of a blade and mechanical vibrations may generate cyclical stresses which can cause failure due to fatigue.

• Metallurgical Stability

The mechanical properties of metals can be modified by heat treatment. Blade materials must be resistant to such changes and the microstructure must remain stable at high temperatures.

• Density

The density must be low to keep engine weight as low as possible. The separate document “Superalloys” <link to be inserted>, which can be found in the GCE Physics section of the WJEC website, gives details of how engineers have worked to produce single crystal turbine blades which satisfy these design criteria.

HEAT TREATEMENT OF METALS Strength and hardness are two mechanical properties of a solid metal which are affected by crystal grain size. The smaller the grains, the stronger a material is- fracture is more difficult with small grains because there are more grain boundaries and dislocations (moving within one grain) have difficulty passing into adjoining grains. The atomic planes of adjoining grains are in different directions so fractures tend to be halted at grain boundaries. The more boundaries there are, the stronger the material is. The mechanical properties of metals can be controlled by the following common treatments: • Work hardening.

This is a process which makes a metal stronger. The metal is worked or deformed (by hammering or repeated bending) when cold to make it stronger and harder. The effect of working the metal is to increase the number of dislocations, so increasing its strength. The effects of work-hardening can be felt by bending the wire of a steel coat hanger backwards and forwards until it snaps.

• Quench hardening.

Suggested experiment: Heat one end of a 20cm (approx) length of steel wire (held with tongs) in a Bunsen flame until it becomes cherry red in colour- about 800ºC. Then plunge the hot end of the wire quickly into cold water. When the rest of the wire has cooled try to bend the quenched end. What do you notice? Rapid cooling ‘freezes’ a particular grain structure into the metal. The higher the quenching temperature the smaller the grains and the harder and more brittle the resulting metal.

• Annealing. Suggested experiment: Use the same sample of wire as above and heat the other end of until it is red hot, and keep it at red heat for about 15 seconds. Withdraw it from the heat very slowly so that it cools gradually. When cool, try to bend the annealed end. What do you notice? This experiment can be carried out using a length of copper instead of steel. Slow cooling allows grains to grow larger, making the metal softer, more easily bent, hammered or scratched.

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Griffith cracks and brittle failure of amorphous solids A. A. Griffith, investigating the breaking stress of glass in the 1920s, estimated that its value should be about 1010 Pa. The glass under study had a breaking stress of only 108 Pa but he found that very thin fibres had much higher breaking stresses, with fibres of diameter 10-3 mm having a breaking stress of 3 × 109 Pa. Thus, the breaking stress varies with the diameter of the glass rod and approaches the theoretical breaking stress as the diameter of the rod decreased. The results obtained are sketched in the following graph.

6 1

Strength/ Arbitrary units

10 20 Diameter/ μm The glass fractures by a process known as brittle fracture. This is accelerated by the presence of surface imperfections or cracks. This is shown in the diagrams on the next page. The stress becomes concentrated around the tips of a crack. Bonds near the crack will break, increasing the load on neighbouring bonds which are still intact, causing them to break and the crack propagates rapidly [at approximately the speed of sound in the glass.

Crack

Key: The pecked lines like this are called stress lines. They represent the way the tensile load is transmitted along the rod from bond to bond. Notice how the lines are concentrated near the tip of the crack.

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Stress lines and stress concentrations can be photographed by making specimens out of Perspex and stressing them between crossed polaroids. The pictures on the next page show this. The picture on the left shows stress lines in a uniform bar which is stressed. The bar on the right has a small crack half way up its left side, resulting in a high concentration of stress around the tip.

This diagram represents the atoms and bonds around the tip of a crack:

The force in bond A will be large since it has to balance the forces exerted on molecules X and Y from above and below. The top two lines are incomplete because of the crack, so that the stress they carry is transferred to the line of atoms below. The bond A at the bottom of the crack is therefore carrying a much higher stress than the rest of the bonds. The stress can exceed the breaking stress of the material only in this region causing the bond to break, increasing the size of the crack and also the stress concentration. The crack will therefore propagate quickly through the material causing it to fracture. In the case of the glass fibres, surface cracks are caused

among other things by differential cooling at the surface and in the centre. The narrower the thread, the more uniform the temperature and so the less significant are any cracks that form. This makes the small diameter rods much stronger. The very narrowest glass threads [~ 1 μm] approach the theoretical strength predicted by Griffith. For very narrow threads, inducing cracks by simply touching the surface brings their tensile strength back to that of the bulk glass. This property of brittle materials is exploited by glaziers when “cutting” a piece of glass to size by putting a scratch in it and then snapping it – similarly with tiles. Since amorphous solids break by brittle fracture, they will be weak under tension, but under compression they will be very strong as the stress will cause the cracks to close preventing propagation. When amorphous solids such as brick are used for building, the structures produced are strong provided the material is kept under compression.

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Experiments to investigate the strength of glass. 1) Heat the end of a glass rod so that it softens enough to bend it into a hook shape to support weights. When cooled, heat the centre of the rod until soft, then remove the rod from the flame and quickly draw it out into a fibre. (An alternative method for producing fibres is to hang a 100g mass from the hook, heat the centre of the glass and as the glass softens and begins to fall, immediately withdraw the heat. The mass should be allowed to fall through a distance of about 0.5m to 1.0m). Then clamp the straight end so the fibre hangs vertically. Load the fibre with weights until it snaps. Note the final weight and, using a micrometer, measure the diameter of the broken fibre. Collating class results would allow graphs of breaking force or breaking stress versus diameter or cross-sectional area to be drawn. 2) Support a glass rod horizontally at either end. Load its centre with weights until it snaps. Repeat the test with the glass marked with a glass cutter underneath at the middle. The cut rod should snap more easily. 3) Heat a glass rod and pull out a fibre about 0.5 m long (as in experiment 1). When it is cool bend it into an arc on the bench. Release it, run your fingers over the fibre and bend it again. The fibre should now snap more easily.

THE BEHAVIOUR OF RUBBER & POLYTHENE A polymer macromolecule consists of long chain molecules, each containing up to 105 atoms and these chains are held together by cross-bonds, the structure being similar to that shown in the diagram. Diagram 1. A possible arrangement for three long-chain rubber molecules. The behaviour of a polymer depends on the strength of the cross-bonds and examples of two types of polymer are considered below. (i) Rubber – an example of polymer with weak cross bonds. Natural rubber is a polymer of the molecule iso-prene. It has weak van der Waals cross-bonds and only a few covalent (strong) cross-bonds. Its behaviour under increasing stress is shown by the following graph.

A

Bstres

straiO

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Between points O and A, the deformation is elastic and from the slope of the graph it can be seen that, after an initial stiff region, Young’s modulus is small. At stresses greater than A, the deformation is still elastic, but the value of Young’s modulus is much greater. If suffi iently stressed, the material breaks. Initially, as the rubber is deformed, no bonds are extended; the long chain molecules are straightened against their thermal motion (which tends to increase the amount of folding in the molecular chains). The van der Waal’s bonds are responsible for the initial stiff region, but once they are overcome, the rubber molecules unfold and the material can extend by several times its original length. Because bonds are not being broken here, the additional stress needed to do this is small. The structure of the material changes as shown in the following diagram. _______ molecule 1 - - - - - - molecule 2 Diagram 2. Stretched rubber At point A, the molecules the sections of the molecules which are free to unwind are more or less straight, therefore if any further extension of the material takes place, bonds are stretched. This is far more difficult to do than straightening the molecules, therefore the value of Young’s modulus increases at this point. When the stress is removed the thermal motion of the chain molecules makes the polymer return to its original dimensions. The value of Young’s modulus for such a polymer increases with temperature, the opposite to the variation in crystalline and amorphous solids. This is due to the fact that the chain molecules have to be straightened against their thermal motion. As the temperature increases, the thermal motion increases the amount of folding, so that the average end-to-end distance in an individual molecule decreases, with the result that straightening the molecules becomes more difficult.

A

Bstress

strain O

C

These polymers also show elastic hysteresis i.e. the stress-strain curves for the loading and unloading do not coincide. This is shown in this graph: OAB is the stretching curve and BCO the contracting. The strain for a given stress is greater when unloading than for loading. The unloading strain can be considered to ‘lag behind’ the loading strain. The area under OAB represents the work done [i.e. the energy supplied] to cause stretching; similarly the area under BCO represents the energy given up by rubber during contraction. 68

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This closed curve is called a hysteresis loop; its area is the energy per unit volume converted into internal energy [or, ‘lost as heat’ in common parlance] during one cycle. Thus when a polymer is repeatedly stressed, its temperature increases. Rubber with a hysteresis loop of small area is said to have resilience. This is an important property where the rubber undergoes continual compression and relaxation as does a car tyre when it touches the road as it rolls on. If the rubber used did not have a high resilience, there would be appreciable loss of energy resulting in increased petrol consumption and lower maximum speed. Heat build up could even lead to tyre disintegration.

Not for examination: Chemical engineers alter the properties of natural rubber by the process of vulcanization, in which strong covalent bonds are deliberately introduced between the long molecules. This has the effect of making the rubber stiffer and increasing its resilience. This very stiff form of rubber is useful for applications which involve repeated deformation, e.g. car tyres.

Polymers exhibit a property called creep during which the chain segments slowly disentangle under a constant stress as a consequence of the thermal motion of the chain segments. On the release of stress, thermal motion restores the mixing, but slowly, since the segments get in each other’s way during the shuttling process.

(ii) Polythene a polymer with strong cross-bonds The behaviour of a polymer with strong cross bonds e.g. a polythene strip is as shown in the following graph.

A

Bstress

strain O

Between O and A, the deformation is elastic. After the point A as far as B, the deformation becomes plastic, becoming elastic once again between B and C. In such a polymer, the cross-bonds are initially sufficiently strong to hold the chain molecules in place and so no straightening takes place. The elastic deformation between O and A is due to the stretching of bonds. At the point A, the stress becomes large enough to break the cross bonds and allows the molecules to straighten. The molecules will not return to their original positions when the stress is removed, as new cross bonds will have formed, holding the molecules in their new positions. After the point B the deformation becomes elastic. The plastic deformation which occurs between A and B is called ‘cold drowning’. Considerable necking takes place and the narrow part becomes longer without becoming any narrower.

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The behaviour of polythene when it is stressed. At the point B, the chains are straight and any additional strain is due once more to the stretching of bonds, thus the behaviour shown beyond this point is once more elastic. At C, the material breaks.

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Unit PH5 Option D – Biological Measurement and Medical Imaging General The optional unit deals with several different medical imaging and measurement techniques:

• X-rays including production, absorption, use in diagnosis and therapy and CAT scans.

• Ultrasound including acoustic impedance and Doppler techniques. • The principles of Magnetic Resonance Imaging including comparison with X-rays

and Ultrasound for imaging. • ECG including the interpretation of the cardiogram. • Nuclear imaging including radiation dose and PET scanning.

All these techniques build upon the physics content of PH2, PH4 and PH5. The study of this option provides an ideal synthesis of many of the ideas developed especially in the A2 course.

X-rays The nature and properties of X-rays, and their production in an X-ray tube are covered in PH2.3 (e) and (f). The following diagram describes their production in sufficient detail.

Heater filament

Very high voltage

X rays Focussing anode

Electron beam

Heater Current supply

Cooling fins

Lead shielding

Copper/ Tungsten block (anode)

The heater ‘boils off’ electrons by thermionic emission. These are then accelerated to very high velocities by the p.d. between the heater filament and anode. They are collimated by the focussing anode. The tube is evacuated so the electrons travel in straight lines and collide with a tungsten target (the anode) embedded in a copper block. The resulting deceleration produces an enormous amount of heat (up to 99% of the energy input) and also X-rays, which emerge from a window in the lead housing. A continuous spectrum, then, can be obtained by electrons decelerating rapidly in the target and transferring their energy to single photons. This radiation is known as ‘Bremsstrahlung’ or braking radiation. Superimposed on the continuous spectrum are several sharp lines. These result from the bombarding electrons knocking out orbital electrons from the innermost shells of the target atoms. Electrons from outer shells will then make transitions to fill the gaps in the inner shells, emitting photons whose energies are characteristic of the target atom.

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Transitions into the K shell give rise to K lines, the L shell L lines and so on. For heavy metal targets the resulting photons are in the X-ray range. A typical intensity spectrum would be: The intensity of X-rays is defined as the energy per second per unit area passing through a surface. This can be increased by increasing the voltage of the X-ray tube, or by increasing the current supplied to the filament. The photon energy is also determined by the tube voltage with the maximum photon energy being given by:

maxmin

hcE eVλ

= = ,

where V is the tube voltage. The optimum photon energy for radiography is around 30 keV which is obtained using a peak tube voltage of 80 – 100 kV. A narrow beam of X-rays is preferred as this reduces scattering and so leads to a sharper image. Blurring can also occur due to scattered radiation. This can be reduced by introducing a grid directly in front of the detector. This grid consists of a large number of lead strips so that only primary or direct radiation will get through to the film.

0.5

1.0

λmin 0.05 0.1 0.15

Patient

Transmitted Radiation

Scattered

R di ti

Grid

X-ray beam

photographic film

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When X-rays pass through matter they are absorbed and scattered and therefore the beam is attenuated. This attenuation can be calculated using the equation:

0xI I e μ−=

Where I = intensity at a depth x Io= intensity at the surface µ = the attenuation coefficient

Note that the half value thickness, x½ can be calculated using

12

ln 2xμ

= .

This can be derived in the same way as the half life equation in radioactivity. The main absorption mechanism of X-rays in the body is the photoelectric effect. The X-ray photon is absorbed by an electron which then leaves the atom. This is more efficient for atoms with larger numbers of electrons i.e. higher atomic numbers. Consequently denser materials such as bone will absorb more X-ray photons than less dense areas such as soft tissue. This will lead to a large contrast between bones and soft tissue and therefore a sharp image. If there is not a great contrast between the areas of the body being studied then sometimes a contrast media is used, e.g. a barium meal when studying the stomach or intestines. Computed tomography (CT or CAT scan) also uses X-rays, but in this case the X-ray tube moves in a circle around the patient taking images of the body at all different angles. A computer combines these images to produce a cross sectional image of the body. By adding these slices together a 3-D image can be produced. CT scans are very quick to produce and show a wide range of different tissue clearly. They do however subject a patient to a high dose of radiation and the machines are very expensive. Ultrasound Ultrasound can be generated using piezoelectric crystals. If you apply an alternating p.d. across the crystal you cause it to become deformed, with the crystal vibrating at the same frequency as the applied p.d. This can be used to generate ultrasound. The process also works in reverse, with the crystal receiving ultrasound and converting it to an alternating p.d. The crystal, then, can act as both an emitter and a receiver of ultrasound. Ultrasound can be used in diagnosis in two different ways 1. A-scans, or amplitude scans, where a short pulse of ultrasound is sent into the body and a

detector (usually connected to a C.R.O.) scanning for reflected pulses. Using the time base, the time the ‘echo’ takes to return can be found and the distance between structures in the body can calculated. A-scans are usually used when the anatomy of the section is well known but the precise depth is needed e.g. a delay in measuring a known position in the brain could indicate the presence of a tumour.

2. B-scans, or brightness scans in which the reflected pulse is displayed by the brightness of the spot. If an array of transducers is used a 2-D image can be built up. This is widely used to assess the health and growth of a prenatal foetus.

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Acoustic impedance is defined by the equation Z vρ=

Where Z = acoustic impedance of the medium Ρ = Density of the medium v = Speed of sound in the medium The acoustic impedance determines how much energy (ultrasound) is reflected at a boundary. If two materials have a large difference in Z then a lot of the energy will be reflected back, but if there is little or no difference in Z then there will be little or no reflection. For soft tissue such as skin the acoustic impedance is very different from that of air, so, if an ultrasound probe were simply placed upon the exterior of the body, most of the ultrasound would be reflected rather that entering the body. To prevent this, a coupling medium such as a gel or oil which has a Z value much closer to that of soft tissue must be first applied to the patient. This removes the thin layer of air and enables a much greater percentage of the ultrasound to enter the body. Blood flow around the body can be studied using a Doppler Ultrasound probe. The Doppler Effect (PH4.5) is the shift in frequency of a wave when it received by a moving object (either towards or away from the source). It also occurs when a moving source sends out a wave. A continuous source of ultrasound is sent out and its echo received back off a moving object such as blood cells. Because the blood cells are moving, the Doppler shift is doubled: once for the blood cells receiving the ultrasound and once for the blood cells acting as transmitters back to the stationary receiver. As the ultrasound is sent out continuously, two transducers are needed: one to produce the ultrasound; the other to receive it. By analysing the shift in wavelength of the received wave ∆λ and comparing it to the initial wavelength λ the velocity can be calculated using the equation:

2vc

λλ

Δ= ,

where c = the speed of the ultrasound wave. Note the 2 in the equation. This technique will show up any changes in the blood flow through a vein or artery and so can be used to detect clots or thrombosis. Magnetic Resonance Imaging [MRI] Nucleons (protons and neutrons) possess spin, which makes them behave like small magnets. Usually these will cancel each other out. However a hydrogen nucleus only has one proton and it is this nucleus that is studied using an MRI scan. Under normal conditions the hydrogen nuclei will be randomly arranged and cancel each other out. However if a strong magnetic field is applied they tend to align themselves, in almost equal numbers, either with the field lines (in parallel) or exactly opposite to the field (antiparallel). The nuclei are in continuous motion, due to thermal energies, and will all wobble or precess around the field lines at the same frequency (called the Larmor frequency) If radio waves are directed at the hydrogen nuclei at the same frequency as they are precessing (Larmor frequency), they will resonate and flip from one alignment to another so producing a magnetic field. When the radiowaves are switched off the nuclei revert back to their original state giving off electromagnetic radiation. It is this signal that is detected by the scanner. The time taken for the nuclei to switch back is called the relaxation time, and depends on what tissue type the nuclei are in. By measuring the various properties of the MRI signal along with the relaxation time a detailed image of a cross section of the body can be built up.

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Magnetic resonance imaging is particularly good in obtaining high quality images of soft tissue such as the brain, but is not as good for harder objects such as bone. Some of the advantages and disadvantages of X-rays, ultrasound and MRI for examining internal structures can be summarised by the following table:

Technique Advantages Disadvantages

X-rays

X-rays are absorbed by bone and so produce good shadow images. Unlike ultrasound they can produce images of, e.g. cancer on the lungs.

High radiation dose for the patient. People working with X-rays need to take care to limit their annual dosage.

Ultrasound

No known side effects. Good quality images of soft tissue. Moving images can be obtained. Machines are relatively cheap and portable

Doesn’t penetrate bone and so cannot study the brain. Cannot pass through air and so cannot study the lungs. Low resolution.

MRI

No Known side effects. High quality images of soft tissue. Image can be made for any part/orientation of the body.

Images of hard tissue such as bone are poor. Uncomfortable for the patient, causes claustrophobia. Very expensive.

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Electrocardiograph (ECG)

The heart is a large muscle which acts like a double pump. The left hand side receives oxygenated blood from the lungs and pumps it to the rest of the body. The right hand side pumps the blood returning from the body, at low pressure, to the lungs. The heart typically beats at between 60 and 100 times a minute. Each beat is triggered by a pulse starting in the upper right region by a cluster of cells called the sinoatrial node. This signal spreads through the atria causing them to contract, forcing blood into the ventricles. A short time later the electrical pulse reaches the ventricles causing them to contract forcing blood out of the heart. There is a one way valve between the atrium and the ventricle to ensure the blood flows the right way.

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A typical ECG recording consists of three parts:

1. The P wave which occurs because of the contraction of the atria; 2. The QRS wave which is due to the contraction of the ventricles; 3. The T wave which is due to the relaxation of the ventricles.

It is the signals from the sinoatrial node which are detected by the ECG. This signal is very weak by the time it reaches the body’s surface. The electrodes ( to detect the signal) need to be placed on the limbs and chest, where the arteries are close to the surface, and also need to be attached with conducting gel after all body hair has been removed. The signals also need to be heavily amplified once received. Any deviation from a ‘normal’ ECG indicates some form of cardiac disorder. This can be used to look for muscle damage (heart attacks), irregular pumping (arrhythmia), blockages in the heart due to disease and the heart going into fibrillation, where the beating is fast and irregular. Nuclear Imaging The effects of α, β and γ radiation on living matter will be examined in the same depth as in PH5.4. The unit of absorbed dose for matter is the gray (Gy), where

1Gy = 1 joule per kilogram

Because α, β and γ radiation interact differently with living tissue, the gray does not adequately describe the effects of the different radiations. 1 mJ kg−1 of α particles has a much greater biological effect that X-rays or γ-rays because the radiation is so heavily ionising and therefore the range of the α particles is so low. To allow for this, a quality factor Q is used: For many tissues a value of Q = 20 is used for α particle and Q = 1 for β, γ and X-radiation. Different tissues also respond differently and hence different Q-factors are employed by medical physicists. With this quality factor, the quantity is referred to as the “dose equivalent” and its unit, the sievert (Sv).

For γ and X-rays the dose is equal to the dose equivalent. In general: Dose / Sv = Q × Dose equivalent / Gy

In examination questions, the value of the Q-factor will always be given. A gamma camera uses tracers to produce images. A common nuclide used is technetium -99. This is attached to a molecule that will be taken up by the tissue to be studied. It has a half life of about 6 hours, which is long enough to allow the nuclide to be transported to the site of interest and for the radiation to be studied but short enough so that the nuclide not stay active inside the patient for too long. Once the isotope has been absorbed by the body the gamma rays are directed towards a crystal (usually sodium iodide with a small amount of thallium added) through a lead collimator, which consists of a lead circle which has a regular number of holes drilled in it. This absorbs all the gamma rays that enter the collimator at an angle. The gamma photons that pass straight through the collimator hit the crystal and cause it to scintillate. The gamma ray excites electrons in the crystal causing them to give off visible light. This light is detected by a bank of photomultiplier tubes which build up an image of the levels of gamma radiation being emitted from different parts of the tissue.

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Positron Emission Tomography (PET) Scanning This requires the use of an isotope that emits positrons (beta+ particles). These will only travel very short distances before slowing down and attracting an electron from a nearby atom. These will annihilate each other giving off two gamma rays, of identical wavelength, which will move off in opposite directions (thus conserving momentum). The PET scanner detects these gamma rays when they reach a scintillator in the scanning device. This produces a small flash of light which is picked up and amplified by a series of photomultiplier tubes in a similar way to the gamma camera. This technique depends on the simultaneous detection of a pair of gamma photons. Individual gamma photons are ignored. In order to produce positron emitting isotopes a cyclotron is needed (spec reference PH5.2) as they have very short half lives. This is very expensive. PET scans are now often combined with CT scans which enable both soft and hard tissue to be seen clearly. REFERENCES Advanced Physics Adams and Allday Oxford press Advanced Science Physics P. Fuller Heinemann Medical Physics M. Hollins University of Bath Science Nelson Medical Physics J.A.Pope Heinemann WEB REFERENCES www.wikpedia.org Medical Physics www.teachingmedicalphysics.org Institute of Physics www.s-cool.co.uk www.antonine-education.co.uk www.medphys.ucl.ac.uk

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Unit PH5 Option E – Energy Matters The aim of this option is to allow students to explore arguably the most pressing topic of our age in the context of underlying physical principles. After studying this option, students will be in a position to absorb and dissect information, often contradictory and misleading which is presented in the popular media and to make informed decisions. Energy already pervades much of the specification. The Table below identifies these earlier energy-related topics and gives an overview in the centre box of how they are developed, extended and linked in this option.

RENEWABLES TIDAL HYDROELECTRIC WIND STORAGE

SOLAR ENERGY GREENHOUSE EFFECT

WORK FROM HEAT SECOND LAW HEAT PUMP FUEL CELL

FISSION Enrichment Breeding FUSION Problems & Prospects (JET, ITER)

SAVING (Thermal Conductivity) STOCKS HAZARDS WIDER ISSUES: (Economic, Social, Political)

PH1 MECHANICS ENERGY

PH2.5 BLACK BODY RADIATION. STEFAN & WIEN LAWS

PH5.5

NUCLEAR PHYSICS

PH4 THERMAL PHYSICS

PH5.2 B FIELDS

PH1.5 SUPERCONDUCTIVITY

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Electricity Generation from available environmental kinetic energy and gravitational potential energy – statements (a) – (c). The enormous world-wide efforts now being made to increase and develop “renewable” energy provision are the result of two factors: first, fossil fuels, on which we now chiefly depend, are running out; secondly, these fuels are causing potentially catastrophic environmental damage. Renewable in this context simply means “does not run out” within the life times of human civilisation. Renewable sources and storage systems of the kind listed in (a), (b) and (c) largely involve applications of basic physics developed at AS (PH1 Mechanics and Energy). In the case of wind power, the maximum theoretical power Pmax available is determined by the rate of kinetic energy transfer through the turbine and candidates should be able to deduce (but not remember) Pmax = ½ρAv3 and draw conclusions. The power derived in practice is much below the theoretical maximum due to not all the KE being transferred, losses in the turbine etc. For tidal and hydroelectric sources, and also storage systems, estimates can be made from gravitational potential energy calculations based on simple models. The importance of projects such as Dinorwig in storing energy at times of low consumption should be recognised. The importance of renewals is nowhere greater than in the UK where there are Government targets to increase renewals from the present 4% of our total energy consumption to 10% by 2010 and 20% by 2020. Of the projects listed in the Specification, the recently completed Three Gorges (Yangtze) is worth special mention because of its sheer size, and also because of the social, economic and political implications. This is essentially a large 1.4 mile dam with 370 miles of headwater flooding 620 square miles and having a generating capacity of 18.2 GW – originally estimated to supply 10% of China’s energy needs. More than a million people have been displaced in its construction – an exercise more easily accomplished in China than in most countries. This is an extreme case; in all major projects there are negative factors: noise, disruption, use of land, effect on wildlife etc and almost always there are protest groups. Though the physics of all the above is straightforward, the handling and conversion of the various units can be troublesome. The kilowatt-hour conversion 1 kWh = 3.6 MJ is needed frequently and worth remembering while familiarity with the SI prefixes M, G, T, P and E will be found helpful. Some National and International data tables give energies in mtoes (million tonnes of oil equivalent). The conversion is 1 mtoe = 42 TJ approximately and this will be provided in any question.

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Nuclear sources – nuclear equations, fission, breeding and enrichment Uranium derived from mined ore contains only 0.7% of U235, the isotope which fissions with thermal neutrons and is the main source of nuclear power. U238, which makes up the remaining 99.3%, does not fission with thermal neutrons though it does make a small energy contribution by limited fission with fast neutrons. The ideal fission reactor would be fuelled by pure U235, but it extremely difficult to separate the isotopes as their masses are so nearly the same. The current method is by ultracentrifuge. Vessels containing Uranium hexafluoride gas are spun at enormous angular velocity. Because the two isotopes have different masses they will experience (slightly) different radial forces with the result that the heavier U238 tend to concentrate on the outside of the vessel and the lighter U235 nearer the axis. The process is slow and the apparatus complex and costly. In practice reactors running on “enriched” Uranium, in which the U235 has been increased to just a few percent, are more efficient and cost effective so that the costs of enrichment are more than recovered. Also, pure Uranium235, obtained through repeated enrichment, is used in the fission bomb which is a cause of unease when new nations embark on enrichment programs. The remaining U238 after the U235 has been separated is known as depleted uranium (DU). It is much less radioactive than the original uranium, because the half-life of U-238 is so long [4.5 × 109 years] and because of its high density has been used lately in armor penetrating shells amid some controversy [PH6 resource folder 2003]. U238 can itself be made to produce useful fissionable material by “breeding”. U238 captures fast (high-energy) neutrons to form unstable U239 which decays to Np239 by β− emission which in turn decays to Pu239 by further β− emission . (A useful exercise might be to write down the equations involved in this sequence given that Z = 92 for Uranium). Pu239 is an isotope of plutonium which does not occur naturally [or, more strictly, any Pu-239 originally present in the primordial solar nebula has long since decayed]. It turns out that Pu239 fissions with thermal neutrons similarly to U235 and can therefore be used as a primary source of nuclear energy. Reactors which produce Pu239 in this way are known as Fast Breeder Reactors – fast because fast or high energy neutrons are required to start the process. These reactors have the materials and moderators so arranged that enough fast neutrons are absorbed for breeding while sufficient moderation occurs to provide thermal neutrons to sustain the U235 chain reaction. The eventual separation of plutonium from uranium is relatively easy (compared with U235 and U238 separation) because they are chemically different. Note that fission produces radioactive waste which must be safely disposed of (still a major problem), that there are risks (Chernobyl), that stocks of ore are limited (therefore non-renewable) but that there are no carbon emissions other than that involved in the initial building of the necessary infrastructure. Nuclear fusion It is important to know the DT (deuterium-tritium) reaction and why it is the most suitable for terrestrial fusion (timescale and temperature). It is useful to look again at the proton chain in PH2.5 and to be reminded why this would not work on earth. An excellent account of nuclear fusion is given on the Joint European Torus (JET) website www.jet.efda.org . The key points to note are:

• the kinetic energies of the particles must be greater than the Coulomb interaction for interaction to occur meaning temperatures of 108 K;

• plasma containment at this temperature only possible by a combination of magnetic fields – the tokamac;

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• very strong B fields are required to deflect and therefore contain fast particles (see PH5.2(m) for background);

• fields of around 5 T require currents of around 7 MA which are only really achievable with superconducting coils (see PH1.5 (k) to (p)).

The problems are immense and continuous energy through fusion is still a long way off. But huge efforts and investments are being made. The International Thermonuclear Experimental Reactor, ITER ( www.iter.org ), a joint venture by most of the great Nations –including China, India, USA, Russia, EEC – is underway in France and due to power up in 2016. Fusion, if it works, will provide all our energy needs. Deuterium is abundant in seawater [~ 1 in 104 hydrogen atom is deuterium] and tritium can be obtained by neutron capture by lithium in the reactor itself. There are no toxic products. Heat transfer processes – convection and conduction

These are familiar topics well covered in standard textbooks. Emphasis will be on thermal insulation and energy-saving, but note that publications on these topics use Thermal Transmittance, (U value) rather than thermal conductivity K. The U value of a slab of thickness d is given by U = K/d. This will be provided, if required, in any question. Solar radiation as an energy source A form of renewable energy quite different from those treated earlier is solar energy. The background physics has already been developed in PH2.5(a to d). Revision of this material is a good starting point with emphasis on the laws of Wien and Stefan, the inverse square law and what is meant by black body. A key quantity is the Solar Constant – the total radiated power per square metre crossing a plane perpendicular to the earth-sun radius measured just outside the earth’s atmosphere. The value is not constant (despite the name), as the earth-sun distance varies over the year, but averages at 1.35 kW m-2. We can estimate the rate of solar power arriving at earth, ignoring clouds, atmospheric absorption etc. as of the order of 1017 W and compare this with the rate at which energy is consumed throughout the world (of the order of 1013 W). So there is abundant solar energy; the problem is harnessing it effectively. There are two ways:

• solar panels; • photovoltaic cells.

In the solar panel, water is heated directly from sunlight. The panel contains a flat coil of pipe connected to the domestic hot water cylinder and is placed, ideally, on a South-facing roof. As the name suggests, the photovoltaic cell produces electrical energy from solar energy. At present, photovoltaic cells make very little contribution to our energy because of high manufacturing cost. Most of the cells currently in use are made of very pure silicon which has to be doped and cut in a special way – all very expensive.

Not for examination: As semiconductor devices and band theory are not in the specification, this rough outline may be helpful: the silicon cell consists of n- and p-doped regions forming a p-n junction. Incident photons excite electrons into the conduction band creating electron-hole pairs which migrate to form an electric current. Detailed knowledge will not be expected.

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Much work is in hand to develop cheaper and more efficient cells using, for example, composite materials. The Energy Conversion Efficiency of a photovoltaic cell is defined by the usual efficiency equation, in this case written as:

Conversion Efficiency Useful energy extracted 100%Total energy input

= ×

Values range from around 6% for the cheapest commercial cells to around 40% for the most expensive state-of-art cells. It follows that large areas of cell are required for even moderate power such as typical domestic consumption, but small cells of around 5 cm2 are sufficient to power pocket calculators which require less than 1 mW. Carbon footprint Candidates can not be expected to remember statistics, but some key figures are worth bearing in mind. For example, about one fifth of UK electricity is from nuclear reactors and three quarters from fossil fuels (coal, oil and natural gas). Fossil fuels have two major drawbacks. First, the stocks are finite. Secondly they produce carbon dioxide gas which is harmful if allowed to escape into the atmosphere. In a chemical reaction in which carbon is oxidised (burned), each carbon atom combines with two oxygen atoms from the atmosphere to form carbon dioxide CO2. Straightforward calculation from the atomic masses shows that one kilogram of carbon produces 2.66 kg of carbon dioxide. Carbon dioxide is a “greenhouse” gas and its increased presence in the atmosphere leads to global warming in the following way:

The solar radiation spectrum covers a range of wavelengths with maximum power at around 480nm which is at the blue end of the visible spectrum. This value is determined by the temperature of the sun’s surface (Wien’s displacement law; λmax∝ T-1).

The atmosphere is essentially transparent to this wavelength so the solar energy passes through and is absorbed at the earth’s surface.

The earth in turn radiates thermal energy but, because the earth’s surface temperature is much lower than that of the sun, this peaks at around 10 μm which is in the far infrared region.

Carbon dioxide absorbs strongly at this wavelength, and re-emits in all directions including back to earth leading to global warming. Other polyatomic molecules such as methane and nitrous oxide behave similarly but carbon dioxide is more abundant. This is how greenhouses heat up – hence the name; glass, like CO2 is transparent in the visible but absorbs in the IR.

Experiments show that burning 1 kg of carbon produces about 13 kWh of energy which works out at around 6 eV per carbon atom. It is interesting to compare this with the 200 MeV produced by the fission of one U235 nucleus. The consequences of increasing greenhouse gases need to be recognised: global warming, polar icecap melting, weather changes, flooding, more hurricanes etc. Also important is the decline of vegetation, particularly the rain forests, which remove CO2 from the atmosphere through organic growth. Important too is recognition that the worlds population is increasing as is the industrialisation (and hence energy requirements) of emerging nations: also to be noted are the measures to counter the ill effects (national and international reduction targets, Kyoto protocol, “carbon footprints”, Environmental Impact ratings etc).

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Fuel cells Interest is reviving in fuel cells as they offer the possibility of efficient and environmentally friendly energy production, especially for transport, and could become a replacement for the internal combustion engine when the oil runs out. Prototype cars powered by fuel cells already exist. The fuel cell is electrolysis in reverse. As electrolysis has long disappeared from physics specification, a brief outline is necessary. When an electric current is passed through water, ionization of the water molecules occurs through collision with the charge carriers. Avoiding the detailed chemistry, the upshot of this is that water is broken down into its constituent gases with hydrogen bubbles collecting at the cathode and oxygen at the anode. The apparatus is simple: a dish of water with two electrodes each with an inverted jar above it to collect the gases, and a current source. A drop of acid is needed to make the water conducting and the anode made of platinum to avoid oxidation. So, in summary, electrical energy breaks water down into oxygen and hydrogen gases. Can the reverse take place in which hydrogen is recombined with oxygen to provide electrical energy? Fuel cells do just this. The process is complex but in crude outline the following is what happens in the Polymer Electrolyte Fuel Cell (PEFC):

Hydrogen is supplied to the anode where the atoms are ionized by a catalyst. A polymer electrolyte then routes the electrons to the cathode via an external circuit

forming a useable electric current. The protons continue through the polymer electrolyte to the anode where they

recombine with the electrons, and the hydrogen reacts with oxygen, which is fed directly into the anode, to form water.

One great advantage is that there are no damaging products – particularly no carbon dioxide. Another great advantage is that there is no heating – useful energy is not being obtained from heat; this will be returned to later after Heat Engines. Also the cell can be connected directly to electric motors on drive wheels of cars, cutting out the heavy and inefficient engines (cylinders, reciprocating pistons etc) of traditional cars. Hydrogen of course is a hazard and there are difficulties over its delivery and storage, but its supply will become plentiful if fusion succeeds – hydrogen and oxygen produced by electrolysis of water from electricity from turbines powered by fusion reactors – but this is a long way off. At present, the experimental fuel cell cars are extremely expensive and the electrolyte polymer degrades and has to be replaced within the lifetime of the car. A useful website, albeit commercial is: http://automobiles.honda.com/fcx-clarity/how-fcx-works/v-flow/

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Thermodynamics – Carnot cycles, heat pumps and the 2nd Law of Thermodynamics

The groundwork for understanding the central problem of obtaining useful work from heat has been developed already in PH4.3 Thermal Physics (i) to (d) and a good starting point is to look again at these. One ideal heat engine consists of a cylinder with a piston and containing ideal gas (the working substance). The engine is also “ideal” in the sense that the walls and the piston are perfect heat insulators, the base is a perfect conductor and there are no friction losses as the piston moves. The process involved is treated in many textbooks but is set out here for convenience.

1. The engine is first placed on heat reservoir at temperature T1; initially the state of the gas is shown by point A on the p – V diagram. Heat Q1 passes from the reservoir into the gas as the state of the gas changes from A to B. Work is done as the gas expands (piston goes up) but the internal energy does not change as the curve is an isotherm (temperature constant so internal energy constant). The changes along are given by the First Law of Thermodynamics (in the form ΔU = Q − W ) and are shown in the first line of the table.

ABuuur

2. The engine is now transferred to a perfectly insulating stand and allowed to expand further to state C; no heat is transferred but work is done (no need to mention adiabatic); changes are given in line 2.

3. The engine is now transferred to second reservoir at T2 and the gas is compressed isothermally to state D; changes are given on line 3 but note particularly that heat is ejected from the gas into the second reservoir – the sink.

4. Finally the cylinder is placed back on the insulating stand and compressed to return to state A. The cycle is complete, and we can see from the bookkeeping table that an amount of work (Q1-Q2) has been obtained from an amount of heat Q1.

T1 T2

ABuuur

BCuuur

CDuuur

DAuuur

Heat reservoir

Heat sink

Step Q ΔU W

A to B Q1 0 Q1

B to C 0 −(U1−U2) U1−U2

C to D -Q2 0 −Q2

D to A 0 U1−U2 −(U1−U2)

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pressure, p

Volume, V

T2

T1

A

B

C

D

Q1

Indicator diagram for a Carnot cycle

Q2

The procedure can be summarized as shown below:

HOT T1

COLD T2

ENGINE

HEAT Q2

HEAT Q1

WORK W = Q1 − Q2

The question arises, “Why does heat have to be ejected?” Or, equivalently, “Why does there have to be a sink?” If the process terminated at B the engine would be of no further use. To obtain useful work the process must be continuous, which requires that the cycle be repeated over and over again for as long as is necessary. This means repeatedly returning the gas to its original state – something which can only be achieved by ejecting heat at one stage in each cycle. The efficiency of the heat energy is defined by:

Useful work outputEfficiency 100%Total energy input

= × .

So 1 2

1 1

Efficiency 1Q Q QQ Q

2−= = − (1)

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All that we know, or need to know, about the source and sink is that they have temperatures of, respectively, T1 and T2. Clearly the amounts of heat transferred will be governed by these temperatures. In fact, the ratio Q2/Q1 is used to define the ratio of Kelvin temperatures so that

2 2

1 1

Q TQ T

=

and equation (1) above becomes

2

1

Efficiency 1 TT

= − (2)

So a Carnot engine working between 100oC and 0oC [373 K and 273 K] can not have an efficiency of greater than 27%. In practice there will be other factors such as friction and heat loss which will make the actual efficiency even less. In the ideal engine described here there are no such losses, and the cycle is therefore reversible in that if the operations described are performed in the opposite (anticlockwise) sense the system is returned to precisely its initial state. This would not happen if there were losses. All this shows a fundamental difference between heat and other forms of energy. While electrical energy can be transformed entirely into heat (I2R heating in a resistor) only a fraction of heat can be transformed into useful work. This has been shown here to be true for the ideal Carnot engine; it is in fact generally true and is formulated in the Second Law of Thermodynamics which will be looked at later. Details of actual engines, to which the same principles apply, will not be expected. The simplest example is probably the steam engine, but this is now of historical rather than practical interest. The Otto cycle for the internal combustion engine is worth looking at as a more complex example. The running of the Carnot cycle in reverse has already been mentioned and this is the basis of the refrigerator and the heat pump. They operate on the same principle – that of extracting heat from a cold source and ejecting it at a hot sink – and the Carnot cycle runs anti-clockwise around the indicator diagram. Work is required to achieve this and a schematic diagram for the process is given below. Note that the same diagram applies both to the refrigerator and the heat pump, but that we do not use the term “efficiency” to describe their effectiveness – efficiency is reserved for the heat engine. Instead, the figure of merit for these devices is the Coefficient of Performance. The definition of the CoP is essentially the same as that for efficiency:

i.e. Coefficient of Performance Useful energy transfer 100%Work input

= × .

The nature of the “Useful energy transfer” differs however and the CoP is defined separately for each case below.

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For the fridge: HOT

T1

COLD T2

ENGINE

HEAT Q2

HEAT Q1

WORK W = Q1 − Q2

COP Heat extracted from cold source 100%Work input

= ×

2 2

1 2

2

1 2

Q QW Q Q

TT T

= =−

=−

For the heat pump:

COP Heat delivered to hot sink 100%Work input

= ×

1 1

1 2

1

1 2

Q QW Q Q

TT T

= =−

=−

For refrigeration, the source is the inside of the fridge and the sink is the kitchen or, more accurately, the cooling grill at the back of the cabinet. In the case of the heat pump the source is the ground, preferably in ground water or a river for better heat transfer, and the sink is the radiators inside of the house to be heated. Practical details are not expected but the broad principles should be understood. For example, the working substance or “refrigerant” might be a liquid which can be made to evaporate at the cold source, thus absorbing heat, and then to eject heat at the hot sink where the vapor condenses back to liquid. Work is done in circulating the refrigerant and bringing about the necessary phase changes. The COPs are, like the Carnot efficiency, theoretical maximums. In practice, performance is much poorer owing to the usual losses, but it is still instructive to insert numbers for typical situations. Heat pumps seem a good proposition, but the capital expenditure is high and the losses great. They are used in major buildings (Festival Hall, Buckingham Palace, and more recently the Senedd at Cardiff) while many firms offer domestic appliances (try inserting “Heat Pump” into a search engine). As already mentioned, the limitations of heat into work are a consequence of the Second Law of Thermodynamics, the Kelvin statement of which is: “No process is possible the only result of which is the total conversion of heat into work”. To illustrate this, look again at the Carnot cycle and the step from A to B. This would seem at first to contradict the law for all the heat absorbed in the step is converted into work. But this is not the only result because, in the process, the state of the gas (pressure and volume) has changed. The law is fundamental, far reaching and one of the great cornerstones of science. For example, an essential stage in obtaining work from a nuclear or any other power plant is that of transforming heat to drive a turbine, and all the limitations of the Carnot cycle apply. Suppose steam enters the turbine at 500 oC and then condenses to water at 60 oC; the Carnot efficiency is 0.57 and the actual efficiency will be much less again. So, most of the energy is wasted. One way to recover some of this is to pump the hot water from the power station condenser around local housing in a massive central heating system. This is known as a Combined Heat and Power (CHP) scheme and was pioneered in Britain at the old Battersea power station.

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The overall efficiency obtained in a CHP scheme is much greater than the Carnot efficiency because a large fraction of the “waste” heat Q2 now becomes useful – though there will be some losses between the power station and the houses. In practice, CHP generators are run with a higher temperature cold sink [~ 100°C], thus reducing the efficiency of the electricity generation but allowing for more useful heat energy distribution. It is easy to understand now why electricity should not be used for heating – most of the original energy has already been wasted as heat. We can also now better understand a great advantage of fuel cells – no heat is involved so there is no Carnot wastage in the cell itself, though heat may have been involved at an earlier stage in producing the hydrogen and oxygen.

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4.6 – PH6 – Experimental & Synoptic Assessment The attention of centres is drawn to the specification of this unit and the internal assessment guidelines on pages 48 and 57 of the GCE Physics specification. The focus of this unit is undertaking measurements and observations and the an appreciation of the uncertainties inherent in these observations. Reference should be made to the Guidelines on the Treatment of Uncertainties <link to be inserted> on the WJEC website. Administration of the Internal Assessment. Task A Based upon the preliminary entries which centres make in October, centres will receive in February multiple copies of the data analysis task. The scheduled date for this task is in March. Bearing in mind the need to preserve the integrity of the 45-minute assessment, centres are free to arrange for candidates to undertake it in several sessions. Those scheduled to take it later on will need to be under supervision before the first group of candidates completes the task. Task B Based upon the preliminary entries which centres make in October, centres making entries will receive in January of each year a document entitled Confidential Instructions for Supervisors. This will contain general instructions for the administration of the assessment and a detailed description of the apparatus needed for the investigation. The question will not be included with this mailing. Well before the scheduled time for the assessments, centres should assemble the required apparatus. The subject officer is available to answer any questions and deal with problems that may arise in doing this. The scheduled sessions for the assessment will be in two consecutive days in the last week in mid March. Centres are expected to enter candidates on the first day and only use the second day if candidates cannot be conveniently accommodated in one day. As the duration of the assessment is only 1¼ hours, there is ample time for 2 or 3 sessions on each day. Centres which need to use more than one session may opt to use session 1 on day 1 and session 1 on day 2 rather than using two sessions on the same day. The assessment will come in two versions: version I is to be used on the first day and version II on the second. Centres will receive copies of the assessment questions and mark schemes in good time. In addition to the multiple copies of the assessment papers, centres will receive a containing a single copy of the assessment tasks which may be opened a week in advance. Supervisors should work through the tasks and ensure that the apparatus and questions work as intended. Following the completion of the tasks, supervisors should mark the work using the marking scheme provided. Moderation samples and marks should be despatched in accordance with the WJEC Internal Assessment Manual for that year.

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5. CONTRIBUTORS TO THE TEACHERS' GUIDE WJEC acknowledges with gratitude the contribution of the following members of the A level Physics examining team to the production of this guidance material: Dr J P G Richards Chair of Examiners Mr P N Wood Chief Examiner Mr D P Edwards Principal Examiner Mr S W Evans Principal Examiner Dr I L Morris Principal Examiner

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Appendix A Thermodynamics Notes

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Introduction These notes on Thermodynamics were produced as a result of discussions at the GCE Physics Inset sessions in autumn 2003 and 2004. The document contains much material, which is intended to clarify terms and conventions in Thermodynamics, which are often misunderstood. Examples of this are: • the distinction between heat and internal energy • the use of a sign convention to indicate direction of energy transfer • the use of Work in other than mechanical situations e.g. electrical work The last section of the notes on the 2nd Law of Thermodynamics and the idea of entropy are included for interest only and clearly outside the core specification.

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Systems The laws of thermodynamics apply to systems. A system is just about anything which we can imagine to be defined by a boundary. At A-Level the favourite system – because it’s simple but not trivial – is a sample of ideal gas in a cylinder fitted with a piston. Other examples of systems are: • a rubber band • a mixture of oxygen and hydrogen in a sealed vessel • a lamp filament • a star • a black hole • the electromagnetic radiation inside a furnace.

The last example is included because it started a revolution in Physics. By applying thermodynamics (and its sister science, statistical mechanics), the German physicist Max Planck was led to conclude that the radiation was emitted from, and absorbed by, the walls of the furnace in discrete packets of energy. From this idea grew Quantum Theory, which has guided most of the discoveries in Physics from 1900 to the present day. The Thermodynamic State of a System For many systems, including gases, any physical property you can think of can be expressed in terms of just two variables. For gases, pressure and volume are often chosen as these two variables. They are said to determine the state of the system. So a particular point on a plot of p against V represents a particular state of a sample of gas. If the system is n moles of an ideal gas, then we have:

pV = nRT This is called the equation of state of an ideal gas. It gives the property, temperature, in terms of pressure and volume. [We could just as well say that eq.1 gives the pressure in terms of volume and temperature. In other words we can choose which two variables in terms of which we express the system’s (other) properties.] Different systems have different equations of state. For example, the equation of state of a rubber band, relates tension, length and temperature. This equation is beyond A-Level!

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The Internal Energy of a System The internal energy, U, of a system is the sum of the potential and kinetic energies of its particles. [We shall not include gravitational energy or energy due to nuclear forces. This is because they don’t change in the cases we shall be dealing with, and might just as well be zero.] The Internal energy of an ideal gas For an ideal monatomic gas, the forces between molecules are negligible (except during collisions) and this means that the potential energy can be taken as zero. The internal energy is, then, simply the sum of the kinetic energies of the molecules. So for N molecules each of mass m and with mean square speed 2c :

212U N mc= ×

But, using Newton’s Laws, it can be shown that pressure × volume is given by:

213pV Nmc=

So:

32U pV=

For a given pressure and volume U can, then, have only one value. We say that the system’s internal energy is a function of the system’s state. This is true of all systems. A special feature of an ideal gas is that U can be expressed in terms of the number n of moles and the temperature T alone. Using pV = nRT (eq.1) to define T, we have: 3

2U nRT= eq.2 Internal energy of a real gas The internal energy of a real gas depends on its volume as well as its temperature. This is because of forces which act between the molecules. These are fairly negligible for a gas at lowish density, such as oxygen at room temperature and pressure, which is nearly ideal in behaviour. A-Level questions on gases will assume ideal behaviour! Even at low densities the factor of 3/2 in eq.2 is only correct for monatomic gases. For oxygen and other diatomic molecules (molecules consisting of two atoms bonded together) the factor is usually close to 5/2. This is because the molecules have kinetic energy of rotation as well as ordinary translational movement through space.

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Internal energy of a rubber band A molecule of rubber is a long chain of atoms. The bonds between segments of the chain allow rotation of the segments, of the type suggested by the top diagram. This means that the chain is constantly changing shape. The most frequently occurring shapes are ‘folded up’ tangles (see lower diagram). Even an approximately straight chain would be fantastically improbable – unless tension is applied to the rubber. The internal energy of a rubber band includes the kinetic energy of random rotation of the segments. The band’s internal energy hardly changes at all when it is stretched, provided its temperature is kept constant. How is this like ideal gas behaviour?

Changing the internal energy of a system A system can gain internal energy by having work done on it or by having heat flowing into it. A system can lose internal energy by doing work on something external to it, or by having heat flowing out of it. Indeed, in accordance with the Law of Conservation of Energy: eq. 3a Each of the three terms in this equation can be either positive or negative. For example, the net heat flowing into a system is negative if, in fact, heat flows out of the system. Work The basic definition is: eq.4

Gain in system’s internal energy = Net heat flowing into

system + Net work done on system

work done by a force = magnitude of

force × distance moved by force in direction of force

Here are some examples of systems doing work or having work done on them: Work done by a rubber band

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When we increase the length of a rubber band by a small length Δx by applying a pull F, then: Work done on band = FΔx We could equally well write this as Work done by band = – FΔx To see the point of this, suppose we allow the band to contract, exerting a pull F. In this case Δx is negative so the work done by the band is positive, which makes sense. If we stretch the band a lot, then F will change significantly during the stretching. In this case we add together all the bits of work, FΔx, which means adding together the areas of all the narrow strips under the graph (see above), from the initial extension x1 up to the final extension, x2. So: Work done on (or by) band = area under Force-extension graph eq.5 A positive amount of work is done on the band if x is increasing; a positive amount of work is done by the band if x is decreasing. Work done by a gas

When a gas exerting a pressure p expands by a small volume ΔV, then: Work done by gas = pΔV [This is, in fact, just a more convenient way of writing FΔx, in which F is the force on the piston and Δx is the distance it moves.] We could equally well write

Work done on gas = –pΔV

If we push the piston in a little way ΔV is negative so a positive amount of work is done on the gas – as expected, since we’ve had to do the pushing. If the gas expands a lot, then p will change significantly. In this case we add together all the bits of work, pΔV, which means adding together the areas of all the narrow strips under the graph (see diagram), from the initial volume V1 up to the final volume, V2. So: Work done by gas = area under pressure - volume graph eq.6 A positive amount of work is done by the gas if V is increasing; a positive amount of work is done on the gas if V is decreasing.

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Frictional Work Suppose we push or pull a file across a piece of metal. We are doing work because we are exerting a force which is moving in the same direction as the force itself. The system on which we are doing work is the metal block (and the file). An important feature of frictional work is that it is irreversible – the block won’t push or pull the file and move it backwards! Compare with the reversible work done on the rubber band or the gas when we push in the piston. Electrical Work If a potential difference is applied across a resistor (e.g. a wire) and a current I flows for a

time t:

Electrical work done on resistor = VIt eq.7

What has VIt to do with force × distance? It is not very difficult to show that the sum of the forces on the free electrons caused by the electric field set up by V, multiplied by the mean distance which they move in time t as a result, is equal to VIt. [See E-fields in PH4] The electrical work done on a resistor is irreversible. The resistor won’t be able to do work pushing the electrons back the other way. The electrical work done on a pure inductor or a capacitor is, however, reversible. Heat Heat is energy flowing from a region of higher temperature to a region of lower temperature because of the temperature difference. Compare with the flow of charge due to a potential difference…

If there is no temperature difference, no heat will flow. [In the electrical case, if there is no potential difference, no charge will flow.] It takes time for a finite amount of heat to flow, though the rate of flow is greater the greater the temperature difference (other things being the same).

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Thermodynamics: Applying the ideas Example 1: Rapid expansion of an ideal gas

Think about the terms on the right hand side of eq.3a: What about the heat? If the expansion is really rapid the heat flow will be (almost) zero. What about the work? As the gas expands work is done by the gas. The last term in the equation is negative. Another way of seeing this is to write the equation as: eq.3b

Gain in system’s internal energy = Net heat flowing into

system + Net work done on system

Gain in system’s internal energy = Net heat flowing into

system − Net work done by system

Whichever way we look at it, because the heat term is zero, the right hand side of the equation is negative, so the gain in internal energy of the gas is negative, i.e. the internal energy decreases. So the gas temperature falls (see eq.2). It really does happen… • Try this… Squeeze some air down to a quarter of its volume or less in a large plastic

syringe. Wait a few seconds. Let the piston move outwards quickly, doing work on your hand (i.e. not simply letting go of it). Feel the coolness of the syringe.

• Suppose you let the trapped gas return to room temperature, keeping its volume

constant. Draw a line on the graph above to show what happens to the pressure. • When you squashed the gas in the first place what happened to the temperature and

why? Assume you squashed it very quickly. You notice the effect when using a bicycle pump. In a diesel engine rapid squashing of air and fuel causes the temperature of the mixture to rise so high that the fuel ignites (without needing a spark).

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Example 2: Slow expansion of an ideal gas

This time heat will have time to flow. For each small increase in volume the gas temperature will drop a little (Example 1) and heat will flow in from the surroundings – limiting further temperature drop. If the expansion is really slow (and the cylinder walls conduct heat well) the temperature drop is negligible, so the expansion is isothermal. An isothermal change is a change at constant temperature. Now look at eq.3b. Re-arranging it slightly we have: eq.3c Since, in this case, the temperature does not change, there is no change in the internal energy of the gas (see eq.2). So This work can, in principle, be used to lift weights, generate electricity, propel a vehicle and so on. The process has its uses! [Unfortunately the gas pressure drops until no more useful work can be done. But if we could restore the gas to its original state, we could do the same useful thing all over again. The problem is that restoring the state simply by pushing the piston back in again (slowly) requires us to put in the same amount of work the gas gave out when it expanded! The solution is to use a cycle of changes – see page 10.] We see from this example that… • Constant temperature is not at all the same thing as no heat flow. • Heat flowing into a system does not necessarily make it hotter (raise its temperature). Example 3: A hot gas cools Suppose we have a sample of hot gas confined in a cylinder by a piston. If we let the gas cool down at constant volume (that is with the piston held in one place), no work is done. So adapting eq.3c,

Net heat flowing into system = Gain in system’s

internal energy + Net work done by system

Gain in system’s internal energy = Net work done on

system

Heat flowing out of gas = Decrease in internal

energy of gas

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Can’t we say, then, that the hot gas was ‘storing heat’? No, because the hot gas could have cooled down (i.e. lost internal energy) without giving out heat. It could have done work instead, as in Example 1. If we had let the piston move out quickly, doing work, then:

Work done by gas = Decrease in internal energy of gas

• The energy stored by the gas is internal energy. It isn’t heat and it isn’t work. Its

decrease could result in heat being given out or in work being done (or both). Heat and work are both energy in transit. Thinking of them as ‘stored’ in a system leads to confusion in thermodynamics!

Example 4: A spark ignites a mixture of hydrogen and oxygen in a vessel A chemical reaction occurs and the contents of the vessel turn wholly or partly to steam. There is a sudden huge rise in the temperature and pressure in the vessel. What has happened to the internal energy of the system (i.e. the contents of the vessel)? Has heat flowed into or out of the system? Hardly at all in the short time of the chemical reaction. The spark itself contributes negligible energy. Afterwards, heat will flow out. Has work been done or by the system? Not during the reaction. Almost immediately afterwards, the vessel may shatter and the pieces acquire kinetic energy as the expanding gas does work on them. So eq.3 (any version: 3a, 3b or 3c) shows that during the reaction there is no change in the internal energy. How can this be, when the system gets hotter? The increase in molecular kinetic energy is at the expense of a decrease in chemical potential energy as the atoms bond with different partners. The overall internal energy is unchanged – at first. Example 5: Quick extension of a rubber band We do work on the band. Hardly any heat will flow out of the band if we do the work quickly. So the internal energy will rise. Since, as for an ideal gas, this is mainly kinetic in form, the band’s temperature will rise. • Try it, using a fairly stout band. Feel its temperature immediately (on your lips?) • Wait a few seconds, so that heat can flow out of the band into the air, and the band

regain room temperature. Now let the band contract, doing work on you. Feel it again.

Example 6: A filament lamp Suppose we connect the lamp to a supply giving a steady p.d. of 12·0V. The filament is initially at room temperature and the current is 30A. The filament gets hotter, and finally achieves a steady ‘working’ temperature. It now takes a current of 4.0A. [The current is lower because the resistance of the filament is higher.]

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• How much does the filament’s internal energy increase during the first millisecond? The filament will still be very nearly at room temperature, so negligible heat will flow from the system (the filament) during this time.

Using eq.3a (or 3b or 3c – they’re all equivalent):

12 0 V 30 A 0 0010s0 36 J

VIt== ⋅ × × ⋅= ⋅

• How much heat does the filament give out in 1.0 ms at its working temperature? Since the filament’s temperature is steady it is no longer gaining internal energy. So:

12 0 V 4 0 A 0 0010s0 048J

VIt== ⋅ × ⋅ × ⋅= ⋅

The First Law of Thermodynamics We’ve already used it – many times – without giving it a name. Equations 3a, 3b and 3c (where it is understood that internal energy is a function of the system’s state) are all ways of writing it. In symbols we can use eq.3c and write:

Δ −U = Q W

Gain in filament’s internal energy = Net work done on

filament

Net heat flowing out of filament = Net work done on

filament

Gain in system’s internal energy = Net heat flowing

into system + Net work done by system

ΔU is a change in a property of the system, its internal energy, U. A positive value of ΔU means an increase in U; a negative value means a decrease in U. As we said earlier, for a given system U is a function of the system’s state. For example, for n moles of an ideal monatomic gas, U is given by 3/2nRT (= 3/2pV). Q is heat entering the system from (hotter) surroundings. A negative value of Q means heat leaving the system (to cooler surroundings). We don’t have a ‘Δ’ in front of Q, because heat flow is not a change in heat. It’s energy in transit. It is not a function of the system’s state. W is work done by the system. A negative value of W means a positive amount of work done on the system. We don’t have a ‘Δ’ in front of W for the same reason as for Q; namely, W is not a change in work. It’s energy in transit. Work is not a function of the system’s state.

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As practice in using the symbols, state whether Q, ΔU, W are positive, negative or zero in the following cases. The first line of the table is filled in as an example. The empty space is for your own examples.

Process ΔU Q W A gas expands very quickly, doing work − 0 +

An ideal gas expands into a vacuum very quickly, doing no work. Note: this is an irreversible process.[Answers a bit repetitive]

An ideal gas expands isothermally, doing work

Water is being heated in an electric kettle. Take the system as being the whole kettle (including heating elements) and contents.

Water is being heated in an electric kettle. Take the system as being just the water.

Cyclic processes – this theme is taken up in the PH5 Energy option.

Suppose an ideal gas is taken through the cycle of changes ABCDA shown above on the left. Irrespective of exactly what is going on in the individual stages (AB, BC, CD, DA), or the exact shapes of the curves, we can draw some general conclusions… • When the gas has undergone one cycle and is back at A, its internal energy is the

same as it was originally, that is ΔU = 0. This is because internal energy is a function of state (see page 2), and the gas is back in the same state as originally.

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• Over the cycle as a whole, the gas has done a positive amount of work. This is because the area under ABC represents the gas doing a positive amount of work. The area under CDA represents work being done on the gas (see page 4), but this area is smaller.

• Thus applying the First Law, we see that for the cycle as a whole, there has been a net

flow of heat into the gas.

Some heat has been turned into work, and this will happen each time the cycle repeats. Question: When this was first done on an industrial scale, what (non-ideal) gas was used? Go through the argument again for the right hand diagram, where the cycle is anticlockwise. What are the differences? A Special Cycle Suppose AB in the left hand diagram represents an isothermal expansion in which an ideal gas pushes a piston (see page 7, Example 2). Since the gas does work, and ΔU = 0, heat is taken in. If the compression, CD, is also isothermal, heat is given out, but less than is taken in along AB. Since pV is less along CD than along AB, the isothermal process CD is at a lower temperature than the isothermal process AB. [Note that the surroundings must be slightly hotter than the gas for heat to flow in along AB, and slightly cooler than the gas for heat to flow out along CD. So different environments (e.g. an oven and a cold water bath) must be provided for these stages.] Let us now suppose that BC and DA occur so rapidly that no heat enters or leaves the gas in these stages. In this case, applying the First Law to the complete cycle: Refrigerators If we run the same special cycle backwards (right hand diagram above), heat flows out along AB, a smaller quantity of heat flows in along CD, and a net quantity of work has to be put in over the cycle. So…

Net work out over a cycle = heat taken in along AB (at

higher temperature) − heat given out along CD (at lower temperature)

Net work in over a cycle = heat given out along AB

(at higher temperature) − heat taken in along CD (at lower temperature)

In an ordinary domestic fridge, you can feel the heat coming out from the pipework at the back. A fluid capable of evaporating and condensing (not, then, an ideal gas) circulates in the pipes. The heat is taken in from anything placed in the fridge, (and also comes in through the walls and door of the fridge). The work is supplied electrically.

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The Second Law of Thermodynamics (just for interest) For the ‘special cycle’ on page 11, not all the heat taken in during the isothermal process AB could be used to produce work. Some heat had to be ‘excreted’ at a lower temperature (during the process CD). In fact, no exceptions have ever been found to the rule that… It is not possible, by any cyclic process using any substance, to take in a quantity of heat at one temperature and turn it all into work. This is one version of the Second Law of Thermodynamics. If we could take in heat at one temperature and turn it all into work, life would be a lot simpler. For example we might be able to take heat out of the polar ice caps (so slowing down their melting) and get out electrical work. Of course using (that is converting) the electrical work would give heat, but we could turn this into work. Dream on! It is possible to show from the Second Law that a very simple rule relates the quantities of heat taken in and given out to the temperatures in the special cycle of page 11.

heat taken in along ABheat given out along CD

AB

CD

TT

=

This applies for any substance, not just an ideal gas, undergoing the special cycle. The one proviso is that each stage in the process has to be exactly reversible. Example: Suppose AB is an isothermal at 400 K, and CD an isothermal at 300 K. If the substance takes in 100 J of heat along AB, it must give out 75 J of ‘waste’ heat along CD. The net output of work over the cycle will be 25 J. We say that the efficiency of the cycle is 25%. In practice the efficiency will be lower because of irreversible effects like friction (page 5). We can increase the cycle’s efficiency by making TAB larger or TCD smaller. There are clearly technical limits to how large we can make TAB – components will melt! But what about making TCD small? The problem here is that we must have some body of large heat capacity outside the system, at a temperature marginally less than TCD, in order that heat will flow out of the system during the process CD. That’s why, for large-scale practical purposes, TCD can’t be much less than 300 K. A modern power station has an efficiency of less than 40%. This means that for every joule of heat supplied from burning fuel (or from nuclear fission) more than 0.6 J is given out as low temperature heat. It usually goes to waste. Remember this if you use an electric heater at home! Degradation of Energy (for interest) Could we not use the heat excreted at TCD as the input to another ‘heat engine’? Yes, but note that it would be even more difficult to get a decent yield of work out of that engine, since there would be even less scope for a large difference between the TAB and TCD for that engine. In this sense heat at low temperature is low-grade energy: it is less capable of being converted to work. That’s why we don’t bother to try to re-use the waste heat from (say) the backs of fridges and television sets. There is a tendency, in fact, for energy always to degrade – think about effects of friction and electrical resistance.

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There is a deeper, microscopic, interpretation of the degradation of energy. When energy is delivered to a system as heat it increases the disorderliness of energy distribution among the particles of the system. This disorderliness (measured by the quantity entropy) makes energy less available for conversion. As an example, consider again Example 2, the isothermal expansion of an ideal gas. After the expansion, the gas has the same amount of internal energy as originally, but the particles are now moving about all over the place – well, in a larger volume than before! And we know that it is harder to get the expanded gas to do work. Work is energy transferred in its least degraded form. The force and the distance moved are in a single direction; the energy transfer is orderly.

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Appendix B Revolutions in Physics Notes

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REVOLUTIONS IN PHYICS ELECTROMAGNETISM AND SPACE-TIME

1. Introduction One of the most exciting things in Physics is to discover relationships between observed effects (or phenomena) that were previously thought to be quite distinct. What happened in electromagnetism in the nineteenth century is a wonderful example. In the year 1800 there were only the vaguest indications that magnetism had anything to do with moving electric charges, and no evidence at all that light had anything to do with electricity or magnetism. By 1900 magnetism and electricity had been firmly linked, and light had been shown to be an electromagnetic wave. How this came about, sometimes in small steps, and sometimes by seemingly bizarre lines of reasoning, is the subject of this option.

In one respect the new theory that linked electricity, magnetism and light seemed not to agree with the facts, as found in experiments. In 1905 Einstein’s Special Theory of Relativity came to the rescue. At the same time, it actually simplified the theory of electromagnetism (and light). Included in this option there is a small taste of Relativity theory. 2. Questions and answers about this option Q What is the point of studying this option? A • It re-inforces some of the non-optional A-Level material, coming at it from a different angle, giving it a wider context, and adding ‘human interest’. • It brings the student into contact with great minds and great ideas. • Sheer self-indulgence – it’s a wonderful story.

Q How can the material presented in this option, derived from what others have written, give the promised ‘contact with great minds’?

A A few extracts from some of the key figures (Young, Faraday, Maxwell and Einstein) are provided. The extracts are not very long, but are to be studied closely. Guidance is given.

Q Does the student have to learn dates? A No, but having the right half-decade is good. In fact people often ‘absorb’ dates easily when

there’s a chain of events – and when there’s no stress to learn dates! Q What has to be left out in order to fit the story into an A-level option?

A This is a real problem. Looking back on past events and ideas, it’s easy to see, or to think we see, which of them led nowhere or were of secondary importance, and to leave them out. But at the time they may have been considered very important. They may have influenced the way physicists thought, in ways we cannot now know. By omitting them we distort history. Please be aware that this option cannot tell the whole story.

Q Can anything be done to give a more balanced picture? A Websites references are sprinkled throughout this WJEC material. Two thinnish and very

readable books which provide good support are…

Michael Faraday and the Royal Institution by John Meurig Thomas (ISBN 0-7503-0145-7).

Relativity and its Roots by Banesh Hoffmann (ISBN 0-486-40676-8). Chapter 4 tells pretty much the same story as this course, but, as the book’s title makes clear,

Hoffmann has a special agenda, and his emphases are different.

All the material to be tested in the PH5 examination is contained in this WJEC printed material, but students are urged to visit the websites, as they help to bring the basic material of the option alive and make it easier to learn. They often contain pictures and diagrams.

3. Electricity, Magnetism and Light: What was known in 1800

3.1 Electric Charge

• It had been known from ancient times that objects, in particular lumps of amber, could be ‘charged’ by rubbing, and could sometimes attract attract or repel other objects. [Our word electricity comes from the greek word for amber.]

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• Around 1730, Stephen Grey (www.sparkmuseum.com/BOOK_GRAY.HTM) had found that damp thread, and metals, would conduct charge from one object to another, whereas many materials were insulators (when dry). [Charge was often referred to as ‘electricity’ and charging, as ‘electrifying’.]

• Soon after, it emerged that there were two sorts of electric charge, and that these could neutralise each other. Some years later, the american statesman and scientist, Benjamin Franklin, called them positive and negative. Amber gains a negative charge when rubbed with fur; glass, a positive, when rubbed with silk.

• Franklin showed, by extremely dangerous experiments, that thunder clouds contain electric charge, and that lightning is an electrical phenomenon. (www.inventors.about.com/cs/inventorsalphabet/a/Ben_Franklin_4.htm )

• In about 1745 Dutch investigators discovered that opposite charges could be stored on conducting surfaces coating the inside and the outside of a glass bottle, and so separated by the insulator, glass. The device quickly came to be called a Leyden jar, after Leyden, now Leiden, in the Netherlands. It was used in demonstrations all over Europe to produce sparks and electric shocks - and much excitement.

• In the late 1780s, Coulomb (www.en.wikipedia.org/wiki/Charles_Augustin_de_Coulomb ) made the first quantitative investigation of the forces between charged spheres. These were of small enough diameter, in relation to their separation, to be considered ‘point charges’. Using a torsion balance of his own devising, he showed that there was an inverse square law, that is, when the separation of the centres of the spheres was doubled, the force between the spheres quartered, and so on. (http://library.thinkquest.org/C001429/electricity/electricity11.htm )

[The reclusive Henry Cavendish had made the same discovery some years earlier, but did not publish his findings.]

Coulomb and his contemporaries were struck by the similarity between this inverse square law for charges and Newton’s inverse square law of gravitation for masses.

3. Electricity, Magnetism and Light: What was known in 1800

3.2 Magnetism In the year 1800, most of the knowledge about magnetism dated from 1600, when William Gilbert had published his great work De Magnete (‘About the Magnet’). He described his experiments to magnetise iron bars using a lodestone (naturally occurring magnetised iron ore), reported on the ‘magnets’ having poles at either end (the word ‘poles’ is his), and found that even if you cut a magnet in half, each of the two halves still had both a North and a South pole. He investigated the effect of the Earth on a pivoted magnet, and came to the conclusion that the Earth itself was a magnet. He

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demolished many superstitions about magnetism, but we would regard his own view as to the cause of magnetic effects as very odd. (http://galileo.rice.edu/sci/gilbert.html )

Although the attraction and repulsion behaviour of magnetic poles resembles that of electric charges, Gilbert was very careful to explain that magnetic and electric effects were quite distinct.

3.3 The Battery This was hot news in the year 1800. Back in the 1780s, Luigi Galvani had observed the twitching of a leg cut from a dead frog, when a nerve was touched by a piece of metal which was also in contact with the foot. The effect, he found, was much greater if two different metals were joined together. There are various versions of how the discovery was made; see for example www.bioanalytical.com/info/calendar/97/galvani.htm . Galvani attributed the twitching to ‘animal electricity’, perhaps in the frog’s nerves.

Alessandro Volta took up the investigation and became convinced that it was the different metals which played the key role. He devised a cell consisting of a strip of zinc and a strip of copper dipping into a cup of brine or dilute acid, but not touching each other, and then started putting cells in series (as we would now say). Two forms of ‘battery’ emerged, the ‘crown of cups’ (www.scienceandsociety.co.uk/results.asp?image=10207373 ) and the famous ‘voltaic pile’ (www.en.wikipedia.org/wiki/Voltaic_pile ). [In French the name still survives: une pile or une pile electrique is a battery.] News of Volta’s invention spread quickly, and batteries, sometimes very large ones, were built all over Europe and in America. They were found to melt wires, connected across their terminals, and to enable the splitting up of water up into oxygen and hydrogen. Some investigators were nearly killed by electric shocks from batteries of many cells. Humphry Davy (www.rigb.org/rimain/heritage/ripeople/davy.jsp ), at the recently founded ‘Royal Institution’ in London, used batteries to perform electrolyses which isolated sodium, potassium and various other elements for the first time. He also fascinated audiences with demonstrations of what a battery could do. Davy’s audiences weren’t made up entirely, or even mainly, of people we would now call ‘scientists’. Any intelligent person – with the leisure – could contribute to a scientific debate. Davy himself was quite a gifted poet and was a friend of Wordsworth and Coleridge. There wasn’t really an ‘arts-science divide’. ‘Galvanism’, the term used then for the study of the battery and what it could do, was much talked about, and we might guess that it was one of the influences on the young Mary Shelley, when she was writing Frankenstein (published in 1818). Volta himself had established a connection between batteries and electric charge. He discovered that the terminals of his batteries were charged positively and negatively. Charge collected from the terminals could be used to make bodies attract and repel, in specially designed instruments. The battery provided for the first time the means of producing a continuous flow of charge, or electric current. [Charge in this context was often referred to as an ‘electric fluid’, and there was controversy over whether there were really two fluids or just one. We shan’t follow this particular sub-plot.]

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3. Electricity, Magnetism and Light: What was known in 1800

3.4 Light

In the 1660s Newton had performed a brilliant series of experiments showing that ‘white light’ was a mixture of colours. He made other major contributions to optics. Naturally he wondered what light was.

Newton’s rival, Robert Hooke (of Hooke’s Law fame) believed it to be a wave-like disturbance travelling through, and by means of, a universal medium (often called the aether or ether). Christiaan Huygens, a strong supporter of a wave theory of light, showed how to predict where a wavefront will be, and what its shape will be, if we know its position and shape now. He gave convincing wave theory accounts of reflection and refraction.

(http://encarta.msn.com/encyclopedia_761567208/Christian_Huygens.html )

For Newton and others, the problem with the wave theory was that light doesn’t seem to bend round corners, for example when opaque objects are put in its path. Water waves, though, do bend and spread into the ‘shadow’ behind obstacles, sound travels round corners – and so do Huygens’ wavefronts. For this reason, mainly, Newton could not accept that light was a wave, or, more accurately, just a wave. He held that it consisted of a stream of corpuscles or particles, coming from its source. But he knew there were problems with this: if light fell on a sheet of glass, some goes through and some is reflected. Why should some corpuscles do one thing and others another? Newton wrote of light as having ‘fits’ of easy reflection and fits of easy refraction, and hinted that possibly some sort of wave-like disturbance might accompany the corpuscles and determine what they did.

Such was the awe in which Newton was held for showing how an inverse square law of gravitation accounted for the motion of the planets, the moon and the tides, that his corpuscular theory of light was given enormous respect. If you challenged it, even long after Newton’s death, you would have to defend yourself very convincingly.

3.5 Questions on section 3

(1) It was discovered in the 1700s that metals could be charged up by rubbing with a dry cloth. In what special way would the metal have to be held?

(2) A leyden jar would now be classed as a sort of …………………….. ?

(3) How, mathematically, do we now write Coulomb’s inverse square law for electric charges?

(4) What, according to William Gilbert, was the ‘soul of the Earth’?

(5) In what you have read, have you come across any pre-1800 evidence for a connection between electricity and magnetism?

(6) What was ‘galvanism’, and why was it so called?

(7) Is it true that none of the effects of an electric current could have been observed before the work of Galvani and Volta?

(8) How does the wave theory of light account for refraction?

(9) What political upheaval was shaking Europe in the 1790s?

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4. Re-birth of the Wave Theory of Light

4.1 Thomas Young Thomas Young (born in 1773) was a child prodigy. When four years old, he is said to have read the

bible in its entirety…twice. By the age of fourteen he had mastered several languages, ancient and modern.

He lived up to his early promise. As a medical student he discovered the mechanism by which the eye focuses (or accommodates), and, at the age of 21 was elected a Fellow of the Royal Society. This is Britain’s most prestigious scientific society, dating from the time of Newton.

In 1801, when Young had set up as a doctor in London, he was chosen as Professor of Natural Philosophy (roughly speaking, Physics) at The Royal Institution. [He turned out not to be as charismatic a lecturer as Humphry Davy.]

At about this time Young started his researches on light – see below.

Later in life he made some headway in deciphering the ancient Egyptian heiroglyphics on the Rosetta Stone.

www.whonamedit.com/doctor.cfm/1715.html

Writing about light, Young stated two ‘hypotheses’ ; “A luminiferous [light-carrying] ether pervades the universe.” “Undulations [waves!] are excited in this ether whenever a body becomes luminous.” He explained that: “an undulation is supposed to consist in a vibratory motion; transmitted successively through different parts of a medium without any tendency in each particle to continue its motion except in consequence of the transmission of successive undulations from a distinct vibrating body.”

Young’s new idea, apparently not grasped by Huygens, was that light had to be a regular sequence of undulations. This implied that light from the same source, travelling to the same point by different routes would interfere either constructively or destructively, according to phase difference. Using the idea of interference, Young was able to explain ‘Newton’s Rings’ a phenomenon which had puzzled Newton himself. Visit the website below for pictures – strictly ‘for interest only’! www.physics.montana.edu/demonstrations/video/6_optics/demos/newtonsrings.html

Note that it did not occur to Young at the time that light could be anything other than a longitudinal wave, like sound.

Young seems [historians argue about it] first to have shown a version of his famous two slits experiment in a lecture given to The Royal Society in 1803. Here is the account he gives of such an experiment…

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4. Re-birth of the Wave Theory of Light

4.1 Thomas Young (Continued)

“It has been shown that two equal series of waves, proceeding from centres near each other, may be seen to destroy each other’s effects at certain points, and at other points to redouble them; and the beating of two sounds has been explained from a similar interference. We are now to apply the same principles to the alternate union and extinction of colours.

“In order that the effects of two portions of light may thus be combined, it is necessary that they be derived from the same origin, and that they arrive at the same point by different paths in directions not much deviating from each other. This deviation may be produced in one or both the portions by diffraction, by reflection, by refraction, or by any of these effects combined: but the simplest case appears to be, when a beam of homogeneous light falls on a screen in which there are two very small holes or slits, which may be considered as centres of divergence, from whence the light is diffracted in every direction.

“In this case, when the two newly formed beams are received on a surface placed so as to intercept them, their light is divided by dark stripes into portions nearly equal, but becoming wider as the surface is more remote from the apertures, so as to subtend very nearly equal angles from the apertures at all distances, and wider also in the same proportion as the apertures are closer to each other. The middle of the two portions is always light, and the brighter stripes on each side are at such distances, that the light coming to them from one of the apertures, must have passed through a longer space than that which comes from the other, by an interval which is equal to the breadth of one, two, three or more of the supposed undulations, while the intervening dark spaces correspond to a difference of half a supposed undulation, of one and a half, of two and a half, or more.

“From a comparison of various experiments, it appears that the breadth of the undulations constituting the extreme red light must be supposed to be, in air, about one 36 thousandth of an inch, and those of the extreme violet, about one 60 thousandth; the mean of the whole spectrum, being about one 45 thousandth. From these dimensions it follows, calculating upon the known velocity of light, that almost 500 millions of millions of the slowest of such undulations must enter the eye in a single second.”

Young continues with a description of the ‘beautiful diversity of tints’ in the fringes which are seen when white light is used. The above extract is as Young wrote it, apart from one comma being removed and one new paragraph created. There were no diagrams (apart from the one below); readers were supposed to … read. And visualise!

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4. Re-birth of the Wave Theory of Light 4.1 Thomas Young (Continued) Here are some must-do ‘comprehension’ questions on this first-ever description of a now famous experiment. (1) What did Young mean by a ‘luminiferous ether’? What purpose did it serve?

(2) Draw the set-up described by Young in the second paragraph and the beginning of the third paragraph in the long extract. It should be familiar!

(3) What – in a word – does Young mean by ‘the breadth of an undulation’ (near the bottom of the third paragraph)?

(4) WJEC gives the ‘Young’s fringes formula’ as (a) Re-arrange it to make the fringe separation the subject.

(b) Pick out the phrase from Young’s third paragraph in which he states the effect on the fringe separation of altering D.

(c) Pick out the phrase from Young’s third paragraph in which he states the effect on the fringe separation of altering a.

λ =a yD .

(5) The bright stripe next the central bright stripe is at such a distance, to use Young’s terminology, that the light coming to it from one of the apertures must have passed through a longer space than that which comes from the other, by an interval which is equal to the breadth of one of the supposed undulations. Put this in modern ‘path difference’ language.

(6) 1 inch = 2.54 cm. Hence express in metres Young’s results (fourth paragraph) for the wavelengths of the extremes of the visible spectrum. Do they agree with what textbooks give?

(7) What is conspicuously missing from this account of a quantitative experiment? (8) When, at the end of the passage, Young refers to ‘the slowest of such undulations, he means

those of the lowest frequency. What does he give as their approximate frequency? (9) Young refers near the end to ‘the known velocity of light’. [It had been inferred a long time

previously by two different methods based on two quite different sorts of astronomical measurements.] Work backwards from Young’s figures for longest wavelength and lowest frequency to deduce what figure he must have been using for the velocity of light.

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4. Re-birth of the Wave Theory of Light (Continued) 4.2 Reactions to Young Young’s experiment is the classic demonstration that light has wave-like properties. But that is not how it was seen at the time. Maybe Young’s contemporaries would have been more convinced if he’d given his actual readings, and explained properly how he’d arrived at his results for wavelengths. Then there was the long-dead Newton to contend with. How dare this upstart, Young, challenge the great Newton’s view that light was a stream of particles? Henry Brougham, a barrister who later rose to become Lord Chancellor, wrote an infamous review of one of Young’s Royal Society papers. He accused Young of putting forward an (unjustified) theory, and having to make changes to it …

“A mere theory is in truth destitute of all pretentions to merit of every kind, except that of a warm and misguided imagination. It demonstrates neither patience of investigation, nor rich resources of skill, nor vigorous habits of attention, nor powers of abstracting and comparing, nor extensive acquaintance with nature. It is the unmanly and unfruitful pleasure of a boyish and prurient imagination, or the gratification of a corrupted and depraved appetite. “If, however, we condescend to amuse ourselves in this manner, we have the right to demand, that the entertainment shall be of the right sort – that the hypothesis shall be so consistent with itself, and so applicable to the facts, so as not to require perpetual mending and patching – that the child we stoop to play with shall be tolerably healthy, and not of the puny, sickly nature of Dr Young’s productions [...]”

Not impressed, then? In another paragraph (which no writer today could expect to get away with) Brougham accused Young of bringing the Royal Society into disrepute…

“Has the Royal Society degraded its publications into bulletins of news and fashionable theories for the ladies who attend the Royal Institution? Proh Pudor! [For shame!] Let the professor continue to amuse his audience with an endless variety of such harmless trifles; but, in the name of Science, let them not find admittance into that venerable repository which contains the works of Newton, and Boyle, and Maskelyne, and Herschell.” (http://homepages.wmich.edu/~mcgrew/brougham.htm for interest only!)

Brougham’s reaction was extreme, but, even putting it aside, Young’s work on interference and the wave theory didn’t attract much enthusiasm at the time.

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4. Re-birth of the Wave Theory of Light (Continued) 4.3 Transverse waves Real trouble soon arrived for the wave theory. In about 1808 Etienne Malus discovered an astonishing fact about the light reflected from a transparent sur-face. The effect is observed to perfection for the light reflected off a glass plate, A, when the angle of incidence is 57°. The reflected ray is found to be reflected from another glass plate, B, when this is as shown in the left hand diagram, but not when B is turned about the ray as axis, so that it is as shown on the right. The light must be asymmetrical about its direction of travel! [A related effect involving certain crystals, called ‘double refraction’, had puzzled natural philo-sophers for well over a century. Polaroid had not been invented.]

To an A-level student the solution should be obvious: light is a transverse wave, and A must be polarising it. But it hadn’t occurred to Young that light could be anything else but a longitudinal wave, like sound. Eventually, though, (c1818) the penny dropped.

By this time another powerful wave theorist, Augustin Fresnel, was at work in France. (http://micro.magnet.fsu.edu/optics/timeline/people/fresnel.html ). He came upon the significance of interference independently of Young, and developed the wave theory mathematically. He showed convincingly that the reason we don’t normally see light bending round corners is because of its short wavelength. He accounted for polarisation by reflection, double refraction and the diffraction patterns caused by various obstacles. For a spherical obstacle his equations made an unlikely prediction … (www.physics.brown.edu/physics/demopages/Demo/optics/demo/6c2010.htm )

4.4 Problems with the Ether Fresnel effectively killed off the corpuscular theory. Most natural philosophers were persuaded that light was a transverse wave. The only sort of wave anyone could imagine was a mechanical wave, in which a pattern of displacements transmits itself through a medium, the ‘ether’. Try and follow this crude and sketchy explanation… In the diagram a transverse wave is travelling to the right. The medium is stiff, so the shaded slice experiences an upward tangential or ‘shearing’ force from the upwardly displaced slice to its left. The shaded slice will accelerate upwards, and the peak displacement, P, will move to the right – and so on. There were severe problems with this ‘mechanical’ theory… • It is difficult to see why the ether shouldn’t transmit

longitudinal waves as well as transverse waves. Yet no longitudinal waves were observed.

• Transverse waves need a stiff medium, a solid, rather than a liquid or gas. But we receive sunlight and starlight, so all space must be full of this medium. How, then can the planets move without obstruction? Indeed, how can anything move freely?

For the next few decades, elaborate attempts were made to devise ether structures which would not have these problems. We shall return to the ether…

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5. Discoveries in Electromagnetism 5.1 Ørsted Electromagnetism was born in 1820 when Hans Christian Ørsted (or Oersted) (http://en.wikipedia.org/wiki/Hans_Christian_Ørsted) discovered that a copper wire connected across the terminals of a battery could deflect a compass needle (in other words, a pivoted magnet). The effect was just as large if non-magnetic substances other than air were placed between the wire and the magnet. As long as it was close enough to the wire, the magnet was deflected to be almost at right angles to the wire. The North-seeking pole pointed in opposite directions according to whether the magnet was below or above the wire. It seemed as if the magnet directions were tangential to

circles going round the wire.

uick Checks

• Do the needle directions shown agree with the right hand grip (or screw) rule? right angles to the

• st-West?

A Historical Puzzle

Twenty years had gone by between the invention of the battery and Ørsted’s discovery, and this is

argument which claimed to

ad found compass needles being ‘affected’ during experiments with batteries. But

Q

• Why does the needle have to be close to the wire to be deflected almost at wire? What other influence is there on the needle? Why won’t the experiment work if the wire runs Ea

rather odd. For one thing, there was a sort of ‘galvanism mania’ after Volta announced his invention, and the powers of the battery were explored with great zeal. For another, there were tantalising clues that magnetism and electricity were related, such as in stories of cutlery becoming magnetised, and ship’s compasses suffering reverses in polarity, during thunder-storms. What is more, many investigators were influenced by a philosophical show that the ‘forces of nature’ must have an underlying unity. Ørsted held this view, and seems to have been searching on and off for years for magnetic effects due to a battery. It wasn’t at all obvious, though, that the battery had to be in a closed circuit, in other words that there had to be a current. When the effect was discovered (during one of Ørsted’s lectures, according to a popular version of the story), it was not as anyone had guessed. Instead of pointing parallel to the wire, or radially towards or away from the wire, the compass seemed to want to point at right angles to both these directions. [Note… Others hØrsted was the first, as far as we know, to investigate systematically what was happening, and to publish a clear, detailed description of the phenomenon.]

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5. Discoveries in Electromagnetism (Continued) 5.2 Ampère Ørsted’s experiment was demonstrated at a meeting of the French Académie des Sciences. One of those present was the mathematician André-Marie Ampère, a friend of Fresnel and a supporter of the wave theory of light. (http://www-history.mcs.st-and.ac.uk/history/Biographies/Ampere.html ) Ampère immediately plunged into an intense period of investigations. He reported discoveries at a rate of around one a week for the next two or three months.

Improved version of Ørsted’s experiment One of the first things Ampère did was to use magnets to cancel the effect of the Earth on the compass magnet, over a region around the wire. He then found that even when it was not very close to the wire, the compass magnet pointed at right angles to the wire and tangentially to circles around the wire. [Ampère referred to electric current in the wire, and used this term consistently, with the convention that the current in a wire is from the positive terminal of the battery to the negative.]

Forces between current-carrying wires Ampère went on to demonstrate a totally new phenomenon: that wires carrying currents exert forces on each other. Parallel wires attract each other if carrying currents in the same direction, and repel if the currents are in opposite directions. On the left is Ampère’s diagram of his apparatus. The parallel wires are AB (fixed to the base) and CD (able to swing on pivots E and F).

Coils and Magnets Ampère believed that the basic forces involved both between his parallel wires, and between the wire and the magnet in Ørsted’s experiment, were forces

between currents. So Ampère believed there were currents inside magnets? Yes. He strengthened his case by showing that current-carrying coils and solenoids behaved very much like magnets... • He showed that the ends of two coils seemed to attract and repel each other like the poles

of two magnets. • He took the wires from the ends of a solenoid (AB in the right hand diagram) back

through the inside of the solenoid and out through the centre, then taking the wires up and down to cups of mercury (N and M), connected to the terminals of a battery. Thus the solenoid could turn freely. He found it to behave like a compass magnet.

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5. Discoveries in Electromagnetism (Continued) 5.2 Ampère (Continued)

Ampère’s Theory of Magnetism What might be the paths of currents inside magnets to make magnets behave like solenoids? At first Ampère thought they might be big loops, like the turns of a coil. He then took up a suggestion of Fresnel, that the loops were ‘molecular’, in other words on a minute scale. In a magnet the loops’ axes were supposed to be roughly parallel (see diagram); in unmagnetised iron they were supposed to be arranged randomly.

Current elements Ampère regarded a series circuit as made up of a succession of ‘current elements’, that is very short, near-enough-straight lengths of current-carrying conductor. He wanted to find a formula for the force between two current elements which would do the same for current elements as Coulomb’s inverse square law did for stationary point charges. But it needed to be more complicated as it had to take account of the angles, (ε, α and β) between the current elements, and between them and the line joining them. Take a quick look at the formula Ampère decided upon, by courtesy of www.rwgrayprojects.com/energy/VACE/calc/calc01.html (top four lines only)

To find the force that a whole circuit (1) exerts on circuit 2, you would need to add up all the forces that all the current elements in 1 exert on all the elements in 2. This is every bit as difficult as it sounds, except for certain symmetrical cases, like long straight wires. Ampère had to try various formulae for the force between current elements until he found one which gave answers for forces between circuits which agreed with experiment. [There are other possible formulae which do so.]

Ampère was not the only one in France to be galvanised into action by Ørsted’s discovery. Jean-Baptiste Biot and Félix Savart discovered that the torque on a compass magnet due to a long straight current-carrying wire varied inversely with the distance of the magnet from the wire. Like Ampère, they developed the idea of current-elements.

Self-test questions on Ørsted and Ampère

(1) If you haven’t already done so, find out Ørsted’s nationality. (2) In Ørsted’s experiment the tendency of the magnet to point in directions tangential to circles

around the wire was probably the result least expected. Which two directions might have been considered less strange?

(3) How did Ampère’s ‘improved’ version of Ørsted’s experiment make it more conclusive? (4) (a) What is the basis of the definition of the SI unit of current?

(b) Discuss the appropriateness of naming it after Ampère. (5) Do physicists today believe that a magnet’s magnetism has anything to do with small-scale

electric currents inside it? (6) Explain why the force between current elements cannot be measured directly. (7) Find, in your list of formulae, the one which contains Biot’s and Savart’s discovery about the

long straight wire.

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5. Discoveries in Electromagnetism (Continued) 5.3 Faraday Michael Faraday is perhaps the best known and most admired of nineteenth century scientists. His career began with a fairy-tale ‘elevation’ from bookbinder’s apprentice to Humphry Davy’s assistant at the Royal Institution. (www.rigb.org/rimain/heritage/faradaypage.jsp) [The first three chapters of Michael Faraday and the Royal Institution by J Meurig Thomas set the scene. The whole book is very readable.]

Faraday was more an experimental scientist than a theorist, but he had extraordinary, almost intuitive, insight. He had the patience to tease out the details of the effects he investigat-ed, and the flair to judge which were important. His achievements included the discovery of benzene, the liquefaction of several gases, and the formulation of the laws of electrolysis. He discovered that materials other than iron experienced forces (even though weak or very weak) when placed near the poles of a magnet. It is his work in electromagnetism for which he is probably most famous…

Faraday, like the french scientists, was stimulated by Ørsted’s discov-ery. But, unlike them, Faraday had no maths beyond arithmetic, nor was he convinced that mathematical theories, such as those using ‘curr-ent elements’, served much purpose.

Instead, Faraday’s ‘feeling’ for the wire-and-magnet phenomenon, led him to devise set-ups in which rotations took place – see diagram. On the left hand side, the uppermost pole of a magnet partially immersed in mercury rotated about a current-carrying wire. On the right hand side a current-carrying wire rotated about the uppermost pole of a magnet. The wire was pivoted at its top end, and dipped into mercury at its lower end. Check that you can trace the path of the current.

In these experiments, as in those of Ørsted and Ampère, electric currents produced magnetic effects. But magnets hadn’t been shown to produce currents. Faraday’s instinct was that there must be such an effect, “magnetism causing electricity”; it just needed to be found. Over the next ten years, he made several attempts to find it. Success came on the twenty-ninth of August, 1831…

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5. Discoveries in Electromagnetism (Continued) 5.3 Faraday (Continued) The Discovery of Electromagnetic Induction Faraday’s famous laboratory diary entry for August 29th 1831 (with a little more punctuation added) begins as follows: “Have had an iron ring made (soft iron); iron round and 7/8 inches thick and ring 6 inches in external diameter. Wound many coils of copper round, one half of the coils being separated by twine and calico – there were 3 lengths of wire each about 24 feet long, and they could be connected as one length or used as separate lengths. […] Will call this side of the ring A. On the other side but separated by an interval was wound wire in two pieces together amounting to about 60 feet in length, the direction being as with the former coils. This side call B.

Charged a battery of 10 pr plates [10 pairs of plates] 4 inches square. Made the coil [coils] on B side one coil, and connected its extremities by a copper wire passing to a distance and just over a magnetic needle (3 feet from iron ring) then connected the ends of one of the pieces on A side with battery; immediately a sensible effect on needle. It oscillated and settled at last in original position. On breaking connection of A side with battery, again a disturbance of the needle.”

Notes and self-test questions on the diary extract

• The coils were insulated from each other and from the ring.

• The two coils on side B were connected in series. [How does Faraday express this?]

• In this first experiment, Faraday used only one of the coils on side A; the other coils on side A might as well not have been there.

• In the language of transformers, what are coils A and B?

• In magnetic terms, what does coil A do when connected to the battery?

• Faraday used Ørsted’s set-up, with wire and compass needle, as a ‘galvanometer’ to detect any current in the coil B circuit – pick out the phrase Faraday uses to describe the arrangement. [In fact his galvanometer wasn’t very sensitive, and he went on to use more sensitive instruments.]

• Why did Faraday place the galvanometer as far as 3 feet away from the ring?

• The current in the B circuit – Faraday soon started calling it the induced current – was only transient; it was present only when the current in A was turned on and off.

This is probably the main reason why Faraday took so long to find ‘magnetism causing electricity’. No-one seems to have guessed that the effect would take place only when a change was occurring.

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5. Discoveries in Electromagnetism (Continued) 5.3 Faraday (Continued) Further Exploration of Electromagnetic Induction Faraday knew he had made a major discovery, and set about a thorough investigation of the phenomenon. He soon found, as he had expected, that even without iron, a changing current in one circuit could induce currents in a nearby circuit, though the effect was much weaker than with iron present. If there were any doubts that the induced current was a magnetic effect, Faraday put paid to them by thrusting one end of a bar-magnet into a solenoid connected to a galvanometer. The needle deflected in one direction when the pole was thust in, returned to its zero position and stayed there if the magnet was left stationary inside the solenoid, but deflected in the opposite direction when the pole was withdrawn. (http://micro.magnet.fsu.edu/electromag/java/faraday2/ - not historical but fun)

Magnetic Lines of Force Not only did Faraday demonstrate many instances of electromagnetic induction, he developed a simple but powerful way of visualising when it would take place. He relied on lines of force (now called lines of flux). These are the curved lines that can be ‘plotted’ with iron filings or a compass magnet. In Faraday’s diagram (of 1832) they arise from a magnet, AB. Faraday explains that if a conductor is part of a closed circuit, a current will flow in it when it ‘cuts’ lines of force. In the diagram the conductor PN which he draws is a knife blade – re-inforcing the cutting metaphor. He gives a rule for the direction of current flow which is equivalent to the (later) Fleming’s Right Hand Generator Rule.

• In Faraday’s diagram A is the North pole of the magnet. If PN is moved upwards what will be the direction of current flow through it (if the circuit is completed)?

This picture of cutting lines of force doesn’t really seem to apply to Faraday’s original experiment with the ring of iron. There were no moving conductors (or magnets). But the notion of lines of force can still be used… At the point of turning on the current in A the number of lines of force going around inside the ring, and therefore ‘linked’ with coil B suddenly increases. The reverse happens

when the current in A is turned off. The rule that a current is induced when there is a change in the number of lines of force linking a circuit changes fits all cases of electromagnetic induction, including… • plunging one pole of a magnet into a coil – draw the ‘before’ and ‘after’ pictures, including some

lines of the magnet’s lines of flux. • part of a circuit cutting lines of force: the number of lines linked with the complete circuit will

change as a result of the change in area enclosed by the circuit.

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5. Discoveries in Electromagnetism (Continued) 5.3 Faraday (Continued)

A Quantitative Law Faraday came close to a quantitative rule when he wrote: “If a wire moves across lines of force slowly, a feeble current is produced in it, continuing for the time of the motion; if it moves across the same lines quickly, a stronger current is produced for a shorter time.”

We nowadays sum up electromagnetic induction in the equation:

Et

ΔΦ= −

Δ

We see that Faraday’s insights have been ‘developed’ considerably… • The equation deals with e.m.f. rather than current, since the induced e.m.f. does not depend on the

resistance of the circuit (whereas the current does). • Φ represents Faraday’s idea of the number of lines of force linking a circuit. Check that you can

define Φ the modern way! • The minus sign acknowledges the insight of Heinrich Lenz, working in St Petersburg in 1834.

Check you can state Lenz’s Law. • The proportionality was deduced around 1845 by Franz Neumann (from Ampère’s work!). In the

S.I. the proportionality constant is 1, so we can use ‘=’ rather than ‘∝’.

Action at a Distance? How does a current-carrying wire influence a compass magnet, or exert a force on another current-carrying wire, or, if the current is changing, induce a current in another circuit? How does the one thing (call it ‘X’) influence the other, ‘Y’, even though there’s empty space in between X and Y?

In general, continental physicists (Ampère and others) saw this ‘action-at-a-distance’ as a thing that simply happens, not requiring explanation. The work of the physicist, they thought, was to find mathematical laws for the forces between X and Y.

Faraday, though, was not content with action-at-a-distance. Something had to be going on in the space between X and Y in order to convey an influence from one to the other. Faraday felt that lines of force were involved. He knew this was controversial.

[In most of his writings Faraday used the term ‘magnetic lines of force’ uncontrovers-ially to mean lines (or curves) which tell you which way a compass magnet will point, or iron filings will line up, if you put them in the vicinity of a wire or magnet.]

Electric Lines of force Faraday also developed the idea of electric lines of force, starting on positive charges and ending on negative charges. They can be plotted by using a non-conducting pivoted needle, with a positive charge at one end and a negative at the other. Although they have some of the properties of magnetic lines of force, the two sorts of line mustn’t be confused.

Some of the lines of force for a charged capacitor are sketched in the diagram.

[Faraday found out a great deal about capacitors. In particular he investigated dielectrics and their effect on capacitance.]

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6. Electromagnetic Waves 6.1 Faraday Faraday drew a clear distinction between his experimental researches and his ‘speculations’ for which there was little experimental evidence. He talked about one such speculation when he had to fill in for a Royal Institution guest speaker who had taken fright and run away. Here are some extracts from a summary Faraday wrote for a friend. Referring to electric, magnetic and gravitational lines of force…

“[We can] affect these lines of force in a manner which may be conceived as partak- ing of the nature of a shake or lateral vibration. For suppose two bodies, A, B, distant from each other and under mutual action, and therefore connected by lines of force, and let us fix our attention upon one resultant of force having an invariable direction as regards space; if one of the bodies move in the least degree right or left […] then an effect equivalent to a lateral disturbance will take place in the resultant […]

My view which I am so bold as to put forth considers, therefore, radiation as a high species of vibration in the lines of force which are known to connect particles and also masses of matter together. It endeavours to dismiss the ether, but not the vibrations. The kind of vibration which, I believe, can alone account for the wonder-ful, varied, and beautiful phenomena of polarization, is not the same as that which occurs on the surface of disturbed water, or the waves of sound in gases and liquids, for the vibrations in these cases are direct, to and from the centre of action, whereas the former are lateral. It seems to me, that the resultant of two or more lines of force is an apt condition for that action which may be considered as equi-valent to a lateral vibration; whereas a uniform medium, like the ether, does not appear apt, or more apt than air or water.

The occurrence of a change at one end of a line of force easily suggests a consequent change at the other. The propagation of light, and therefore probably of all radiant action, occupies time; and that a vibration of a line of force should account for the phenomena of radiation it is necessary that such vibration should occupy time also.”

Notes and questions on Faraday’s Speculation (1) What, in modern wave terminology, does he mean by a ‘shake, or lateral vibration? (2) What, according to Faraday (first paragraph) would you have to do to send such a vibration

along a line of force? This is crudely illustrated for an electric line …

(3) Faraday says (second paragraph) that (for light) lateral vibrations are needed to account for polarization effects. (a) What phrase does he use to describe the vibrations in sound waves? (b) What is the modern term? (c) Is he right about the nature of surface water waves?

(4) Faraday’s speculations had implications for the luminiferous ether. [Revise section 4.4 – if necessary!] These implications are summed up in one short sentence in the second paragraph. Which sentence?

Faraday’s idea was indeed bold. It was nothing less than an attempt to link light and electromagnetism. To be considered a successful attempt, it would need developing into a theory which could make predictions, including quantitative ones.

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6. Electromagnetic Waves (continued)

6.2 Maxwell

James Clerk Maxwell was arguably the greatest theoretical physicist of the nineteenth century. Unlike Faraday, Maxwell was born to well-to-do parents, and he received a good education, including a thorough training in mathematics.

Maxwell was brilliant at spotting analogies between different branches of physics, developing them mathematically – and knowing when to drop the analogy. His most far-reaching work was in kinetic theory of gases, and in electromagnetism. (The following link may not work, but the URL is fine: www-history.mcs.st-and.ac.uk/history/Biographies/Maxwell.html)

On Physical Lines of Force

This is the title of a four-part paper of 1861-2 in which Maxwell sets out to “examine magnetic phenomena from a mechanical point of view, and determine what tensions in, or motions of, a medium are capable of producing the mechanical phenomena observed.” • The ‘mechanical phenomena observed’ are the attractions and repulsions between poles of magnets.

He goes on to hint that his ‘medium’ theory will also account for electromagnetic effects such as induced currents.

• Since magnets will ‘work’ in a vacuum, Maxwell’s medium must fill even ‘empty’ space. [An invisible, space-filling medium was not a new idea – revise section 4.4].

Maxwell’s starting point was magnetic lines of force. He writes… “[If] we strew iron filings on paper near a magnet, each filing will be magnetized by induction, and the consecutive filings will unite by their opposite poles, so as to form fibres, and these fibres will indicate the direction of the lines of force. The beautiful illustration of the presence of magnetic force afforded by this experiment, naturally tends to make us think of the lines of force as something real, and as indicating something more than the mere resultant of two forces, whose seat of action is at a distance and which do not exist there at all until a [compass magnet or iron filing] is placed in that part of the field. We are dissatisfied with the explanation founded on the hypothesis of attractive and repellent forces directed towards the magnetic poles […] and we cannot help thinking that in every place where we find these lines of force, some physical state or action must exist […]”

• What, then, was Maxwell’s take on action-at-a-distance? [See Section 5.3]

The properties Maxwell gave his space-filling medium allowed it to form into lines of force. The structure of the medium was machine-like. He showed that the machinery seemed to account for the phenomena of electromagnetism.

On the next three pages we look in some detail at Maxwell’s ‘machinery’. It may seem weird and quite different from anything you’ve met in Physics before, but the basic ideas aren’t particularly difficult. If you do find it a struggle, don’t give up: a general feel for what Maxwell was up to is worth having, even if you lose some of the details.

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6. Electromagnetic Waves (continued) 6.2 Maxwell (continued)

Vortices Maxwell asks us to suspend disbelief and to suppose that space is filled with elastic beads. If a bead spins about an axis [diagram (a)], it will become Smartie-shaped (like the Earth), contracting along its axis and expanding sideways. He called the spinning beads ‘vortices’ – whirlpools.

Diagram (b) shows some of the lines of force between two opposite magnetic poles attracting each other. It is as if the lines are under tension, pulling the poles together, and are pushing out sideways, pushing each other apart. This is just what would happen if the axes of the spinning beads lie along the lines of force. So magnetic lines of force are imagi-nary lines along which lie the axes of spin of the vortices.

The angular velocity of the vortices was proportional to the field strength. No field strength meant no spin.

Idlers If you could look along any line of force going from the North pole of one magnet to the South pole of another, the vortices would be spinning in the same sense – anticlock-wise, let us suppose. This presents a problem if space is chock-a-block with vortices. Between a North and South pole, they are all rotating in the same sense, so where vortices on adjacent lines of force touch, the vortex surfaces will be moving in opposite directions, and will interfere with each other’s motion [diagram (c)]. Maxwell’s solution was to suppose the vortices to be separated by ball-bearing-like ‘idlers’ [as in (d)]. By rotating in the opposite direction to the vortices, the idlers enable the vortices to rotate in the same direction as each other. Note: idlers never slip on vortices.

Maxwell’s (in)famous ‘honeycomb’ diagram of his ‘vortex medium’ is given below. Try not to worry about the sharp corners and the 2-dimensionality; it is just a stylised way of showing space completely filled with vortices separated by idlers. But, even so, could Maxwell seriously have believed that space was full of ‘machinery’ of this sort? He wrote:

“The conception of a particle having its motion connected with that of a vortex by perfect rolling contact may appear somewhat awkward. I do not bring it forward as a mode of connexion existing in nature, or even as that which I would willingly assent to as an electrical hypothesis. It is, however, a mode of connexion which is mechanically con-ceivable, and easily investigated, and it serves to bring out the actual mechanical connexions between the known electro-magnetic phenomena; so that I venture to say that anyone who understands the provisional and temporary character of this hypothesis, will find himself rather helped than hindered by it in his search after the true interpretation of the phenomena.” Let us now see how it does help…

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6. Electromagnetic Waves (continued) 6.2 Maxwell (continued)

Ørsted revisited

Spinning wasn’t the only motion Maxwell allowed his idlers. They could also move ‘sideways’. The diagram shows a line, I, of idlers moving (‘translating’) to the right without spinning. They must exert tangential forces on the vortices with which they are in contact, making them rotate as shown. This mot-ion spreads outwards from I via spinning idlers and vortices.

In this 2-dimensional diagram, the vortices above I are being made to spin anticlockwise, those below I, clockwise. So we are looking at a section through lines of force going in circles around I. But we know that an electric current in a straight wire has circular lines of force around it. So a line of translating idlers must constitute an electric current!

• Look again at Maxwell’s ‘honeycomb’ diagram – especially the arrows – and spot the one (zigzag) line of translating idlers. [Note: in the fourth row down of vortices, all four should be spinning clockwise!]

• You should now have some inkling of the capabilities of Maxwell’s ‘machinery’. In fact (with the help of rather a lot of mathematics) Maxwell showed how it would give rise to all the known effects of electromagnetism, including forces between currents and the e.m.f. induced in a conductor cutting lines of force.

Self-induction This material in this box will not be tested. It should, though, be of interest to anyone who is also studying the Further Electromagnetism and A.C. Theory option. The vortices have inertia and will acquire kinetic energy when made to spin. This energy will have to come from the line of translating idlers that set them in motion, in other words from the electric current. So the current will experience an opposing e.m.f., when the current is increasing. Once it reaches a steady value, the line of idlers will be translating at a constant speed, and the vortices spinning at a constant angular velocity, so they will not be acquiring KE. If the current decreases, the vortices will give back energy to the current, opposing its decrease, so there will be an e.m.f. in the other sense. This ‘explains’ the phenomenon of self-induction, which had been discovered independently in the early 1830s by Joseph Henry in America and by Faraday.

• Make sure you know the definition of e.m.f.. • Revise, or look up, the defining equation for self-inductance, L, and think about how it sums up the phenomenon of self-induction. [We cannot, it should be said, calculate L for an isolated straight wire; we have to take into account a ‘return path’ for the current (such a parallel wire).]

• But could the machinery tell us anything about electromagnetism that we didn’t already know? In other words, could it be used to make predictions?

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6. Electromagnetic Waves (continued) 6.2 Maxwell (continued)

Transverse Waves We now look in more detail at how a current-carrying wire sets up a magnetic field around it. Maxwell’s machinery predicts that when the current is switched on the field will take time to spread out. The crude diagram below helps to explain this... Suppose an idler, i, starts to turn. Because of its inertia, the vortex V ‘above’ i will not turn immediately, and i will roll to the left. But i will exert a tangential force on V, giving an anticlockwise torque on V, which will deform as shown, as it is made of elastically deformable material. Soon, the whole of V will start to turn anticlockwise, the deformation and stress will disappear and i will return to its original position. As it starts to turn, V will turn the idler ‘above’ it and the same thing will happen all over again for the ‘next vortex out’, and so on.

Don’t worry if you struggled with the last paragraph. The points to grasp are these...

• A magnetic field propagates outwards from its source at a finite speed.

• The ‘wavefront’ of the spreading magnetic field is accompanied by temporary stress on the vortex material. Maxwell interpreted this stress as an electric field. The vortices are temporarily distorted and the idlers temporarily displaced. Maxwell called their motion a ‘displacement current'. The direction of the electric field is the direction of idler displacement.

• The magnetic field and the electric field are at right angles to each other, and to the direction of travel of the disturbance. Maxwell’s machinery is predicting transverse waves.

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6. Electromagnetic Waves (continued) 6.2 Maxwell (continued)

Speed of travel of ‘Vortex’ waves Maxwell derived a formula for the speed at which the transverse waves would travel, in terms of the stiffness and the density of the vortex material. But for Maxwell’s ‘machinery’ to reproduce electromagnetic effects properly, the stiffness and density had to be expressible in terms of constants which appear in the equations of electromagnet-ism. The wave speed formula could then be written (using modern notation) as

V = 1

μ0 ε0 μ0 is the permeability of free space, and ε0 is the permittivity of free space. V is the speed of the waves in so-called empty space, where there is nothing (except vortices and idlers!)

Maxwell evaluated the right hand side of this formula using electrical measurements which had already been made (in Germany). He found: V = 310 740 000 000 millimetres per second. He also noted the speed of light, as measured fairly recently in France: VL = 314 858 000 000 millimetres per second. He then remarked, in one of the most famous sentences in the history of Physics: “The velocity of transverse waves in our hypothetical medium, calculated from the electro-magnetic experiments of MM. Kohlrausch and Weber, agrees so exactly with the velocity of light calculated from the optical experiments of M. Fizeau, that we can scarcely avoid the inference that light consists in the transverse undulations of the same medium which is the cause of electric and magnetic phenomena.”

The Cheshire Cat The equations relating to Maxwell’s ‘machinery’ could be expressed as relationships between electromagnetic quantities. Most of them were versions of the known laws of electromagnetism, such as Coulomb’s Law and Faraday’s Law of electromagnetic induction. One sub-set of the equations, though, was entirely new. It contained the idea that a changing electric field had lines of magnetic force curling around it. Maxwell realised that the equations contained everything that his machinery had to say about electromagnetism. He kept using the equations and stopped referring to the machinery. [Recalling Alice’s Adventures in Wonderland, someone later commented that the Cheshire Cat had disappeared, but its grin remained.] In fact Maxwell still believed that electromagnetic influences did travel by means of a medium, but he stopped investigating the workings of any particular hypothetical medium. The equations themselves are enough to predict transverse waves. The waves emitted from a charge oscillating up and down can be represented as shown, at one instant. An instant later the ‘profile’ of electric and magnetic fields will have moved to the right. Following the

spirit of Maxwell’s equations, we explain their propagation in this way.. The changing electric field gives rise to a (changing) magnetic field [Maxwell’s discovery] and the changing magnetic field gives a (changing) electric field [Faraday’s discovery], and the changing electric field gives a changing magnetic field and so on. Maxwell was claiming that this was light!

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6. Electromagnetic Waves (continued)

6.2 Maxwell (continued)

Self-test Questions (1) Find out in which country was Maxwell born and brought up.

(2) What was Maxwell trying to do, when he invented his ‘medium’ of vortices and idlers?

(3) (a) What was different in Maxwell’s medium when there was a magnetic field? (b) What, in terms of vortices, gave the direction of the field? (c) And what gave the magnitude of the field strength?

(4) What, in terms of vortices and idlers, was an electric field?

(5) What two properties of the vortex medium determined the speed at which waves would propagate?

(6) Explain the remark about the Cheshire cat. What does its grin represent? (www.ruthannzaroff.com/wonderland/Cheshire-Cat.htm )

(7) (a) Was anything important lost when Maxwell ‘ditched’ the machinery of the vortex medium and just kept the equations?

(b) Do equations explain things?

(c) What counts as an explanation in Science?

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6. Electromagnetic Waves (continued)

6.3 Hertz

Maxwell’s work commanded great respect, but by no means everyone was convinced it was correct. What in particular was needed was a direct experimental demonstration that electrical oscillations could give rise to transverse waves. This, and more, was provided by Heinrich Hertz between 1887 and 1889. Hertz was working with very high frequency electrical oscillations produced by the apparatus shown in replica on www.sparkmuseum.com/HERTZ.HTM.

When a spark occurred between the small spheres the air in the gap between them had ‘broken down’ and become a conductor. There was a current in the air gap and the rods either side. This current dropped to zero, reversed in direction, rose to a maximum, fell to zero, reversed and so on. The frequency of these electrical oscillations was determined by the system’s inductance (mainly due to the rods) and its capacitance (mainly due to the large spheres). Hertz estimated the frequency to be 108

cycles per second.

When the sparking occurred, Hertz could also see sparks jumping across a narrow gap in a wire ring, even when the ring was a few metres away. Further investigation strongly suggested that transverse waves were involved.

Hertz modified his apparatus to improve its range and precision. The ‘transmitter’ lost its large spheres, and the oscillation frequency increased by about 10 times. Hertz found that the ‘radiation’ could be concentrated into a beam using a concave metal reflector. [See diagram (size of rods and spheres exaggerated).] To detect the radiation he started using a pair of straight wires with an offset spark gap. The gap could be adjusted with a micrometer screw. The longer the sparks he could get, the

stronger the electric field.

Stationary Waves Hertz placed a large flat metal sheet in front of the transmitter and facing it. He moved the detector between the transmitter and the sheet and reported very distinct maxima and minima. He could distinguish nodal points at the wall and at 33, 65 and 98 cm distance from it. He concluded that interference was taking place, leading to a standing wave pattern. Here was clear wave-like behaviour.

• Which two ‘streams’ of waves were interfering? • What wavelength was Hertz using? • What was the frequency of the oscillations? • Which devices in the 21st century use this sort of frequency? ‘v.h.f.’ radios, televisions with traditional (spiky) aerials, or microwave ovens?

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6. Electromagnetic Waves (continued) 6.3 Hertz (continued)

Polarisation No sparking occurred in the detector when it was turned so its wires were horizontal, as shown. Hertz deduced that the waves were polarised, with the electric field direction parallel to the rods in the transmitter (as predicted by Maxwell’s equations). Clearly they were transverse waves. With the detector wires vertical again, Hertz interposed a grille of parallel wires between the transmitter and detector. The detector sparking was unaffected when the wires were horizontal, but no sparks could be had when the grille was turned so that the wires were vertical.

• What special material, containing parallel molecules, can do for light what Hertz’s grille of wires did for u.h.f. waves?

Refraction Hertz’s account (translated by D E Jones) began

“In order to find out whether any refraction of the ray takes place in passing from air to another insulating medium, I had a large prism made of so-called hard pitch, a material like asphalt. The base was an isosceles triangle 1.2 metres in the side, and with a refracting angle of nearly 30°. The refracting edge was placed vertical, and the height of the whole prism was 1.5 metres. But since the prism weighed about 12 cwt [600 kg or 0.6 tonne], and would have been too heavy to move as a whole, it was built up of three pieces, each 0.5 metres high, placed one above the other.”

What Hertz found is summarised in the plan above. Observe that he was now using a concave reflector

behind his detecting wires as well as behind the transmitting rods. • Hertz calculated the refractive index of the pitch as 1.69. Check this figure, by drawing relevant

normals and calculating angles. Note the symmetry.

Consequences Hertz’s findings were soon accepted as establishing the reality of electromagnetic waves. The possibility of using the waves for communication was taken up by several people, most famously by Guglielmo Marconi. On 12th December 1901, he reported that signals sent from Cornwall had been received in Newfoundland. And now we have radio, television and mobile phone technology, all based on electromagnetic waves.

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7. Assault on the Ether 7.1 The Triumph of the Ether? If light is a wave, surely it has to have a medium to travel in? This was the compelling reason for belief in the existence of a ‘luminiferous ether’ from about 1820 onwards. [Revise section 4.4] In the 1860’s Maxwell showed that a medium with the right structure might be able to account for electromagnetic effects – of which light was one. Hertz’s work in the late 1880s seemed to confirm Maxwell’s ideas. At least in Britain, few physicists doubted the existence of the ether, though its structure was … debatable.

There was no direct evidence for the ether’s existence. But Maxwell realised that in principle such evidence was available… Since the time of Galileo people had stopped believing that the Earth was the stationary centre of the universe, so it would be odd to think of the ether as stationary relative to the Earth. Stationary relative to the Sun seemed a much better bet. So as the Earth moves round the Sun it is presumably also moving through the ether, and the motion is in principle detectable. • The Earth’s orbit is roughly a circle of radius 1.5 × 1011m. Show that the Earth’s orbital speed is

3.0 × 104 m s−1. What is this as a fraction of the speed of light?

7.2 The Michelson Morley Experiment (1887) The challenge of detecting the motion of the Earth through the ether was taken up in America by Albert Michelson. (http://nobelprize.org/nobel_prizes/physics/laureates/1907/michelson-bio.html )

Michelson designed a piece of apparatus which came to be called an interferometer. The semi-silvered plate acted as a beam-splitter, so light travelled from source to telescope by two routes: SOAOT and SOBOT. Interference occurred between the light taking the different routes. Suppose that the apparatus happened to be orientated so that the interferometer was moving to the left

through the ether. This is equivalent to the ether moving to the right past the apparatus, at velocity v, say. [Think of a plane in a wind-tunnel.] As a result the observed interference pattern was expected to change if the apparatus was turned about a vertical axis (see next page).

After an inconclusive first experiment, Michelson, joined by E.W. Morley (who had been making precision measurements in a quite different area of science), redesigned the apparatus. It was now mounted on a massive concrete block, floating in mercury, so it could be turned smoothly and was not affected too badly by vibrations. By using multiple reflections, the effective length, L, of each arm, OA and OB, was made to be 11 m.

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7. Assault on the Ether 7.2 The Michelson Morley Experiment (Continued)

Light taking the route OAO ‘Ordinary’ waves, such as sound waves, travel at a fixed speed relative to their medium, so it was assumed that light would travel at a fixed speed, c, relative to the ether. If the ether is itself rushing past the apparatus at velocity v then the light should travel ‘downstream’ (OA) at velocity (c + v) and ‘upstream’ (AO) at velocity (c – v) relative to the apparatus (vector addition). The total time for the light to travel OAO is therefore

If there were no ‘ether wind’ the total time for AOA would be 2Lc

L

c − v + Lc + v

So the extra time taken to travel AOA because of the ether wind’ is

OAO

2L Lt

c v c v cΔ = + −

− +

L

Putting L = 11 m, c = 3.00000 × 108 m s−1, and v = 3.0 × 104 m s−1 [Why?] gives 16

OAO 7.3 10 st −Δ = × • You should check this. Try also using a better figure for c e.g. c= 2.99792 × 108 m s−1.

Light taking the route OBO In this case the ether wind is at right angles to the ‘forward’ and ‘back’ paths OB and BO. According to vector addition the velocity of light relative to the apparatus is reduced. However the delay due to the ether wind turns out to be only half as much as for OAO.

In other words 16

OBO 3.6(5) 10 st −Δ = ×

So light will return to O, and from there to the telescope, in a shorter time via B than via A. The difference in times is (ΔtOAO – ΔtOBO) which is 3.7 × 10-16 s. Michelson and Morley took the wavelength of the light as 5.5 × 10-7 m, corresponding to a frequency of 5.5 × 1014 cycles per second (5.5 × 1014 Hz). Number of cycles occurring in 3.7 × 10−16 s = 5.5 ×1014 Hz × 3.7 × 10−16 s = 0.20 cycles

Expected results and actual results The light travelling via A is therefore delayed by 0.2 cycles compared with that via B. Suppose that the apparatus is turned through 90°. The route OBO will now be the slower one, so the change in delay will be 0.2 cycles – (–0.2 cycles) = 0.4 cycles. If, in the original orientation, A had been moved a minute amount towards O so as to give full constructive interference between the light travelling the two routes, then on turning the apparatus through 90° there would be almost complete destructive interference.

In fact, Michelson and Morley had the apparatus adjusted so that A and B were not quite at right angles to each other. This meant that the telescope revealed a pattern of parallel bright and dark fringes much like Young’s fringes. When the apparatus was rotated through 90°, a 0.4 cycle change in delay would make the fringe pattern shift by 0.4 of a fringe, so a bright fringe would almost be replaced by a dark one and vice versa.

In fact hardly any fringe shift was observed. But OA might not have been parallel to the ether wind in the first place, so Michelson and Morley kept the apparatus slowly turning, and examined the fringe pattern at 16 orientations of the apparatus. They repeated the observations at different times of day and night and at different times of year. The maximum shift they found was about 0.01 of a fringe. This was, to all intents and purposes, negligible.

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7. Assault on the Ether

7.3 After Michelson Morley

What do scientists do when a successful theory is contradicted by experimental evidence? Give up the theory? This is not usually the first response. It certainly wasn’t when the Michelson Morley experiment gave a null result. Rather than give up the idea of the ether, physicists tried to think up explanations for why the ether did not show up in the experiment. Here are the two most famous… • The ether in the neighbourhood of the Earth is dragged along by the Earth, rather as a moving ship

is surrounded with a layer of stationary water. So even though the Earth is moving around the Sun, and even if the whole solar system is moving through the ether, there will be no ether wind on the Earth’s surface.

The trouble with this idea was there were other effects which the ether theory could explain, but only if the ether moved freely past the earth! [For interest only: the main such effect was ‘stellar aberration’, which is explained in Banesh Hoffmann’s book, Relativity and its Roots – even though ‘aberration’ is not in the index.]

• As well as the ether wind changing the velocity of light relative to the interferometer, it also changes the shape of the interferometer in a way which exactly neutralises the extra delay on the upstream-downstream arm due to the velocity changes. This idea was put forward in 1889 by George Fitzgerald, who was working in Dublin.

A similar explanation was offered independently by the Dutch physicist Hendrik Lorentz some three years later. He claimed that the only change in shape was a contraction of the ‘upstream-downstream’ arm. Using Maxwell’s equations, and making various assumptions about electrons and the role of electromagnetic forces in holding matter together, he argued that all objects should contract in the direction parallel to the ether wind.

7.4 Einstein

(http://www-groups.dcs.st-and.ac.uk/~history/Biographies/Einstein.html) Albert Einstein was barely known to the world of Science until, in 1905, at the age of 26, three major papers by him were published in the prestigious German scientific journal Annalen der Physik. They have been described as setting the agenda for Physics for the next hundred years.

The first paper contained the curious notion that light might sometimes behave as if it consisted of packets of energy, and the prediction of the photo-electric equation. The second showed how to demonstrate the existence of molecules by observations on Brownian motion.

The third paper was called (in translation) On the Electrodynamics of Moving Bodies. It lays the foundations of what is now called the Special Theory of Relativity.

The theory takes two innocent-looking starting points, oruthlessly logical fashion, to come to some momentous conclusions. The first postulate is the Principle of Relativity…

r ‘postulates’ and builds on them in a

7. Assault on the Ether

7.4 Einstein (Continued) The Principle of Relativity The laws of Physics are the same in all inertial frames of reference. All such frames are equivalent.

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The Principle generalises the finding that mechanics experiments give exactly the same readings when performed in a laboratory on a smoothly moving, non-accelerating train or aircraft as they do in a ‘stationary’ laboratory. The train and the plane are (approximately) ‘inertial’ frames of reference – ones in which a body at rest stays at rest, provided no resultant force acts on it. Inertial frames are the only ones we use in A-Level Physics. The generalisation that Einstein makes is that all laws of Physics, including those of electromagnetism and light, hold good in all inertial frames. There is no privileged ether frame of reference, and in all inertial frames of reference light travels through empty space at speed c given by

0 0

1c

ε μ=

But suppose the light source is moving towards the observer (in a laboratory equipped with rulers and light-activated clocks accurate to the picosecond!). This is the same thing as saying that the observer is moving towards the light source. Will the observer then measure a larger speed for the light? Not according to Einstein…

Second Postulate The speed of light is independent of the motion of its source. • The Michelson Morley experiment was repeated in the 1920s using starlight and sunlight, rather

than a lamp in the laboratory. What was the point of doing these further experiments? [Again, no directional differences were observed.]

The time of an event To deduce things from the postulates we have to be very precise about what we mean by the time when an event takes place. Einstein wrote [translated from the German]… We have to take into account that all our judgements in which time plays a part are always judgements of simultaneous events. If, for instance, I say, “That train arrives here at 7 o’ clock.”, I mean something like this: “The pointing of the small hand on my watch to 7 and the arrival of the train are simultaneous events.”. It might appear possible to overcome all the difficulties attending the definition of ‘time’ by substituting ‘the position of the small hand of my watch’ for ‘time’. And in fact such a definition is satisfactory when we are concerned with defining a time exclusively for the place where the watch is located, but it is no longer satisfactory when we have to connect in time a series of events occurring in different places. The way to deal with the problem is to have a clock at every place where an event might happen – and to make sure the clocks are synchronised. We can in principle put a whole line of clocks down the laboratory (or, if needed, a three-dimensional array of clocks).

Suppose we have a line of clocks at intervals of 0.30 m… How do we synchronise them? Before starting them we could adjust their displays to read 0.0, 1.0 ns, 2.0 ns and so on as we go from left to right along the line. We then trigger them to start by a light signal originating at the left hand end of the line and travelling down the line past each clock. • How does this work? How long does it take the light signal to travel 0.30 m?

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7. Assault on the Ether 7.4 Einstein (Continued) A though-experiment We shall look at the consequences of Einstein’s postulates in one specific case, where we can imagine an experimental set-up and work out what – according to the postulates – must happen. In other words we shall do a thought-experiment (or Gedankenexperiment). [The term is believed to have been invented by Ørsted!] Suppose a light flashes close to the end, A, of a rod of length L. The flash triggers a nearby clock to start. The light reflects off a mirror at the other end, B, of the rod. When it has returned to A it triggers the clock to stop. If the clock records a time interval Δτ between the events of the light leaving A and returning to A, then:… 2L = c Δτ. Now suppose that the rod is actually moving through a laboratory at speed v at right angles to itself. [This won’t affect the previous equation, since this was written for the rod’s own frame of reference.] In the laboratory frame of reference the light travels the path PQR (see diagram below).

Clearly in the laboratory frame the light has had to travel further between its leaving the end A of the ruler and its arriving back there. But the speed of light is the same in all frames. So the time, Δt, between the light leaving A and the light returning to A must be greater than the time, Δτ, between the same two events as measured in the rod’s frame of reference. This effect is called time dilation. Time intervals are different for different observers!

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7. Assault on the Ether

7.4 Einstein (Continued) A thought experiment (continued) How different are the time intervals measured in the two frames? It is easy to find out… In the laboratory frame the rod moves a distance v Δt in the time Δt. But the light has travelled distance c Δt. So, applying Pythagoras’s theorem to either of the two right angled triangles in the diagram…

( ) ( )2 22 1 12 2L c t v t= Δ − Δ

12 cΔτ( )2

= 12 cΔt( )2

− 12 vΔt( )2

Substituting for L from the rod frame equation,

( ) ( ) ( )2 21 1 12 2 2c c t vτΔ = Δ − Δ

2t

2tΔ

Doing the squarings and multiplying through by 4,

( ) ( ) ( )2 22 2 2c c t vτ = −Δ Δ that is ( ) ( )( )2 22 2 2c c vτ = tΔ − Δ

Dividing both sides by c2 and then taking the square roots of each side, ( ) ( )( )2

2

2 21 vc

tτΔ = − Δ so

2

21 vc

tτΔ = − Δ

Finally, dividing both sides by the square root,

2

21 vc

t τΔΔ =

• Try to calculate Δt if Δτ = 1.000000000 ms and v = 1000 ms-1. Check that your calculator gives Δt = 1.000000000 ms. Time dilation doesn’t show up, even to 10 significant figures, for a relative velocity of three times the speed of sound between the frames of reference. No wonder it is such an unfamiliar idea!

• But for relative velocities approaching the speed of light the effect is large. Calculate Δτ if Δτ = 1.00 ms and v = 3/5 c.

• The formula doesn’t just apply to this set-up, or just to flashes of light. The time interval between any two events is greater in a frame of reference in which the events occur in different places than in the frame in which they occur at the same place. The time interval in this latter frame is called the proper time interval, Δτ.

• The effect has been confirmed by experiment and the formula checked. (www.youtube.com/watch?v=gdRmCqylsME : a bit incoherent, but gives the idea.)

What causes time dilation? Are measurements made in the rod’s frame of reference invalid because it is moving? No, all inertial frames of reference are equivalent; none is favoured. In any case, an exper-imenter on the rod is perfectly entitled to say that it is the laboratory which is moving! Has the electronics of the rod’s clock been affected by its motion? No; the laws of Physics are the same in all inertial frames. Nothing is different about the way the clocks run in the two frames. Anyway, in the rod’s frame it is the laboratory clocks that are moving. So what does cause time dilation? It is the non-independence of space and time, as acknowledged in the term, space-time. The time interval between two events is least when measured in a frame of reference in which the events occur at the same place. It is greater in a frame of reference in which the events occur in different places, and there-fore have to have their times recorded by different clocks. [Note the line of synchronised clocks shown in the laboratory frame diagram.] [In fact what stays the same for two events if we go from one inertial frame to another is the quantity c2 (Δτ)2 = c2(Δt)2 – (Δx)2– (Δy)2– (Δz)2. This looks a bit like Pythagoras’s theorem in 4 dimensions, which is why time is sometimes called the fourth dimension.]

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7. Assault on the Ether

7.4 Einstein (Continued) Special Relativity results: not for learning

The time dilation thought-experiment was, as promised in the introduction, a small taste of Special Relativity theory – but no more than a taste. Many other results, some of them equally extraordinary, can also be deduced from the two postulates. The results include…

• Events which are simultaneous at different places in one frame of reference are generally not simultaneous in other frames (moving with respect to the first).

• A ruler stationary in one frame of reference is shorter in any other frame moving parallel to the ruler.

This might remind the alert reader of the idea of Fitzgerald and Lorentz (section 7.3) that the upstream-downstream arm in the Michelson Morley experiment was shortened by its motion through the ether. In fact some of Lorentz’s mathematics was very similar to Einstein’s – and published before 1905, but his interpretation of the equations was very different. For example, Lorentz argued that the ruler would be contracted in length compared with its length if stationary in the ether frame of reference. According to Relativity theory there is no such special frame.

• Lengths at right angles to the relative velocity between frames of reference are the same measured in either frame. We have already assumed this. Where?

• No object can move faster than the speed of light – in any frame.

• Some of the formulae of Newtonian mechanics have to be altered. The alterations usually only make any significant difference for bodies moving very fast indeed (say above 1.0 × 106 m s-1).

• Mass and energy are equivalent. The conversion factor between units is c2.

• Maxwell’s equations are valid in all frames of reference, not just in one special ether frame, as Maxwell and Hertz believed.

• The strengths of components of magnetic and electric fields vary according to reference frame. We illustrate this with a thought-experiment…

If you want to learn more, Relativity and its Roots by Banesh Hoffmann is helpful. Should you want to do some serious study, consider an internet search for a secondhand copy of An Introduction to Special Relativity by James H Smith.It’s an old book (first published 1965) but it’s down to earth and the explanations are very clear.

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GCE AS and A PHYSICS Teachers' Guide 142 7. Assault on the Ether 7.5 Einstein (Continued) Electrons moving side-by-side: a thought-experiment

Suppose two electrons emerge simultaneously with the same high velocity from electron guns side by side. The electrons will repel each other so their paths will diverge.

Consider the ‘top’ electron. Home in on two events: (a) the electron leaves the gun, and (b) the electron hits a target, having been displaced upwards a very small distance, y, by the action of the repulsive force. In the laboratory frame (left hand diagram) these events are spatially far apart, and the time interval, t, between them is ‘improper’. Now imagine we could ride along with the electrons, keeping pace with their horizontal motion (and clutching a clock!). In this new frame of reference (the ‘electrons’ frame’), events (a) and (b) are only slightly separated in space (by distance Δy). The time interval between the events is to all intents and purposes the proper time, Δτ. Since Δt is greater than Δτ we must conclude that the repulsive force between the electrons is less in the laboratory frame than in the electrons’ frame. The force reduction will be very small unless the electrons’ speed approaches the speed of light. Is this some weird new phenomenon? No – we can predict it from A-Level Physics, by a quite different line of reasoning… We first note that in the electron’s frame, the only force between the electrons is the repulsive Coulomb force or electrostatic force. [Gravitational forces are negligible.] In the laboratory frame the repulsive Coulomb force acts, but there is also an attractive force, because moving charges constitute electric currents, and like currents attract. We could call this the Ampère force. [See section 5.2.] We could also call it the magnetic force, because each electron sets up a magnetic field and the other electron moves through this field and experiences a Motor Effect (BIl) force. This Ampère force is much smaller than the Coulomb force unless the electrons’ speed is approaching that of light. All the same, the resultant force between the moving electrons will be slightly less than that between stationary electrons. But we arrived at this conclusion by a time dilation argument, without any appeal to Ampère forces: that is to magnetic forces. It looks as if the only fundamental force between charges is the Coulomb force, and magnetic forces are an effect due to measuring the force between charges in certain reference frames. Quite an insight!

[To tell the whole truth, electric fields strengths also, generally, change according to the frame of reference. In the thought-experiment, the repulsive Coulomb force between the electrons is actually slightly increased when they are moving relative to us. But the attractive Ampère force is a greater effect. If we take account of both effects the reduction in repulsive force turns out to be exactly as calculated from the time dilation argument.]

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7. Assault on the Ether

7.6 Einstein (Continued)

Relativity and the Ether Clearly, if all inertial frames of reference are equivalent and the speed of light (in empty space) is the same in all frames, then the Michelson-Morley experiment would have had to give a null result: there being no difference in the speed of light to detect!

• It would, though, be misleading to say that the Special Theory of Relativity explains the null result of the experiment. Why?

Einstein was motivated at least as much by wanting to tidy up the theory of electro-magnetism as by the null result of the Michelson-Morley experiment. In particular he did not like the idea of equations which were valid only in a special frame of reference.

The Special Theory of Relativity held together well and made predictions which were confirmed in the years that followed. The theory made no use of the idea of an ether, and took as a starting point the non-existence of a special ether frame of reference. Physicists came to see the ether as being of no use in explaining anything. They stopped believing in it.

• Why, in the first place, did the ether become such an important part of nineteenth century thinking on light? What role was it supposed to play?

• What major discovery arose from using an ether theory of electromagnetic fields?

Some quick Revision

(1) Name the two scientists who did most to establish the wave theory of light between 1800 and 1820.

(2) Name three scientists who made discoveries in electromagnetism between 1820 and 1840, and make summaries of what they discovered.

(3) Whose concept in (electro)magnetism did James Clerk Maxwell build upon when he started to develop his idea of a vortex medium? What was the concept?

(4) What was the inference from the calculated value of 0 0

1μ ε

which, according to Maxwell, ‘we

can scarcely avoid’?

(5) What were Einstein’s two postulates on which he based the Special Theory of Relativity?

(6) What is meant by time dilation?

What happened next? In the 21st century we still believe that light travels like a wave, with oscillating electric and magnetic fields, and that it doesn’t need a medium. When it comes to understanding how light interacts with matter we need to think of light as photons. The most highly developed theory we have in Physics is called Quantum Electrodynamics (QED). It explains electromagnetic forces in terms of the exchange of photons. If you’re remotely interested, read: QED: The Strange Story of Light and Matter by Richard Feynman. He was one of the inventors of the theory, a colourful character, a brilliant teacher and writer – and one of the greatest physicists of the twentieth century.

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Appendix C Superalloys Notes

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INTRODUCTION Aircraft jet engines are required to operate within extreme conditions of temperature and pressure. Jet engine turbine blades rotate at a typical speed of 10,000 rpm for long periods in an environment of combustion products at working temperatures of 1250 ºC (though the inlet temperatures of high performance engines can exceed 1650 ºC), non aviation gas turbines operate at approximately 1500 ˚C. The blades must be able to withstand impact and erosion from debris drawn in with the air stream. In addition, different parts of the blade may be at different temperatures and they will be subjected to large and rapid temperature changes when the engine is started up and turned off. The following is a list of the properties required of the material from which the blades are made. CREEP RESISTANCE. Centripetal forces acting on the blade at high rotational speeds provide a considerable load along the turbine blade axis. Over prolonged periods of time this can cause creep. It becomes increasingly pronounced as temperature increases. Creep could cause a turbine blade to deform sufficiently that it might touch the engine casing. CORROSION RESISTANCE. Iron corrodes to form rust. At high temperatures, the presence of carbon dioxide, water vapour and other products of the combustion of fuel constitute a highly corrosive environment. TOUGHNESS. The blades must resist impact with debris passing through the engine. In addition, stresses generated by expansion and contraction, between different parts of the blade at different temperatures, must not give rise to cracking. MECHANICAL AND THERMAL FATIGUE RESISTANCE. Variations of gas pressure and temperature on different parts of a blade and mechanical vibrations, may generate cyclical stresses which can cause failure due to fatigue. METALLURGICAL STABILITY. The mechanical properties of metals can be modified by heat treatment. Blade materials must be resistant to such changes and the microstructure must remain stable at high temperatures. DENSITY. The density must be low to keep engine weight as low as possible. Metallurgists have developed superalloys to meet these stringent specifications. Nickel-based superalloys are able to withstand stresses of over 250 MPa for 30 hours at 850˚C with less than 0.1% irreversible creep. The alloy contains 18 constituents and its composition is shown below:

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Table 1: Composition of creep-resistant turbine blade superalloy Element/wt% Element/wt% Nickel Ni 59 Molybdenum Mo 0.25 Cobalt Co 10 Carbon C 0.15 Tungsten W 10 Silicon Si 0.1 Chromium Cr 9 Manganese Mn 0.1 Aluminium Al 5.5 Copper Cu 0.05 Tantalum Ta 2.5 Zirconium Zr 0.05 Titanium Ti 1.5 Boron B 0.015 Hafnium Hf 1.5 Sulphur S <0.008 Iron Fe 0.25 Lead Pb <0.005 Why the need for so many elements and what does each do? Alloying elements (re-introducing ‘foreign’ atoms such as carbon atoms in steel) disturb the regularity of the lattice and by doing so hinder the movement of dislocations. Also dislocations have difficulty in moving across grain boundaries. In superalloys, obstacles in the form of insoluble precipitates are introduced to hinder dislocation movement. Some elements are also introduced to reinforce grain boundaries. Some elements form a layer of oxide (Cr2O3 in this case) on the blade surface which greatly improves resistance to corrosion. Cobalt, tungsten and chromium are all soluble in Nickel (which crystallizes in a cubic closed pack or face centred cube structure). Their atoms are different in size from nickel atoms and they are distributed randomly throughout the nickel matrix – they are in solid solution and they produce irregularities in the crystal. Any irregularity in the crystal will hinder the progress of a dislocation. Strains set up around substitute atoms impede the movement of dislocations. As the temperature of a metal increases, creep becomes more pronounced. More vacancies are introduced as temperature rises and diffusion of atoms is easier. Additives which made diffusion more difficult, therefore, enhance creep resistance. Hard precipitates are more resistant to deformation. Their presence in a softer matrix makes it more difficult for planes to slip over one another. We can think of them as acting like boulders thrown into a stream to dam the flow of water. It is also difficult for dislocations to pass through regions with closely spaced hard precipitates. A dislocation passing through such a region has been compared with trying to blow up a balloon in a bird cage. It is difficult for the balloon membrane to pass through the bars. The dislocation is similarly confined by the precipitates in superalloys.

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Fig. 1 Effect of matrix strengtheners (precipitates) on dislocation movement Cobalt, tungsten and chromium thus act as matrix strengtheners. Aluminium and titanium react with the Nickel to form stable compounds such as Ni3Al and Ni3Ti. The crystal structure of Ni3Al and Ni3Ti have a similar packing arrangement to the original (Nickel based) matrix and do not disrupt the regularity of the original matrix to which they are bonded. However, these particles are extremely hard and are very resistant to sheer deformation. Metalurgists sometimes call this process the Gamma prime (γ’) phase. [Note: Molybdenum, tantalum, tungsten and titanium also form Carbides MoC, TaC, WC and TiC. These are very hard materials which can also act as obstructions to matrix deformation. ] Other Carbides, mainly based on Chromium (CrC3) accumulate at the grain boundaries in the matrix. It is believed that they strengthen these regions by reducing the formation of cracks which lead to failure. The grain boundaries become the source of weakness following the strengthening of the matrix. If they are filled with hard materials, which are firmly bonded to the grains, it becomes more difficult to shear the grains apart. Grain boundary strengtheners act rather like the cement in crazy paving. Some elements may have a number of functions in strengthening the alloy. Chromium is a good example. Chromium forms a layer of oxide (Cr2O3) on the blade surface which greatly improves resistance to corrosion. Table 2 summarises the purpose of each of the alloying elements. Table 2: Functions of different elements used in super-alloys Purpose Cr Al Co Mo W Ti Ta Nb Hf C B Zr Matrix strengheners Gamma prime formers Carbide formers Oxide scale formers Grain boundary strengtheners

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Processing developments Turbine blades were shaped by forging before the introduction of super-alloys, but the new materials were so hard that they could not be forged or easily shaped and so had to be produced by casting into moulds. Conventional (early) casting processes produced blades with a fire grain structure (fig. 3).

Fig. 3 Conventional as-cast grain structure The grains were formed during solidification in the casting mould. Each grain had a different orientation of its crystal lattice from its neighbours. The weakest parts of the structure were the grain boundaries and blade failure often occurred at these points due to slippage (under stress and creep). In the 1960s researchers at the jet engine manufacturer Pratt and Whitney set out to eliminate grain boundaries from turbine airfoils altogether. The first development was to produce blades with all the grains aligned parallel to the stress axis by a process called directional solidification. A mould of molten metal is enclosed in the hot zone of a furnace and the heat is gradually removed from the bottom of the mould. As the mould is gradually removed from the furnace, columnar grains develop along the axis (only) of the blade (fig. 4). The final result is a turbine airfoil composed of columnar crystals or grains running along the length of the blade. For the case of a rotating blade subjected to centripetal forces of the order of 20,000g, the grains are now aligned along the major stress axis. Their alignment strengthens the blade and eliminates intergranular crack formation in directions normal to the blade span. The improved creep properties of directional solidification blades allowed engine temperatures to be increased by approximately 50˚C with further improvement in efficiency.

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Fig. 4 Directionally solidified grain structure Building upon directional solidification, Pratt and Whitney reached the goal of eliminating turbine airfoil grain boundaries in the late 1960s. Complete elimination of grain boundaries has further advantages. A blade without grain boundaries is a single crystal. Creep resistance is improved and because there are no grain boundaries, the grain boundary strengtheners such as Carbon, Boron, Zirconium and Hafnium used in early superalloys are not needed. All these elements contributed to the lowering of the melting point of the blade. The development of single crystal blades has increased the melting temperatures of turbine blades by a further 150˚C 200˚C. Single crystal blades are grown by incorporating a geometrical construction called a ‘pigtail’ into the base of the mould. The pigtail is attached to the ‘starter’ crystal and is helical in construction. It admits only a few columnar crystals from the starter and only allows one crystal to emerge into the blade root, to start the single crystal structure of the airfoil itself. This early pioneering work has been taken over by other manufacturers and improved upon over the past 30 years. Yields (successfully manufactured single crystals with no defects) greater than 95% are now commonly achieved in the casting process. Early on, Pratt and Whitney investigated single-crystal turbine airfoil use in various jet engines. (One of the first was the J58, which powered the Lockheed SR-71 Blackbird). The very first actual engine use was in Pratt & Whitney’s JT9D-7R4 which received jet engine flight certification in 1982. This first single-crystal bladed engine powers the Boeing 767 and the Airbus A310. In jet engine use, single-crystal turbine airfoils have proven to have as much as nine times more relative life in terms of creep strength and thermal fatigue resistance and over three times more relative life for corrosion resistance, when compared to the original cast, granular blades. Modern high turbine inlet temperature jet engines with long life (that is, 25,000 hours of operation between overhauls) would not be possible without the use of single-crystal turbine airfoils. By eliminating grain boundaries, single-crystal airfoils have longer thermal and fatigue life, are more corrosion resistant, can be cast with thinner walls – meaning less material and less weight – and have a higher melting point temperature. These improvements all contribute to higher efficiencies.

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The newest chapter of the story is their recent introduction in new, large land-based gas turbines. Gas turbines used to produce electric power in the 200 to 400 MW range have turbine airfoils that can be 10 times larger than jet engine turbine airfoils. These large castings have had production problems in the industry, causing casting yields to go down, driving costs up. As an example, one 1999 study done for the U.S. Department of Energy, found that for a $6,000, 13.6 kg single-crystal blade, a 90 percent yield would raise the cost to $7,000, while a 20 percent yield would shoot unit costs up to $30,000 each. Much work has been going on in the casting industry to increase yields for these large turbine blades. General Electric’s 9H, a 50 Hz combined-cycle gas turbine, is the world’s largest. The first model went into service in 2003 at Baglan Bay on the south coast of Wales, feeding as much as 530 MW into the United Kingdom’s electric grid at a combined-cycle thermal efficiency just under 60 percent. The 9H, at 367,900 kg, has a first-stage single-crystal turbine vane with a length of 30 cm and first-stage single-crystal blade of 45 cm (the blade lengths in the PW JT9D-7R4 are about 8 cm). Each finished casting weighs about 15 kg and each is a single crystal airfoil. Paul Edwards. September 2007. References: Cooke (B) and Sang (D) (1989). Physics of Materials for A-level students (2nd ed). Leeds University. Leeds press. www.memagazine.org. A feature article by Longston (Lee.S); ‘Crown Jewels – these crystals are the gems of turbine efficiency’. Feb 2006.

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Appendix D Ductile Materials Notes

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The plastic behaviour of ductile metals Recap on terms: Elastic deformation is a change of size or shape which is reversed when the deforming stress is removed. If an object undergoes plastic deformation it doesn’t return to its original size or shape when the stress is removed, but suffers permanent set. The key to understanding the behaviour of ductile metals at stresses above the elastic limit lies in the almost perfectly regular nature of their structure. They are crystalline metals; that is they possess long-range order, consisting of metal ions arranged in flat planes. Each ion is surrounded by the same number of ions as all the others, usually 12, in an arrangement known as close packing. A two dimensional representation would be: In this diagram, the black circles represent ions of the lattice, and each is surrounded by 6 neighbours in the plane, and this is just part of one of the planes of ions, with other planes situated above and below it. The diagram below shows a (grey) plane of ions below. I’m not going to attempt adding a layer above! In these diagrams, the size of the ions should not be taken too seriously. It would be better to think of them as touching one another, but the diagrams are more difficult to cope with. The ions are bonded into the lattice by bonds between them. [If you’ve covered PH2 already, you may know that the “glue” that holds them in place comes from free conduction electrons which move around in the lattice, but that is an issue for another day!]

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In the rest of this article, we are going to be thinking more about the bonds between the atoms than about the atoms themselves, so it will be better to represent the planes of atoms like this: We are not going to be concerned with the precise atomic arrangement, so we’ll stick to a square array. The diagrams are easier to draw and to interpret. There are also horizontal bonds between the ions, but these have been left off to make the diagram simpler. Polycrystalline materials This is really a note for the purists. Strictly, we should refer to metals as polycrystalline, rather than crystalline. They consist of an interlocking mass of individual crystals. The orientations of the lattice planes in neighbouring crystals are independent of one another. Plastic ‘slip’ Sometimes textbooks describe plastic strain in terms of crystal planes sliding over one another. force Plane x Plane y

force According to this idea, when a force is applied, every atom in plane x has to break bonds with atoms in plane y and then form new ones with different atoms in plane y. This process does not happen however because is would requires stresses many times greater than obtained in practice. Real metals are not as strong as this model suggests. Edge dislocations can account for this difference. Edge dislocations No one puts these crystals together. They grow spontaneously as the molten metal cools down when it is smelted. Sometimes mistakes happen as the metal ions join the crystal. A frequent mistake – one every million atomic planes or so – is that half a plane of atoms is missed out. This is known as an edge dislocation [see next page].

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X

Edge dislocations are the key to plastic deformation. The secret is in the bonds around the ion X. These bonds are all under strain, so they are places of weakness. Suppose forces are applied to this region as in the diagram below: If the forces, F, are small, the horizontal bonds are stretched reversibly [if the force is removed, they contract again] and the material behaves elastically. If the forces become larger, the already strained bonds below and to the right of X [shown in red] are stretched even more and at some point, the Yield Point of the material, they snap making the dislocation migrate to the right:

X

F

F

Plane x

X

F

F

Plane

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If the same force that causes this movement continues to be applied, the dislocation carries on moving, through the snapping and reformation of bonds, until it reaches the edge of the crystal. In this way, the dislocation has moved from left to right through the crystal. It appears as if plane x and plane y have slipped over each other. However, it has been achieved more easily since only one (short) line of bonds, rather than a whole plane, has been broken at a time. The crystal is now more elongated in the horizontal direction. If the forces are removed, the dislocation does not move back as there is no force to make it do so, and so the deformation is permanent. In the plastic region of deformation, as the bonds are not being stretched, the material does not increase in volume as it stretches. It contracts laterally. This “necking” can be seen dramatically if the break point in a ductile fracture is examined. Signs of flow, rather like a fluid, can be seen around the break point. In the diagram, the crystal does not look dramatically longer than it did before, but imagine the effect of a large number of edge dislocations at the top of the crystal migrating to the right and a similar number of edge dislocation at the bottom moving to the left. The crystal is more elongated (in the horizontal direction). And finally [not for examination] Of course, this isn’t the whole story. With a small amount of increased stress, new edge dislocations can also be created; especially in locations where there is an atom missing from the lattice [it happens!] or an impurity atom has a different size from the others. The extra edge dislocations can produce more and more plastic strain as they migrate. For a fuller treatment see Gordon. Reference: THE NEW SCIENCE OF STRONG MATERIALS Why You Don't Fall Through the Floor

by J. E. Gordon London, 1976.

GCE Physics – Teacher Guidance 4 December 2007

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