2 senarai rumus add maths k2 trial spm sbp 2010
3
2 The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. Rumus-rumus berikut boleh membantu anda menjawab soalan. Simbol-simbol yang diberi adalah yang biasa digunakan. ALGEBRA 1 a ac b b x 2 4 2 − ± − = 8 a b b c c a log log log = 2 n m n m a a a + = × 9 T n = a + (n – 1)d 3 a m ÷ a n = a m-n 10 S n = 2 n [ 2a + (n – 1) d ] 4 ( a m ) n = a m n 5 log a mn = log a m + log a n 11 T n = ar 1 − n 6 log a n m = log a m – log a n 12 S n = 1 ) 1 ( − − r r a n = r r a n − − 1 ) 1 ( , r ≠ 1 7 log a m n = n log a m 13 , r a S − = ∞ 1 r < 1 CALCULUS / KALKULUS 1 2 y = uv, dx du v dx dv u dx dy + = v u y = , 2 v dx dv u dx du v dx dy − = 4 Area under a curve Luas di bawah lengkung = ∫ b a y dx or (atau) = ∫ b a x dy 3 dx du du dy dx dy × = 5 Volume generated / Isipadu janaan = ∫ b a y 2 π dx or ( atau) = ∫ b a x 2 π dy
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Transcript of 2 senarai rumus add maths k2 trial spm sbp 2010
2
The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. Rumus-rumus berikut boleh membantu anda menjawab soalan. Simbol-simbol yang diberi adalah yang biasa digunakan.
ALGEBRA 1 a
acbbx2
42 −±−=
8 a
bb
c
ca log
loglog =
2 nmnm aaa +=× 9 Tn = a + (n – 1)d
3 a m ÷ a n = a m-n
10
Sn = 2n [ 2a + (n – 1) d ]
4 ( a m ) n = a m n
5 loga mn = loga m + loga n
11 Tn = ar 1−n
6 loga n
m = loga m – loga n 12
Sn = 1
)1(−−
rra n
= rra n
−−
1)1(
, r ≠ 1
7 loga mn = n loga m 13 ,
raS−
=∞ 1 r < 1
CALCULUS / KALKULUS 1 2
y = uv, dxduv
dxdvu
dxdy
+=
vuy = , 2v
dxdvu
dxduv
dxdy −
=
4 Area under a curve Luas di bawah lengkung
= ∫b
a
y dx or (atau)
= ∫b
a
x dy
3
dxdu
dudy
dxdy
×=
5
Volume generated / Isipadu janaan
= ∫b
a
y 2π dx or ( atau)
= ∫b
a
x 2π dy
3
STATISTICS / STATISTIK 1
x =N
x∑ 7
∑∑=
i
ii
WIW
I
2 x =
ffx
∑∑
8 r
n P = )!(
!rn
n−
3 σ =
Nxx∑ − 2)(
= 2
2
xN
x−∑
9 r
nC = !)!(
!rrn
n−
4 σ =
∑∑ −
fxxf 2)(
= 2
2
xf
fx−
∑∑
10 11
P(A∪B) = P(A) + P(B) – P(A∩B) P(X = r) = rnr
rn qpC − , p + q = 1
5
m = L +
−
f
FN
m
21
C 12 13
Mean / Min , µ = np σ = npq
6 I =
0
1
× 100
14 Z =
σµ−X
GEOMETRY / GEOMETRI
1 Distance / Jarak
= 212
212 )()( yyxx −+−
4 Area of triangle / Luas segitiga
= )()(21
312312133221 yxyxyxyxyxyx ++−++
2 Midpoint / Titik tengah
(x, y) =
++
2,
22121 yyxx
5 6
22 yxr +=
22 yx
yxr
+
+=
∧ ji
3 A point dividing a segment of a line Titik yang membahagi suatu tembereng garis
(x, y) =
++
++
nmmyny
nmmxnx 2121 ,
4
TRIGONOMETRY / TRIGONOMETRI 1 Arc length, s = r θ
Panjang lengkok, s = j θ
8 sin (A ± B) = sin A cos B ± cos A sin B sin (A ± B) = sin A kos B ± kos A sin B
2 Area of sector, A = 2
21 r θ
Luas sektor, L = 2
21 j θ
9
cos (A ± B) = cos A cos B sin A sin B kos (A ± B) = kos A kos B sin A sin B
3 sin 2 A + cos 2 A =1 sin 2 A + kos 2 A =1
10 tan (A ± B ) = tan A ± tan B 1 tan A tan B
4
sec 2 A = 1 + tan 2 A
sek 2 A = 1 + tan 2 A
11 tan 2 A =
AA2tan1
tan2−
5 cosec 2 A = 1 + cot 2 A kosek 2 A = 1 + kot 2 A
12 A
asin
=B
bsin
=C
csin
6 sin 2A = 2 sin A cos A
sin 2A = 2 sin A kos A
13 a 2 = b 2 + c 2 – 2bc cos A
a 2 = b 2 + c 2 – 2bc kos A
7 cos 2A = cos2 A – sin2 A = 2 cos 2 A – 1 = 1 – 2 sin 2 A kos 2A = kos2 A – sin2 A = 2 kos 2 A – 1 = 1 – 2 sin 2 A
14 Area of triangle / Luas segitiga
= 21 ab sin C
