Lecture2_CFD_Course_Governing Equations [Compatibility Mode].pdf
160.9.1 Indet analysis force method...Write the n Compatibility Equations at Relevant Points Solve...
Transcript of 160.9.1 Indet analysis force method...Write the n Compatibility Equations at Relevant Points Solve...
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Analysis of Statically Indeterminate Structures Using the Force Method
StevenVukazichSanJoseStateUniversity
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Statically Indeterminate Structures
At the beginning of the course, we learned that a stable structure that contains more unknowns than independent equations of equilibrium is Statically Indeterminate.
• Redundancy (several members must fail for the structure to become unstable);
• Often maximum stresses is certain members are reduced;
• Usually deflections are reduced.
Advantages Disadvantages
• Connections are often more expensive;
• Finding forces and deflections using hand analysis is much more complicated.
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Steps in Solving an Indeterminate Structure using the Force Method
Determine degree of Indeterminacy Let n =degree of indeterminacy
(i.e. the structure is indeterminate to the nth degree)
Define Primary Structure and the n Redundants
Define the Primary Problem
Solve for the nRelevant
Deflections in Primary Problem
Define the nRedundant Problems
Solve for the nRelevant Deflections in each Redundant
Problem
Write the nCompatibility Equations at
Relevant Points
Solve the nCompatibility
Equations to find the n Redundants
Use the Equations of Equilibrium to
solve for the remaining unknowns
Chapter 3
Chapters 3,4,5 then 7 or 8
Construct Internal Force
Diagrams (if necessary)
Chapter 3
Chapters 3,4,5 then 7 or 8
Chapters 3,4,5
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Force Method of Analysis
EBA C
w P
Consider the beam
FBD
EBA D
w P
Ax
Ay
MA
Dy
X = 5
3n = 3(1) = 3
Beam is stable
Statically Indeterminate to the 2nd degree
EI D
C
Cy
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Define Primary Structure and Redundants• Remove all applied loads from the actual structure;• Remove support reactions or internal forces to define a primary structure;• Removed reactions or internal forces are called redundants;• Same number of redundants as degree of indeterminacy• Primary structure must be stable and statically determinate;• Primary structure is not unique – there are several choices.
EBA D
Primary Structure Redundants
MA
EBA DDy
EBA DMQ
C
C Cy
Cy
CyQ C
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Define and Solve the Primary Problem
• Apply all loads on actual structure to the primary structure;• Define a reference coordinate system;• Calculate relevant deflections at points where redundants were
removed.
DBA C
w Py
x
Δ"
EIE
Δ#
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Define and Solve the Redundant Problems• There are the same number of redundant problems as degrees of indeterminacy;• Define a reference coordinate system;• Apply only one redundant to the primary structure;• Write the redundant deflection in terms of the flexibility coefficient and the
redundant for each redundant problem.• Calculate the flexibility coefficient associated with the relevant deflections for
each redundant problem;
EBA
y
x
Δ##
EI D
Cy
EBA
y
x
𝛿##
EI D1
Δ## = 𝐶'𝛿##C
Δ"#
𝛿"#
C
Redundant Problem 1
Δ"# = 𝐶'𝛿"#
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Define and Solve the Redundant Problems
EBA
y
x
Δ#"
EI D
Dy
EBA
y
x
𝛿#"
EI D1
Δ#" = 𝐷'𝛿#"
C
Δ""
𝛿""
C
Redundant Problem 2
Δ"" = 𝐷'𝛿""
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Compatibility Equations
Δ# + Δ## + Δ#" = 0
Compatibility at Point C
Δ" + Δ"# + Δ"" = 0
Compatibility at Point D
Compatibility Equations in terms of Redundants and Flexibility Coefficients
∆# + 𝐶'𝛿## + 𝐷'𝛿#" = 0∆" + 𝐶'𝛿"# + 𝐷'𝛿"" = 0
Solve for Cy and Dy
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The Force Method is
Based on the Principle of
Superposition
IndeterminateProblem
PrimaryProblem
RedundantProblem 1
RedundantProblem 2
EBA C
w P
EI D
DBA C
w Py
xΔ"
EIEΔ#
EBA
y
x
Δ#"
EI DDy
C
Δ""
EBA
y
x
Δ##
EI DC
Δ"#
Cy
y
x
=
+
+
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Example Problem
AB
P
EI C
𝐿2
𝐿2
y
x
For the indeterminate beam subject to the point load, P, find the support reactions at A and C. EI is constant.
A B
P
EI C
𝐿2
𝐿2
y
xAx
Ay
MA
Cy
FBD
X = 4
3n = 3(1) = 3
Beam is stable
Statically Indeterminate to the 1st degree
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Define Primary Structure and Redundant• Remove all applied loads from the actual structure;• Remove support reactions or internal forces to define a primary structure;• Removed reactions or internal forces are called redundants;• Same number of redundants as degree of indeterminacy• Primary structure must be stable and statically determinate;• Primary structure is not unique – there are several choices.
BAC
Primary Structure Redundant
MA
BA CCy
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Define and Solve the Primary Problem
• Apply all loads on actual structure to the primary structure;• Define a reference coordinate system;• Calculate relevant deflections at points where redundants were
removed.
B
A C
Py
x
EI𝜃/
𝐿2
𝐿2
𝜃/ = −𝑃𝐿2
16𝐸𝐼
From Tabulated Solutions
+ Counter-clockwiserotations positive
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Define and Solve the Redundant Problem• There are the same number of redundant problems as degrees of indeterminacy;• Define a reference coordinate system;• Apply only one redundant to the primary structure;• Write the redundant deflection in terms of the flexibility coefficient and the
redundant for each redundant problem.• Calculate the flexibility coefficient associated with the relevant deflections for
each redundant problem;
𝜃// = 𝑀/𝛼//
Redundant ProblemBA C
y
x
EI𝜃//MA
BA Cy
x
EI𝛼//1
𝛼// = −𝐿3𝐸𝐼
From Tabulated Solutions
L
L
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Compatibility Equation at Point A
𝜃/ + 𝜃// = 0
Compatibility at Point A
Compatibility Equation in terms of Redundant and Flexibility Coefficient
𝜃/ +𝑀/𝛼// = 0
−𝑃𝐿2
16𝐸𝐼+ 𝑀/ −
𝐿3𝐸𝐼
= 0
𝑀/ =𝑃𝐿2
16𝐸𝐼−3𝐸𝐼𝐿
𝑀/ = −316𝑃𝐿
Solve for MA
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A B
P
EI C
𝐿2
𝐿2
y
xAx
Ay
MA
Cy
Free Body Diagram
𝑀/ = −316𝑃𝐿
A B
P
EI C
𝐿2
𝐿2
y
xAx
Ay Cy
316𝑃𝐿
Can now use equilibrium equations to find the remaining three unknowns
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Find Remaining Unknowns
:𝑀/
�
�
= 0+
:𝐹=
�
�
= 0+
:𝐹'
�
�
= 0+
Ax = 0
A B
P
EI C
𝐿2
𝐿2
y
xAx
Ay Cy
316𝑃𝐿
Can now use equilibrium equations to find the remaining three unknowns
𝐶' =516𝑃
𝐴' =1116𝑃
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+
+V
M0
Draw V and M Diagrams of the Beam
A B
P
EI C
𝐿2
𝐿2
y
x
316𝑃𝐿
516𝑃
1116𝑃
1116𝑃
−516𝑃
𝑀@ = −316𝑃𝐿 +
1132𝑃𝐿 =
532𝑃𝐿
𝑀@ − 𝑀/ =1116𝑃
𝐿2
−3𝑃𝐿16
532𝑃𝐿
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V
M 0
Superposition of Primary and Redundant Problems
A
C
P
B𝐿2
𝐿2
316𝑃𝐿
516𝑃11
16𝑃
1116𝑃
−316𝑃𝐿
532𝑃𝐿
P
12𝑃
14𝑃𝐿
316𝑃
−332𝑃𝐿
−12𝑃
12𝑃
12𝑃
316𝑃 3
16𝑃
316𝑃𝐿
−316𝑃𝐿
B B
0
IndeterminateProblem
PrimaryProblem
RedundantProblem= +
C CA A
0
−516𝑃
0