1 CS 140 Lecture 9 Sequential Networks Professor CK Cheng CSE Dept. UC San Diego.

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1 CS 140 Lecture 9 Sequential Networks Professor CK Cheng CSE Dept. UC San Diego
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Transcript of 1 CS 140 Lecture 9 Sequential Networks Professor CK Cheng CSE Dept. UC San Diego.

Page 1: 1 CS 140 Lecture 9 Sequential Networks Professor CK Cheng CSE Dept. UC San Diego.

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CS 140 Lecture 9Sequential Networks

Professor CK Cheng

CSE Dept.

UC San Diego

Page 2: 1 CS 140 Lecture 9 Sequential Networks Professor CK Cheng CSE Dept. UC San Diego.

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Combinational

CLK CLK

A B C D

Sequential Networks

1. Components F-Fs2. Specification3. Implementation: Excitation Table

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Specification

• Finite State Machine: – Input Output Relation– State Diagram– State Table

• Circuit: – Logic Diagram– Netlist– Boolean Expression

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Netlist State Table State Diagram Input Output Relation

y(t) = Q1(t)Q0(t)Q0(t+1) = D0(t) = x(t)Q1(t)Q1(t+1) = D1(t) = x(t) + Q0(t)

xQ0

Q1

DQ

Q’

DQ

Q’

y

Q1

Q0

D1

D0

Clk

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Netlist State Table State Diagram Input Output Relation

xQ0

Q1

DQ

Q’

DQ

Q’

y

Q1

Q0

D1

D0

y(t) = Q1(t)Q0(t)Q0(t+1) = D0(t) = x(t)Q1(t)Q1(t+1) = D1(t) = x(t) + Q0(t)

Clk

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State table

0 0 0 11 01 1

PSinput

x=0 x=1

00, 0 10, 010, 0 10, 000, 0 11, 010, 1 11, 1

Q1(t) Q0(t) Q1(t+1) Q0(t+1), y(t)

S0

S1

S2

S3

PSinput

x=0 x=1

S0, 0 S2, 0S2, 0 S2, 0S0, 0 S3, 0S2, 1 S3, 1

Let:S0 = 00S1 = 01S2 = 10S3 = 11

Remake the state table using symbols instead of binary code , e.g. ’00’

y(t) = Q1(t) Q0(t)Q0(t+1) = D0(t) = x(t) Q1(t)Q1(t+1) = D1(t) = x(t) + Q0(t)

Logic Diagram => State Table

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State Table => State Diagram

Example: Output sequence

S0

S1

S2

S3

PSinput

x=0 x=1

S0, 0 S2, 0S2, 0 S2, 0S0, 0 S3, 0S2, 1 S3, 1

x/y

S1 S2 S3S0

0,1/0 1/0

0/11/0

0/00/0

1/1

Time 0 1 2 3 4 5

Input 0 1 1 0 1 -

State S0 S0 S2 S3 S2 S3

Output 0 0 0 1 0 1

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y(t) = Q1(t)Q0(t)Q0(t+1) = T0(t) = x(t) Q1(t)Q1(t+1) = T1(t) = x(t) + Q0(t)

X

TQ

Q’

TQ

Q’

y

Q0

Q1

T0

T1

Example with T Flip-Flops

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Logic Diagram => Excitation Table => State Table

y(t) = Q1(t)Q0(t)T0(t) = x(t) Q1(t)T1(t) = x(t) + Q0(t)Q0(t+1) = T0(t) Q’0(t)+T’0(t)Q0(t)Q1(t+1) = T1(t) Q’1(t)+T’1(t)Q1(t)

id Q1(t) Q0(t) x T1(t) T0(t) Q1(t+1) Q0(t+1) y

0 0 0 0 0 0 0 0 0

1 0 0 1 1 0 1 0 0

2 0 1 0 1 0 1 1 0

3 0 1 1 1 0 1 1 0

4 1 0 0 0 0 1 0 0

5 1 0 1 1 1 0 1 0

6 1 1 0 1 0 0 1 1

7 1 1 1 1 1 0 0 1

Excitation Table

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id Q1(t) Q0(t) x T1(t) T0(t) Q1(t+1) Q0(t+1) y

0 0 0 0 0 0 0 0 0

1 0 0 1 1 0 1 0 0

2 0 1 0 1 0 1 1 0

3 0 1 1 1 0 1 1 0

4 1 0 0 0 0 1 0 0

5 1 0 1 1 1 0 1 0

6 1 1 0 1 0 0 1 1

7 1 1 1 1 1 0 0 1

Excitation Table =>State Table => State Diagram

0/0

S0 S1 S3

S2

0/0

1/1

0/1

0, 1/01/0

1/0

PS\Input X=0 X=1

S0 S0,0 S2,0

S1 S3,0 S3,0

S2 S2,0 S1,0

S3 S1,1 S0,1

State AssignmentS0 00S1 01S2 10S3 11

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Excitation Table =>State Table => State Diagram

0/0

S0 S1 S3

S2

0/0

1/1

0/1

0, 1/01/0

1/0

PS\Input X=0 X=1

S0 S0,0 S2,0

S1 S3,0 S3,0

S2 S2,0 S1,0

S3 S1,0 S0,1

Time 0 1 2 3 4 5

Input 0 1 1 0 1 -

State S0 S0 S2 S1 S3 S0

Output 0 0 0 0 1 0

Example: Output sequence

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Implementation: State Diagram => State Table => Netlist

Pattern Recognizer: A sequential machine has a binary input x in {a,b}. For x(t-2, t) = aab, the output y(t) = 1, otherwise y(t) = 0.

S1S0a/0

b/0

a/0

b/1

S2a/0

b/0

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State Diagram => State Table with State Assignment

State AssignmentS0: 00S1: 01S2: 10

PS\x a b

S0 S1,0 S0,0

S1 S2,0 S0,0

S2 S2,0 S0,1

PS\x 0 1

00 01,0 00,0

01 10,0 00,0

10 10,0 00,1

Q1(t+1)Q0(t+1), ya 0b 1

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State Table => Excitation Table

PS\x 0 1

00 01,0 00,0

01 10,0 00,0

10 10,0 00,1

id Q1Q0x D1D0 y

0 000 01 0

1 001 00 0

2 010 10 0

3 011 00 0

4 100 10 0

5 101 00 1

6 110 -- -

7 111 -- -

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0 2 6 4

1 3 7 5

x(t)

Q1

0 1 - 1

0 0 - 0

Q0D1(t):

D1(t) = x’Q0 + x’Q1

D0 (t)= Q’1Q’0 x’y= Q1x

id Q1Q0x D1D0 y

0 000 01 0

1 001 00 0

2 010 10 0

3 011 00 0

4 100 10 0

5 101 00 1

6 110 -- -

7 111 -- -

Excitation Table => Boolean Expression

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DQ

Q’

DQ

Q’

Q1

Q0

D1

D0

Q0

Q1

x’

D1(t) = x’Q0 + x’Q1

D0 (t)= Q’1Q’0 x’y= Q1x

x

y

Q’1

Q’0x’

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Canonical Form: Mealy and Moore Machines

Combinational Logic

x(t) y(t)

CLK

C2

C1

y(t)

CLK

x(t)

C1 C2

CLK

x(t)

y(t)

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Moore Machine: yi(t) = fi(X(t), S(t))Mealy Machine: yi(t) = fi(S(t))

si(t+1) = gi(X(t), S(t))

C1 C2

CLK

x(t)

y(t)

Mealy Machine

C1 C2

CLK

x(t) y(t)

Moore Machine

s(t) s(t)

Canonical Form: Mealy and Moore Machines

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Finite State Machine Example

• Traffic light controller– Traffic sensors: TA, TB (TRUE when there’s traffic)

– Lights: LA, LB

TA

LA

TA

LB

TB

TB

LA

LB

Academic Ave.B

rava

do

Blv

d.

Dorms

Fields

DiningHall

Labs

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FSM Black Box

• Inputs: CLK, Reset, TA, TB

• Outputs: LA, LB

TA

TB

LA

LB

CLK

Reset

TrafficLight

Controller

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FSM State Transition Diagram

• Moore FSM: outputs labeled in each state• States: Circles• Transitions: Arcs

S0LA: greenLB: red

Reset

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FSM State Transition Diagram

• Moore FSM: outputs labeled in each state• States: Circles• Transitions: Arcs

S0LA: greenLB: red

S1LA: yellowLB: red

S3LA: redLB: yellow

S2LA: redLB: green

TATA

TB

TB

Reset

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FSM State Transition Table

PS Inputs NS

TA TB

S0 0 X S1

S0 1 X S0

S1 X X S2

S2 X 0 S3

S2 X 1 S2

S3 X X S0

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State Transition TablePS Inputs NS

Q1(t) Q0(t) TA TB Q1(t +1) Q0(t +1)

0 0 0 X 0 1

0 0 1 X 0 0

0 1 X X 1 0

1 0 X 0 1 1

1 0 X 1 1 0

1 1 X X 0 0

State Encoding

S0 00

S1 01

S2 10

S3 11

Q1(t+1)= Q1(t) Q0(t)

Q0(t+1)= Q’1(t)Q’0(t)T’A + Q1(t)Q’0(t)T’B

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FSM Output TablePS Outputs

Q1 Q0 LA1 LA0 LB1 LB0

0 0 0 0 1 0

0 1 0 1 1 0

1 0 1 0 0 0

1 1 1 0 0 1

Output Encoding

green 00

yellow 01

red 10

LA1 = Q1

LA0 = Q’1Q0

LB1 = Q’1

LB0 = Q1Q0

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FSM Schematic: State Register

S1

S0

S'1

S'0

CLK

state register

Reset

r

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Logic Diagram

S1

S0

S'1

S'0

CLK

next state logic state register

Reset

TA

TB

inputs

S1 S0

r

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FSM Schematic: Output Logic

S1

S0

S'1

S'0

CLK

next state logic output logicstate register

Reset

LA1

LB1

LB0

LA0

TA

TB

inputs outputs

S1 S0

r