1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries...
-
date post
20-Dec-2015 -
Category
Documents
-
view
213 -
download
0
Transcript of 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries...
![Page 1: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/1.jpg)
1
Chain ladder for Tweedie distributed claims data
Greg TaylorTaylor Fry Consulting Actuaries
University of New South Wales Actuarial Symposium
9 November 2007
![Page 2: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/2.jpg)
2
Overview
• Description of chain ladder
• Previous maximum likelihood (ML) results
• Tweedie family
• ML results for Tweedie
• Convenient approximation for computation
• Separation method
![Page 3: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/3.jpg)
3
Description of chain ladder
![Page 4: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/4.jpg)
4
Data set-up and notation
• Familiar claims triangle• We are not specific about the nature of the
entries, e.g.• Counts
• Notifications• Finalisations • etc
• Amounts• Paid claims• Incurred claims• etc
![Page 5: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/5.jpg)
5
Data set-up and notation (cont’d)
Accident period i
Development period j
Incremental triangle
Entries Yij ≥ 0
Assume E[Yij] finite
![Page 6: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/6.jpg)
6
Data set-up and notation (cont’d)
Accident period i
Development period j
Incremental triangle
Entries Yij ≥ 0
Assume E[Yij] finite
Accident period i
Development period j
Cumulative triangle
Entries Sij ≥ 0
Sij = ∑jk=1 Yik
![Page 7: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/7.jpg)
7
Data set-up and notation (cont’d)
Accident period i
Development period j
Denote sum over row i by ∑R(i)
Denote sum over column j by ∑C(j)
Any triangle Denote sum over diagonal k by ∑D(k)
![Page 8: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/8.jpg)
8
Chain ladder formulation
• Assumption CL1:
E[Si,j+1 | Si1,Si2…,Sij] = Sij fj, j=1,2,…,n-1, independently of i for some set of parameters fj
• Assumption CL2: Rows of the data triangle are stochastically
independent, i.e. Yij and Ykl are independent for i≠k
• CL1 implies that E[Yij] = αiβj for parameters αi, βj
![Page 9: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/9.jpg)
9
Parameter estimation
• E[Si,j+1 | Si1,Si2…,Sij] = Sij fj
• fj estimated by
Fj = ∑n-ji=1 Si,j+1 / Sij [age-to-age factor]
• The Fj may be converted to estimates of αi, βj
βj = β1 [F1… Fj-2 (Fj-1 – 1)] [chain age-to-age factors]
αi = Si,n-i+1/∑R(i) βj
^
^^
![Page 10: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/10.jpg)
10
Previous ML results
![Page 11: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/11.jpg)
11
Over-dispersed Poisson error structure
Theorem. Suppose that Yij are independent, Yij ~ ODP(μij,φ) with μij = αiβj. Then ML estimates of αi, βj are given by precisely the chain ladder algorithm.
• Proved by Hachemeister & Stanard (1975) for simple Poisson
• Proved by England & Verrall (2002) for ODP
![Page 12: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/12.jpg)
12
Gamma error structure
• Suppose that Yij are independent, Yij ~ Gamma with mean μij = αiβj and CoV independent of i, j
• Mack (1991) derives reasonably simple ML equations
• However• They are not chain ladder
• They do not lead to closed form solutions
![Page 13: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/13.jpg)
13
Tweedie family
![Page 14: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/14.jpg)
14
Exponential dispersion family
• Exponential dispersion family (EDF) consists of those log-likelihoods of the form
ℓ(y;θ,λ) = c(λ)[yθ – b(θ)] + a(y,λ)
for some functions a(.,.), b(.) and c(.) and parameters θ and λ
![Page 15: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/15.jpg)
15
Tweedie sub-family
• EDFℓ(y;θ,λ) = c(λ)[yθ – b(θ)] + a(y,λ)
• Can be shown thatμ = E[Y] = b'(θ), Var[Y] = b''(θ)/c(λ)
• Tweedie sub-family given by restrictionsc(λ) = λ
Var[Y] = μp/λ for some p≤0 or p≥1This restricts b(.) to the form
b(θ) = (2-p)-1[(1-p)θ](2-p) / (1-p) • Denote this Y ~ Tw(μ,λ,p)
![Page 16: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/16.jpg)
16
Special cases of Tweedie
• Tweedie family
ℓ(y;θ,λ) = λ[yθ – b(θ)] + a(y,λ)
Var[Y] = μp/λ for some p≤0 or p≥1
• Special cases• p=0: Y ~ normal
• p=1: Y ~ ODP
• p=2: Y ~ gamma
• p=3: Y ~ inverse Gaussian
![Page 17: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/17.jpg)
17
ML results for Tweedie
![Page 18: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/18.jpg)
18
ML equations
Theorem. Suppose that Yij are independent, Yij ~ Tw(μij,λ/wij,p) for given wij, p with μij = αiβj. Then the ML equations for αi, βj are
∑R(i) wij μij1-p [yij – μij] = 0, i=1,…,n
∑C(j) wij μij1-p [yij – μij] = 0, j=1,…,n
![Page 19: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/19.jpg)
19
Special case: Y ~ ODP
• ML equations∑R(i) wij μij
1-p [yij – μij] = 0, i=1,…,n∑C(j) wij μij
1-p [yij – μij] = 0, j=1,…,n• Special case p=1 (Y ~ ODP) with wij=1 (same over-dispersion in all
cells)∑R(i) [yij – μij] = 0, i=1,…,n∑C(j) [yij – μij] = 0, j=1,…,n
• Equivalently ∑R(i) yij = ∑R(i) μij, i=1,…,n∑C(j) yij = ∑C(j) μij, j=1,…,n
• This is called marginal sum estimation• Row and column sums of the observations and the fitted values are set
equal• It may be shown that the chain ladder is a marginal sum estimator
![Page 20: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/20.jpg)
20
Special case: Y ~ ODP: summary
ML estimation
Marginal sum estimation
Chain ladder estimation
![Page 21: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/21.jpg)
21
General Tweedie case
• ML equations∑R(i) wij μij
1-p [yij – μij] = 0, i=1,…,n∑C(j) wij μij
1-p [yij – μij] = 0, j=1,…,n• Suppose weights take the form
wij = ui vj [includes the case wij=1]• Introduce the transformations
Zij = wij μij1-p Yij
ηij = wij μij2-p = uivj (αiβj)2-p = aibj
whereai = ui αi
2-p
bj = vj βj2-p
![Page 22: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/22.jpg)
22
General Tweedie case (cont’d)
• ML equations
∑R(i) wij μij1-p [yij – μij] = 0, i=1,…,n
∑C(j) wij μij1-p [yij – μij] = 0, j=1,…,n
• Transformations
Zij = wij μij1-p Yij
ηij = wij μij2-p = uivj (αiβj)2-p = aibj
• ML equations become
∑R(i) [zij – ηij] = 0, i=1,…,n
∑C(j) [zij – ηij] = 0, j=1,…,n
![Page 23: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/23.jpg)
23
General Tweedie case (cont’d)
• ML equations∑R(i) [zij – ηij] = 0, i=1,…,n∑C(j) [zij – ηij] = 0, j=1,…,n
• c.f. chain ladder∑R(i) [yij – μij] = 0, i=1,…,n∑C(j) [yij – μij] = 0, j=1,…,n
• So estimation in the general Tweedie case is carried out by applying the chain ladder to “observations” Zij = wij μij
1-p Yij
• This returns estimates of parametersai = ui αi
2-p
bj = vj βj2-p
![Page 24: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/24.jpg)
24
General Tweedie case (cont’d)
• Transformation of observations
Zij = wij μij1-p Yij requires knowledge of
estimand μij
• So ML equations are implicit in parameters
• No closed form solution
• Need to be solved iteratively
![Page 25: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/25.jpg)
25
General Tweedie case – iterative algorithm
• Implicit solution
Zij = wij μij1-p Yij
wij μij2-p = aibj
• Iterative solution• Denote r-th iterate of any quantity by
an upper (r), r=0,1,etc.
Z(r)ij = wij μ(r)
ij1-p Yij
• Apply chain ladder to data set {Z(r)ij}
to obtain estimates a(r+1)i, b (r+1)
j of parameters ai, bj
• Estimate new iterate μ(r+1)ij according
to
wij μ(r+1)ij
2-p = = a(r+1)ib(r+1)
j
• Repeat until convergence of {a(r)i,b(r)
j}
• Initiate iteration with a(0)i,b(0)
j given by standard chain ladder
![Page 26: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/26.jpg)
26
Special Tweedie cases
• p = 1, wij = 1 (ODP)
• p=0 (normal)
• p=2 (gamma)
• Zij = Yij
• Standard chain ladder (known)
Zij = wij μij Yij
Zij = wij [Yij / μij]
Zij = wij μij1-p Yij
![Page 27: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/27.jpg)
27
Numerical performance
• Speed of convergence declines as p increases above 1
• For one particular data triangle
p = Number of iterations
Convergence of loss reserve to
accuracy
1 1 0
2 5 0.05%
2.4 24 0.10%
![Page 28: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/28.jpg)
28
Convenient approximation for computation
![Page 29: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/29.jpg)
29
Approximation
• Transformed observations for general Tweedie are Zij = wij μij
1-p Yij to yield estimates of ai = ui αi2-p, bi =
vi βi2-p
• Implicitness of ML equations arises from the fact that Z involves estimand μ
• Approximation
μij ← Yij
Zij ← wij Yij2-p
• Perform chain ladder on these quantities to estimate• Note that approximation become meaningless at p=2
![Page 30: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/30.jpg)
30
Numerical performance
p= Error in approximation to outstanding liability
1.7 -6
1.9 -7
1.99 -8
2
2.01 -8
2.2 -9
2.4 -7
![Page 31: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/31.jpg)
31
Separation method
![Page 32: 1 Chain ladder for Tweedie distributed claims data Greg Taylor Taylor Fry Consulting Actuaries University of New South Wales Actuarial Symposium 9 November.](https://reader030.fdocuments.us/reader030/viewer/2022032704/56649d4a5503460f94a27389/html5/thumbnails/32.jpg)
32
Comparison of chain ladder and separation method
Chain ladder
μij = E[Yij] = αiβj
• Marginal sum estimation
∑R(i) [yij – μij] = 0
∑C(j) [yij – μij] = 0
Separation method
μij = E[Yij] = αi+j-1βj
• Marginal sum estimation
∑D(k) [yij – μij] = 0
∑C(j) [yij – μij] = 0
• Each chain ladder result has counterpart for separation method